Robin,
Why would you be able to add the masses of the 2 electrons to that of the nickel? They would need to be regenerated every time a reaction was required or eventually you would run out of them. If you are thinking of some form of radiation release that produces an electron and positron pair, then that energy would also need to be subtracted from what is released by the reaction. Has the existence of that hydrino been proven? I like the concept, but am not aware that anyone has been able to actually capture a number of them to measure. Dave -----Original Message----- From: mixent <mix...@bigpond.com> To: vortex-l <vortex-l@eskimo.com> Sent: Tue, Jan 22, 2013 9:43 pm Subject: Re: [Vo]:understanding Piantelli et al.'s 2013 EP2368252B1 patent In reply to mix...@bigpond.com's message of Wed, 23 Jan 2013 07:08:56 +1100: Hi, [snip] >In reply to Eric Walker's message of Mon, 21 Jan 2013 00:08:43 -0800: >Hi, >[snip] >>Has anyone studied Piantelli's work enough to comment on whether I've >>gotten this right or missed something important? Can anyone (Robin?) >>comment on which parts are controversial and which are accepted physics? I >>understand that you can see the emission of a gamma ray from large, >>metastable nuclei, when the nucleons rearrange to a lower energy level, but >>is this possible with as light an atom as nickel? > >Apparently a double beta decay of 58Ni to 58Fe is energetically possible, with >the release of 1.9 MeV, which falls in the middle of the range reported by >Piantelli for his proton energy. This is actually a double beta+ conversion, two protons converting to two neutrons, so it might also be seen as a double electron capture reaction. A Hydrino molecule might merge with the 58Ni. The shrunken electrons are captured and convert protons into neutrons, and two protons are ejected in place of the Hydrino molecule. Or alternatively, the two shrunken electrons of the Hydrino molecule are captured by the 58Ni nucleus, converting it into 58Fe, and the protons of the Hydrino molecule are ejected. Either way, energy is released, and protons are ejected. BTW a double electron capture reaction would add the energy of two electron masses to the reaction, i.e. adding another 1 MeV, thus neatly accounting for the 3 MeV that Piantelli reports as his maximum. Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
