On 9/20/07, Les Szklanny <[EMAIL PROTECTED]> wrote: > > > But, shouldn't have to do this or use $super(name). The superclass > constructor should be called automatically (as in Dojo for example).
We have modeled OOP support in Prototype based on the most traditional inheritance model. Most of the users don't expect overridden constructors to be called automatically. If you want to call the superclass constructor, you must use $super (please don't do Foo.prototype.bar.apply anymore) - that also works with any other method in your classes. So, thanks for the suggestion, but we're keeping constructors this way. --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Prototype: Core" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/prototype-core?hl=en -~----------~----~----~----~------~----~------~--~---
