On Tue, Jul 9, 2013 Jason Resch <[email protected]> wrote: >>> If we call that new number tau (t). Then Euler's identity becomes: >>> e^(t * i) = 1 >>> >> >> >> There is no disputing matters of taste but I think the original >> equation is more beautiful because it shows a relationship between 5 of the >> most important numbers in all of mathematics. Your new equation only has 4 >> important numbers, it doesn't include zero, it has the multiplicative >> identity but not the additive identity. >> > > > If you want to see all the constants at once there is an easy > correction: e^(t*i) - 1 = 0 >
Then it has the additive identity but not the multiplicative identity and I still prefer Euler's original. John K Clark -- You received this message because you are subscribed to the Google Groups "Everything List" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To post to this group, send email to [email protected]. Visit this group at http://groups.google.com/group/everything-list. For more options, visit https://groups.google.com/groups/opt_out.
