On 4/25/2022 6:06 PM, John Clark wrote:
On Mon, Apr 25, 2022 at 6:42 PM Bruce Kellett <bhkellet...@gmail.com>
wrote:
>> The only reason we think the gravitational constant does not
change is because when we measure the potential gravitational
energy in something today against a standard calibration
energy we find that we get the same number of energy units
that we got yesterday when we measured the potential
gravitational energy it was in against a standard calibration
energy.
/> Sure, a spring balance needs to be calibrated against some
standard mass. But we do not calibrate every day. Once the scale
is set, we assume that the spring constant or whatever remains the
same, so that recalibration is not necessary./
You're right, it's not necessarybecauseas long as the test mass and
the mass standard decrease by an equal percentage you're always gonna
get the same result and you'll never notice that anything has changed.
/> So if all energies (including mass) drop by 90%, we will be
able to detect this as long as the spring constant does not also
change by this amount. Springs tend to rely on the
electromagnetic properties of metals, and these will not
change just because we measure a spin component in the next room./
IfMany Worlds is correct then of course thespring constant will change
because the world will split due to ANY measurement, and the absolute
non-relative amount of energy of EVERY type will decrease.
/> I used a spring balance to compare a mass against the
gravitational field, where I assumed that Newton's constant does
not change on a spin measurement. If all energies (and masses)
drop by 50% in each branch of the spin measurement, then the mass
of the earth decreases by 50%, and the local acceleration due to
gravity, g, also drops by 50%. Now consider a simple pendulum: the
period of swing is T = 2*pi*sqr(L/g), where L is the length of the
pendulum. If g drops by 50%/,[...]
But g does NOT drop by 50% and I never said it did, I said the
gravitational potential energy drops by 50%, and that will happen if
the mass/energy of a gravitationally bound system drops by 50% even if
g remains constant. If yesterday I measured the mass/energy of a
pendulum and of the entire earth against an energy standard and I
measure those things again today against today's energy standard, and
if the mass/energy of the pendulum and the earth and today's energy
standard have all decreased by 50%, then I will get the same measured
value that I got yesterday even if g really is the same as it was
yesterday.
If all mass were scaled down by the same factor the gravitational
interactions, like orbits and pendulums, would seem unchanged. But what
about the natural frequency of spring-mass systems? Halving the mass
while the EM forces between molecules of the spring stay the same means
the frequency will go up. So must all interaction constants change to
save the appearance?
Brent
And yes the force that the earth is pulling down on that pendulum
would only be half as strong as it was yesterday, HOWEVER the inertia
(which is proportional to the mass/energy) of the pendulum would only
be half as much as it was yesterday, so the two changes with cancel
out and the pendulum would fall with the same acceleration that it did
yesterday, and the period of its swing would be the same too.
John K Clark See what's on my new list at Extropolis
<https://groups.google.com/g/extropolis>
maq
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