Brent,

First thanks for your comment. 

I think Jesse and I are both aware of that, but we are considering the age 
relationship JUST BETWEEN A and B and so must consider only how they see it 
in their OWN frames, not the view of a 3rd observer of that relationship. 
Though Jesse would probably disagree.

The current discussion is about choice of frames though. Check my latest 
post for a synopsis of one case..

Edgar



On Tuesday, March 4, 2014 2:56:49 PM UTC-5, Brent wrote:
>
>  On 3/4/2014 11:19 AM, Jesse Mazer wrote:
>  
>  
> On Tue, Mar 4, 2014 at 2:02 PM, Edgar L. Owen <[email protected]<javascript:>
> > wrote:
>
>> Jesse, 
>>
>>  You ask me to choose between 1. and 2.
>>
>>  1. If B's proper age at this point in spacetime is T, then C's proper 
>> age at this point in spacetime must be T as well (i.e. their proper ages 
>> are "simultaneous" in the sense that they must reach the same age 
>> simultaneously).
>>
>>  2. If B and C's worldlines both pass through a specific point in 
>> spacetime P, and B's age is T1 when she passes through P, while C's age is 
>> T2 when she passes through P, then B must be at age T1 simultaneously with 
>> C being at age T2 (i.e. whatever two specific ages they have at P, they 
>> must reach those two ages simultaneously, even if the two ages are 
>> different)
>>
>>  
>>  First I assume that by "passing through the same point in spacetime" 
>> you mean that the worldlines cross at P simultaneously by the operational 
>> definition of no light delay.
>>
>>  1. is true only in a SYMMETRIC case. In the symmetric case they would 
>> have the same ages as they pass through the same point P, but in that case 
>> they have the same ages during the WHOLE trip so no big surprise.
>>  
>   
> This isn't true.  In the inertial frame of a third party passing by, B and 
> C age at different rates in different segments of their world lines even 
> though those rates integrate to the same total aging between their two 
> meetings.
>
> Brent
>
>  

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