According to Mr. Ohm, the voltage drop over a resistor is equal to the 
resistance multiplied by the current. In the off state, the current is 0A, so 
regardless of the value of the anode resistor, the drop over the anode resistor 
is 0V. The switching transistor therefore sees the full voltage minus the 
internal drop in the tube.

 

Bill

 

From: [email protected] [mailto:[email protected]] On 
Behalf Of alex nolan
Sent: Friday, October 23, 2015 3:30 AM
To: neonixie-l
Subject: [neonixie-l] How much voltage do cathode transistors need to be able 
to handle?

 

I'm struggling to get my head around this. But considering the following setup 
for a nixie tube, wouldn't the voltage across the cathode transistor be close 
to 0? Most of the voltage should be dropped across the tube itself, with the 
remained dropped across the current-limiting resistor, right? Does it have to 
do with the transistors keeping the other cathodes open? If so, how do we 
calculate those voltages given the tube is on, just to a different cathode?

 <http://www.mcamafia.de/nixie/images/nix_th01.jpg> 

 

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