php-general Digest 5 Oct 2010 10:48:35 -0000 Issue 6974
php-general Digest 5 Oct 2010 10:48:35 - Issue 6974
Topics (messages 308450 through 308454):
Re: Connecting to MySql with PHP
308450 by: a...@ashleysheridan.co.uk
308451 by: mrfroasty
Bug #52782: DOMDocument subclass forgotten using -ownerDocument after closure
308452 by: Jan Moesen
Filesystem path creation function
308453 by: Gary
Continuance of the struggle (trying to understand)
308454 by: Col Day
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--
---BeginMessage---
Have you installed the php mysql module? Basically, it tells php how to connect
to mysql.
This question has come up a few times this week, have you tried installing
something like xampp or easyphp rather than the individual software components:
Apache, php mysql.
Thanks,
Ash
http://www.ashleysheridan.co.uk
- Reply message -
From: sueandant hollandsath...@tiscali.co.uk
Date: Mon, Oct 4, 2010 22:08
Subject: [PHP] Connecting to MySql with PHP
To: php-gene...@lists.php.net
I am running PHP 5.3.3, with Apache 2.0 Handler and MySql Server 5.1. My OS
is Vista Home Premium 32 bit with SP2.
MySql works fine from the command prompt, Apache is running and PHP works.
But I cannot access the mysqli classes. This simple program:
?php
$mysqli = new mysqli(localhost, root, ##, testDB);#I've
deliberately obliterated the password
if (mysqli_connect_errno()) {
printf(Connect failed: %s\n, mysqli_connect_error());
exit();
} else {
printf(Host information: %s\n, mysqli_get_host_info($mysqli));
}
?
produces this error message:
Warning: mysqli::mysqli() [mysqli.mysqli]: [2002] A connection attempt failed
because the connected party did not (trying to connect via
tcp://localhost:3306) in C:\Apache\htdocs\mysqlconnect.php on line 3
Warning: mysqli::mysqli() [mysqli.mysqli]: (HY000/2002): A connection attempt
failed because the connected party did not properly respond after a period of
time, or established connection failed because connected host has failed to
respond. in C:\Apache\htdocs\mysqlconnect.php on line 3
Fatal error: Maximum execution time of 30 seconds exceeded in
C:\Apache\htdocs\mysqlconnect.php on line 3
I guess PHP cannot find the mysqli classes. I've checked the phpinfo() output
and discovered :
Configuration File (php.ini) Path C:\Windows
Loaded Configuration File C:\PHP\php.ini
I don't know if this ok. I've tried changing the location of the loaded file
to C:\Windows\php.ini, but to no avail, and I don't know how to change the
location of the config file.
I am obviously doing something wrong, but I don't know what. Can anyone help?
Ironically, everything worked perfectly before I upgraded to PHP 5.3.3!---End Message---
---BeginMessage---
The code execute fine on my LAMP server, but I am wondering does
localhost really works on Windows ?As this on MAC you need to actually
tell a complete path.On MAC with Zend-Server I had to mention something
like /var/tmp/mysql
Anyways, by looking on the error it might be mysql server is not
accessed...Can you actually access the myql server with anything else
like phpmyadmin or cli ?
Gr
mrfroasty
On 10/04/2010 11:21 PM, a...@ashleysheridan.co.uk wrote:
Have you installed the php mysql module? Basically, it tells php how to
connect to mysql.
This question has come up a few times this week, have you tried installing
something like xampp or easyphp rather than the individual software
components: Apache, php mysql.
Thanks,
Ash
http://www.ashleysheridan.co.uk
- Reply message -
From: sueandant hollandsath...@tiscali.co.uk
Date: Mon, Oct 4, 2010 22:08
Subject: [PHP] Connecting to MySql with PHP
To: php-gene...@lists.php.net
I am running PHP 5.3.3, with Apache 2.0 Handler and MySql Server 5.1. My OS
is Vista Home Premium 32 bit with SP2.
MySql works fine from the command prompt, Apache is running and PHP works.
