On Thu, Jan 2, 2014 at 11:44 AM, Edgar L. Owen <edgaro...@att.net> wrote:
> Jason, > > No, please carefully read my new topic post "Another shot at how spacetime > emerges from quantum events" where I explain this process in detail. You > will see why it doesn't lead to MW but instead to many fragmentary > spacetimes (entanglement networks) which link and align via shared events. > But all this occurs in the same underlying computational (not dimensional) > space which everything is part of. > > The spin orientation of the two particles is fixed in their mutual frame > when they are created. > Edgar, Your theory contradicts the It<Bit theory of Wheeler which predicts that the properties of all particles vanish including spin in the phase of their existence between observations. All properties fixed at their creation are therefore subsequently lost; only to be restored by the binary yes-no question asked by an observer at detection. Richard It's just that that frame (entanglement network) is not linked to that of > the observer until a common event (observer's measurement of one particle's > spin) links and aligns the particles' spin orientation frame to that of the > observer's. Prior to that they are completely separate spacetimes. That's > why the spins are indeterminate in the frame of the observer until he > measures one and by doing so links and aligns their frame with his. > > This process falsifies FTL, non-locality, MWI (unless you want to call the > fragmentary entanglement networks separate worlds. They are separate > spacetime fragments but not really separate 'worlds' since they continually > merge and align at common events in the SAME computational reality.) > > Edgar > > On Thursday, January 2, 2014 9:11:57 AM UTC-5, Jason wrote: >> >> >> >> >> On Thu, Jan 2, 2014 at 7:53 AM, Edgar L. Owen <edga...@att.net> wrote: >> >>> Jason, >>> >>> Great! An amazing post! You seem to have correctly gotten part of the >>> theory I proposed in my separate topic "Another stab at how spacetime >>> emerges from quantum events." Please refer to that topic to confirm... >>> >>> Do you understand how the fact that the spins are determined in the >>> frames of the spinning particles WHEN they are created falsifies FTL and >>> non-locality? >>> >> >> Yes, but I also think this leads to many worlds, since there is not a >> single state of the superposition. The particle pair is not just Up_Ddown >> or Down_Up, but both Up_Down + Down_Up. After the measurement, it is >> Measured_Up_Down + Measured_Down_Up. >> >> Bell's inequality leads to a refutation that the two particles can have >> just a single state. >> >> Jason >> >> >>> >>> Edgar >>> >>> >>> >>> On Wednesday, January 1, 2014 2:21:33 PM UTC-5, Jason wrote: >>>> >>>> >>>> >>>> >>>> On Wed, Jan 1, 2014 at 4:33 AM, LizR <liz...@gmail.com> wrote: >>>> >>>>> On 1 January 2014 21:34, meekerdb <meek...@verizon.net> wrote: >>>>> >>>>>> On 12/31/2013 7:22 PM, LizR wrote: >>>>>> >>>>>> On 1 January 2014 13:54, meekerdb <meek...@verizon.net> wrote: >>>>>> >>>>>>> Of course in Hilbert space there's no FTL because the system is >>>>>>> just one point and when a measurement is performed it projects the >>>>>>> system >>>>>>> ray onto a mixture of subspaces; spacetime coordinates are just some >>>>>>> labels. >>>>>>> >>>>>> >>>>>> I thought there was no FTL in ordinary space, either? (I mean, none >>>>>> required for the MWI?) >>>>>> >>>>>> Right, but the state in Hilbert space is something like |x1 y1 z1 s1 >>>>>> x2 y2 z2 s2> and when Alice measures s1 at (x1 y1 z1) then s2 is >>>>>> correlated >>>>>> at (x2 y2 z2). As I understand it the MWI advocates say this isn't FTL >>>>>> because this is just selecting out one of infinitely many results |s1 >>>>>> s2>. >>>>>> But the 'selection' has to pair up the spins in a way that violates >>>>>> Bell's >>>>>> inequality. >>>>>> >>>>> >>>>> If I understand correctly ... actually, let me just check if I do, >>>>> before I go any further, in case I'm talking out my arse. Which wouldn't >>>>> be >>>>> the first time. >>>>> >>>>> I assume we're talking about an EPR correlation here? >>>>> >>>>> If yes, I've never understood how the MWI explains this. >>>>> >>>> >>>> The thing to remember is entanglement is the same thing as measurement. >>>> The entangled pair of