Le mercredi 06 janvier 2010 à 00:29 +1100, Stathis Papaioannou a écrit : > 2010/1/5 Quentin Anciaux <[email protected]>: > > >> Consider a set of three one minute intervals of experience, {S1, S2, > >> S3}, which belong to a person S. S2 remembers S1 and remembers no gap > >> or intervening experiences between S2 and S1; S3 remembers S1 and S2 > >> and remembers that S1 preceded S2; and S3 also remembers no gap or > >> intervening experiences between S2 and S1 or between S3 and S2. In > >> other words, they are subjectively three consecutive minutes in the > >> life of S. S is aware that his experiences are generated on a > >> computer, and he is also aware that they are being generated in one of > >> two ways: in sequence as S1, S2, S3 or out of sequence as S2, S1, S3. > >> Does S have any basis for deciding that it is more likely that his > >> experiences are being generated in sequence? > >> > > > > It seems to me that it depends if the computation is iterative or not... in > > other words, to compute step N you must have computed step N-1 before that. > > > > If you can directly compute step N without computing prior step, S2/S1/S3 is > > possible. If not you had necessarily computed step S1 before S2, only by > > doing a replay of a previously done computation you could do it : > > > > - first generate S1/S2/S3 in order and save each intermediate result, then > > you can do > > - S2 (taking the previously intermediate result of S1), S1 then S3 (taking > > S2 result). > > > > But running the same thing more times add a priori nothing. If the process > > is iterative then "in order" computation win the measure battle (because any > > out of order one require a genuine in order computation before). > > Another way to compute S2 without using S1 would be to run the UD. >
Yes but the UD will generate infinitely more often the in order S1/S2/S3 than out of order... with what you are saying I don't even understand what is a computation if not a rules ordered sequential state order. Quentin -- All those moments will be lost in time, like tears in rain. -- You received this message because you are subscribed to the Google Groups "Everything List" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/everything-list?hl=en.
