Re: webfaction django installation
This article really helped. For all those django and webfaction newbies out there: this article is a must read. Worked perfect! Ben On Sep 21, 1:26 am, tupixo <[EMAIL PROTECTED]> wrote: > > I had also similar problems, because instead of documentation they have a > > screencast(?!) and the forum. > > Did you at least spend 30 seconds looking for docs before writing > that? > They have a Django category in their knowledge base with quite a few > articles:https://help.webfaction.com/index.php?_m=knowledgebase&_a=view... > (btw, that link is included in their welcome e-mail). > > The "Getting started with Django at WebFaction" article should solve > Bobby's > problem:https://help.webfaction.com/index.php?_m=knowledgebase&_a=viewarticle... > > Kevin. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
sharing a module level variable
i have an wget event in a cron job. the view does some processing which involves calling external websites and databases (takes about 25 seconds) and updates some module level dictionary lookup variables (about 7 MB of data) which the rest of the program reads. but unfortunately, only the one apache child process seems to be updated, not all the others. how can i share this module level variable across processes? this lookup happens multiple times per request. but the internal data gets updated nightly. thanks, bryan --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
django signals
i'm having touble finding documention about django signals that explain how they behave under apache child processes. if i have a signal go off and have a listener for that signal. will only the listener in same child process receive it or will that same listener in all apache child processes receive it? what is the best way to signal all of your apache child process for you project? thanks, bryan --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Dojango question
Wolfram,
You bet I've read your blogs! Wouldn't have gotten where I got to
without them!
Clearly I had missed the to_dojo_data(), that's exactly what I was
looking for.
This works super.
Thanks a lot,
Rob
On Nov 1, 2008, at 4:45 PM, Wolfram Kriesing wrote:
>
> Hi Rob,
>
> aehm, maybe what you were looking for was this:
>
> @json_response
> def send_toxids_list(request):
>ret = Toxid.objects.all()
>return to_dojo_data(ret, identifier='docno')
>
> the json_response decorator takes care of extrcting only the
> fields form the model, you dont have to do this
> by hand. And the to_dojo_data() function converts the
> data into a dojo.data store compatible format.
>
> See also this blog post about more info
> about the json_response decorator/function
> and insight details.
> http://wolfram.kriesing.de/blog/index.php/2007/json-serialization-for-django
>
>
> --
> cu
>
> Wolfram
>
> http://uxebu.com - the AJAX experts
> You need AJAX, RIA, JavaScript and all this modern stuff? We got it!
> On Nov 1, 2008, at 4:34 PM, Wolfram Kriesing wrote:
>>
>> Hi Rob,
>>
>> did you see the blog article
>> http://blog.uxebu.com/2008/07/26/ajax-with-dojango/
>> and the examples in
>> http://code.google.com/p/dojango/source/browse/trunk/dojango/views.py
>>
>> tbh I don't really understand what you are using the JSON
>> serializer for.
>> Could you may be explain, if the links above dont help?
>>
>> --
>> cu
>>
>> Wolfram
>>
>> http://uxebu.com - the AJAX experts
>> You need AJAX, RIA, JavaScript and all this modern stuff? We got it!
>> On Sat, Nov 1, 2008 at 11:31 PM, Rob Goedman <[EMAIL PROTECTED]> wrote:
>>
>> Hi,
>>
>> Just for Django & Dojo users.
>>
>> Working through the 'Mastering Dojo' book, updating the examples
>> where
>> applicable to Dojo 1.2 (i.e. grids) and making them work with Django
>> svn has gone pretty smoothly. I wonder if below method is a
>> reasonable
>> way to generate fairly generic xhr* responses?
>>
>> I use something like (e.g. from the dojo.data chapter on
>> QueryReadStore):
>>
>> @json_response
>> def send_toxids_list(request):
>> """
>> Creates a JSON/Dojo hash with the filtered contents
>> for a grid. This method is called by Dojo xhr*.
>>
>> To do:
>>
>> 1) Change ...all() into ...filter()
>> according to qDict info.
>>
>> """
>>
>> qDict = request.GET
>> print qDict['user'], qDict.get('query', None)
>>
>> queryset = Toxid.objects.all()
>> json_serializer = serializers.get_serializer("json")()
>> toxids_json = json_serializer.serialize(queryset,
>> ensure_ascii=True)
>> t = eval(toxids_json)
>> a = []
>> for i in t: a.append(i['fields'])
>> ret = {
>> "identifier": "docno",
>> "label": "substance",
>> "items": a,
>> }
>> return ret
>>
>> It seems a frequently recurring pattern in my views, so I would like
>> to do it right and efficient. Particularly the 'eval' step feels
>> weird.
>>
>> I did have a look at dojox.dtl (Django Templating Language) but
>> haven't (yet?) figured out if that is applicable for this.
>>
>> Thanks,
>> Rob
>>
>>
>>
>>>
>>
>
> >
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Re: Dojango question
Hi Rob,
aehm, maybe what you were looking for was this:
@json_response
def send_toxids_list(request):
ret = Toxid.objects.all()
return to_dojo_data(ret, identifier='docno')
the json_response decorator takes care of extrcting only the
fields form the model, you dont have to do this
by hand. And the to_dojo_data() function converts the
data into a dojo.data store compatible format.
See also this blog post about more info
about the json_response decorator/function
and insight details.
http://wolfram.kriesing.de/blog/index.php/2007/json-serialization-for-django
--
cu
Wolfram
http://uxebu.com - the AJAX experts
You need AJAX, RIA, JavaScript and all this modern stuff? We got it!
On Sat, Nov 1, 2008 at 11:31 PM, Rob Goedman <[EMAIL PROTECTED]> wrote:
>
> Hi,
>
> Just for Django & Dojo users.
>
> Working through the 'Mastering Dojo' book, updating the examples where
> applicable to Dojo 1.2 (i.e. grids) and making them work with Django
> svn has gone pretty smoothly. I wonder if below method is a reasonable
> way to generate fairly generic xhr* responses?
>
> I use something like (e.g. from the dojo.data chapter on
> QueryReadStore):
>
> @json_response
> def send_toxids_list(request):
>"""
>Creates a JSON/Dojo hash with the filtered contents
>for a grid. This method is called by Dojo xhr*.
>
>To do:
>
>1) Change ...all() into ...filter() according to
> qDict info.
>
>"""
>
>qDict = request.GET
>print qDict['user'], qDict.get('query', None)
>
>queryset = Toxid.objects.all()
>json_serializer = serializers.get_serializer("json")()
>toxids_json = json_serializer.serialize(queryset, ensure_ascii=True)
>t = eval(toxids_json)
>a = []
>for i in t: a.append(i['fields'])
>ret = {
>"identifier": "docno",
>"label": "substance",
>"items": a,
>}
>return ret
>
> It seems a frequently recurring pattern in my views, so I would like
> to do it right and efficient. Particularly the 'eval' step feels weird.
>
> I did have a look at dojox.dtl (Django Templating Language) but
> haven't (yet?) figured out if that is applicable for this.
