On 4/9/2019 11:55 AM, agrayson2...@gmail.com wrote:


On Tuesday, April 9, 2019 at 12:05:11 PM UTC-6, Brent wrote:



    On 4/9/2019 7:52 AM, agrays...@gmail.com <javascript:> wrote:


    On Monday, April 8, 2019 at 11:16:25 PM UTC-6,
    agrays...@gmail.com wrote:

        In GR, is there a distinction between coordinate systems and
        frames of reference? AG??


    Here's the problem; there's a GR expert known to some members of
    this list, who claims GR does NOT distinguish coordinate systems
    from frames of reference. He also claims that given an arbitrary
    coordinate system on a manifold, and any given point in
    space-time, it's possible to find a transformation from the given
    coordinate system (and using Einstein's Equivalence Principle),
    to another coordinate system which is locally flat at the
    arbitrarily given point in space-time. This implies that a test
    particle is in free fall at that point in space-time. But how can
    changing labels on space-time points, change the physical
    properties of a test particle at some arbitrarily chosen point in
    space-time? I believe that such a transformation implies a
    DIFFERENT frame of reference, in motion, possibly accelerated,
    from the original frame or coordinate system. Am I correct? TIA, AG

    You're right that a coordinate system is just a function for
    labeling points and, while is may make the equations messy or
    simple, it doesn't change the physics.?? If you have two different
    coordinate systems the transformation between them may be
    arbitrarily complicated.?? But your last sentence referring to
    motion as distinguishing a coordinate transform from a reference
    frame seems to have slipped into a 3D picture.?? In a 4D
    spacetime, block universe there's no difference between an
    accelerated reference frame and one defined by coordinates that
    are not geodesic.

    Brent


Suppose the test particle is on a geodesic path in one coordinate system, but in another it's on an approximately flat 4D surface at some point in the transformed coordinate system.

A geodesic is a physically defined path, one of extremal length. It's independent of coordinate systems and reference frames.  If a geodesic is not a geodesic in your transformed coordinate system, then you've done something wrong in transforming the metric.

Brent

Doesn't this represent a change in the physics via a change in labeling the space-time points?  How is this possible without a change in the frame of reference, and if so, how would that be described if not by acceleration? AG
--
You received this message because you are subscribed to the Google Groups "Everything List" group. To unsubscribe from this group and stop receiving emails from it, send an email to everything-list+unsubscr...@googlegroups.com <mailto:everything-list+unsubscr...@googlegroups.com>. To post to this group, send email to everything-list@googlegroups.com <mailto:everything-list@googlegroups.com>.
Visit this group at https://groups.google.com/group/everything-list.
For more options, visit https://groups.google.com/d/optout.

--
You received this message because you are subscribed to the Google Groups 
"Everything List" group.
To unsubscribe from this group and stop receiving emails from it, send an email 
to everything-list+unsubscr...@googlegroups.com.
To post to this group, send email to everything-list@googlegroups.com.
Visit this group at https://groups.google.com/group/everything-list.
For more options, visit https://groups.google.com/d/optout.

Reply via email to