On Sat, May 16, 2020 at 12:24 PM Gene Heskett <ghesk...@shentel.net> wrote:
>
> Which then brings up the need for some math.  So how would one go about
> getting from a 3 phase stepper motors holding power, say 3 NM to lbs/ft
> at the output of a 12/1 cycloidal gear?
>
> Assuming zero losses in the bearings, which I'd guess at 5% if decent
> bearings.
>
> Could that 3NM motor hold it, or even move it under cutting loads?

Torque multiplies by the gear ratio.  So if the motor holds 3.0 Nm and
there is a 10X r
eduction then the part can be held to 30 Nm.   If you need the result
in foot-pounds it is an easy conversion.

But many times they use two reduers in series to get an effective 100x
reduction then you have 300 Nm.      What is needed?  You need to know
the force from your cutter and the distance from the cutter to the
axis.  You can always adjust the cutter force by taking smaller cuts.

> >
> >
> Cheers, Gene Heskett
> --
> "There are four boxes to be used in defense of liberty:
>  soap, ballot, jury, and ammo. Please use in that order."
> -Ed Howdershelt (Author)
> If we desire respect for the law, we must first make the law respectable.
>  - Louis D. Brandeis
> Genes Web page <http://geneslinuxbox.net:6309/gene>
>
>
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--

Chris Albertson
Redondo Beach, California


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