On 19/04/2016 12:17 am, Bruno Marchal wrote:

On 18 Apr 2016, at 09:45, Bruce Kellett wrote:Let me reduce this to simple steps:1) MWI is an interpretation of QM only. I.e., it reproduces all theresults of QM without adding any additional structure or dynamics.What do you mean by QM? I am not sure I agree with you. Everett didnot talk about a new intepretation of QM, but about a new formulationof QM. And he is right in the sense of the logician. Before Everett:QM was formulated roughly SWE + Collapse + an implicit dualist theoryof mind or of scale (mircro/macro). Everett's QM is SWE, the abandonof collapse, + a mechanist theory of mind, with the implicit use ofthe FPI.

`No, you are confusing the mathematical theory of QM with its various`

`interpretations. The mathematical theory of quantum mechanics is the`

`theory that associates physical states with vectors in Hilbert space;`

`observables with Hermitian operators in that space; and measurement`

`results with the eigenvalues of the corresponding operator. Supplemented`

`with the Born rule, which states that the probability for obtaining any`

`particular eigenvalue as the result of a measurement is given by the`

`absolute square of the coefficient of that eigenvalue in the`

`superposition describing the state, we get the standard mathematical`

`theory of quantum mechanics.`

`Note that this says nothing about collapse or not, about one or many`

`worlds, or about any interpretational issues. Interpretational issues`

`are overlaid on this basic theory of QM, and it is central to the whole`

`discussion that the predicted experimental results depend only on the`

`underlying theory and not on the interpretational superstructure. All`

`interpretations must give the same predictions for experimental results`

`or else they are alternative theories and not interpretations of`

`(standard) QM.`

For a logician, if QM (without collapse) is formalized, you get an"Herbrand minimal model" which contains already all relative state(like we get them already in the sigma_1 arithmetic with the MechanistHypothesis in the Cognitive Science).Given the linearity of the tensor product and the evolution, we canonly abstract away the self-superposition, although we would have totake them into account if we get a quantum brain (and here the SWEgive non ambigous result where a collapse theory has to first makemore precise how the (non local) collapse is made physically.

`I don't know what you are talking about. But you are still confusing the`

`theory with its interpretation.`

2) The QM state describing an entangled singlet pair does not referto, or depend on, the separation between the particles.OK. But the singlet state describe an infinity of Bob and Alice withtheir spin correlated, yet both of them see their own particles with arandom result, as none of them know in which universe they are. Theyknow only one thing for sure: their spin are correlated, and remainsso independently of the distance.

`The only thing either of them knows for sure locally is that they have`

`50% probability of getting |+> and 50% probability of getting |->. After`

`the experiment is complete and completely decohered locally, they have`

`just one result. You might interpret this situation by claiming that`

`there are two local copies of each, one with |+> and one with |->, but`

`that is an interpretation, it is not the mathematical theory, which`

`predicts only the probabilities.`

3) The quantum calculation of the joint probabilities depends on therelative orientation between the separate measurements on theseparated particles.No problem.4) This quantum calculation is the same for any physical separation,since the singlet state itself does not depend on the separation.No problem.5) The quantum calculation is, therefore, intrinsically non-localbecause it does not depend on the separation, which can bearbitrarily large.This does not follow. It would be if the state |psi> = (|+>|-> -|->|+>) would be interpreted by We know that Alice has a particle instate |+> or in state |-> and Bob the opposite. But the state (|+>|->- |->|+>) means eaxctly that neither Alice nor Bob know in whichuniverse they are. It could be one with |+'> or |-'> or whatever.

`Again, you are confused by the basis issue. The singlet state can be`

`expanded in the above form in any basis whatsoever, sure, but you are`

`forgetting the crucial matter of contextuality. For Alice, sitting there`

`with her EPR particle, the basis in which the singlet state is expanded`

`is completely irrelevant -- there is only one Alice at this stage. Once`

`she chooses the setting for her magnet, she needs to be able to`

`calculate the probabilities for the possible results that she can get.`

`To calculate these probabilities she chooses the basis that corresponds`

`to the orientation of her magnet. This is the effect of contextuality.`

`She could, of course, choose to make her calculations in any of the`

`other infinite number of possible bases. But then, in order to relate`

`the results of her calculation to the results of her experiment, she has`

`to perform the rotation to bring the theoretical and experimental bases`

`into alignment.`

6) Since MWI does not add anything to standard QM, and standard QMgives a non-local account of the probabilities we are considering,any MWI account must also be intrinsically non-local.Proof?

