On Thu, Sep 11, 2014 at 1:50 PM, Dan Bron <j...@bron.us> wrote:

> Pepe wrote:
> > My only question is: Does the Dictionary support this behavior?
>
> Raul responded:
> > Yes, it does.
>
> I am intrigued.  Can you elaborate?
>

I assumed that by not mentioning it, the implementation is free to do what
it chooses. It could be anything!


> In particular, can you help me see, given only the text of the Dictionary,
> that  u/y  where 1=#y  must be  y  ?  And not, for example, an error?
>
> -Dan
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