Russell Standish wrote:
> On Fri, Oct 13, 2006 at 07:03:18AM -0000, [EMAIL PROTECTED] wrote:
> >
> > Also see my reply to Russell below:
> >
> >
> > >Russell Standish
> > >
> > >The Multiverse is defined as the set of consistent histories described
> > >by the Schroedinger equation. I make the identification that a quantum
> > >state is an observer moment, and the set of consistent quantum
> > >histories is the set of observer histories. As such all observer
> > >moments are in the Multiverse.
> > >
> > >But I appreciate this is not a widely held interpretation...
> >
> >
> > Indeed so.  And there's a good reason why it isn't a widely held
> > interpretation, as J.barbour explained in 'The End Of Time'.  In order
> > to define 'the Multiverse' in terms of QM one needs a *static*
> > wave-function solution for the entire universe (one which doesn't
> > change) , whereas conventional QM solutions to real world problems are
> > *dynamic* wave-function solutions (wave functions which evolve with
> > time).  No one has yet succeeded in demonstrating a static
> > wave-function solution for the entire universe.
> >
> I haven't read Barbour's book, but if that is what he is saying, he
> would be wrong. Consider a universe of a single electron living in a
> potential well

Where does the potential well come from?

>V(x)=|x|^2, x\in R^3. There is a well defined solution
> \psi(t,x) = \sum_j <\psu_0|j><j| exp(-iE_j t) given the initial
> condition \psi_0.
> The function \psi: R x R^3 -> C is a static (time independent)
> mathematical object (I wrote it the mathematicians write to emphasize
> this point). Why wouldn't you identify this with the Multiverse of
> that electron?
> Now I am aware that several people (Hawking included I gather) have
> proposed various "wave functions of the universe", which tend to be
> solutions of the Wheeler de Witt equation, which is a time independent
> equation. However, I'm not so interested in following that literature.

That is roughly the approach Barbour takes.

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