On 31/03/14 06:56, Brian Rogoff wrote:

I made a first pass through. I notice that almost every 'alias' is of
the form

   alias existing_name new_name;

I thought that in the latest D the alias syntax was

   alias new_name = existing_name;

Should I be following Walter's lead with respect to alias?

No, use the new syntax.

--
/Jacob Carlborg

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