Very well, my friends!
And now listen.
The Birth of Jesus Christ is thought to be a mistake because Saint
Mattew told of Jesus in Egypt and of events that were before the year
0 in which the Church put his birth.
But you have to consider this thing.
We have TWO different descriptions of the first years of the Jesus
life.
In fact Saint Lucas does not tell of the travel in Egypt, but of Jesus
that, after 8 days, goes in his Templec and receives his circumcision.
Afterwards his family returns to Nazareth and reamins only in that
place.
So we have 2 different possibilities.
If We consider the 3 Kings, the Star, and all the narration of Sain
Mattew, it seems a fairy-tale. The desire of this Apostle counted this
birth introducing in it the precedent events used to carry Divine
Glory on Jesus.
So, those who have Faith in this fairy-tale, afterwards affirm the
mistake introduced in his birth.
We must think that the real <truth> exists only in the Gospel of Saint
Lucas.
He described of Jesus at 12 year, that begins his work as the Son of
His Father...
and so... <1000 and not a new 1000> are the 2000 years that, added to
this beginning of Jesus, makes exactly the year 2012 that we are
speaking about.
In this case, the calculus that I have done doesn't start from a
mistake!
Romano Amodeo
On 16 Lug, 19:18, amoram <[EMAIL PROTECTED]> wrote:
> Here is a FANTASTIC question:
> "Was born, Jesus, just to reveal the world's end?"
>
> In facts this precise math calculus, made in power:
> [(10^5 ×10^100)^1/300]^2 = (10^0.35)^2 = 10^0.122500
> "virtually" inserts Jesus into the world, with the most precision at
> the 0,1225 power meaning year 0, month 12 and the precise day 25.00 of
> the Christmas.
>
> And this sequent similar calculus shows in the exponent 2012.122200 of
> the power, the year 2012, month 12 and day 22.00 that had been already
> predicted by the Mayas, how the end of a complete cycle of the Sun:
>
> { (10^10×10)^4
> ×[(10^10×10)^8 : 10^3]^10^-2
> ×[(10^10×10)^6]^10^-4
> ×[(10^10×10)^8 : 10^3]^10^-6
> ×(10^10×10^3)^10^-8 } ^2 =
> (10^44.85668513)^2 = 10^2012.122200.
> NOW I explain - step by step - these two "incredible" calculations.
>
> JESUS CHRISTMAS, THROUGH:
> [(10^5 ×10^100)^1/300]^2 = (10^0.35)^2 = 10^0.122500
>
> 10^5 ×10^100 (in atomic units named Angstrom) is the electric (or
> magnetic) unit 10^5, multiplied by the 10^100 that is the Area of 1
> m^2, in Angstrom^2, to get the electric (or magnetic) Volume 10^105.
> It represents very well, "in transcendental meaning", also the
> Communion Man-God, in its "divine" Volume.
> The power 1/300, on (10^5 ×10^100), gets 1/3 of the Trinity xyz of
> this Volume, how it is referred to 1/100 of the Area's power 100
> before introduced, and so we have again a length, in power.
> 0.35^2 is ALL THE QUANTITY of the power 10^-35, that is contained in
> the Area having the side 0.35 long in length.
> Since 10^4 is ALL the reality, and 10^2 is ALL its Area, ALL the flow
> in line is the same 10^2 quantity of the area.
> So the area 0.35^2 = 0.122500 is also the number representing ALL the
> flow in the line of the time, and it inserts Jesus into the world, in
> the Christmas day of the 0 year, 12 (December), 25th.
>
> You know that Jesus was born 5 years before of the 0 year based on
> his birth... but something of "transcendent of the reality" collocated
> this date in the "virtual" situation to be in the perfect line with
> all the dimensions of the world. Is it happened for the "dogma" (of
> the Christian Faith) of an "infallible Pope" ???
>
> THE "END OF THE TIME" AS ALL THE MOVEMENT
> OF THE 10^3 UNITARY MASSES CONTAINED IN 1 m^3
>
> Now, the interesting continues, because if we consider ALL the
> possible RUN of a volume 10^3 equal to 1 m^3 and containing all the
> unitary quantity of kg, and if we do the same calculus, first of the
> power in line and afterwards of the Area, to can know also ALL the
> flow of the 10^3 unitary masses, we have just the power 2012.122200
> meaning the END already expected by the Mayas. Let us see because.
