Pepe wrote:
>  My only question is: Does the Dictionary support this behavior?

> Raul responded:
>  Yes, it does.

I replied:
>  I am intrigued.  Can you elaborate?

Thomas followed-up:
>  I assumed that by not mentioning it, the implementation 
>  is free to do what it chooses. It could be anything!

That's what I think too.  The behavior is, in the strictest literal sense,
undefined.  But Raul differs. I'm interested in his rationale (which,
historically, has been both solid and instructive).

-Dan

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