But I cannot access the mysqli classes. This simple program:
?php
$mysqli = new mysqli(localhost, root, ##, testDB);#I've
deliberately obliterated the password
if (mysqli_connect_errno()) {
printf(Connect failed: %s\n, mysqli_connect_error());
exit();
} else {
printf(Host information: %s\n, mysqli_get_host_info($mysqli));
}
?
produces this error message:
Warning: mysqli::mysqli() [mysqli.mysqli]: [2002] A connection attempt failed
because the connected party did not (trying to connect via
tcp://localhost:3306) in C:\Apache\htdocs\mysqlconnect.php on line 3
Warning: mysqli::mysqli() [mysqli.mysqli]: (HY000/2002): A connection attempt
failed because the connected party did not properly respond after a period of
[PHP] Bug #52782: DOMDocument subclass forgotten using -ownerDocument after closure
(I filed bug #52782 about a month ago, but have not received any reply. I am posting here to try and get some feedback on it.) We have custom XML document and element classes that extend the original DOMDocument and DOMElement classes for convenience. There is a class that uses an instance of XmlElement obtained via a callback specified at construction time. That XmlElement works fine and stays that way. However, when we get its ownerDocument outside of the closure, the result is not an XmlDocument but a DOMDocument. I cannot see a single reason why. I tried several options, and it only seems to happen with that closure. I have checked versions 5.3.1, 5.3.2, 5.3.3 and now the latest 5.3.4 snapshot compiled with './configure make'. More details and a test case: http://bugs.php.net/bug.php?id=52782 Jan -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Continuance of the struggle (trying to understand)
Hi all, After my escapades with the real basics and realizing my laptop wasn't logged on as Administrator, I now am trying to work out why this script works sometimes but not others. html head titlePHP Test/title /head body pThis is an HTML line ?php echo pThis is a PHP line/p; phpinfo(); ? /body /html If I save this as phptest.php and open IE pointing it to localhost/phptest.php it works fine. Get both lines of text followed by the pages of gumpf about php. However if I paste this into a -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: Continuance of the struggle (trying to understand)
Col Day colind...@aol.com wrote in message news:23.81.45586.2820b...@pb1.pair.com... Hi all, After my escapades with the real basics and realizing my laptop wasn't logged on as Administrator, I now am trying to work out why this script works sometimes but not others. html head titlePHP Test/title /head body pThis is an HTML line ?php echo pThis is a PHP line/p; phpinfo(); ? /body /html If I save this as phptest.php and open IE pointing it to localhost/phptest.php it works fine. Get both lines of text followed by the pages of gumpf about php. However if I paste this into a That was weird! I was saying, If I paste this into a webpage I only get the HTML line as before. Anyone have any ideas? PHP is obviously working as is apache. Just don't understand why they don't show up in web pages. Cheers again all! -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] file_get_contents() failing on CentOS.
The issue _WAS_ the firewall. All sorted. Thank you. -- Richard Quadling Twitter : EE : Zend @RQuadling : e-e.com/M_248814.html : bit.ly/9O8vFY -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Re: Continuance of the struggle (trying to understand)
Col, Can you let us know what exactly you see when you say http://localhost:/phptest.php ? Regards, Shreyas On Tue, Oct 5, 2010 at 4:20 PM, Col Day colind...@aol.com wrote: Col Day colind...@aol.com wrote in message news:23.81.45586.2820b...@pb1.pair.com... Hi all, After my escapades with the real basics and realizing my laptop wasn't logged on as Administrator, I now am trying to work out why this script works sometimes but not others. html head titlePHP Test/title /head body pThis is an HTML line ?php echo pThis is a PHP line/p; phpinfo(); ? /body /html If I save this as phptest.php and open IE pointing it to localhost/phptest.php it works fine. Get both lines of text followed by the pages of gumpf about php. However if I paste this into a That was weird! I was saying, If I paste this into a webpage I only get the HTML line as before. Anyone have any ideas? PHP is obviously working as is apache. Just don't understand why they don't show up in web pages. Cheers again all! -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- Regards, Shreyas Agasthya
Re: [PHP] Filesystem path creation function
On 5 October 2010 09:07, Gary php-gene...@garydjones.name wrote:
Does such a thing exist in php? My searches have lead nowhere.
What I am looking for is a function which you would pass two parts of a
path to (which might be a directory and a filename, say) and it would
return a string containing the parameters separate by the correct number
of path separators according to the current OS.
