On Fri, Dec 11, 2015 at 3:17 PM, wrote:
The implication being that as particles go slower, their De Broglie
> wavelength increases, thus so does the distance at which the force reversal
> applies. This looks a lot like the increase in cross section for slower
> neutrons.
In reply to Eric Walker's message of Wed, 9 Dec 2015 21:50:31 -0600:
Hi,
[snip]
>On Wed, Dec 9, 2015 at 9:00 PM, wrote:
>
>The nuclear force is very short range.
>
>
>Here is where I'm inclined to part with conventional wisdom. Consider that
>1 barn is the approximate area
In reply to David Roberson's message of Wed, 9 Dec 2015 22:06:19 -0500:
Hi,
[snip]
>Guys, what would you expect to happen if the identity of individual nucleons
>is lost once they enter the nucleus? Since each is supposed to be constructed
>from 3 quarks, it may be logical to assume that
On Wed, Dec 9, 2015 at 10:45 PM, Jones Beene wrote:
*From:* Eric Walker
>
>
>
> The nuclear force is very short range.
>
>
>
> Ø Here is where I'm inclined to part with conventional wisdom.
> [...snip...]
>
This is arguable not true.
>
Interesting points.
Also, it
I wrote:
About the matter of the Coulomb barrier -- I like your and Dave's argument
> that the Coulomb barrier should be expected to work in one direction (and
> this would also seem to be implied by the shell theorem). But Krane on
> three or so occasions has written things that imply that the
On Wed, Dec 9, 2015 at 2:39 PM, wrote:
So I suspect that it's just the naming convention that is confusing you.
>
In oblong nuclei, there is an angular dependency on the alpha tunneling
probability. Alpha particles are more likely to tunnel out of poles of
such nuclei
In reply to Eric Walker's message of Tue, 8 Dec 2015 20:00:24 -0600:
Hi,
[snip]
>About the matter of the Coulomb barrier -- I like your and Dave's argument
>that the Coulomb barrier should be expected to work in one direction (and this
>would also seem to be implied by the shell theorem). But
In reply to Eric Walker's message of Tue, 8 Dec 2015 20:00:24 -0600:
Hi,
[snip]
>That would also create daughters with much higher energies. A nice thing
>about the lower energies involved in alpha captures is that the daughters end
>up having ~ 300 keV/nucleon, which is not that much. Also,
On Wed, Dec 9, 2015 at 2:39 PM, wrote:
IOW the barrier does work in two directions (due to the two forces at
> work), but
> is never named accordingly. So I suspect that it's just the naming
> convention
> that is confusing you.
>
When calculating the tunneling probability
In reply to Eric Walker's message of Wed, 9 Dec 2015 16:06:32 -0600:
Hi,
[snip]
>In oblong nuclei, there is an angular dependency on the alpha tunneling
>probability. Alpha particles are more likely to tunnel out of poles of such
>nuclei rather than at the circumference. Krane writes, "Since
In reply to Eric Walker's message of Wed, 9 Dec 2015 15:11:42 -0600:
Hi,
[snip]
>On Wed, Dec 9, 2015 at 2:39 PM, wrote:
>
>IOW the barrier does work in two directions (due to the two forces at
>> work), but
>> is never named accordingly. So I suspect that it's just the naming
prove that each proton
and neutron keeps its identity separate?
Dave
-Original Message-
From: mixent <mix...@bigpond.com>
To: vortex-l <vortex-l@eskimo.com>
Sent: Wed, Dec 9, 2015 10:00 pm
Subject: Re: [Vo]: How many atoms to make condensed matter?
In reply to Eric Walk
From: Eric Walker
The nuclear force is very short range.
Ø Here is where I'm inclined to part with conventional wisdom. Consider that
1 barn is the approximate area of a medium-sized nucleus presented to an
oncoming neutron, that nuclei such as 135Xe have neutron-capture cross
On Wed, Dec 9, 2015 at 8:26 PM, wrote:
1) I'm curious as to how they know that tunneling from the poles is more
> likely,
> given that they can't actually see what's going on. (Perhaps the anisotropy
> shows up in experiments done in a strong magnetic field?)
