I said three phase has no neutral. Well neutral is "earth". Each phase's voltage to earth is 120 V with phase to phase voltage at 208 V. Facilities with single phase loads combined with three phase loads have a neutral. But these single phase loads must be balanced. Search on delta vs wye.
This is why Rossi's reactor uses a delta three phase input. I elaborated this on an earlier post that was ignored as are most of my posts. I don't blame people for ignoring my posts as it is difficult to tell when I am serious. Life is too short to be serious. Night night. On Tue, Oct 28, 2014 at 11:21 PM, Terry Blanton <[email protected]> wrote: > I took a quick look at it. I think the author is confusing "split > phase" with "three phase". Split phase is how you get 240 V in your > home with only a single phase being distributed by the power company. > The single phase is fed into a transformer with a center tap. You > then get two 120 volt circuits referenced to a neutral. These are > circuits are 180 degrees out of phase. > > True three phase has no neutral. The three phases all carry power, > each 120 degrees out of phase with the other two. Hence the constant > 1.73 or the square root of three constant required. In three phase, > the phase to phase voltage in US distribution is 208 V. > > I already suffer from narcolepsy. Gotta get some sleep. > > On Tue, Oct 28, 2014 at 11:08 PM, Terry Blanton <[email protected]> wrote: >> It's bed time here; so, I'll have to check it out tomorrow. Meanwhile >> three phase power is calculated by: >> >> Watt's Law: W = V avg. x A avg x p.f. x 1.732 >> >> Where: >> >> W = wattage (watts) >> Vavg = average voltage of the three separate phases (volts) >> Aavg = average current of the three separate phases current (amps) >> p.f. = average power factor or the three separate phases >> 1.732 = a constant necessary with 3 phase. >> >> Meanwhile again, here's another "revelation" occurring late today: >> >> https://drive.google.com/file/d/0B8mt4mJOTGvBei1sbThCMzJybm8/view?usp=sharing >> >> Sorry, I have a lot going on at the moment. >> >> On Tue, Oct 28, 2014 at 9:41 PM, Jones Beene <[email protected]> wrote: >>> This guy makes an interesting point that is not clear to me. >>> >>> Terry, Dave, Bob et al - what do you EEs who have looked at the input power >>> think about this approach? >>> >>> “The currents in the three C1 wires are all equal and they are measured by >>> the true RMS >>> >>> instrument PCE-830. The three heating resistors are also equal and therefore >>> they will >>> >>> all be heated by equal currents, I2. The authors of the report have assumed >>> that I2 is half >>> >>> of the current in the C1 wires. That turns out to be not true. Instead the >>> full current I1 is alternating between the two wires in the C2 wire pairs, >>> so the voltage drop will be the same as for a single wire. For calculation >>> of the resistance Re in the wire system, see paragraph E1in the spreadsheet >>> and reference. >>> >>> From: Brad Lowe >>> >>> http://lenr.fysik.org/eCat/COP=1_or_3.pdf >>> >>> Sent from my iPhone
