Hi,

On Mon, Mar 30, 2015 at 6:59 PM, dmccunney <dennis.mccun...@gmail.com> wrote:
>
> Win98 is a protected mode OS, and DOS serves as a real mode
> loader.  Once Win98 is up and running, DOS is out of the loop, and
> Win98 *is* the OS.

If DOS is "out of the loop", then why are you still able to run DOS
files (.COM, .EXE, .BAT)?? Does Windows emulate it? Or is it really
just calling back to DOS itself? What is responding to the int 21h
kernel calls?

For something like Windows XP, then definitely DOS isn't there, it's
emulated in NTVDM. But to pretend that Win98 runs all by itself
without DOS is a bit of a stretch.

Hasn't this already been discussed to death before? MS was later sued
(and lost) for illegally bundling their DOS with their Windows. I
think Caldera (or Lineo or whatever they were eventually called) even
legitimately proved that they could boot Win95 atop DR-DOS. Win95 and
MS-DOS weren't bundled for technical reasons, only marketing reasons.
It was much closer (technically) to Windows 3.1 than most people
realize.

I'm not sure why they bothered. Obviously NT had much higher
requirements back then (mid '90s), e.g. 16 MB minimum (and 80 MB disk
space?) while Win95 could (very slowly) run atop a 4 MB 386. They
wouldn't even fix NTVDM bugs for Quake (from id Software, compiled for
DOS via DJGPP) because "NT wasn't for games"! But that's all lost to
the sands of time now that XP fully replaced Win9x for "home" users.
(2000 first added Win9x-era LFNs and FAT32, but even that wasn't yet
targeted at home users, hence we were only offered Windows ME.)

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