> Sparkaround wrote:
> > It seemed that this example code make the problem more clear.
> > The program will never exit if I press 'a' !
>
> Oops, my bad -- since your widget derives from Fl_Widget,
> I don't think it responds to FL_ENTER/LEAVE/FOCUS by default,
> so the code needs a small modification to react to the FL_KEYDOWN event
> (see below).
>
> I don't think this will affect your problem of slowness to respond,
> but it should make it react to the KEYDOWN event..
>
> #include <FL/Fl.H>
> #include <FL/Fl_Widget.H>
> #include <FL/Fl_Double_Window.H>
> #include <FL/fl_draw.H>
> #include <stdlib.h> // exit()
>
> #define DELAY 0.001
>
> class Test_Draw: public Fl_Widget {
> public:
> Test_Draw(int x, int y, int w, int h, char *l=0):Fl_Widget(x,y,w,h,l) {
> }
> void draw() {
> static int d=0;
> d++;
> fl_rectf(x(),y(), (int) d%w(), (int)d%h(), d%255,d%255,d%255);
> }
> int handle(int e) {
> int ret = Fl_Widget::handle(e);
> switch (e) {
> case FL_ENTER: // must handle these to get FL_KEYDOWN
> case FL_LEAVE:
> case FL_FOCUS:
> ret = 1;
> break;
> case FL_KEYDOWN:
> ret = 1;
> printf("KEYDOWN: %d\n", Fl::event_key());
> if ( Fl::event_key('a') ) exit(0);
> break;
> }
> return(ret);
> }
> };
>
> Test_Draw *t;
> static void update(void *) {
> t->redraw();
> Fl::repeat_timeout(DELAY, update, 0);
> }
>
> int main(int argc, char **argv) {
> Fl_Double_Window w(200,200,Fl::w()/2, Fl::h()/2);
> //Fl_Window w(200,200,Fl::w()/2, Fl::h()/2);
> t = new Test_Draw(0,0,w.w(),w.h());
> w.end();
> w.show(argc, argv);
> Fl::add_timeout(DELAY, update, 0);
> return(Fl::run());
> }
>
> > I have to stop the program with 'ESC'. It take me about ten seconds to
> > press 'ESC' before the program exited.
Thanks.
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