For example:
?php
$d = 'foo';
$f = 'bar';
$path = createPathString($d, $f);
?
Would result in 'foo\bar' (Windows), 'foo/bar' (*n*x).
And
?php
$d = 'foo/'; // note the trailing slash
$f = 'bar';
$path = createPathString($d, $f);
?
on *n*x would also result in 'foo/bar' (i.e. the path would only contain
one /).
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Yep.
function createPathString($d, $f){return $d. DIRECTORY_SEPARATOR . $f;}
--
Richard Quadling
Twitter : EE : Zend
@RQuadling : e-e.com/M_248814.html : bit.ly/9O8vFY
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Re: [PHP] Filesystem path creation function
On 5 October 2010 09:07, Gary php-gene...@garydjones.name wrote: Does such a thing exist in php? My searches have lead nowhere. What I am looking for is a function which you would pass two parts of a path to (which might be a directory and a filename, say) and it would return a string containing the parameters separate by the correct number of path separators according to the current OS. For example: ?php $d = 'foo'; $f = 'bar'; $path = createPathString($d, $f); ? Would result in 'foo\bar' (Windows), 'foo/bar' (*n*x). And ?php $d = 'foo/'; // note the trailing slash $f = 'bar'; $path = createPathString($d, $f); ? on *n*x would also result in 'foo/bar' (i.e. the path would only contain one /). -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php http://www.php.net/manual/en/dir.constants.php -- Richard Quadling Twitter : EE : Zend @RQuadling : e-e.com/M_248814.html : bit.ly/9O8vFY -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Re: Continuance of the struggle (trying to understand)
Hi Shreyas, Ok, as far as I can tell the script should show This is an HTML line reflecting that I am seeing the HTML part of the script followed by This is a PHP line to show that PHP is installed and working fine. If I view the script directly in IE by going to http://localhost/phptest.php I get the output: This is an HTML line This is a PHP line followed by a large and detailed list of the PHP install which includes things like compiler language etc. If I paste the script into a web page then all that is displayed is This is an HTML line. Nothing else whatsoever. I am fairly confused. I've tried a couple of different web page creators (Webplus 10 and Web page maker) and get the same result. Sorry if I sound extremely naive but it's bugging me now and I want to understand. Cheers Shreyas Agasthya shreya...@gmail.com wrote in message news:aanlkti=4ke1stf8tan7+ecjo-ux5cj=t9-0qctcfk...@mail.gmail.com... Col, Can you let us know what exactly you see when you say http://localhost:/phptest.php ? Regards, Shreyas On Tue, Oct 5, 2010 at 4:20 PM, Col Day colind...@aol.com wrote: Col Day colind...@aol.com wrote in message news:23.81.45586.2820b...@pb1.pair.com... Hi all, After my escapades with the real basics and realizing my laptop wasn't logged on as Administrator, I now am trying to work out why this script works sometimes but not others. html head titlePHP Test/title /head body pThis is an HTML line ?php echo pThis is a PHP line/p; phpinfo(); ? /body /html If I save this as phptest.php and open IE pointing it to localhost/phptest.php it works fine. Get both lines of text followed by the pages of gumpf about php. However if I paste this into a That was weird! I was saying, If I paste this into a webpage I only get the HTML line as before. Anyone have any ideas? PHP is obviously working as is apache. Just don't understand why they don't show up in web pages. Cheers again all! -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- Regards, Shreyas Agasthya -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: New to PHP and struggling with the basics
Thanks Gary! Nice to know I'm not the only one who has struggled with the Basics. Hopefully I can get my brain around it sometime soon. Cheers Col. Gary php-gene...@garydjones.name wrote in message news:i8f1r9$j4...@dough.gmane.org... Col Day wrote: Yes I did install apache then php, however I tried to follow the instructions in the Dummies book (what does it make me if I can't follow the dummies book?) but to no avail. Don't know what it makes you, but I remember trying to install Apache PHP separately a couple of years ago. The frustration of mismatching versions (Apache only supporting PHP version something, PHP only playing well with Apache version something-else) was... rather high. Head met keyboard several times. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: Continuance of the struggle (trying to understand)
LOL! This is WITH xammp!! Gary php-gene...@garydjones.name wrote in message news:i8f26m$j4...@dough.gmane.org... Col Day wrote: Col Day colind...@aol.com wrote in message news:23.81.45586.2820b...@pb1.pair.com... html head titlePHP Test/title /head body pThis is an HTML line /p !-- close your tag, you evil man! :-) -- ?php echo pThis is a PHP line/p; phpinfo(); ? /body /html If I paste this into a webpage I only get the HTML line as before. What do you mean, webpage? foo.php, for example, or foo.html? If the latter then I am guessing your Apache will serve the page purely as html, and it will never be processed by php. If the former then check that Apache is configured to run php files through php before serving them (must admit, I'm not sure how to do that, it depends on your Apache and PHP). Or, really, just install xampp, it's by far the easiest way and will avoid all the problems associated with configuring two rather complex pieces of software. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RES: [PHP] Connecting to MySql with PHP
Sueandant :
Goto your my.ini file
In my case located in C:\Arquivos de programas\MySQL\MySQL Server 5.1
Search is this configuration option is enabled = skip-networking
And comment to enabled listen on a TCP/IP port. Default port 3306
Or
Put = enable-named-pipe to enable named pipes
Alejandro M.S.