>
> Thanks,
> Rob
>
>
>
> >
>
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Re: Dojango question
Hi Rob,
did you see the blog article
http://blog.uxebu.com/2008/07/26/ajax-with-dojango/
and the examples in
http://code.google.com/p/dojango/source/browse/trunk/dojango/views.py
tbh I don't really understand what you are using the JSON serializer for.
Could you may be explain, if the links above dont help?
--
cu
Wolfram
http://uxebu.com - the AJAX experts
You need AJAX, RIA, JavaScript and all this modern stuff? We got it!
On Sat, Nov 1, 2008 at 11:31 PM, Rob Goedman <[EMAIL PROTECTED]> wrote:
>
> Hi,
>
> Just for Django & Dojo users.
>
> Working through the 'Mastering Dojo' book, updating the examples where
> applicable to Dojo 1.2 (i.e. grids) and making them work with Django
> svn has gone pretty smoothly. I wonder if below method is a reasonable
> way to generate fairly generic xhr* responses?
>
> I use something like (e.g. from the dojo.data chapter on
> QueryReadStore):
>
> @json_response
> def send_toxids_list(request):
>"""
>Creates a JSON/Dojo hash with the filtered contents
>for a grid. This method is called by Dojo xhr*.
>
>To do:
>
>1) Change ...all() into ...filter() according to
> qDict info.
>
>"""
>
>qDict = request.GET
>print qDict['user'], qDict.get('query', None)
>
>queryset = Toxid.objects.all()
>json_serializer = serializers.get_serializer("json")()
>toxids_json = json_serializer.serialize(queryset, ensure_ascii=True)
>t = eval(toxids_json)
>a = []
>for i in t: a.append(i['fields'])
>ret = {
>"identifier": "docno",
>"label": "substance",
>"items": a,
>}
>return ret
>
> It seems a frequently recurring pattern in my views, so I would like
> to do it right and efficient. Particularly the 'eval' step feels weird.
>
> I did have a look at dojox.dtl (Django Templating Language) but
> haven't (yet?) figured out if that is applicable for this.
>
> Thanks,
> Rob
>
>
>
> >
>
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Template inheritance
Hello, I feel I have learned a lot about Django, and am loving it, but I seem to be missing something quite fundamental about template inheritance. Should templates be a set up only for "straight line" inheritance? My thinking about them leads to a "tree" where a template renders a "chunk" of a page (e.g. a sidebar, a content area) and that many "leaf" templates might extends a part of the same parent template. If that not the wrong way to "think", then how do "siblings" get rendered? I realize I can render many templates into variables in a single view function, but that seems to defeat the purpose of template inheritance... I feel like I'm missing something obvious, so I appreciate any guidance! Alaric (I saw one post that suggested that custom template tags, and context processors might be involved. True? I get how to write tags, but the docs, while being clear on how to _write_ them, seem a bit sketchy on how to _use_ them, esp. context processors.) --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
access request.user in class Meta
I am trying to dynamically generate a form, the fields will vary if
the user is logged in. Here is where I am so far
forms.py
==
class LinkForm(ModelForm):
def __init__(self, *args, **kw):
self.request = kw.pop('request')
super(LinkForm, self).__init__(*args, **kw)
class Meta:
model = Link
if self.request.user:
exclude = ['ip_address', 'timestamp', 'user', 'method', ]
else:
exclude = ['ip_address', 'timestamp', 'user', 'method',
'notes', 'private_stats',]
views.py
==
def index(request):
form = LinkForm(request=request)
The error I get makes it clear I don't have access to request within
class Meta:
NameError at /
name 'self' is not defined
Thanks,
Merrick
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Re: Deploying multiple django applications in a single apache server
Just be aware that by default mod_python assigns sub interpreters per name based virtual host and doesn't take into consideration the listener port. Therefore, if having two listener ports on the same host name, the same sub interpreter will be used for both, which means that Django instances will not be separated and will not work properly. In mod_python you will need to use PythonInterpreter directive to override name of sub interpreter in each VirtualHost for which only difference is listener port. Better still, use mod_wsgi instead as it is more sensible and by default separates the applications by default as it delegates to sub interpreters on the basis of combination of server name and port. The only except being that 80/443 are merged into same sub interpreter as they would generally be the same application. Graham On Nov 2, 1:00 am, "Karen Tracey" <[EMAIL PROTECTED]> wrote: > On Sat, Nov 1, 2008 at 9:03 AM, bluefireredsky <[EMAIL PROTECTED]>wrote: > > > > > > > Hello, > > > I have followed the link from django documentation on deploying an > > application to apache2. > > >http://docs.djangoproject.com/en/dev/howto/deployment/modpython/ > > > I have two applications, which I would like to run on two different > > ports on the server. Basically one being an administrative website > > (not the django inbuilt admin website) and the other the user front > > end. > > > Currently I have the following on my ports.conf: > > > === > > Listen 80 > > > > > Listen 443 > > > > === > > > My httpd.conf is as follows: > > > > > > > SetHandler python-program > > PythonHandler django.core.handlers.modpython > > SetEnv DJANGO_SETTINGS_MODULE mysitename.settings > > PythonOption django.root /mysitename > > PythonDebug On > > PythonPath "['/usr/local/'] + sys.path" > > > > > > SetHandler None > > > > > > SetHandler None > > > > > > > What changes should I do on these files to run my second django > > application on a different port, say 8080, on the same apache server? > > This is really more an Apache question than a Django one. First you'll need > to add a Listen for the second port in your ports.conf, the doc for that is > here: > > http://httpd.apache.org/docs/2.2/bind.html > > At the bottom of that page they point to the VirtualHost directive, which is > the second thing you'll need to do. You need to enclose your existing > directives for the app on port 80 in a VirtualHost block for port 80, and > create a second VirtualHost with directives for the new app that you want on > the second port. > > Karen --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Dojango question
Hi,
Just for Django & Dojo users.
Working through the 'Mastering Dojo' book, updating the examples where
applicable to Dojo 1.2 (i.e. grids) and making them work with Django
svn has gone pretty smoothly. I wonder if below method is a reasonable
way to generate fairly generic xhr* responses?
I use something like (e.g. from the dojo.data chapter on
QueryReadStore):
@json_response
def send_toxids_list(request):
"""
Creates a JSON/Dojo hash with the filtered contents
for a grid. This method is called by Dojo xhr*.
To do:
1) Change ...all() into ...filter() according to
qDict info.
"""
qDict = request.GET
print qDict['user'], qDict.get('query', None)
queryset = Toxid.objects.all()
json_serializer = serializers.get_serializer("json")()
toxids_json = json_serializer.serialize(queryset, ensure_ascii=True)
t = eval(toxids_json)
a = []
for i in t: a.append(i['fields'])
ret = {
"identifier": "docno",
"label": "substance",
"items": a,
}
return ret
It seems a frequently recurring pattern in my views, so I would like
to do it right and efficient. Particularly the 'eval' step feels weird.
I did have a look at dojox.dtl (Django Templating Language) but
haven't (yet?) figured out if that is applicable for this.
Thanks,
Rob
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Re: Overriding admin templates
On Sat, Nov 1, 2008 at 5:54 PM, Lars Stavholm <[EMAIL PROTECTED]> wrote:
>
> Low Kian Seong wrote:
> > http://www.djangobook.com/en/1.0/chapter17/
>
> Yes, thank you, that's it.
