On Wed, Jul 16, 2014 at 7:34 PM, Andrea Faulds <a...@ajf.me> wrote: > What are you suggesting you do for an integer division, then? ($a - ($a % > $b)) / > $ b? The division operator already returns an integer. Or should I just use > intdiv()? > It does, but it returns the float truncated result of division. I'm suggesting having it to integer division. So you'd do: $a / $b and it's be smart enough to do the right method.
>> If we're really set on adding a new operator, I'd vote for something >> which provides dividend *and* remainder in some way. (Useful for time >> arithmetic, for example) >> In all seriousness, you could just have the compiler optimise using % and %% > successively with the same operands to just be a single division, if that's > possible. > Assuming you meant / and %, then probably in opcache+'s optimizer. -Sara -- PHP Internals - PHP Runtime Development Mailing List To unsubscribe, visit: http://www.php.net/unsub.php