-Mensagem original-
De: sueandant [mailto:hollandsath...@tiscali.co.uk]
Enviada em: segunda-feira, 4 de outubro de 2010 18:08
Para: php-general@lists.php.net
Assunto: [PHP] Connecting to MySql with PHP
I am running PHP 5.3.3, with Apache 2.0 Handler and MySql Server 5.1. My
OS is Vista Home Premium 32 bit with SP2.
MySql works fine from the command prompt, Apache is running and PHP works.
But I cannot access the mysqli classes. This simple program:
?php
$mysqli = new mysqli(localhost, root, ##, testDB);#I've
deliberately obliterated the password
if (mysqli_connect_errno()) {
printf(Connect failed: %s\n, mysqli_connect_error());
exit();
} else {
printf(Host information: %s\n, mysqli_get_host_info($mysqli));
}
?
produces this error message:
Warning: mysqli::mysqli() [mysqli.mysqli]: [2002] A connection attempt
failed because the connected party did not (trying to connect via
tcp://localhost:3306) in C:\Apache\htdocs\mysqlconnect.php on line 3
Warning: mysqli::mysqli() [mysqli.mysqli]: (HY000/2002): A connection
attempt failed because the connected party did not properly respond after a
period of time, or established connection failed because connected host has
failed to respond. in C:\Apache\htdocs\mysqlconnect.php on line 3
Fatal error: Maximum execution time of 30 seconds exceeded in
C:\Apache\htdocs\mysqlconnect.php on line 3
I guess PHP cannot find the mysqli classes. I've checked the phpinfo()
output and discovered :
Configuration File (php.ini) Path C:\Windows
Loaded Configuration File C:\PHP\php.ini
I don't know if this ok. I've tried changing the location of the loaded
file to C:\Windows\php.ini, but to no avail, and I don't know how to change
the location of the config file.
I am obviously doing something wrong, but I don't know what. Can anyone
help?
Ironically, everything worked perfectly before I upgraded to PHP 5.3.3!
