This guy makes an interesting point that is not clear to me. Terry, Dave, Bob et al - what do you EEs who have looked at the input power think about this approach?
“The currents in the three C1 wires are all equal and they are measured by the true RMS instrument PCE-830. The three heating resistors are also equal and therefore they will all be heated by equal currents, I2. The authors of the report have assumed that I2 is half of the current in the C1 wires. That turns out to be not true. Instead the full current I1 is alternating between the two wires in the C2 wire pairs, so the voltage drop will be the same as for a single wire. For calculation of the resistance Re in the wire system, see paragraph E1in the spreadsheet and reference. From: Brad Lowe http://lenr.fysik.org/eCat/COP=1_or_3.pdf Sent from my iPhone