>
> It worked nicely for the change_form.html example given in that
> chapter. However, for the change_list.html it still doesn't work.
> Seems to me I've hit a django bug. Anyone else?
>
I just tried this, and it works for me for change_list.html. So I'm not sure
what is going on in your case. For me it just works, overriding change_list
on a per-model basis using a file:
templates/admin///change_list.html
Karen
> /L
>
> > On Sat, Nov 1, 2008 at 6:20 PM, Lars Stavholm <[EMAIL PROTECTED]> wrote:
> >> Low Kian Seong wrote:
> >>> You are supposed to put the admin template you want to override in
> >>> your own template directory definition in settings.py
> >>>
> >>> So, if you defined it as /home/stava/ >>> name>/template/admin/change_list.html
> >> Huh?
> >> /L
> >>
> >>> On Sat, Nov 1, 2008 at 5:32 PM, Lars Stavholm <[EMAIL PROTECTED]>
> wrote:
> I'd like to override part of an admin change_list template.
>
> Reading the documentation, my understanding is that I can place
> a template in a certain place in the templates directory hierarchy,
> and django will look for it and use it, i.e.:
>
> templates/admin/build/job/change_list.html
>
> ...where "build" is my application and "job" is my model class.
>
> The change_list.html file only contains the part I want to override,
> i.e. the extrahead block. It contains:
>
> {% extends "admin/change_list.html" %}
> {% block extrahead %}
>
> {% endblock %}
>
> However, this does not work for me, so I'm expecting it to be some
> mistake on my part, I just can't figure out what the mistake is.
>
> Now, if I put the file in ./templates/admin/build/change_list.html
> it still wont work. On the other hand, this would be overriding all
> "build" application change lists, which is not what I was looking for.
>
> Only way I've found is to copy the change_list.html from the django
> installation in contrib/admin/templates/admin, and then modify it to
> my needs, using "if" statements to figure out which application model
> class is being rendered, and the put the change_list.html in my app's
> templates/admin directory, which doesn't feel right.
>
> Any input appreciated
> /Lars Stavholm
>
>
> >>
> >>
> >
> >
> >
>
>
>
> >
>
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Re: Dev & Production difference: escaping html in admin
On Sat, Nov 1, 2008 at 4:21 PM, Alexey Moskvin <[EMAIL PROTECTED]> wrote: > > Hi, I have developer (win) & production (debian) installations of > Django 0.97. There is not such thing as a 0.97 release, are you sure you are using the same SVN revisions in both environments? > [...] > But on my production stage there is a problem: no pictures are > displayed, all tags, returned by show_thumb method are escaped, and I > have raw HTMl in corespondend column. Auto-escaping was added in revision 6671, read http://code.djangoproject.com/wiki/BackwardsIncompatibleChanges#Auto-escapingintemplates to see if you are being affected by it. -- Ramiro Morales --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Overriding admin templates
Low Kian Seong wrote:
> http://www.djangobook.com/en/1.0/chapter17/
Yes, thank you, that's it.
It worked nicely for the change_form.html example given in that
chapter. However, for the change_list.html it still doesn't work.
Seems to me I've hit a django bug. Anyone else?
/L
> On Sat, Nov 1, 2008 at 6:20 PM, Lars Stavholm <[EMAIL PROTECTED]> wrote:
>> Low Kian Seong wrote:
>>> You are supposed to put the admin template you want to override in
>>> your own template directory definition in settings.py
>>>
>>> So, if you defined it as /home/stava/>> name>/template/admin/change_list.html
>> Huh?
>> /L
>>
>>> On Sat, Nov 1, 2008 at 5:32 PM, Lars Stavholm <[EMAIL PROTECTED]> wrote:
I'd like to override part of an admin change_list template.
Reading the documentation, my understanding is that I can place
a template in a certain place in the templates directory hierarchy,
and django will look for it and use it, i.e.:
templates/admin/build/job/change_list.html
...where "build" is my application and "job" is my model class.
The change_list.html file only contains the part I want to override,
i.e. the extrahead block. It contains:
{% extends "admin/change_list.html" %}
{% block extrahead %}
{% endblock %}
However, this does not work for me, so I'm expecting it to be some
mistake on my part, I just can't figure out what the mistake is.
Now, if I put the file in ./templates/admin/build/change_list.html
it still wont work. On the other hand, this would be overriding all
"build" application change lists, which is not what I was looking for.
Only way I've found is to copy the change_list.html from the django
installation in contrib/admin/templates/admin, and then modify it to
my needs, using "if" statements to figure out which application model
class is being rendered, and the put the change_list.html in my app's
templates/admin directory, which doesn't feel right.
Any input appreciated
/Lars Stavholm
>>
>>
>
>
>
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Keeping track of online users
I have found some post of 2007 on this argument but maybe with django 1.0 something is changed. how do you do that ? thanks everyone :) --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Django Model key limits
Hello !I'm working in a project using django an postgresql and probably i will manage a big model table. I have a few questions about the limits of the primary key in django model. By default the pk was defined in postgresql as a SERIAL NOT NULL with the integer data type. I search for the limits of this type and this postgresql page [1] puts the limit at (range -2147483648 to +2147483647). This is a big table, but first estimations make this number not really big. As I can read in the same page, if we use a bigint the limit will be (-9223372036854775808 to 9223372036854775807) , this is a really big number :D So... i change the type of the id column in my database to bigint and i insert a new row with the id 277147483647 ( big for int , good por bigint). I start testing the admin of my model and... it works great with this numbers. What consequences will have this change in the future ? This will work ? Django is ready to this pk numbers? Thanks a lot PD : Sorry about my bad english [1] http://www.postgresql.org/docs/7.4/interactive/sql-createsequence.html -- neo2001[at]gmail.com neo[at]art-xtreme.com --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Dev & Production difference: escaping html in admin
Hi, I have developer (win) & production (debian) installations of
Django 0.97. There is one difference in admin app.
I have a photogallery, and Picture model has this method:
def show_thumb(self) :
return '%s' %
(self.get_image_url(), self.get_image_thumb_url(), self.image)
also I have this:
class Admin:
list_display = ('description', 'show_thumb', 'quality')
in admin section.
This stuff allows me to see previews of the pictures in admin panel.
But on my production stage there is a problem: no pictures are
displayed, all tags, returned by show_thumb method are escaped, and I
have raw HTMl in corespondend column.
How can I change this behaviour?
Thanks!