>
Yes -- this
On Wed, Dec 9, 2015 at 9:06 PM, David Roberson wrote:
Guys, what would you expect to happen if the identity of individual
> nucleons is lost once they enter the nucleus?
There is an assumption that the identity is lost, in a sense. Through meson
exchange, neutrons are
e: [Vo]: How many atoms to make condensed matter?
On Wed, Dec 9, 2015 at 9:06 PM, David Roberson <dlrober...@aol.com> wrote:
Guys, what would you expect to happen if the identity of individual nucleons is
lost once they enter the nucleus?
There is an assumption that the identity i
In reply to Eric Walker's message of Wed, 9 Dec 2015 20:49:09 -0600:
Hi,
[snip]
>Understood. I only wanted to get agreement on what Krane's understanding
>is. I think Krane's understanding is the mainstream position. This is not
>necessarily the correct one, but it's good to know what it is if
On Wed, Dec 9, 2015 at 9:00 PM, wrote:
The nuclear force is very short range.
Here is where I'm inclined to part with conventional wisdom. Consider that
1 barn is the approximate area of a medium-sized nucleus presented to an
oncoming neutron, that nuclei such as 135Xe
On Tue, Dec 8, 2015 at 6:18 PM, wrote:
Note that with alpha fusion some extra energy is available, so I suppose
> that in
> theory that means you could start a little lower, however that would also
> not be
> spontaneous fission, but rather triggered fission.
>
Agreed. The
In reply to Eric Walker's message of Tue, 8 Dec 2015 16:18:31 -0600:
Hi,
Note that with alpha fusion some extra energy is available, so I suppose that in
theory that means you could start a little lower, however that would also not be
spontaneous fission, but rather triggered fission.
If you
I had in mind atomic mass (i.e., nuclides in the neighborhood of
zirconium). I got this tidbit from Wikipedia (second paragraph):
https://en.wikipedia.org/wiki/Spontaneous_fission
I have now added a reference to this page in the paper. Wikipedia shows
"(SF)" in some cases for isotopes in this
In reply to Eric Walker's message of Mon, 7 Dec 2015 22:20:18 -0600:
Hi Eric,
In the sentence "Spontaneous fission becomes energetically possible at atomic
masses greater than 92."
Do mean "masses" or "numbers". IOW are you talking about Uranium and up, or
upward of about Zirconium?
>For those
On Mon, Dec 7, 2015 at 8:57 AM, Bob Higgins
wrote:
OTOH, if even one electron was placed in a deep Dirac level, would it
> enhance the possibility of electron capture reactions? How would we even
> know if happened? Chemically, it would behave like the electron
t or nano powders,
> however there is the Mills mechanism of self catilization that would
> present a possible avenue for this.
>
> Fran
>
>
>
> *From:* Eric Walker [mailto:eric.wal...@gmail.com]
> *Sent:* Sunday, December 06, 2015 4:36 PM
> *To:* vortex-l@eskimo.com
> *S
, however there is
the Mills mechanism of self catilization that would present a possible avenue
for this.
Fran
From: Eric Walker [mailto:eric.wal...@gmail.com]
Sent: Sunday, December 06, 2015 4:36 PM
To: vortex-l@eskimo.com
Subject: EXTERNAL: Re: [Vo]: How many atoms to make condensed matter
For those who have had the patience to follow the argument this far, here
is a paper that goes into further detail on the general idea:
https://drive.google.com/open?id=0BzKtdce19-wySFBVLXJET3k2TlU
There should be a "download" link at the top that will allow it to be
downloaded as a PDF. I am
On Sat, Dec 5, 2015 at 2:33 PM, wrote:
In short it should
> fuse with almost anything stable, provided that the Coulomb barrier can be
> overcome.
>
Do you have a sense of a lower bound? My impression so far has been that
it would be hard to fuse a 4He with anything lighter
On Sun, Dec 6, 2015 at 3:00 PM, wrote:
BTW, If "shrunken Helium" should exist (along the same lines as Mills'
> shrunken
> Hydrogen), then it might provide a simple means of overcoming the Coulomb
> barrier.
>
If there is shrunken hydrogen, it seems likely that there would
In reply to Eric Walker's message of Sun, 6 Dec 2015 08:11:00 -0600:
Hi,
[snip]
>Do you have a sense of a lower bound? My impression so far has been that it
>would be hard to fuse a 4He with anything lighter than beryllium, say, even if
>energetically it is possible.
