On Thu, Jul 11, 2013 at 3:23 PM, John Clark <johnkcl...@gmail.com> wrote:

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> On Thu, Jul 11, 2013 at 3:31 PM, Jason Resch <jasonre...@gmail.com> wrote:
>
> > 1 is in the modified version I provided: e^(t*i) - 1 = 0
>>
>
> I only see a -1. 1* X is always equal to X but -1*X is never equal to X
> unless X=0.
>
>
Perhaps this suits you better then: e^(t*i) = 1 + 0
Jason
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