On Tue, Jul 9, 2013  Jason Resch <jasonre...@gmail.com> wrote:

>>> If we call that new number tau (t).  Then Euler's identity becomes:
>>> e^(t * i) = 1
>> >> There is no disputing matters of taste but I think the original
>> equation is more beautiful because it shows a relationship between 5 of the
>> most important numbers in all of mathematics. Your new equation only has 4
>> important numbers, it doesn't include  zero, it has the multiplicative
>> identity but not the additive identity.
> > If you want to see all the constants at once there is an easy
> correction:  e^(t*i) - 1 = 0

 Then it has the additive identity but not the multiplicative identity and
I still prefer Euler's original.

  John K Clark

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