Hey Raul,

You got me to rethink whether I needed to know if Feb 29th is included in the 
interval. It turns out that I didn't. It also turns out that by using your leap 
year I found that I didn't need todayno either! 
Here is my considerably simpler version with a test suite. As a general 
comment, I rarely work on these problems without having a test suite to check 
that my 'solutions' work in all the cases I think are valid.

   2014 9 23 age 2002 2 2  NB. Groundhog age
12 7 21

Cheers, bob

age =: 3 : 0 NB. age in yyyy mm dd as of x if born on y 
'left argument is today ; right argument is birth day result is age in yyyy mm 
dd'
:
if. x <&(1000#.]) y do. 'Wasn''t born yet!' return. end.  
'yb mb db'=. y
'yt mt dt'=. x
ly=. 2| +/ 0= 4 100 400 | yb 
dcount=.  31 , (28 + ly ) , 31 30 31 30 31 31 30 31 30 31  
(yt-yb) , ((12|mt-mb) - dt<db) , ((mt-2){dcount )|dt-db 
)

testdate =: 3 : 0
assert. 0 0 0 -: 2000 2 28 age 2000 2 28 NB. same date
assert. 0 0 1 -: 2000 3 2 age 2000 3 1 NB. event and current after feb 29 in 
leap year
assert. 0 0 1 -: 2000 2 28 age 2000 2 27 NB. event and current before feb 29 in 
leap year
assert. 0 0 2 -: 2000 3 1 age 2000 2 28 NB. event before and current after feb 
29 in leap year
assert. 'Wasn''t born yet!' -: 2000 2 28 age 2000 3 1 NB. event before current 
in leap year
assert. 0 0 1 -: 1900 3 2 age 1900 3 1 NB. event and current after feb 28 in 
non leap year
assert. 0 0 1 -: 1900 2 28 age 1900 2 27 NB. event and current before feb 28 in 
non leap year
assert. 0 0 1 -: 1900 3 1 age 1900 2 28 NB. event before and current after feb 
28 in leap non year
assert. 'Wasn''t born yet!' -: 1900 2 28 age 1900 3 1 NB. event before current 
in non leap year
assert. 1 0 1 -: 2000 3 2 age 1999 3 1 NB. event previous year and current 
after feb 29 in leap year
assert. 1 0 1 -: 2000 2 28 age 1999 2 27 NB. event previous year and current 
before feb 29 in leap year
assert. 1 0 1 -: 2000 3 1 age 1999 2 28 NB. event previous year before and 
current after feb 29 in leap year
assert. 1 11 0 -: 2000 2 1 age 1999 3 1 NB. event previous year after and 
current before feb 29 in leap year
assert. 1 0 1 -: 1900 3 2 age 1899 3 1 NB. event previous year and current 
after feb 28 in non leap year
assert. 1 0 2 -: 1900 3 1 age 1899 2 27 NB. event previous year and current 
before feb 28 in non leap year
assert. 1 0 1 -: 1900 3 1 age 1899 2 28 NB. event previous year before and 
current after feb 28 in non leap year
assert. 1 11 0 -: 1900 2 1 age 1899 3 1 NB. event previous year after and 
current before feb 29 in non leap year
)

testdate ''


On Sep 23, 2014, at 2:47 AM, Raul Miller <[email protected]> wrote:

