Sorry to jump in halfway.
--- "Peter K." <[EMAIL PROTECTED]> wrote:
> OK. Here is what I am saying. On a 30D you have a
> sensor that
> is 22.5mm x 15mm with 8.2 million effective pixels.
> The total area of that sensor is 337.5 square mm.
>
> On a 5D you have a sensor that is 35.8mm x 23.9mm
> with 12.7
> effective pixels. The area of that sensor is larger
> at 855.62 square mm. However,
> the 5D has an area that is 2.5 times greater than
> the 30D yet has only 55% more
> pixels. So the density is less.
>
> If you look at the newer Rebel XTi with 10.2
> effective
> pixels in a sensor that is slightly smaller at
> 22.2mm x 14.8mm you have an area
> of coverage for an image of 328.5 square mm. This
> means again the 5D will have
> an area that is 2.6 times larger but has only 25%
> more pixels than the XTi. Again,
> the density of pixels for a given area is greater in
> the XTi.
Agree on all the above.
>
> So if I have a small object in the image I would
> have more
> pixels covering that area of the image with a 30D or
> XTi than I would with a
> 5D.
>
This statement is true if the photographer uses the
same lens, stands at the same place, but uses
different camera bodies to do the shooting. However,
I don't think the photographer will want to do so, to
have a rather imbalance composition on the image,
either too loose on the 5D, or too tight, or might
even cropped of certain part of the resulting image.
So if I were to use a 35 mm on a 5D, standing at the
same place I'd use a 22 mm on a 30D/400D, to have a
similarly composed picture. The only difference would
have is the DOF, but that's not the original point of
argument here. Or I'll have to move a backward when
shooting with the same 35mm lens on a 30D/400D. But
that would change the perspective. In both cases, the
resulting image from the 5D will have 'more pixels
covering the same area'.
regards,
Huang Shao Hui
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