On 4/11/2019 1:58 PM, agrayson2...@gmail.com wrote:
He might have been referring to a transformation to a tangent
space where the metric tensor is diagonalized and its derivative
at that point in spacetime is zero. Does this make any sense?
Sort of.
Yeah, that's what he's doing. He's assuming a given coordinate system
and some arbitrary point in a non-empty spacetime. So spacetime has a
non zero curvature and the derivative of the metric tensor is
generally non-zero at that arbitrary point, however small we assume
the region around that point. But applying the EEP, we can transform
to the tangent space at that point to diagonalize the metric tensor
and have its derivative as zero at that point. Does THIS make sense? AG
Yep. That's pretty much the defining characteristic of a Riemannian space.
Brent
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