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Formset in template with extra per form
I have a formset, each form representing a row in a table. I also have a list of dictionaries, each list item providing additional data to print on that row. The formset and list of dictionaries are of arbitrary lengths, and potentially in the hundreds or even low thousands, so efficiency counts. I also want to keep the logic as simple and clear as possible. I would like to be able to loop over both at once in the template while rendering the table, but I don't see a good way to do that with Django templates. And I don't see an obvious way to efficiently zip up 'formset.forms' with 'items' to do things that way, But I don't have the deepest understanding of formsets, so perhaps that is possible. Any thoughts? Thanks, Steve Bergman --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: HttpRequest with chunked encoding is not buffered
On Sat, Nov 1, 2008 at 11:37 AM, [EMAIL PROTECTED] < [EMAIL PROTECTED]> wrote: > > I actually am seeing some input, but it is divided into several, well, > chunks. I guess it's the same problem as seeing no input - I'd say > you're right and chunked encoding is silently unsupported (it would be > nice if Django said something though). > However, could you please suggest any workaround? If mod_python does > not work, what should I use? (My goal is to be able to receive chunked > requests in some normal way in my django application). > Here's a workaround if you must used chunked requests with servers (apparently many) that don't support it: you can send a chunked request through Apache's mod_proxy and force it to unchunk and add a content-length. Described here: http://www.atnan.com/2008/8/8/transfer-encoding-chunked-chunky-http Karen > > On Nov 1, 10:28 am, Graham Dumpleton <[EMAIL PROTECTED]> > wrote: > > On Nov 1, 10:40 am, "Tomáš Brambora" <[EMAIL PROTECTED]> wrote: > > > > > I have a standard Django installation without any changes in the > > > settings (except adding mysql db to the settings.py) and I'm sending > > > the message to localhost:8000, so there is no proxy or anything else > > > in the way. Still, the request body comes after me sending the > > > response... > > > > As I said in the other similar thread you created about this. > > > > If you are getting empty input on read, then you are using hosting > > mechanism that doesn't properly filter out chunked request content as > > not being supported and instead assumes that content length of > > request was 0. > > > > In other words, chunked request content is not supported. Most hosting > > mechanisms will flag it as an error. The internal Django development > > server appears just to assume that content length on request is 0 > > since Content-Length header wouldn't be set. Thus why you are seeing > > no input. > > > > Graham > > > > > > > > > On Fri, Oct 31, 2008 at 11:50 PM, Graham Dumpleton > > > > > <[EMAIL PROTECTED]> wrote: > > > > > > [EMAIL PROTECTED] wrote: > > > >> Hello, > > > >> I'm trying to receive a possibly large XML message via HttpRequest > > > >> (POST method) with chunked encoding. However, when I send a > response, > > > >> I found out (using Wireshark) that the response is being sent before > > > >> the whole POST request body is available. I expected Django to be > > > >> buffering the chunks and that the request would be complete, but > > > >> that's apparently not happening... > > > > > >> I'm reading the body like this: > > > >> request.POST.values()[0] > > > > > >> (Which is probably a wrong way, but I don't know how to do it > > > >> otherwise.) > > > > > > What hosting mechanism are you using. Anything that uses WSGI (eg, > > > > mod_wsgi, fastcgi/flup) or mod_python will not work as neither WSGI > > > > specification or mod_python support chunked transfer encoding on > > > > request content. Certainly for mod_python and mod_wsgi, it should > give > > > > an error back before even gets to Django saying that content length > > > > required to be set. > > > > > > Graham > > > --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Why is my string not auto escaped?
On Wed, Oct 29, 2008 at 8:35 AM, shabda <[EMAIL PROTECTED]> wrote:
>
> I need to create a custom filter which displays some data from db
> depending on its data type.
>
> My code is something like,
>
> from django.template.defaultfilters import linebreaks, urlize
>
> def filterxx(data)
> return linebreaks(urlize(data.value))
>
> My data.value is
>
> Asdfghjkl
>
> alert('hole')
>
> This is used in templates, and shows up unescaped, which allows users
> to run arbitrary scripts. What am I doing wrong?
>
You are calling built-in filters that rely on being told the current
autoescape setting without passing along the current autoescape setting in
effect. I think you want something more like:
def filterxx(data, autoescape=None):
return linebreaks(urlize(data.value, autoescape), autoescape)
filterxx.needs_autoescape = True
Karen
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Re: HttpRequest with chunked encoding is not buffered
I actually am seeing some input, but it is divided into several, well, chunks. I guess it's the same problem as seeing no input - I'd say you're right and chunked encoding is silently unsupported (it would be nice if Django said something though). However, could you please suggest any workaround? If mod_python does not work, what should I use? (My goal is to be able to receive chunked requests in some normal way in my django application). On Nov 1, 10:28 am, Graham Dumpleton <[EMAIL PROTECTED]> wrote: > On Nov 1, 10:40 am, "Tomáš Brambora" <[EMAIL PROTECTED]> wrote: > > > I have a standard Django installation without any changes in the > > settings (except adding mysql db to the settings.py) and I'm sending > > the message to localhost:8000, so there is no proxy or anything else > > in the way. Still, the request body comes after me sending the > > response... > > As I said in the other similar thread you created about this. > > If you are getting empty input on read, then you are using hosting > mechanism that doesn't properly filter out chunked request content as > not being supported and instead assumes that content length of > request was 0. > > In other words, chunked request content is not supported. Most hosting > mechanisms will flag it as an error. The internal Django development > server appears just to assume that content length on request is 0 > since Content-Length header wouldn't be set. Thus why you are seeing > no input. > > Graham > > > > > On Fri, Oct 31, 2008 at 11:50 PM, Graham Dumpleton > > > <[EMAIL PROTECTED]> wrote: > > > > [EMAIL PROTECTED] wrote: > > >> Hello, > > >> I'm trying to receive a possibly large XML message via HttpRequest > > >> (POST method) with chunked encoding. However, when I send a response, > > >> I found out (using Wireshark) that the response is being sent before > > >> the whole POST request body is available. I expected Django to be > > >> buffering the chunks and that the request would be complete, but > > >> that's apparently not happening... > > > >> I'm reading the body like this: > > >> request.POST.values()[0] > > > >> (Which is probably a wrong way, but I don't know how to do it > > >> otherwise.) > > > > What hosting mechanism are you using. Anything that uses WSGI (eg, > > > mod_wsgi, fastcgi/flup) or mod_python will not work as neither WSGI > > > specification or mod_python support chunked transfer encoding on > > > request content. Certainly for mod_python and mod_wsgi, it should give > > > an error back before even gets to Django saying that content length > > > required to be set. > > > > Graham --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Cascading List List Boxes
Hi, Is it possible to populate a list depending on another list choice? I am working on an event guide, when creating the event the user will need to select a place from a drop down list, some places have different rooms, so I want another drop down list containing the rooms that relate to the place selected in the first drop down list. Any ideas? --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Splitting models.py won't install models
Right I managed to fix it and feel really stupid at the same time but I thought I would post here in case anyone else has the same issue my mistake was using class meta: and not class Meta: doh! got to love case sensitivity. Thanks to all that offered suggestions Alistair --- Alistair Marshall http://www.thatscottishengineer.co.uk --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Accessing Model field from ModelForm?
Thanks, that's a big help.
On Nov 1, 5:14 am, Daniel Roseman <[EMAIL PROTECTED]>
wrote:
> On Nov 1, 5:33 am, killsto <[EMAIL PROTECTED]> wrote:
>
>
>
> > I have a basic form that shows what a person entered when it is
> > submitted. However, it shows up as a form.CharField (textbox) instead
> > of model.CharField. Is there a way to access the model's saved data
> > from the Forms? Also does form_for_model (http://www.djangobook.com/en/
> > 1.0/chapter07/) no longer exist? I can't get it to load.
