On Tue, May 26, 2020 at 9:01 PM Edward K. Ream <[email protected]> wrote:

> Let's say we have a tree like below. Note that all nodes are NOT clones
>> unless specifically stated:
>>
>> Node A
>>  + Node A1
>>  + Node A2
>>  + Node A3
>> Node B
>>  + Node A1 (a clone)
>>  + Node B2
>>    + Node A3 (a clone)
>>
>
> There is a problem in your example. A1 and A2 can't be clones in node B
> unless A1 and A3 are clones in Node A (or somewhere else). Did you mean
> that A1 and A2 in A should also be clones? It makes a difference.
>
> This question is: "what nodes should be clones after the copy and paste?"
> There are at least two possible answers:
>
> 1. [non-local] *All* nodes in B that were clones when B was copied,
> provided that they could again be clones after being pasted.
>
> 2. [local] Only nodes in B that were clones of *other* nodes in B when
> the copy was made.
>
> I infer answer 1 if A1 and A3 in A should have been labeled "a clone".
> Otherwise, I infer answer 2.
>
>
Maybe I don't understand what a 'clone' entails, and perhaps others are
having the same misconception?

Are you stating that:  If I create a node "node a" and put data in subnode
"node a1" and that if then I decide I want a clone of "node a1" as a
subnode of "node b", that this implicitly 'undoes' the 'regular node
status' of A>A1 and makes A>A1 and B>A1 clones of eachother?

Said simpler:
Does cloning a normal node, make BOTH nodes clones?
Or is there still an idea of "this is the original" (A>A1) and "this is a
clone of the original" (B>A1)

Because your "problem" listed above seems to imply that by cloning a 1
normal node, the result is 2 clones and 0 regular nodes?

Mike

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