The production of
In reply to Eric Walker's message of Sun, 6 Dec 2015 08:11:00 -0600:
Hi,
BTW, If "shrunken Helium" should exist (along the same lines as Mills' shrunken
Hydrogen), then it might provide a simple means of overcoming the Coulomb
barrier.
Regards,
Robin van Spaandonk
In reply to Eric Walker's message of Fri, 4 Dec 2015 18:12:56 -0600:
Hi Eric,
[snip]
Ok, I had that completely wrong. I forgot that He4 itself doesn't have as high a
binding energy per nucleon as most of the other elements. In short it should
fuse with almost anything stable, provided that the
In reply to Eric Walker's message of Thu, 3 Dec 2015 23:41:26 -0600:
Hi,
[snip]
>On Thu, Dec 3, 2015 at 10:39 PM, wrote:
>
>For elements heavier than Fe/Ni, alpha capture is endothermic, which implies
>> that it could only happen if fast alphas are available.
>>
>
>Here is
On Fri, Dec 4, 2015 at 3:07 PM, wrote:
I guess there are some exceptions. :)
>
For exothermic 4He + Pd reactions with 1-3 daughters which also occur in
nature, I get a count of 269 reactions. If one removes the limitation on
unstable daughters, I get a count of 4556
In reply to David Roberson's message of Wed, 2 Dec 2015 11:24:13 -0500:
Hi,
[snip]
>Your description of the field fluctuations occurring due to random processes
>taking place does seem logical. What would you expect to observe if a
>nucleus that typically emits alphas is placed within a
In reply to Eric Walker's message of Tue, 1 Dec 2015 16:11:27 -0600:
Hi,
[snip]
>I came upon the suggestion because it provides a nice explanation for
>results like those of Iwamura as being successive alpha captures. In his
>case, only two or three captures are needed to get from strontium to
On Thu, Dec 3, 2015 at 10:39 PM, wrote:
For elements heavier than Fe/Ni, alpha capture is endothermic, which implies
> that it could only happen if fast alphas are available.
>
Here is what my script is telling me about that:
4He + 110Pd => gamma + 114Cd + 4108 keV
4He +
;vortex-l@eskimo.com>
Sent: Tue, Dec 1, 2015 4:34 pm
Subject: Re: [Vo]: How many atoms to make condensed matter?
In reply to David Roberson's message of Mon, 30 Nov 2015 18:10:02 -0500:
Hi,
[snip]
Dave, I like your analysis. However it implies that if the field were
spherically symmetrical alpha
On Wed, Dec 2, 2015 at 10:24 AM, David Roberson wrote:
Robin, are you aware of any direct correlation between the energy emitted
> by a particle and its decay rate?
This is a well-established finding. Alpha decays in nature are between 4
and 9 MeV (approx.). The more
to its symmetrical structure.
>
>Dave
>
>
>
>
>
>
>
>-Original Message-
>From: Eric Walker <eric.wal...@gmail.com>
>To: vortex-l <vortex-l@eskimo.com>
>Sent: Mon, Nov 30, 2015 4:03 pm
>Subject: Re: [Vo]: How many atoms to make condensed matter?
On Tue, Dec 1, 2015 at 3:36 PM, wrote:
The emphasis I think should be placed on the word "opposite". IOW one might
> expect the result to be "opposite" as well.
>
True. I suspect it will be hard to get much further insight into the
matter at the level of physical
On Tue, Dec 1, 2015 at 3:33 PM, wrote:
Furthermore a specific arrangement of atoms in a molecule or lattice may
> well create an asymmetric field.
If what is needed is a field that is not spherical, that is also an
interesting idea. Perhaps hydrogen and deuterium
In reply to Eric Walker's message of Mon, 30 Nov 2015 15:19:03 -0600:
Hi Eric,
This is just a restatement of your original position with no further supporting
evidence or logic.
The emphasis I think should be placed on the word "opposite". IOW one might
expect the result to be "opposite" as
On Mon, Nov 30, 2015 at 2:41 PM, wrote:
No, I'm saying it does both. When the alpha particle is far away it
> enhances it,
> but when it get close to a target nucleus it works against it. I'm not
> sure what
> the net result would be.