> Or, in J:
> 
> isleap=: 3 :'2|+/0=4 100 400|/y'
> 
>   isleap 1900 2000 2012 2100
> 0 1 1 0
> 
> (I am mentioning this because I think I included a buggy version of
> this expression in an earlier message - I think I left out the 0=
> part.)
> 
> Thanks,
> 
> -- 
> Raul
> 
> 
> On Mon, Sep 22, 2014 at 10:13 PM, Don Kelly <[email protected]> wrote:
>> Fortunately, the use of "leap" is valid as long as one doesn't go back past
>> 1901 or ahead past 2099.
>> 
>> 1900 and 2100 aren't leap years (Fine tuning of the leap year calculation ).
>> 
>> Don Kelly
>> 
>> 
>> 
>> 
>> On 20/09/2014 10:53 PM, robert therriault wrote:
>>> 
>>> Hi Linda,
>>> 
>>> I share your dream and sometimes the statement 'I have a dream' can change
>>> the world. :-)
>>> 
>>> On to the weekend puzzle...
>>> 
>>> The first thing I need to figure out is whether the birthday has happened
>>> this year or not. If it has then I can pretty easily get the number of days
>>> since the birthday using todayno, but if it hasn't then I need to find the
>>> number of days since the previous year's birthday.
>>> 
>>> 'yg mg dg' =: gbday =: 2002 2 2  NB. Groundhog's birthday
>>> 'ya ma da'=:afterbday =: 2014 9 20      NB. An example of date after the
>>> birthday
>>> 'yb mb db'=:beforebday =: 2014 1 31      NB. An example of a date before
>>> the birthday
>>> 
>>> bdYet=:(0>-/) &: todayno  NB. returns 1 if the current date is in the same
>>> calendar year before the birthday
>>>    ya
>>> 2014
>>>    ya=. ya- afterbday bdYet ({. afterbday),}.gbday NB.use the current
>>> year from example and the birthday
>>>    ya
>>> 2014
>>>    yb
>>> 2014
>>>    yb=. yb- beforebday bdYet ({. beforebday),}.gbday
>>>    yb
>>> 2013
>>> 
>>> Next thing would be to define a vector that gives the accumulated days in
>>> the year if the year were to start on February 1st. The leap year issue
>>> means that the first item in the list will be 29 if it is a leap year. since
>>> I have already figured out whether I am counting from the previous year, I
>>> will use the adjusted year to decide if the year that I am counting from was
>>> a leap year. I will just use a simple (and incorrect) version of leap year.
>>> 
>>> leap=: 0= 4&|
>>> feb=: 28 + leap ya
>>>    feb
>>> 28
>>>    [daysFebFirst=: +/\ (feb), 31 30 31 30 31 31 30 31 30 31 31
>>> 28 59 89 120 150 181 212 242 273 303 334 365
>>> 
>>> Finally, I create the results.
>>> 
>>>    [yr=:ya-yg NB. number of years
>>> 12
>>> 
>>>    [elapsed=: -/ todayno"_1 afterbday,: ya,}.gbday NB. days since the
>>> birthday
>>> 230
>>>    [mr=: +/ elapsed > daysFebFirst NB. number of months
>>> 7
>>>    [dr=: (<:mr){ elapsed - daysFebFirst
>>> 18
>>>    yr,mr,dr
>>> 12 7 18
>>> 
>>> And for the case of a date before the birthday Jan 31st 2014 we get
>>> 
>>>    [feb=: 28 + leap yb NB. No change since 2013 is not a leap year
>>> 28
>>>    [yr=:yb-yg NB. number of years
>>> 11
>>> 
>>>    [elapsed=: -/ todayno"_1 beforebday ,: yb ,}.gbday NB. days since the
>>> previous birthday
>>> 363
>>>    [mr=: +/ elapsed > daysFebFirst NB. number of months
>>> 11
>>>    [dr=: (<:mr){ elapsed - daysFebFirst
>>> 29
>>>    yr,mr,dr
>>> 11 11 29
>>> 
>>> Cheers, bob
>>> 
>>> On Sep 20, 2014, at 10:58 AM, Linda Alvord <[email protected]>
>>> wrote:
>>> 
>>>> The J forum is my elementary school set of sub imjects.  What you suggest
>>>> is
>>>> exactly what I would hope would happen in a J classroom.  All would have
>>>> J.
>>>> All could experiment and exchange ideas. Hopefully they would have
>>>> solutions
>>>> they believe were correct.  Then they could explain their thinking to the
>>>> entire class and the teacher.  At this point in the process, the teacher
>>>> would not be a leader but a follower.
>>>> 
>>>> Possibly I am dreaming....
>>>> 
>>>> Linda
>>>> 
>>>> -----Original Message-----
>>>> From: [email protected]
>>>> [mailto:[email protected]] On Behalf Of robert
>>>> therriault
>>>> Sent: Saturday, September 20, 2014 1:20 PM
>>>> To: [email protected]
>>>> Subject: Re: [Jprogramming] Weekend Puzzle - Age of Groundhog born 2002 2
>>>> 2
>>>> 
>>>> Hi Linda,
>>>> 
>>>> If you are looking for a way to get learners to be interested in the
>>>> problem, why not use the very model of learning that we are using here?
>>>> 
>>>> You put a problem out to your class (forum) and see how the responses go.
>>>> You as the teacher (moderator) are free to choose the rules, knowing that
>>>> the students (participants) are able to put their attention elsewhere if
>>>> things are not kept interesting. It is a style of learning that we use on
