On Jul 23, 2006, at 5:10 PM, Briman wrote:
I have a listbox with 1 column set to :
me.columnType(5) = listbox.typeCheckbox
try (assuming your listbox is called listBox1)
if listbox1.cellCheck(row, column) then
// cell is checked
else
// cell is not checked
end if
Norman,
appreciate this.
I understand your pseudocode but just not grasping what I need to pass to
the Printing Grapgics.
Im a printing moron as they would say :-)
I do appreciate your help.
-Briman
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