what is a bit confusing though is:
$ 3 (i.@{.@$) i. 4 5
0 1 2 3 4
# 3 (i.@{.@$) i. 4 5 ---returns nothing
0
Assuming you meant to apply $ monadically, and just got lucky with the sample
data :)
Lucky?, how about: x (f g) y means x f (g y) or in this case: x f~ (g y) -- Met vriendelijke groet, @@i = Arie Groeneveld ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