>
If the volume of the surplus negative
On Mon, Nov 30, 2015 at 2:41 PM, wrote:
No, I'm saying it does both. When the alpha particle is far away it
> enhances it,
> but when it get close to a target nucleus it works against it. I'm not
> sure what
> the net result would be.
>
More to the point, it might be
In reply to Eric Walker's message of Sun, 29 Nov 2015 21:34:17 -0600:
Hi,
[snip]
>On Sun, Nov 29, 2015 at 7:09 PM, wrote:
>
>
>> As the particle gets
>> closer to the target, the screening electrons get fewer, and the effect
>> eventually reverses, with there being more
Walker <eric.wal...@gmail.com>
To: vortex-l <vortex-l@eskimo.com>
Sent: Mon, Nov 30, 2015 4:03 pm
Subject: Re: [Vo]: How many atoms to make condensed matter?
On Mon, Nov 30, 2015 at 2:41 PM, <mix...@bigpond.com> wrote:
No, I'm saying it does both. When the alpha pa
In reply to Eric Walker's message of Sat, 28 Nov 2015 16:38:41 -0600:
Hi,
[snip]
>It would increase the alpha-capture cross section by screening the Coulomb
>repulsion, allowing a more direct approach by the incident prompt alpha
>particle. In this thinking, tunnelling across the barrier into a
On Sun, Nov 29, 2015 at 7:09 PM, wrote:
> As the particle gets
> closer to the target, the screening electrons get fewer, and the effect
> eventually reverses, with there being more behind the particle than in
> front of
> it.
>
Just so I am clear on what you're arguing --
On Sat, Nov 28, 2015 at 1:47 AM, wrote:
Yes, I know, but the presence of more negative charge close to the nucleus
> increases the energy of the positively charged alpha particle because, not
> only
> is it leaving the positively charged nucleus behind, but it now also has
>
In reply to Eric Walker's message of Sat, 28 Nov 2015 09:34:55 -0600:
Hi,
[snip]
>On Sat, Nov 28, 2015 at 1:47 AM, wrote:
>
>Yes, I know, but the presence of more negative charge close to the nucleus
>> increases the energy of the positively charged alpha particle because,
On Sat, Nov 28, 2015 at 2:44 PM, wrote:
>At any rate, in this case, we
> >seem to have an example of a single environmental factor that would
> >increase the rate alpha emission and increase the alpha capture cross
> >section.
>
> ...and exactly how would it do the latter?
On Fri, Nov 27, 2015 at 6:10 PM, wrote:
> For alpha emission it is actually a nuclear force barrier, since the
> Coulomb
> force actually helps in escaping, rather than hindering.
>
This may be true. But the calculation of the tunneling probability of an
alpha particle to
On Fri, Nov 27, 2015 at 5:44 PM, wrote:
In order to overcome the repulsion, they need to strike another nucleus at
> high
> energy. The need for high energy implies that they must get lucky, and hit
> another nucleus before they lose too much energy to ionization.
> Even if
In reply to Eric Walker's message of Fri, 27 Nov 2015 18:21:42 -0600:
Hi,
[snip]
>This may be true. But the calculation of the tunneling probability of an alpha
>particle to escape a nucleus depends upon the width of the Coulomb barrier.
>The narrower the width, the more likely tunneling is
In reply to Eric Walker's message of Fri, 20 Nov 2015 01:18:19 -0600:
Hi,
[snip]
>The energy is produced as the lighter elements undergo a series of transitions
>under successive alpha captures.
Even fast alphas produces only a trivial amount of alpha captures (e.g.
1/1). This is primarily
In reply to Eric Walker's message of Fri, 27 Nov 2015 18:00:46 -0600:
Hi,
[snip]
>This suggests, then, that the same process that is leading to alpha decay
>(e.g., suppression of the Coulomb barrier) might also be increasing the cross
>section for alpha capture.
The Coulomb barrier is actually
On Fri, Nov 27, 2015 at 7:29 PM, wrote:
Note that the Coulomb barrier width is a function of the particle's energy.
