On 4/25/2022 6:06 PM, John Clark wrote:

On Mon, Apr 25, 2022 at 6:42 PM Bruce Kellett <bhkellet...@gmail.com>wrote:>> The only reason we think the gravitational constant does not change is because when we measure the potential gravitational energy in something today against a standard calibration energy we find that we get the same number of energy units that we got yesterday when we measured the potential gravitational energy it was in against a standard calibration energy. /> Sure, a spring balance needs to be calibrated against some standard mass. But we do not calibrate every day. Once the scale is set, we assume that the spring constant or whatever remains the same, so that recalibration is not necessary./You're right, it's not necessarybecauseas long as the test mass andthe mass standard decrease by an equal percentage you're always gonnaget the same result and you'll never notice that anything has changed./> So if all energies (including mass) drop by 90%, we will be able to detect this as long as the spring constant does not also change by this amount. Springs tend to rely on the electromagnetic properties of metals, and these will not change just because we measure a spin component in the next room./IfMany Worlds is correct then of course thespring constant will changebecause the world will split due to ANY measurement, and the absolutenon-relative amount of energy of EVERY type will decrease./> I used a spring balance to compare a mass against the gravitational field, where I assumed that Newton's constant does not change on a spin measurement. If all energies (and masses) drop by 50% in each branch of the spin measurement, then the mass of the earth decreases by 50%, and the local acceleration due to gravity, g, also drops by 50%. Now consider a simple pendulum: the period of swing is T = 2*pi*sqr(L/g), where L is the length of the pendulum. If g drops by 50%/,[...]But g does NOT drop by 50% and I never said it did, I said thegravitational potential energy drops by 50%, and that will happen ifthe mass/energy of a gravitationally bound system drops by 50% even ifg remains constant. If yesterday I measured the mass/energy of apendulum and of the entire earth against an energy standard and Imeasure those things again today against today's energy standard, andif the mass/energy of the pendulum and the earth and today's energystandard have all decreased by 50%, then I will get the same measuredvalue that I got yesterday even if g really is the same as it wasyesterday.

`If all mass were scaled down by the same factor the gravitational`

`interactions, like orbits and pendulums, would seem unchanged. But what`

`about the natural frequency of spring-mass systems? Halving the mass`

`while the EM forces between molecules of the spring stay the same means`

`the frequency will go up. So must all interaction constants change to`

`save the appearance?`

Brent

And yes the force that the earth is pulling down on that pendulumwould only be half as strong as it was yesterday, HOWEVER the inertia(which is proportional to the mass/energy) of the pendulum would onlybe half as much as it was yesterday, so the two changes with cancelout and the pendulum would fall with the same acceleration that it didyesterday, and the period of its swing would be the same too.John K Clark See what's on my new list at Extropolis<https://groups.google.com/g/extropolis>maq --You received this message because you are subscribed to the GoogleGroups "Everything List" group.To unsubscribe from this group and stop receiving emails from it, sendan email to everything-list+unsubscr...@googlegroups.com.To view this discussion on the web visithttps://groups.google.com/d/msgid/everything-list/CAJPayv0%3DQDjx1KQBSv823YFAVEHhGLdd%3DLWXTtnnKv-CJgJC%3Dw%40mail.gmail.com<https://groups.google.com/d/msgid/everything-list/CAJPayv0%3DQDjx1KQBSv823YFAVEHhGLdd%3DLWXTtnnKv-CJgJC%3Dw%40mail.gmail.com?utm_medium=email&utm_source=footer>.

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