Hi Yu,

Let’s begin with the excellent description written by Andrew Ingraham:

“The voltage sag propagates outward from the chip, consuming charge stored in 
the intrinsic capacitance of the planes bit by bit (not all of it at once!), 
and eventually reaching external capacitors which help hold up the voltage.”

When a chip gate opens, the V (and Q) sag on the metal plane propagates outward 
from the chip at circle front, consuming charges inside the circle. If the 
outgoing circle front meets a decap, charge would be moving from the decap to 
the chip. ... What if the circle does not reach any decap before the end of Tr? 
The gate has closed, no current loop can be formed. That is the scenario I was 
interested in. Now an electrical potential imbalance happens in a metallic 
plane. Charge on the plane would flow toward the circle for regaining 
eqi-potential. ...

Regards,
Barry Ma
ANRITSU company
Morgan Hill, CA 95037

-------------
From: "Yu Wang" <[email protected]>, on 5/17/00 7:45 AM:

Hi, Barry,

I think we all do agree the 1st point you said.
 
But on the 2nd point, I have another opinion. Say, you are right,"When an 
electrical potential imbalance happens in a metallic plane, a current would 
flow on the plane for regaining the equi-potential." But we regard the metallic 
plane as a reference plane,
then, theoretically, there is no an electrical potential imbalance happens in a 
metallic plane. In fact, we can never get a ideal reference plane(even the 
earth is not IDEAL). Based on this, I would say "yes" on your question "Does it 
need EM field support from the dielectric?". Still but, the need of the support 
is usually slight if the electical size of the metallic plane is big enough. 
because we know the metallic plane is a equi-potential plane.

regards,
Yu Wang, Ph.D
U.T. MD Anderson Cancer Center
1100 Holcombe Blvd., Box 217
Houston, TX, 77030
Tel:713-745-1671


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