Not only do we have a simple theoretical argument that the Coulomb barrier
width can be lessened by electron screening, precisely as one might imagine
it
In reply to Eric Walker's message of Fri, 27 Nov 2015 21:28:12 -0600:
Hi Eric,
[snip]
>On Fri, Nov 27, 2015 at 7:29 PM, wrote:
>
>Note that the Coulomb barrier width is a function of the particle's energy.
>
>
>Not only do we have a simple theoretical argument that the
com>
To: vortex-l <vortex-l@eskimo.com>
Sent: Fri, Nov 20, 2015 2:19 am
Subject: Re: [Vo]: How many atoms to make condensed matter?
On Thu, Nov 19, 2015 at 10:21 PM, David Roberson <dlrober...@aol.com> wrote:
The counts for elements of that m value appear quite small when compared to t
<janap...@gmail.com>
To: vortex-l <vortex-l@eskimo.com>
Sent: Fri, Nov 20, 2015 12:25 am
Subject: Re: [Vo]: How many atoms to make condensed matter?
Electrical production has been done in the Papp engine. I go back to the Papp
engine that was self powered by recycling overunity electr
On Fri, Nov 20, 2015 at 9:16 AM, David Roberson wrote:
Good point. As long as it takes a very tiny amount of precious metal the
> cost could be contained. It would be much better to use one of the high
> mass elements that is lower cost if you have any choice.
>
I suspect
On Fri, Nov 20, 2015 at 9:12 AM, David Roberson wrote:
I find it difficult to compare the Papp engine with a Rossi ECAT. They are
> very different in structure and behavior.
They are definitely different in operation, but I would not be surprised to
learn that they work
The Papp engine and the E-Cat just work at different optical frequencies.
The E-Cat uses light in the infrared and the Papp engine in the XUV range.
The Papp system, like in the Holmlid experiment which is also a XUV based
system, there is a shock wave produced that reaches a significant fraction
On Thu, Nov 19, 2015 at 1:20 PM, Axil Axil wrote:
This means that the palladium chloride envelope is the active LENR factor
> and not the hydrogen deposited on the electrode.
This sounds likely to me, although hydrogen may help out.
As Rossi has done on the E-Cat X,
tors Axil. That
> is your thought as far as I am aware.
>
> Dave
>
>
>
> -Original Message-
> From: Axil Axil <janap...@gmail.com>
> To: vortex-l <vortex-l@eskimo.com>
> Sent: Thu, Nov 19, 2015 2:20 pm
> Subject: Re: [Vo]: How many atoms to make condense
ovember 18, 2015 2:15 PM
To: vortex-l <vortex-l@eskimo.com>
Subject: EXTERNAL: Re: [Vo]: How many atoms to make condensed matter?
As posted before, water absorbs UV light about 100,000,000 times better than
infrared light. This makes it a poor partner with any noble metal at pro
gt; *Sent:* Wednesday, November 18, 2015 2:15 PM
> *To:* vortex-l <vortex-l@eskimo.com>
> *Subject:* EXTERNAL: Re: [Vo]: How many atoms to make condensed matter?
>
>
>
> As posted before, water absorbs UV light about 100,000,000 times better
> than infrared light. This m
On Thu, Nov 19, 2015 at 6:08 AM, Roarty, Francis X <
francis.x.roa...@lmco.com> wrote:
> Axil, Jones,
>
> Good insights and dot connecting, would it apply to Patterson
> beads submerged in water with a lithium sulfate (Li2SO4) electrolyte
> solution? (Li2SO4) vs palladium chloride
radiation is consistent with more
recent Japanese patents for remediation.
Fran
From: Axil Axil [mailto:janap...@gmail.com]
Sent: Wednesday, November 18, 2015 2:15 PM
To: vortex-l <vortex-l@eskimo.com>
Subject: EXTERNAL: Re: [Vo]: How many atoms to make condensed matter?
As posted before, water a
t;vortex-l@eskimo.com>
> Sent: Thu, Nov 19, 2015 10:27 pm
> Subject: Re: [Vo]: How many atoms to make condensed matter?
>
> On Thu, Nov 19, 2015 at 7:34 PM, David Roberson <dlrober...@aol.com>
> wrote:
>
> Rossi has never mentioned palladium use within his reactors
nap...@gmail.com>
To: vortex-l <vortex-l@eskimo.com>
Sent: Thu, Nov 19, 2015 11:28 pm
Subject: Re: [Vo]: How many atoms to make condensed matter?
