There are (31-bit and, more relevantly perhaps, 24-bit) virtual storage 
numbers in SMF 30 that might help you. But if you are failing to get 
enough storage maybe they wouldn't.

I'm thinking of Step-End - Subtype 4 - records.

Cheers, Martin

Martin Packer,
zChampion, Principal Systems Investigator,
Worldwide Banking Center of Excellence, IBM

+44-7802-245-584

email: martin_pac...@uk.ibm.com

Twitter / Facebook IDs: MartinPacker
Blog: 
https://www.ibm.com/developerworks/mydeveloperworks/blogs/MartinPacker



From:   Jake anderson <justmainfra...@gmail.com>
To:     IBM-MAIN@listserv.ua.edu
Date:   20/02/2014 09:10
Subject:        Below the Line Storage Allocation
Sent by:        IBM Mainframe Discussion List <IBM-MAIN@listserv.ua.edu>



Hello,

Cross posted to CICS as well

I am running a CICS load module scanner job where it fails with the below
message

10.53.23 JOB02673  IEA995I SYMPTOM DUMP OUTPUT  502
    502             SYSTEM COMPLETION CODE=106  REASON CODE=0000000C
    502              TIME=10.53.23  SEQ=00242  CPU=0000  ASID=0037
    502              PSW AT TIME OF ERROR  070C1000   81391A30  ILC 2 INTC
0D
    502                NO ACTIVE MODULE FOUND
    502                NAME=UNKNOWN
    502                DATA AT PSW  01391A2A - 8400181E  0A0D18FB 180C181D
    502                GR 0: 00001F00   1: 84106000
    502                   2: 26080021   3: 0000000C
    502                   4: 00000014   5: 006FF540
    502                   6: 7F4A6100   7: 0000000C
    502                   8: 7F4A6150   9: 01391F58
    502                   A: 00000024   B: 00000014
    502                   C: 00000000   D: 7F4A6150
    502                   E: 84106000   F: 0000000C
    502              END OF SYMPTOM DUMP

I understand that the Job does not have the enough storage below the Line.
I tried running the Job with REGION=512M,REGION=256M,REGION=8M,REGION=0M
but still the Job does not get the storage below Line.

Is there a way to identify the correct storage mapping for a particular
batch job which has to execute within 16MB. The program is pretty big and
has 24(RM).

I am still not able to find any clue about the exact storage which would 
be
required for this Job to run.

Any pointers are highly appreciated.

Z/OS 1.13 capped at 13MSU

Jake

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