>>>> these forums everyday and it seems to work for us.
>>>> 
>>>> What might not work as well is going into the class and showing them how
>>>> to
>>>> solve the problem, as this takes away so much from the experience that we
>>>> enjoy when we are learning. The challenge for the teacher is not so much
>>>> coming up with a solution, as it is to make sure that they are engaging
>>>> as
>>>> many students as possible. This is especially true at the extremes of the
>>>> class' abilities - both the really adept and those that are struggling
>>>> with
>>>> the concepts are where teachers are most valuable.
>>>> 
>>>> Just my two bits, but I would probably just start with the question of
>>>> 'how
>>>> would you measure time in metric?' and use that as a way to explore all
>>>> the
>>>> ways that you would count and group the types of time and how they way we
>>>> measure time can be pretty crazy and why it might be good if we could get
>>>> computers to do the work of taking care of the crazy systems that we have
>>>> set up. Where the class would take this in terms of topic is wide open,
>>>> as a
>>>> teacher you just make sure that as the core concepts arise they are
>>>> covered
>>>> accurately.
>>>> 
>>>> Cheers, bob
>>>> 
>>>> ps. The quickest way to get me to care about the age of your groundhog is
>>>> to
>>>> have one of my classmates start trying to figure it out, but my learning
>>>> is
>>>> usually socially motivated. :-)
>>>> 
>>>> On Sep 20, 2014, at 9:35 AM, Joe Bogner <[email protected]> wrote:
>>>> 
>>>>> Hi Linda
>>>>> 
>>>>> The solution is quite simple and uses one built verb from an addon. I
>>>>> posted it with the solution masked so others can try it on their own
>>>>> without accidentally seeing mine
>>>>> 
>>>>> The actual solution is the result of this:
>>>>> 
>>>>> |. solution2
>>>>> On Sep 20, 2014 11:54 AM, "Linda Alvord" <[email protected]>
>>>>> wrote:
>>>>> 
>>>>>> We are talking children here.
>>>>>> 
>>>>>> Onyadot. emiTetaDot, ffiDst, onyadot, emiTetaDot, emitetad,  sepyt and
>>>>>> eriuqer  are all denied!
>>>>>> 
>>>>>> How about using +, -, *, ?, %: and that sort of thing.
>>>>>> 
>>>>>> I must admit you did get  the right answer!
>>>>>> 
>>>>>> You can also get a second chance.
>>>>>> 
>>>>>> Cheers,  Linda
>>>>>> 
>>>>>> 
>>>>>> 
>>>>>> -----Original Message-----
>>>>>> From: [email protected]
>>>>>> [mailto:[email protected]] On Behalf Of Joe
>>>> 
>>>> Bogner
>>>>>> 
>>>>>> Sent: Saturday, September 20, 2014 9:10 AM
>>>>>> To: [email protected]
>>>>>> Subject: Re: [Jprogramming] Weekend Puzzle - Age of Groundhog born 2002
>>>>>> 2
>>>> 
>>>> 2
>>>>>> 
>>>>>> solution...
>>>>>> 
>>>>>> 
>>>>>> 
>>>>>> 
>>>>>> 
>>>>>> 
>>>>>> 1
>>>>>> 2
>>>>>> 3
>>>>>> 4
>>>>>> 5
>>>>>> 
>>>>>> 
>>>>>> lightly obfuscated for someone who doesn't want the solution
>>>>>> 
>>>>>> 
>>>>>> solution1=: 0 : 0
>>>>>> 
>>>>>> )2 2 2002 onyadot emiTetaDot( ffiDst )02 9 4102 onyadot emiTetaDot(
>>>>>> 
>>>>>> 'emitetad/sepyt' eriuqer
>>>>>> 
>>>>>> )
>>>>>> 
>>>>>> 
>>>>>> 
>>>>>> to run:
>>>>>> 
>>>>>> 
>>>>>> 0!:1 |. solution1
>>>>>> 
>>>>>> 
>>>>>> 
>>>>>> solution2 =: 0 : 0
>>>>>> 
>>>>>> )2 2 2002( ffiDst )02 9 4102(
>>>>>> 
>>>>>> 'emitetad/sepyt' eriuqer
>>>>>> 
>>>>>> )
>>>>>> 
>>>>>> 
>>>>>> 0!:1 |. solution2
>>>>>> 
>>>>>> 
>>>>>> 
>>>>>> note: both take advantage of a addon. solution1 uses todayno just
>>>>>> because
>>>>>> it was stated in the problem but solution2 is what I'd really use
>>>>>> 
>>>>>> 
>>>>>> 
>>>>>> On Sat, Sep 20, 2014 at 4:54 AM, Linda Alvord <[email protected]>
>>>>>> wrote:
>>>>>> 
>>>>>>> Using the verb  todayno  which provides the number of days since the
>>>>>>> beginning of 1800,  write what you need to find the age today of a
>>>>>>> groundhog
>>>>>>> born on 2002 2 2.
>>>>>>> 
>>>>>>> 
>>>>>>> 
>>>>>>>  todayno 2014 9 2014
>>>>>>> 
>>>>>>> 80418
>>>>>>> 
>>>>>>> 
>>>>>>> 
>>>>>>>  2014 9 20 age 2002 2 2
>>>>>>> 
>>>>>>> 12 7 18
>>>>>>> 
>>>>>>> 
>>>>>>> 
>>>>>>> His age is 12 years, 7 months and 18 days.  Use simple J.  Check that
>>>>>> 
>>>>>> your
>>>>>>> 
>>>>>>> solution provides a correct answer for you birthday.
>>>>>>> 
>>>>>>> 
>>>>>>> 
>>>>>>> Have a pleasant weekend.
>>>>>>> 
>>>>>>> 
>>>>>>> 
>>>>>>> Linda
>>>>>>> 
>>>>>>> 
>>>>>>> 
>>>>>>> 
>>>>>>> 
>>>>>>> 
>>>>>>> 
>>>>>>> 
>>>>>>> 
>>>>>>> 
>>>>>>> 
>>>>>>> 
>>>>>>> 
>>>>>>> 
>>>>>>> 
>>>>>>> ----------------------------------------------------------------------
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>>>>>>> 
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>>> 
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