Re: [JAVA3D] Plane equation

[Dirk L. van Krimpen]

Shyam,   When you rotate along the X-axis, the normal vectors you have to calculate are in the Z and Y directions only. The X direction in that case remains to be zero. So, in my opinion, if the rotation angle is called A, your vector components will be Ydirection=Math.sin(A) and Zdirection=Math.cos(A). So, let's assume you rotate 45 degrees (is 1/4 PI), the resulting values are:   Y= -.707 and Z= .707   Hope, this is what you meant.   Dirk ----- Original Message ----- From: Shyam Prakash To: [EMAIL PROTECTED] Sent: Tuesday, September 02, 2003 11:49 AM Subject: [JAVA3D] Plane equation Hello,             Not exactly a java 3d question. I have a plane with certain normal say (0,0,1), i.e along the XY plane. Now I want to rotate this plane about X axes by a certain alpha value. Does any body know how the value of plane’s normal changes(a relation between alpha value, old plane normal and new plane normal). Any suggestions will be of great help.   Thanks and Regards Shyam   =========================================================================== To unsubscribe, send email to [EMAIL PROTECTED] and include in the body of the message "signoff JAVA3D-INTEREST". For general help, send email to [EMAIL PROTECTED] and include in the body of the message "help". =========================================================================== To unsubscribe, send email to [EMAIL PROTECTED] and include in the body of the message "signoff JAVA3D-INTEREST". For general help, send email to [EMAIL PROTECTED] and include in the body of the message "help". =========================================================================== To unsubscribe, send email to [EMAIL PROTECTED] and include in the body of the message "signoff JAVA3D-INTEREST". For general help, send email to [EMAIL PROTECTED] and include in the body of the message "help".