>
>
>
> > from qotd.models import *
> > from django.shortcuts import render_to_response
> > from django.http import HttpResponseRedirect
>
> > def contact(request, question):
> > if request.method == 'POST': # If the form has been submitted...
> > form = Questionform(request.POST) # A form bound to the POST
> > data
> > if form.is_valid():
> > form.save()
> > #return HttpResponseRedirect('results.html', {'form': form}
>
> > else:
> > form = Questionform()
> > return render_to_response('contact.html', {
> > 'form': form
> > })
>
> The only thing you need to do that you're not doing is to actually
> pass the instance of Question (or Choice) to the form when you
> instantiate it.
>
> Assuming that 'question' is the PK of the Question object:
>
> def contact(request, question):
> question_obj = Question.objects.get(pk=question)
> if request.method == 'POST':
> form = Questionform(request.POST, instance=question_obj)
> if form.is_valid():
> form.save()
> return HttpResponseRedirect('/submission/')
> else:
> form = Questionform(instance=question_obj)
> return render_to_response('contact.html', {
> 'form': form
> })
>
> Note that HttpResponseRedirect takes a *URL*, not a template/context.
> It tells the user's browser to request a different URL so that they
> can't submit the form twice.
> --
> DR.
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Re: Why is my string not auto escaped?
On Oct 31, 8:28 am, Rajesh Dhawan <[EMAIL PROTECTED]> wrote: > > > > So if these built in filters are marking my strings safe, inspite of > > > > unsafe data being passed in, should they not handle escaping as well? > > > > The problem seems to be that your filter function doesn't mark itself > > > with an is_safe attribute (defaulting it to False). So try marking > > > your filter with is_safe=True which means that your filter doesn't > > > introduce any HTML unsafe characters by itself (not including the ones > > > that are already in the input): > > > > filterxx.is_safe = True > > > > Also, it's easier for people to follow a discussion thread if you > > > don't top post your responses. > > > > -RD > > > I don't think setting is_safe is the solution, in fact is sounds like > > the exact opposite. > > It might sound confusing, but is_safe=True is a way for you to > indicate to Django that your filter does not introduce any unwanted > characters. See point #1 in the below doc for a more thorough > explanation: > > http://docs.djangoproject.com/en/dev/howto/custom-template-tags/#filt... > > > Shabda *wants* Django to escape the results. > > Here's an excerpt from the docs for that case: > > "1. Your filter does not introduce any HTML-unsafe characters (<, >, > ', " or &) into the result that were not already present. In this > case, you can let Django take care of all the auto-escaping handling > for you. All you need to do is put the is_safe attribute on your > filter function and set it to True, like so: > > This attribute tells Django that if a "safe" string is passed into > your filter, the result will still be "safe" and if a non-safe string > is passed in, Django will automatically escape it, if necessary." > > -RD But Shadba's example filter is calling urlize which does introduce HTML unsafe characters. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: can't delete many-to-many related record from admin inline
I'm no guru, Im stuck also with some many-to-many features.
1.- why whould you need a 3rd table if you are not using attributes
in the relationship? (Variant).
2.- have you tried to add an models.AutoField(primary=True) to your
model Variant ? I knew django does that if no is specified in order to
preserve the 3rd normal form, but it would be a first aproach.
Hope this helped out a little.
Regards
ndarkduck
On Oct 30, 7:40 am, chris <[EMAIL PROTECTED]> wrote:
> Hi there,
>
> I am still pretty new to django and just trying to figure out how it
> is all supposed to work.
>
> I have the following models:
>
> *models.py:
>
> class Char(models.Model):
> char = models.CharField(max_length=10)
> variants = models.ManyToManyField("self", symmetrical=False,
> through="Variant", related_name="varchars", blank=True, null=True)
>
> class Variant(models.Model):
> char = models.ForeignKey(Char)
> variant = models.ForeignKey(Char, related_name="vars")
>
> *admin.py:
>
> class CharVarInline(admin.StackedInline):
> model = Variant
> fk_name = "char"
> raw_id_fields=("variant", "char",)
> extra = 1
>
> class CharAdmin(admin.ModelAdmin):
> inlines = (CharVarInline,)
>
> This causes the variants part to be displayed with a char record in
> admin. I also get a check-box there, which can be checked to delete
> the inlined related recorded. However, when I try to used this to
> delete the record and click save, the following error occurs:
>
> ValueError at /admin/chardb/char/70524/
>
> 'Variant' instance needs to have a primary key value before a many-to-
> many relationship can be used.
>
> Apparently, something is going wrong with the deletion, which lets
> part of the record hang in empty air. But I have no idea where to
> look or how to fix this. Does anybody has any idea?
>
> Any help appreciated,
>
> Chris
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Re: Deploying multiple django applications in a single apache server
On Sat, Nov 1, 2008 at 9:03 AM, bluefireredsky <[EMAIL PROTECTED]>wrote: > > Hello, > > I have followed the link from django documentation on deploying an > application to apache2. > > http://docs.djangoproject.com/en/dev/howto/deployment/modpython/ > > I have two applications, which I would like to run on two different > ports on the server. Basically one being an administrative website > (not the django inbuilt admin website) and the other the user front > end. > > Currently I have the following on my ports.conf: > > === > Listen 80 > > >Listen 443 > > === > > My httpd.conf is as follows: > > > >SetHandler python-program >PythonHandler django.core.handlers.modpython >SetEnv DJANGO_SETTINGS_MODULE mysitename.settings >PythonOption django.root /mysitename >PythonDebug On >PythonPath "['/usr/local/'] + sys.path" > > >SetHandler None > > >SetHandler None > > > > What changes should I do on these files to run my second django > application on a different port, say 8080, on the same apache server? > > This is really more an Apache question than a Django one. First you'll need to add a Listen for the second port in your ports.conf, the doc for that is here: http://httpd.apache.org/docs/2.2/bind.html At the bottom of that page they point to the VirtualHost directive, which is the second thing you'll need to do. You need to enclose your existing directives for the app on port 80 in a VirtualHost block for port 80, and create a second VirtualHost with directives for the new app that you want on the second port. Karen --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: populating forms using models
To populate select field you have many options. First is using ModelChoiceField. The ModelChoiceField have an argument named queryset, you can use like this example provincia = forms.ModelChoiceField(queryset=Provincia.objects.all() ..) If you can't have a FK of Provincia table you can use a Choice Field and populate externaly like this provincia = forms.ChoiceField( ... ) and inside the form declare a new method named populate(self, list_of_provincias): (for example) and inside this method you can do this... self.fields['provincia'].choices = list_of_provincias In other situations you can populate a ModelcoiceField externaly too: example: You need to populate a modelchoice field with a queryset depending in the user loged ... def populate(self,user): self.fields['boards'].queryset = Board.objects.filter( guild = Guild.objects.get(owner=user) ) When you create a form yo need to call the .populate method with request.user as argument. 2008/11/1 Rock <[EMAIL PROTECTED]> > > In brief, your forms field for province does not have to have anything > to do with your corresponding model field. > Just make a forms.ChoiceField with the data filled in that you need > (or else look up the pattern for loading dynamic data into a > forms.ChoiceField and do something like that.) If you go the dynamic > route, make sure your form gets initialized properly when you create > it for initial use and also when you create it for POST processing. > > > > > -- neo2001[at]gmail.com neo[at]art-xtreme.com --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: updating a single field / attribute, is it possible? or better practices?
