ST> Or extend that example. You have requests at 1am, 5am, 9am, 1pm. x = 4,
ST> m = 12 hours, and analog calculates that the rate is
ST> (x - 1) / m
ST> = 3 / (12 hours)
ST> = 1 / (4 hours).
ST> Your formula, x / m, would give 1 / (3 hours) which is wrong.
ST>
ST> I don't see how I can explain it any better than this.
Finally, I believe I understand what you mean.
If I have requests at 1am, 5am, 9am, 1pm during time period 0:00
to 24:00, x = 4 --- the number of requests is 4. On the other
hand, for the average calculation, you assume the first request
had come at 0:00 and the last (the 4th) request had come at
24:00 (which is 0:00 of the next day). So the rate is (4-1) per
day.
Is my comprehension correct?
--
Satoshi Ikarashi <[EMAIL PROTECTED]>
24 52 51 C3 98 D9 8A CC 5E 34 32 20 E6 18 D6 FD
UNIX Systems Services 1, Software Service Center 1
(Technologies Planning, ASP Business)
Nihon Unisys, Ltd. PH.+81-3-4329-2247, Datafax.+81-3-5546-7849
+------------------------------------------------------------------------
| This is the analog-help mailing list. To unsubscribe from this
| mailing list, go to
| http://lists.isite.net/listgate/analog-help/unsubscribe.html
|
| List archives are available at
| http://www.mail-archive.com/[email protected]/
| http://lists.isite.net/listgate/analog-help/archives/
+------------------------------------------------------------------------