particles have measured each other, but they remain >>>> isolated from the rest of the environment (and thus in a superposition, of >>>> say UD and DU). Once you as an observer measure either of the two >>>> particles, you have by extension measured both of them, since the position, >>>> which you measured has already measured the electron, and now you are >>>> entangled in their superposition. >>>> >>>> Jason >>>> >>>> >>>> >>>>> I've see it explained with ASCII diagrams by Bill Taylor on the FOAR >>>>> forum, and far be it from me to quibble with Bill, but it never made sense >>>>> to me. Somehow, the various branches just join up correctly... >>>>> >>>>> The only explanation I've come across that I really understand for >>>>> EPR, and that doesn't violate locality etc is the time symmetry one, where >>>>> all influences travel along the light cone, but are allowed to go either >>>>> way in time. >>>>> >>>>> So although I quite like the MWI because of its ontological >>>>> implications, this is one point on which I am agnostic, because I don't >>>>> understand the explanation. >>>>> >>>>>> >>>>>> >>>>>> In fact, it's generally assumed to be very, very STL (unless >>>>>>> light itself is involved). At great distances from the laboratory, one >>>>>>> imagines that the superposition caused by whatever we might do to cats >>>>>>> in >>>>>>> boxes would decay to the level of noise, and fail to spread any further. >>>>>>> >>>>>>> That's an interesting viewpoint - but it's taking spacetime instead >>>>>>> of Hilbert space to be the arena. If we take the cat, either alive or >>>>>>> dead, and shoot it off into space then, as a signal, it won't fall off >>>>>>> as >>>>>>> 1/r^2. >>>>>>> >>>>>>> No, but it will travel STL! >>>>>> >>>>>> >>>>>> Sure. I was just commenting on the idea that the entanglement has a >>>>>> kind of limited range because of 'background noise'. An interesting >>>>>> idea, >>>>>> similar to one I've had that there is a smallest non-zero probability. >>>>>> >>>>>> But if you want to get FTL, that's possible if Alice and Bob are near >>>>>> opposite sides of our Hubble sphere when they do their measurements. >>>>>> They >>>>>> are then already moving apart faster than c and will never be able to >>>>>> communicate - with each other, but we, in the middle will eventually >>>>>> receive reports from them so that we can confirm the violation of Bell's >>>>>> inequality. >>>>>> >>>>> >>>>> Hmm, that's a good point. That would, however, fit in nicely with time >>>>> symmetry (which really needs a nice acronym, I'm not sure "TS" cuts it). I >>>>> tend to evangelise a bit on time symmetry, but only because everyone else >>>>> roundly ignores it, and it seems to me that it at least has potential. >>>>> >>>>> >>>>> -- >>>>> You received this message because you are subscribed to the Google >>>>> Groups "Everything List" group. >>>>> To unsubscribe from this group and stop receiving emails from it, send >>>>> an email to everything-li...@googlegroups.com. >>>>> To post to this group, send email to everyth...@googlegroups.com. >>>>> >>>>> Visit this group at http://groups.google.com/group/everything-list. >>>>> For more options, visit https://groups.google.com/groups/opt_out. >>>>> >>>> >>>> -- >>> You received this message because you are subscribed to the Google >>> Groups "Everything List" group. >>> To unsubscribe from this group and stop receiving emails from it, send >>> an email to everything-li...@googlegroups.com. >>> To post to this group, send email to everyth...@googlegroups.com. >>> Visit this group at http://groups.google.com/group/everything-list. >>> For more options, visit https://groups.google.com/groups/opt_out. >>> >> >> -- > You received this message because you are subscribed to the Google Groups > "Everything List" group. > To unsubscribe from this group and stop receiving emails from it, send an > email to everything-list+unsubscr...@googlegroups.com. > To post to this group, send email to everything-list@googlegroups.com. > Visit this group at http://groups.google.com/group/everything-list. > For more options, visit https://groups.google.com/groups/opt_out. > -- You received this message because you are subscribed to the Google Groups "Everything List" group. 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