In the meantime, creating and executing your own update command is not difficult. Here is a snippet for a custom PositionField that updates itself when necessary with an SQL UPDATE: http://www.djangosnippets.org/snippets/884/ --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: populating forms using models
In brief, your forms field for province does not have to have anything to do with your corresponding model field. Just make a forms.ChoiceField with the data filled in that you need (or else look up the pattern for loading dynamic data into a forms.ChoiceField and do something like that.) If you go the dynamic route, make sure your form gets initialized properly when you create it for initial use and also when you create it for POST processing. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Overriding admin templates
http://www.djangobook.com/en/1.0/chapter17/
On Sat, Nov 1, 2008 at 6:20 PM, Lars Stavholm <[EMAIL PROTECTED]> wrote:
>
> Low Kian Seong wrote:
>> You are supposed to put the admin template you want to override in
>> your own template directory definition in settings.py
>>
>> So, if you defined it as /home/stava/> name>/template/admin/change_list.html
>
> Huh?
> /L
>
>> On Sat, Nov 1, 2008 at 5:32 PM, Lars Stavholm <[EMAIL PROTECTED]> wrote:
>>> I'd like to override part of an admin change_list template.
>>>
>>> Reading the documentation, my understanding is that I can place
>>> a template in a certain place in the templates directory hierarchy,
>>> and django will look for it and use it, i.e.:
>>>
>>> templates/admin/build/job/change_list.html
>>>
>>> ...where "build" is my application and "job" is my model class.
>>>
>>> The change_list.html file only contains the part I want to override,
>>> i.e. the extrahead block. It contains:
>>>
>>> {% extends "admin/change_list.html" %}
>>> {% block extrahead %}
>>>
>>> {% endblock %}
>>>
>>> However, this does not work for me, so I'm expecting it to be some
>>> mistake on my part, I just can't figure out what the mistake is.
>>>
>>> Now, if I put the file in ./templates/admin/build/change_list.html
>>> it still wont work. On the other hand, this would be overriding all
>>> "build" application change lists, which is not what I was looking for.
>>>
>>> Only way I've found is to copy the change_list.html from the django
>>> installation in contrib/admin/templates/admin, and then modify it to
>>> my needs, using "if" statements to figure out which application model
>>> class is being rendered, and the put the change_list.html in my app's
>>> templates/admin directory, which doesn't feel right.
>>>
>>> Any input appreciated
>>> /Lars Stavholm
>>>
>>>
>>
>> >
>>
>
>
>
> >
>
--
Low Kian Seong
blog: http://lowkster.blogspot.com
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Re: Installing an app in a sub-directory of another site (urls question)
Hi,
The reason is because of the preceding "/" in your
HttpResponseRedirect.
You could try to redirect to "success/" or to "../success/" based on
which may be applicable to you.
Cheers
On Nov 1, 5:51 pm, "[EMAIL PROTECTED]" <[EMAIL PROTECTED]>
wrote:
> Hi guys,
>
> I installed my app on a subdir of another site (just for staging).
>
> www.example.org/djangoapp
>
> Now my urls keep pointing back to the root of the other site, breaking
> navigation.
>
> So for example if i POST some form to
>
> www.example.org/djangoapp/subscribe/
>
> and then from there issue an HttpResponseRedirect('/success/')
> pretending to be redirected to
>
> www.example.org/djangoapp/success/
>
> i instead get redirected to
>
> www.example.org/success/
>
> What should i look into to fix this, without going through the code
> and changing all my redirects just for staging?
>
> Thanks,
> Lorenzo
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Deploying multiple django applications in a single apache server
Hello, I have followed the link from django documentation on deploying an application to apache2. http://docs.djangoproject.com/en/dev/howto/deployment/modpython/ I have two applications, which I would like to run on two different ports on the server. Basically one being an administrative website (not the django inbuilt admin website) and the other the user front end. Currently I have the following on my ports.conf: === Listen 80 Listen 443 === My httpd.conf is as follows: SetHandler python-program PythonHandler django.core.handlers.modpython SetEnv DJANGO_SETTINGS_MODULE mysitename.settings PythonOption django.root /mysitename PythonDebug On PythonPath "['/usr/local/'] + sys.path" SetHandler None SetHandler None What changes should I do on these files to run my second django application on a different port, say 8080, on the same apache server? Thank you. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Installing an app in a sub-directory of another site (urls question)
Hi guys,
I installed my app on a subdir of another site (just for staging).
www.example.org/djangoapp
Now my urls keep pointing back to the root of the other site, breaking
navigation.
So for example if i POST some form to
www.example.org/djangoapp/subscribe/
and then from there issue an HttpResponseRedirect('/success/')
pretending to be redirected to
www.example.org/djangoapp/success/
i instead get redirected to
www.example.org/success/
What should i look into to fix this, without going through the code
and changing all my redirects just for staging?
Thanks,
Lorenzo
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Re: PROFANITIES_LIST for comments
> I use default comments form, set in settings.py: > > COMMENTS_ALLOW_PROFANITIES = True Uh...while I speak without looking at any code, or documentation, prima facie, this looks backwards...it sounds like you want "Allow profanities = False" -tim --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
PROFANITIES_LIST for comments
I use default comments form, set in settings.py:
COMMENTS_ALLOW_PROFANITIES = True
PROFANITIES_LIST = ('viagra', 'porno')
But when i post comment with this words - it posted =\
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Re: Overriding admin templates
Low Kian Seong wrote:
> You are supposed to put the admin template you want to override in
> your own template directory definition in settings.py
>
> So, if you defined it as /home/stava/ name>/template/admin/change_list.html
Huh?
/L
> On Sat, Nov 1, 2008 at 5:32 PM, Lars Stavholm <[EMAIL PROTECTED]> wrote:
>> I'd like to override part of an admin change_list template.
>>
>> Reading the documentation, my understanding is that I can place
>> a template in a certain place in the templates directory hierarchy,
>> and django will look for it and use it, i.e.:
>>
>> templates/admin/build/job/change_list.html
>>
>> ...where "build" is my application and "job" is my model class.
>>
>> The change_list.html file only contains the part I want to override,
>> i.e. the extrahead block. It contains:
>>
>> {% extends "admin/change_list.html" %}
>> {% block extrahead %}
>>
>> {% endblock %}
>>
>> However, this does not work for me, so I'm expecting it to be some
>> mistake on my part, I just can't figure out what the mistake is.
>>
>> Now, if I put the file in ./templates/admin/build/change_list.html
>> it still wont work. On the other hand, this would be overriding all
>> "build" application change lists, which is not what I was looking for.
>>
>> Only way I've found is to copy the change_list.html from the django
>> installation in contrib/admin/templates/admin, and then modify it to
>> my needs, using "if" statements to figure out which application model
>> class is being rendered, and the put the change_list.html in my app's
>> templates/admin directory, which doesn't feel right.
>>
>> Any input appreciated
>> /Lars Stavholm
>>
>>
>
> >
>
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Re: Accessing Model field from ModelForm?
