On Jul 16, 2012 10:31 AM, "Ray Dillinger" <b...@sonic.net> wrote:
> Um? Will, did you misspeak here or is there something very > fundamental that I'm not understanding? As I see it the same > vector of code ought to produce the same behavior when run. > Different nonempty closures over the same procedure are unique, > of course, but the procedure itself? Different nonempty closures over the same procedure are considered to behave differently, therefore, they cannot be eqv?.
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