The above sequence of steps constitutes the proof.

Don't invoke Bell's theorem, because it assumes Alice and Bob are inthe same reality, where without collapse, the measurement of Bob andAlice propagate only locally from multiple Alice to mutiple Bob, asdescribe by the superposition singlet state (in any base).

`I don't have to invoke Bell's theorem. That is not relevant for what I`

`am saying above. Let me spell it out:`

`1) The QM singlet state |psi> = (|+>|-'> - |->|+'>) is intrinsically`

`non-local. This is universally agreed. If it were local, then QM would`

`be intrinsically local and we would not be having this discussion.`

`2) A hidden variable theory, which would be a "completion" of QM (in`

`Einstein's sense), would be a /different/ theory, not standard QM. (It`

`would have a mechanism whereby the orientation at A was available for`

`the interpretation of the orientation at B. This is the mechanism that`

`Jesse was confusing with the mathematical theory for calculating`

`probabilities. QM is non-local because it provides no such mechanism.`

`Any local theory must provide such a mechanism, and thus must be a`

`different theory from conventional QM.)`

`3) What Bell's argument shows is that even if you "complete" QM by`

`adding hidden variables, the resulting theory is still inescapably`

`non-local.`

`4) Experiment irrefutable bears out the violation of the Bell`

`inequalities, so demonstrates that reality is non-local.`

If I find some time, I might try to describe this with the densitymatrix formalism, which I think can make this more obvious.One physical reality, and/or hidden variables specifying unqiueness ofstate + Violation of Bell's inequality entails non-locality. That isshown by Bell's inequality violatin.But without "collapsing" a wave at a distance, the apparentnon-locality comes only from Alice or Bob determining in whichuniverse they are. There are just no reason they found themsleves inthe same universe. If they can compare the results, it is only afterthe contagion of their superposed state with each other, and in thatcase, the statistics implies the Bell correlations, without anyphysical action at a distance. You need to transform the pure state insome mixture, before the measurement to get non-locality, but suchmixture are local and different for each Alice and Bob in thesuperposition state, so you cannot take them as definite like if Aliceor Bob could know that in advance.

`What can I say? There are only two local possibilities for both Alice`

`and Bob: they get either |+> or |->, relative to their own context as`

`defined by the orientation of their respective magnets. So there can`

`only ever be four distinct worlds. You can multiply them as many times`

`as you like, as Jesse seems to want to do, but it is a basic fact of`

`statistics that if you take an ensemble of a very large number of a`

`limited set of states, any random selection from that ensemble will`

`result in one of the states that you originally put in -- nothing new is`

`generated. The four possible worlds arising from our scenario are`

`|+>|+'>, |+>|-'>, |->|+'>, and |->|-'>, no different combinations can`

`ever arise.`

`This crucial thing here, though, is that these four possibilities are`

`not equally probable. The distinct probabilities for each possible world`

`are given by the fundamental quantum calculation, which is independent`

`of the interpretation you overlay on the theory: the probabilities`

`depend only on the relative orientations of the magnets of Alice and Bob`

`-- they depend on nothing else. To get the *relative* orientation of the`

`magnets you have to compare the separate orientations for Alice and Bob`

`-- /at remote, potentially spacelike, separate locations/. That is why`

`QM is said to be non-local.`

`Nothing that you have said obviates anything in the above argument. The`

`conclusion is sound; you merely obfuscate by your talk of and indefinite`

`number of possible worlds. On further reflection, I think you are really`

`confused by the basis issue. I suggest that you think more carefully`

`about the role of contextuality in the selection of an appropriate`

`basis. You need only one basis for each experimenter -- all other bases`

`are irrelevant.`

It is "shocking" because it is really the self-multiplication whichexplains the apparent non-locality, but then that was also the casefor the apparent indeterminacy.Put in a different way: when Alice and Bob make their measurement,they might get result violating the correlation, but that would maketheir belonging to different cross-product term of the finalsuperposition, so they would not been able to compare those forbiddenresults.

`There are no such cross terms in the expansion. They get only |+> or`

`|->, and any possible combination is allowed in general (unless the`

`theory gives an exactly zero probability for one or more of the four`

`possible worlds). Forbidden results are forbidden by the laws of`

`physics, and the indication that a particular combination is forbidden`

`is that the corresponding probability is calculated to be zero. So there`

`are no "forbidden cross-product terms". You are talking nonsense.`

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