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Re: Continuance of the struggle (trying to understand)
Col: If i am reading this correctly, then i think you're looking at this all wrong. If you're working within some kind of page, stored outside of the http://localhost served by apache, like say the .php file is on the desktop... then yeah, you're not going to get the PHP information displayed. (tech people bare with me here...) PHP pages, are compiled when called... so you need apache to call php and translate the PHP code so that if there is any output, it will display that output. If you're trying to show a .php file from teh desktop, then apache isn't handeling this request, and therefor has no idea that there is php code that has to be compiled, and therefore it will just ignore it. I am sure that I am goign to get flamed for that, but i think that it kinda simplifies what apache does for php. NOW... you can run a php file from the command line, but you're not going to get the HTML results as you would had you ran if from the localhost where apache knows what to do with a .php file. So... long story short, if you want PHP to display the PHP stuff, then you will need to have it interpreted by apache (or IIS, or whatever your web server software is) to have it spit back to a web browser client. Hopefully this makes sense, it is early here, i am just getting into work :(, and it made sense while i was typing it... but my coffee intake has not had time to work it's wonderful magic with me yet, so my thoughts may be scattered. Steve On Tue, 2010-10-05 at 12:57 +0100, Col Day wrote: LOL! This is WITH xammp!! Gary php-gene...@garydjones.name wrote in message news:i8f26m$j4...@dough.gmane.org... Col Day wrote: Col Day colind...@aol.com wrote in message news:23.81.45586.2820b...@pb1.pair.com... html head titlePHP Test/title /head body pThis is an HTML line /p !-- close your tag, you evil man! :-) -- ?php echo pThis is a PHP line/p; phpinfo(); ? /body /html If I paste this into a webpage I only get the HTML line as before. What do you mean, webpage? foo.php, for example, or foo.html? If the latter then I am guessing your Apache will serve the page purely as html, and it will never be processed by php. If the former then check that Apache is configured to run php files through php before serving them (must admit, I'm not sure how to do that, it depends on your Apache and PHP). Or, really, just install xampp, it's by far the easiest way and will avoid all the problems associated with configuring two rather complex pieces of software. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RES: [PHP] Connecting to MySql with PHP
Sueandant :
Reading more carefully your email, and search for this error in the net.
Y find this page
http://coreygilmore.com/blog/2009/11/20/fix-php-5-3-hang-on-windows/
Try this
Alejandro M.S.
-Mensagem original-
De: Alejandro Michelin Salomon [mailto:amichel...@hotmail.com]
Enviada em: terça-feira, 5 de outubro de 2010 09:01
Para: 'sueandant'
Cc: php-general@lists.php.net
Assunto: RES: [PHP] Connecting to MySql with PHP
Sueandant :
Goto your my.ini file
In my case located in C:\Arquivos de programas\MySQL\MySQL Server 5.1
Search is this configuration option is enabled = skip-networking
And comment to enabled listen on a TCP/IP port. Default port 3306
Or
Put = enable-named-pipe to enable named pipes
Alejandro M.S.
-Mensagem original-
De: sueandant [mailto:hollandsath...@tiscali.co.uk]
Enviada em: segunda-feira, 4 de outubro de 2010 18:08
Para: php-general@lists.php.net
Assunto: [PHP] Connecting to MySql with PHP
I am running PHP 5.3.3, with Apache 2.0 Handler and MySql Server 5.1. My
OS is Vista Home Premium 32 bit with SP2.
MySql works fine from the command prompt, Apache is running and PHP works.
But I cannot access the mysqli classes. This simple program:
?php
$mysqli = new mysqli(localhost, root, ##, testDB);#I've
deliberately obliterated the password
if (mysqli_connect_errno()) {
printf(Connect failed: %s\n, mysqli_connect_error());
exit();
} else {
printf(Host information: %s\n, mysqli_get_host_info($mysqli));
}
?
produces this error message:
Warning: mysqli::mysqli() [mysqli.mysqli]: [2002] A connection attempt
failed because the connected party did not (trying to connect via
tcp://localhost:3306) in C:\Apache\htdocs\mysqlconnect.php on line 3
Warning: mysqli::mysqli() [mysqli.mysqli]: (HY000/2002): A connection
attempt failed because the connected party did not properly respond after a
period of time, or established connection failed because connected host has
failed to respond. in C:\Apache\htdocs\mysqlconnect.php on line 3
Fatal error: Maximum execution time of 30 seconds exceeded in
C:\Apache\htdocs\mysqlconnect.php on line 3
I guess PHP cannot find the mysqli classes. I've checked the phpinfo()
output and discovered :
Configuration File (php.ini) Path C:\Windows
Loaded Configuration File C:\PHP\php.ini
I don't know if this ok. I've tried changing the location of the loaded
file to C:\Windows\php.ini, but to no avail, and I don't know how to change
the location of the config file.
I am obviously doing something wrong, but I don't know what. Can anyone
help?
Ironically, everything worked perfectly before I upgraded to PHP 5.3.3!