On Nov 1, 5:33 am, killsto <[EMAIL PROTECTED]> wrote:
> I have a basic form that shows what a person entered when it is
> submitted. However, it shows up as a form.CharField (textbox) instead
> of model.CharField. Is there a way to access the model's saved data
> from the Forms? Also does form_for_model (http://www.djangobook.com/en/
> 1.0/chapter07/) no longer exist? I can't get it to load.
>
>
> from qotd.models import *
> from django.shortcuts import render_to_response
> from django.http import HttpResponseRedirect
>
> def contact(request, question):
> if request.method == 'POST': # If the form has been submitted...
> form = Questionform(request.POST) # A form bound to the POST
> data
> if form.is_valid():
> form.save()
> #return HttpResponseRedirect('results.html', {'form': form}
>
> else:
> form = Questionform()
> return render_to_response('contact.html', {
> 'form': form
> })
The only thing you need to do that you're not doing is to actually
pass the instance of Question (or Choice) to the form when you
instantiate it.
Assuming that 'question' is the PK of the Question object:
def contact(request, question):
question_obj = Question.objects.get(pk=question)
if request.method == 'POST':
form = Questionform(request.POST, instance=question_obj)
if form.is_valid():
form.save()
return HttpResponseRedirect('/submission/')
else:
form = Questionform(instance=question_obj)
return render_to_response('contact.html', {
'form': form
})
Note that HttpResponseRedirect takes a *URL*, not a template/context.
It tells the user's browser to request a different URL so that they
can't submit the form twice.
--
DR.
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Re: Help to Upload image
Yeah, if in doubt you can use the forms.as_p first to see what kind of
html form it outputs and use that as the basis for creating your form.
On Thu, Oct 30, 2008 at 7:05 PM, Giles Thomas
<[EMAIL PROTECTED]> wrote:
>
> please smile wrote:
>> Can anybody please tell how to upload a image ?
>
> I'm new to this myself, but I got something working using Django's forms
> mechanism.
>
> My view function looks something like this:
>
> ---
> class MyForm(ModelForm):
>class Meta:
>model = photos
>
> def upload(request):
>if request.method == "POST":
>form = MyForm(request.POST, request.FILES)
>if form.is_valid():
>sheet = form.save()
>return HttpResponseRedirect(reverse('upload_thanks'))
>
>return render_to_response(
>"upload.html",
>{
>"form" : MyForm(),
>}
>)
> ---
>
> This is then rendered by a template, upload.html, that looks something
> like this:
>
> ---
>
>
>{% for field in form %}
>
>
>
>
>{{ field.errors }}
>
>
>
>
> {{ field.label_tag }}:
>
>
> {{ field }}
>
>
>{% endfor %}
>
>
>
>
> ---
>
> Finally, my urls.py specifies "names" for both the upload and the
> upload_thanks pages:
>
> ---
> urlpatterns = patterns('',
># ...
>url(
>r'^upload/$',
>'my.app.views.upload',
>name="upload"
>),
>url(
>r'^upload/thanks/$',
> 'django.views.generic.simple.direct_to_template',
>{ 'template' : 'upload_thanks.html' },
>name="upload_thanks"
>),
> )
> ---
>
> Hope this helps.
>
>
> Cheers,
>
> Giles
>
> --
> Giles Thomas
> MD & CTO, Resolver Systems Ltd.
> [EMAIL PROTECTED]
> +44 (0) 20 7253 6372
>
> Try out Resolver One!
Re: Using Django
Finding out a bit about urls.py and how it functions would do a world of good. It is very flexible and powerful once you learn how to wield it. Low Kian Seong http://lowkster.blogspot.com On Sat, Nov 1, 2008 at 5:20 AM, [EMAIL PROTECTED] <[EMAIL PROTECTED]> wrote: > > Hello, > > I'm new to Django and it's taken me a while to get things setup > correctly on Dreamhost. I've done the tutorials on my local machine > prior to setting things up on Dreamhost but it seems like I'm missing > instructions on how to actually use Django. Yes, I've read the "Using > Django" section of the website but I don't even know how/where my > pages should reside. If I request http://www.mysite.com, how do I > route that to my "projects" directory where the "mysite" directory > resides, a symbolic link? - which I tried but just returns a 403 > error. I'm still used to the traditional "mysite.com" directory which > contains index.php, contact.php, etc., and I don't understand how the > directory structure for Django works. It seems like the tutorials just > show you how to start a project under test conditions and show off the > built-in admin tools, without really explaining how things are setup > for an actual website. Maybe this system is over my head... > > Thanks, > > Jason > > > -- Low Kian Seong blog: http://lowkster.blogspot.com --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: multiselect populated by another app
I think this might be useful: http://www.zoia.org/blog/2007/04/23/using-dynamic-choices-with-django-newforms-and-custom-widgets/ On Fri, Oct 31, 2008 at 5:36 AM, webcomm <[EMAIL PROTECTED]> wrote: > > Bump. > > There must be a way to do this, right? I have looked all over... the > documentation seems to indicate that there is no way to do this in > django, which is surprising, since this is a necessary part of so many > programs. > > Is there really no way to populate a mutiselect with values from > another app? > > The Definitive Guide to Django says that a ManyToManyField will take > as its one argument only the name of a class from the same app. If > that's true, I don't see how anyone could develop a categories app in > django... perhaps I'm missing something? > > Thanks in advance for your help, > Ryan > > > > On Oct 27, 11:03 am, webcomm <[EMAIL PROTECTED]> wrote: >> Hi, >> >> I have created a simple categories app, and now I want to be able to >> categorize my articles, which are handled by a different app. I'd >> like to create a multiselect categories field in my articles admin >> that is populated by the category entries from my categories app. >> >> In my categories app, I have to ability to create category groups. >> This is the models.py for the categories app... >> >> from django.db import models >> >> class Group(models.Model): >> name = models.CharField(max_length=200) >> >> def __str__(self): >> return self.name >> >> class Category(models.Model): >> group = models.ForeignKey(Group) >> name = models.CharField(max_length=200) >> >> def __str__(self): >> return self.name >> >> class Meta: >> verbose_name_plural = 'categories' >> >> I want to set up my articles admin interface so there is a different >> multiselect box for each category group, or one large multiselect with >> the categories organized in groups. >> >> I am not quite sure what to do in articles/admin.py and/or elsewhere >> to achieve this. >> >> Any ideas? >> >> Thanks, >> Ryan > > > --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Overriding admin templates
You are supposed to put the admin template you want to override in
your own template directory definition in settings.py
So, if you defined it as /home/stava//template/admin/change_list.html
On Sat, Nov 1, 2008 at 5:32 PM, Lars Stavholm <[EMAIL PROTECTED]> wrote:
>
> I'd like to override part of an admin change_list template.
>
> Reading the documentation, my understanding is that I can place
> a template in a certain place in the templates directory hierarchy,
> and django will look for it and use it, i.e.:
>
> templates/admin/build/job/change_list.html
>
> ...where "build" is my application and "job" is my model class.