> We have now to control the calculus:
>
> { (10^10×10)^4
> ×[(10^10×10)^8 : 10^3]^10^-2
> ×[(10^10×10)^6]^10^-4
> ×[(10^10×10)^8 : 10^3]^10^-6
> ×(10^10×10^3)^10^-8 } ^2 =
> (10^44.85668513)^2 = 10^2012.122200.
> (10^10×10)^4 is equal to 10^11 (that represents the 10^10 angstroms
> of 1 m, running in its 10 cycle of the time) at the 4 dimension of
> the reality (3 of space and 1 of time). So its result is the power
> 10^44.
>
> ×[(10^10×10)^8 : 10^3]^10^-2 represents the same 10^11, in the 2^3=8
> dimensions of the complex volume having the side 2 formed by the
> length from -1 to +1. Afterwards, the resulting 10^88 is divided by
> all the 10^3 unitary masses, to count ALL THE RUN 10^85, of these
> masses in 10^88 units.
> The power 10^-2 of 10^85 gets 10^0.85 and refers (to the unit of the
> meter) this quantity that, in itself, is the unit 10^-2 of the Area
> 10^2 of expansion.
> This happens because the meter is the unitary reference of the
> dimension 10^2 (in angstrom), whose unitary reference is 10^-2. So the
> result is 10^0.85.
>
> ×[(10^10×10)^6]^10^-4 represents the same 10^11 power, that RUNS in
> all the 6 direction +x +y +z -x -y -z, of the reality 10^4 that is
> present in the total 10^10 Angstrom of 1 m. Naturally, they must be
> represented in the unitary part of 10^4, that is 10^-4, so the power
> 10^-4 represents this unitary part. This result is 10^0.0066.
>
> ×[(10^10×10)^8 : 10^3]^10^-6, at dimension 10^6 (of all the movement
> of the reality 10^4, in 10^10 Angstrom of 1 m), represents its unit
> 10^-6. The quantity represented is [(10^10×10)^8 : 10^3], the same
> 10^85 already seen, that is ALL TE COMPLEX movement 8, of the 10^3
> unitary masses of 1 m^3. Therefore the result is 10^0.000085.
>
> ×(10^10×10^3)^10^-8 represents at the dimension 10^8 of the light its
> unit 10^-8. The quantity represented is the (10^10×10^3) that shows
> all the absolute movement, of 1 m (equal to 10^10 angstrom), of all
> the 10^3 unitary masses. Therefore 10^0.00000013.
>
> The product 10^44 × 10^0.85 × 10^0.0066 × 10^0.000085 × 10^0.00000013
> is 10^(44+0.85+0.0066+0.000085+0.00000013) = 10^44.85668513.
>
> All this quantity, contained between the parenthesis braces { and },
> is elevated to the square, because we need the Area of 10^44.85668513
> which has the same number of the flow (since area 10^2 × length 10^2,
> gets the reality 10^4). So, finally, { 10^44.85668513 } ^2 =
> 10^2012.122500 represents in power the date of the APOCALYPSE of the
> year 2012, month 12, day 22.00 (with the absolute precision of 0.00
> minutes)
> In this way.... has GOD sent Jesus to establish the 0 year, necessary
> to can do this perfect calculus of THE END OF THE WORLD ????
> My calculus is really perfect one. Let us see it only in the exponents
> of the powers.
> 44 is all the length 22 +22 of a real RUN (up and down) of the 22
> cycles of 10 Volt relative to the most electric tension of 220 Volts.
> 44+44 -3 is the precedent 44, how it exists in the complex reality
> going from -44 to +44 (in the positive-negative time), RUN only in
> real way by the space having 3 dimensions. In the 10^-2 dimension
> since that unitary of the "area" 10^2 of (10^44)^2, equal to the sum
> 44+44 of the exponents.
> 66 is all the length of the 11 dimensions (10 of space and 1 of time)
> of the 10 cycle, RUN in the 6 directions +x+y+z-x-y-z. At the 10^-6
> dimension of all the run of the reality 10^4 in 10^10, that is 10^6.
> 13 is all the run of the space 3, relative to the cycle 10 of the
> unitary mass, at the 10^-8 unitary dimension of that 10^8 that is all
> the run of the Area of 10^2 angstrom^2, in the total 10^10 angstrom
> equal to 1 meter.
>
> What is possible to tell in opposition? Will have the World this END?
> All is BASED on the year 0 that we today have since Jesus Christ, and
> on the "possible-impossible", "mistake-not mistake" of a Pope !!!
>
> Romano Amodeo
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