The cost is cheap if the reactor can produce electricity directly.
On Thu, Nov 19, 2015 at 11:21 PM, David Roberson <dlrober...@aol.com>
gt; powered generator is going to be required anyway. The overall system will
> have to be optimized.
>
> Dave
>
>
>
> -Original Message-
> From: Axil Axil <janap...@gmail.com>
> To: vortex-l <vortex-l@eskimo.com>
> Sent: Thu, Nov 19, 2015 11:28 pm
&g
.
Dave
-Original Message-
From: Eric Walker <eric.wal...@gmail.com>
To: vortex-l <vortex-l@eskimo.com>
Sent: Thu, Nov 19, 2015 10:27 pm
Subject: Re: [Vo]: How many atoms to make condensed matter?
On Thu, Nov 19, 2015 at 7:34 PM, David Roberson <dlrober...@aol.com>
On Thu, Nov 19, 2015 at 7:34 PM, David Roberson wrote:
Rossi has never mentioned palladium use within his reactors Axil. That is
> your thought as far as I am aware.
>
I don't know whether Rossi is now using or has used palladium in the past.
But one detail in the Lugano
On Thu, Nov 19, 2015 at 10:21 PM, David Roberson wrote:
The counts for elements of that m value appear quite small when compared to
> the other elements. Also, why on earth would anyone use such an expensive
> element if a dirt cheap one can substitute? My suspicion is that
On further examination, Ken may be on to an important insight here which is
relevant to LENR. Here is another reference with more detail.
“Single-Atom Catalysts: A New Frontier in Heterogeneous Catalysis”
YANG, et al.
When read in the context of the recently mentioned Szpak interview,
As posted before, water absorbs UV light about 100,000,000 times better
than infrared light. This makes it a poor partner with any noble metal at
producing polaritons at UV frequencies.
However, when chlorine is added to the palladium solution to form palladium
chloride in the electrolyte, the
Question: Not sure if it has been discussed before, but could it be that
nanoparticulate fuel arrangements are not the ideal? Many workers, most
recently JM Thomas (Nature 17 Sept 2015) showed that single atoms, of Pd
especially, make better catalysts than nanoparticles. super catalysts, in
From: Ken Deboer
… most recently JM Thomas (Nature 17 Sept 2015) showed that single atoms, of Pd
especially, make better catalysts than nanoparticles. super catalysts, in fact.
Now that you mention it – if you look back at Pd-D cold fusion, one of the most
effective techniques is
Yet another interesting possibility for anomalous energy, showing up in nature
but heretofore unappreciated - which arguably fits into a version of the
Holmlid effect is in biology. If Holmlid is correct that iron-oxide catalyst
along with an alkali (potassium) and a source of light, can create
I think the answer to your question about gradual decoherence of the
magnetic domains might actually be the opposite. Remember your old
horseshoe magnets? They were always stored with a "keeper" so as to keep
the magnetic field strong. I think what would happen over time is that the
magnet will
It will remain held in place forever unless the magnet heat up.
Dave
-Original Message-
From: Eric Walker <eric.wal...@gmail.com>
To: vortex-l <vortex-l@eskimo.com>
Sent: Sat, Nov 14, 2015 1:53 am
Subject: Re: [Vo]: How many atoms to make condensed matter?
On
rtex-l <vortex-l@eskimo.com>
Sent: Sat, Nov 14, 2015 2:03 am
Subject: Re: [Vo]: How many atoms to make condensed matter?
On Sat, Nov 14, 2015 at 12:25 AM, David Roberson <dlrober...@aol.com> wrote:
I consider electrons in orbits as being equivalent to a superconductor current
s
On Sat, Nov 14, 2015 at 12:25 AM, David Roberson wrote:
The loss in the current carrying magnet is due to series resistance and if
> that resistance is eliminated it would not require any additional power
> once the current is set up.
>
Consider this video:
_
Another interesting possibility for anomalous heat due to the Holmlid effect
(nucleon disintegration) is the planet Jupiter.
Jupiter has a core temperature estimated to be 36,000 K (64,300 °F) despite the
cold surface - but its large gravitational
would apply to an insulator.