>
> The change_list.html file only contains the part I want to override,
> i.e. the extrahead block. It contains:
>
> {% extends "admin/change_list.html" %}
> {% block extrahead %}
>
> {% endblock %}
>
> However, this does not work for me, so I'm expecting it to be some
> mistake on my part, I just can't figure out what the mistake is.
>
> Now, if I put the file in ./templates/admin/build/change_list.html
> it still wont work. On the other hand, this would be overriding all
> "build" application change lists, which is not what I was looking for.
>
> Only way I've found is to copy the change_list.html from the django
> installation in contrib/admin/templates/admin, and then modify it to
> my needs, using "if" statements to figure out which application model
> class is being rendered, and the put the change_list.html in my app's
> templates/admin directory, which doesn't feel right.
>
> Any input appreciated
> /Lars Stavholm
>
>
> >
>
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Overriding admin templates
I'd like to override part of an admin change_list template.
Reading the documentation, my understanding is that I can place
a template in a certain place in the templates directory hierarchy,
and django will look for it and use it, i.e.:
templates/admin/build/job/change_list.html
...where "build" is my application and "job" is my model class.
The change_list.html file only contains the part I want to override,
i.e. the extrahead block. It contains:
{% extends "admin/change_list.html" %}
{% block extrahead %}
{% endblock %}
However, this does not work for me, so I'm expecting it to be some
mistake on my part, I just can't figure out what the mistake is.
Now, if I put the file in ./templates/admin/build/change_list.html
it still wont work. On the other hand, this would be overriding all
"build" application change lists, which is not what I was looking for.
Only way I've found is to copy the change_list.html from the django
installation in contrib/admin/templates/admin, and then modify it to
my needs, using "if" statements to figure out which application model
class is being rendered, and the put the change_list.html in my app's
templates/admin directory, which doesn't feel right.
Any input appreciated
/Lars Stavholm
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Re: HttpRequest with chunked encoding is not buffered
On Nov 1, 10:40 am, "Tomáš Brambora" <[EMAIL PROTECTED]> wrote: > I have a standard Django installation without any changes in the > settings (except adding mysql db to the settings.py) and I'm sending > the message to localhost:8000, so there is no proxy or anything else > in the way. Still, the request body comes after me sending the > response... As I said in the other similar thread you created about this. If you are getting empty input on read, then you are using hosting mechanism that doesn't properly filter out chunked request content as not being supported and instead assumes that content length of request was 0. In other words, chunked request content is not supported. Most hosting mechanisms will flag it as an error. The internal Django development server appears just to assume that content length on request is 0 since Content-Length header wouldn't be set. Thus why you are seeing no input. Graham > On Fri, Oct 31, 2008 at 11:50 PM, Graham Dumpleton > > <[EMAIL PROTECTED]> wrote: > > > [EMAIL PROTECTED] wrote: > >> Hello, > >> I'm trying to receive a possibly large XML message via HttpRequest > >> (POST method) with chunked encoding. However, when I send a response, > >> I found out (using Wireshark) that the response is being sent before > >> the whole POST request body is available. I expected Django to be > >> buffering the chunks and that the request would be complete, but > >> that's apparently not happening... > > >> I'm reading the body like this: > >> request.POST.values()[0] > > >> (Which is probably a wrong way, but I don't know how to do it > >> otherwise.) > > > What hosting mechanism are you using. Anything that uses WSGI (eg, > > mod_wsgi, fastcgi/flup) or mod_python will not work as neither WSGI > > specification or mod_python support chunked transfer encoding on > > request content. Certainly for mod_python and mod_wsgi, it should give > > an error back before even gets to Django saying that content length > > required to be set. > > > Graham --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Templaite:display li items alternatively using for
On Sat, Nov 1, 2008 at 1:58 AM, Xian Chen <[EMAIL PROTECTED]> wrote:
> Hi,
>
> I want to display a list of items by using {% for item in items %}.
>
> To make the web pages look better, I want to use two kinds of
> alternatively.
>
> E.G item
>item
>
> My question is how can i use the tags to implement this requirement?
>
> Any build-in tags for this?
>
Yes:
http://docs.djangoproject.com/en/dev/ref/templates/builtins/#cycle
Karen
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Accessing Model field from ModelForm?
I have a basic form that shows what a person entered when it is
submitted. However, it shows up as a form.CharField (textbox) instead
of model.CharField. Is there a way to access the model's saved data
from the Forms? Also does form_for_model (http://www.djangobook.com/en/
1.0/chapter07/) no longer exist? I can't get it to load.
models.py:
from django.db import models
from django.forms import ModelForm
class Question(models.Model):
question = models.CharField('Question', max_length = '200',
primary_key = True)
pub_date = models.DateField(auto_now_add = True)
def __unicode__(self):
return self.question
class Choice(models.Model):
Question = models.ForeignKey(Question)
choice = models.CharField(max_length = '200')
class Questionform(ModelForm):
class Meta:
model = Question
class Choiceform(ModelForm):
class Meta:
model = Choice
view:
from qotd.models import *
from django.shortcuts import render_to_response
from django.http import HttpResponseRedirect
def contact(request, question):
if request.method == 'POST': # If the form has been submitted...
form = Questionform(request.POST) # A form bound to the POST
data
if form.is_valid():
form.save()
#return HttpResponseRedirect('results.html', {'form': form}
else:
form = Questionform()
return render_to_response('contact.html', {
'form': form
})
template:
{% if not form.is_valid %}
{{ form.as_p }}
{% endif %}
{% if form.is_valid %}
{{ form.question }}
{% endif %}
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Re: S3Storage, FileField -- default_storage.exists() has unwanted side-effects
Actually, it turns out there is a bug in Amazon's S3.py module. The Date field in the header is formatted with AM/PM notation - it should, i.e. MUST, be in 24hr notation. Change the %X to %T and you're good to go. On Oct 30, 6:27 pm, Info Cascade <[EMAIL PROTECTED]> wrote: > I have a model that has a FileField storage field. > The default_storage system is S3Storage. > I noticed that I was getting unusual results when I simply tried to > verify whether the file existed on disk using the > default_storage.exists() method. > If I call it with the FileField object, it causes Django to actually try > to *get* the file, which is not what I intend. The S3Storage module > implements exists() as a simple http HEAD request. That part works > fine. But then Django starts getting the file which eventually results > in an error, so it appears the file doesn't exist when really it does. > (The file is an audio file, which triggers a series of byte-range > requests, the final one having incorrect value, so I'm getting a series > of 206 codes followed by 416 error code. It causes a key error in > S3Storage or S3 on 'etag'.) > > I was able to work around it by using the str() function, which results > in the correct behavior. > > Anyway, it was non-intuitive for me that checking whether a file exists > would make Django do a GET on it! Is this a bug or do I just not > understand what's going on beneath the surface? (Which is the case, > actually.) Can someone explain this? > > Liam > > > > > section_objects = > > Section.objects.in_bulk(section_ids).values() > > if len(section_ids) != len(section_objects): > > print "section count mismatch for article '%d'" % > > (art.id) > > idx = 0 > > for sec in section_objects: > > idx += 1 > > if sec.url: > > try: > > if not default_storage.exists(*str*(sec.url)): > > print "\tarticle '%s' missing content > > for section %d" % (art.id, idx) --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
