On Thursday, April 11, 2019 at 4:37:39 PM UTC-6, Brent wrote: > > > > On 4/11/2019 1:58 PM, [email protected] <javascript:> wrote: > > >>> >> He might have been referring to a transformation to a tangent space where >> the metric tensor is diagonalized and its derivative at that point in >> spacetime is zero. Does this make any sense? >> >> >> Sort of. >> > > > Yeah, that's what he's doing. He's assuming a given coordinate system and > some arbitrary point in a non-empty spacetime. So spacetime has a non zero > curvature and the derivative of the metric tensor is generally non-zero at > that arbitrary point, however small we assume the region around that point. > But applying the EEP, we can transform to the tangent space at that point > to diagonalize the metric tensor and have its derivative as zero at that > point. Does THIS make sense? AG > > > Yep. That's pretty much the defining characteristic of a Riemannian space. > > Brent >
But isn't it weird that changing labels on spacetime points by transforming coordinates has the result of putting the test particle in local free fall, when it wasn't prior to the transformation? AG -- You received this message because you are subscribed to the Google Groups "Everything List" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To post to this group, send email to [email protected]. Visit this group at https://groups.google.com/group/everything-list. For more options, visit https://groups.google.com/d/optout.