--
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To unsubscribe, visit: http://www.php.net/unsub.php
--
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Fw: [PHP] Connecting to MySql with PHP
- Original Message -
From: sueandant
To: a...@ashleysheridan.co.uk
Sent: Monday, October 04, 2010 10:29 PM
Subject: Re: [PHP] Connecting to MySql with PHP
Thanks Ash
Where do I find the PHP mysql module? I have uncommented both the extensions
php-mysql.dll and php-mysqli.dll; do I need to do more?
Thanks
Tony Holland
- Original Message -
From: a...@ashleysheridan.co.uk
To: sueandant ; php-general@lists.php.net
Sent: Monday, October 04, 2010 10:21 PM
Subject: Re: [PHP] Connecting to MySql with PHP
Have you installed the php mysql module? Basically, it tells php how to
connect to mysql.
This question has come up a few times this week, have you tried installing
something like xampp or easyphp rather than the individual software components:
Apache, php mysql.
Thanks,
Ash
http://www.ashleysheridan.co.uk
- Reply message -
From: sueandant hollandsath...@tiscali.co.uk
Date: Mon, Oct 4, 2010 22:08
Subject: [PHP] Connecting to MySql with PHP
To: php-general@lists.php.net
I am running PHP 5.3.3, with Apache 2.0 Handler and MySql Server 5.1. My OS
is Vista Home Premium 32 bit with SP2.
MySql works fine from the command prompt, Apache is running and PHP works.
But I cannot access the mysqli classes. This simple program:
?php
$mysqli = new mysqli(localhost, root, ##, testDB);#I've
deliberately obliterated the password
if (mysqli_connect_errno()) {
printf(Connect failed: %s\n, mysqli_connect_error());
exit();
} else {
printf(Host information: %s\n, mysqli_get_host_info($mysqli));
}
?
produces this error message:
Warning: mysqli::mysqli() [mysqli.mysqli]: [2002] A connection attempt failed
because the connected party did not (trying to connect via
tcp://localhost:3306) in C:\Apache\htdocs\mysqlconnect.php on line 3
Warning: mysqli::mysqli() [mysqli.mysqli]: (HY000/2002): A connection attempt
failed because the connected party did not properly respond after a period of
time, or established connection failed because connected host has failed to
respond. in C:\Apache\htdocs\mysqlconnect.php on line 3
Fatal error: Maximum execution time of 30 seconds exceeded in
C:\Apache\htdocs\mysqlconnect.php on line 3
I guess PHP cannot find the mysqli classes. I've checked the phpinfo()
output and discovered :
Configuration File (php.ini) Path C:\Windows
Loaded Configuration File C:\PHP\php.ini
I don't know if this ok. I've tried changing the location of the loaded
file to C:\Windows\php.ini, but to no avail, and I don't know how to change the
location of the config file.
I am obviously doing something wrong, but I don't know what. Can anyone
help?
Ironically, everything worked perfectly before I upgraded to PHP 5.3.3!
Re: Fw: [PHP] Connecting to MySql with PHP
On Tue, 2010-10-05 at 13:35 +0100, sueandant wrote:
- Original Message -
From: sueandant
To: a...@ashleysheridan.co.uk
Sent: Monday, October 04, 2010 10:29 PM
Subject: Re: [PHP] Connecting to MySql with PHP
Thanks Ash
Where do I find the PHP mysql module? I have uncommented both the
extensions php-mysql.dll and php-mysqli.dll; do I need to do more?
Just curious... BUT
Did you restart apache (or your webserver software) ?
Thanks
Tony Holland
- Original Message -
From: a...@ashleysheridan.co.uk
To: sueandant ; php-general@lists.php.net
Sent: Monday, October 04, 2010 10:21 PM
Subject: Re: [PHP] Connecting to MySql with PHP
Have you installed the php mysql module? Basically, it tells php how to
connect to mysql.
This question has come up a few times this week, have you tried installing
something like xampp or easyphp rather than the individual software
components: Apache, php mysql.
Thanks,
Ash
http://www.ashleysheridan.co.uk
- Reply message -
From: sueandant hollandsath...@tiscali.co.uk
Date: Mon, Oct 4, 2010 22:08
Subject: [PHP] Connecting to MySql with PHP
To: php-general@lists.php.net
I am running PHP 5.3.3, with Apache 2.0 Handler and MySql Server 5.1. My
OS is Vista Home Premium 32 bit with SP2.