Dave
-Original Message-
From: Eric Walker <eric.wal...@gmail.com>
To: vortex-l <vortex-l@eskimo.com>
Sent: Sat, Nov 14, 2015 1:24 pm
Subject: Re: [Vo]: How many atoms to make condensed matter?
On Sat, Nov 14, 2015 at 12:25 AM, David Rober
On Sat, Nov 14, 2015 at 4:26 PM, David Roberson wrote:
So, I would expect to see the falling velocity of the magnet to become less
> and less as the conductor used for the pipe become less resistive. But,
> the geometry is also going to enter into the equation.
Let's
When you introduce the magnet to the presence of the superconductor,
currents are induced in the superconductor that cause the magnetic field to
exactly cancel at the surface of the superconductor such that there is no
penetration of the magnetic field into the superconductor. However, this
On Sat, Nov 14, 2015 at 4:57 PM, Bob Higgins
wrote:
When you introduce the magnet to the presence of the superconductor,
> currents are induced in the superconductor that cause the magnetic field to
> exactly cancel at the surface of the superconductor such that there
: Eric Walker <eric.wal...@gmail.com>
To: vortex-l <vortex-l@eskimo.com>
Sent: Sat, Nov 14, 2015 5:47 pm
Subject: Re: [Vo]: How many atoms to make condensed matter?
On Sat, Nov 14, 2015 at 4:26 PM, David Roberson <dlrober...@aol.com> wrote:
So, I would expect to see th
com>
Sent: Sat, Nov 14, 2015 5:57 pm
Subject: Re: [Vo]: How many atoms to make condensed matter?
When you introduce the magnet to the presence of the superconductor, currents
are induced in the superconductor that cause the magnetic field to exactly
cancel at the surface of the su
I think you are asking the correct questions. As I have come to read more
about the RM and think about their behavior, I have come to respect
Winterberg's concept to a greater degree.
The RM snowflakes have a high magnetic moment due to their large flat
orbitals, and apparently the atoms in the
the%2520Structure%2520of%2520the%2520Sun%2520(KVK%2C%2520Nehru).pdf=AFQjCN>
Hoyt Stearns
Scottsdale, Arizona US
From: Jones Beene [mailto:jone...@pacbell.net]
Sent: Friday, November 13, 2015 9:08 AM
To: vortex-l@eskimo.com
Subject: RE: [Vo]: How many atoms to make condensed matter?
Fro
It is an interesting speculation. Nature is a truly immense experiment,
particularly when considering the number of atoms present. Immense nuclear
trials are constantly happening all around us. If this type of sub-nuclear
shuffle were happening with the "less difficulty" that you describe, it
Side note for the aestheticists amongst us: Isn't it likely that a hexagonal
geometry of pico-snowflakes is a generic form which is reflected in
structures all the way down to dense hydrogen? It's no coincidence that
iron oxide as catalyst, takes on the classic hexagonal nanostructure, and
this
From: Bob Higgins
* Can you say what evidence the natural state should exhibit if such a
sub-nuclear shuffle were as "less difficult" as you describe? Are there
natural occurrences that can be looked for that could validate such a
proposition?
Indeed – such a radical shift would have
Some of this thread has gotten to some of the basics relating to magnetism,
which is a bit of a mystery to me. There's the dynamic magnetism that
arises through a moving current. And there's the static magnetism that is
created through the formation of magnetic domains in a ferromagnetic
On Sat, Nov 14, 2015 at 12:25 AM, David Roberson wrote:
I consider electrons in orbits as being equivalent to a superconductor
> current since the orbits do not collapse with time. No power is radiated
> by an electron orbital and hence no work is required to keep it in the
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From: Eric Walker <eric.wal...@gmail.com>
To: vortex-l <vortex-l@eskimo.com>
Sent: Fri, Nov 13, 2015 9:21 pm
Subject: Re: [Vo]: How many atoms to make condensed matter?
Some of this thread has gotten to some of the basics relating to magnetism,
which is a bit of a mystery to
On Sat, Nov 14, 2015 at 12:25 AM, David Roberson wrote:
The loss in the current carrying magnet is due to series resistance and if
> that resistance is eliminated it would not require any additional power
> once the current is set up.
>
I was thinking about that. But let's
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