I took a quick look at it. I think the author is confusing "split phase" with "three phase". Split phase is how you get 240 V in your home with only a single phase being distributed by the power company. The single phase is fed into a transformer with a center tap. You then get two 120 volt circuits referenced to a neutral. These are circuits are 180 degrees out of phase.
True three phase has no neutral. The three phases all carry power, each 120 degrees out of phase with the other two. Hence the constant 1.73 or the square root of three constant required. In three phase, the phase to phase voltage in US distribution is 208 V. I already suffer from narcolepsy. Gotta get some sleep. On Tue, Oct 28, 2014 at 11:08 PM, Terry Blanton <[email protected]> wrote: > It's bed time here; so, I'll have to check it out tomorrow. Meanwhile > three phase power is calculated by: > > Watt's Law: W = V avg. x A avg x p.f. x 1.732 > > Where: > > W = wattage (watts) > Vavg = average voltage of the three separate phases (volts) > Aavg = average current of the three separate phases current (amps) > p.f. = average power factor or the three separate phases > 1.732 = a constant necessary with 3 phase. > > Meanwhile again, here's another "revelation" occurring late today: > > https://drive.google.com/file/d/0B8mt4mJOTGvBei1sbThCMzJybm8/view?usp=sharing > > Sorry, I have a lot going on at the moment. > > On Tue, Oct 28, 2014 at 9:41 PM, Jones Beene <[email protected]> wrote: >> This guy makes an interesting point that is not clear to me. >> >> Terry, Dave, Bob et al - what do you EEs who have looked at the input power >> think about this approach? >> >> “The currents in the three C1 wires are all equal and they are measured by >> the true RMS >> >> instrument PCE-830. The three heating resistors are also equal and therefore >> they will >> >> all be heated by equal currents, I2. The authors of the report have assumed >> that I2 is half >> >> of the current in the C1 wires. That turns out to be not true. Instead the >> full current I1 is alternating between the two wires in the C2 wire pairs, >> so the voltage drop will be the same as for a single wire. For calculation >> of the resistance Re in the wire system, see paragraph E1in the spreadsheet >> and reference. >> >> From: Brad Lowe >> >> http://lenr.fysik.org/eCat/COP=1_or_3.pdf >> >> Sent from my iPhone