MySql works fine from the command prompt, Apache is running and PHP works.
But I cannot access the mysqli classes. This simple program:
?php
$mysqli = new mysqli(localhost, root, ##, testDB);#I've
deliberately obliterated the password
if (mysqli_connect_errno()) {
printf(Connect failed: %s\n, mysqli_connect_error());
exit();
} else {
printf(Host information: %s\n, mysqli_get_host_info($mysqli));
}
?
produces this error message:
Warning: mysqli::mysqli() [mysqli.mysqli]: [2002] A connection attempt
failed because the connected party did not (trying to connect via
tcp://localhost:3306) in C:\Apache\htdocs\mysqlconnect.php on line 3
Warning: mysqli::mysqli() [mysqli.mysqli]: (HY000/2002): A connection
attempt failed because the connected party did not properly respond after a
period of time, or established connection failed because connected host has
failed to respond. in C:\Apache\htdocs\mysqlconnect.php on line 3
Fatal error: Maximum execution time of 30 seconds exceeded in
C:\Apache\htdocs\mysqlconnect.php on line 3
I guess PHP cannot find the mysqli classes. I've checked the phpinfo()
output and discovered :
Configuration File (php.ini) Path C:\Windows
Loaded Configuration File C:\PHP\php.ini
I don't know if this ok. I've tried changing the location of the loaded
file to C:\Windows\php.ini, but to no avail, and I don't know how to change
the location of the config file.
I am obviously doing something wrong, but I don't know what. Can anyone
help?
Ironically, everything worked perfectly before I upgraded to PHP 5.3.3!
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RE: Fw: [PHP] Connecting to MySql with PHP
-Original Message- From: Steve Staples [mailto:sstap...@mnsi.net] Sent: 05 October 2010 13:55 To: php-general Subject: Re: Fw: [PHP] Connecting to MySql with PHP On Tue, 2010-10-05 at 13:35 +0100, sueandant wrote: - Original Message - From: sueandant To: a...@ashleysheridan.co.uk Sent: Monday, October 04, 2010 10:29 PM Subject: Re: [PHP] Connecting to MySql with PHP Thanks Ash Where do I find the PHP mysql module? I have uncommented both the extensions php-mysql.dll and php-mysqli.dll; do I need to do more? Just curious... BUT Did you restart apache (or your webserver software) ? Also, did you configure the windows firewall to allow connections into the MySQL server? J -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: Fw: [PHP] Connecting to MySql with PHP
On Tue, 2010-10-05 at 14:02 +0100, Jason wrote: -Original Message- From: Steve Staples [mailto:sstap...@mnsi.net] Sent: 05 October 2010 13:55 To: php-general Subject: Re: Fw: [PHP] Connecting to MySql with PHP On Tue, 2010-10-05 at 13:35 +0100, sueandant wrote: - Original Message - From: sueandant To: a...@ashleysheridan.co.uk Sent: Monday, October 04, 2010 10:29 PM Subject: Re: [PHP] Connecting to MySql with PHP Thanks Ash Where do I find the PHP mysql module? I have uncommented both the extensions php-mysql.dll and php-mysqli.dll; do I need to do more? Just curious... BUT Did you restart apache (or your webserver software) ? Also, did you configure the windows firewall to allow connections into the MySQL server? J Jason: if you're using it via localhost, does the firewall come into play here? All: Also, the BIND-ADDRESS in the my.cnf, it may not be set properly (usually they say to comment that line out) Steve. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Re: Continuance of the struggle (trying to understand)
If I paste the script into a web page What do you mean by paste the script into a web page? Can you tell us exactly what you are doing when you do that? Chris. On Tue, Oct 5, 2010 at 7:54 AM, Col Day colind...@aol.com wrote: Hi Shreyas, Ok, as far as I can tell the script should show This is an HTML line reflecting that I am seeing the HTML part of the script followed by This is a PHP line to show that PHP is installed and working fine. If I view the script directly in IE by going to http://localhost/phptest.php I get the output: This is an HTML line This is a PHP line followed by a large and detailed list of the PHP install which includes things like compiler language etc. If I paste the script into a web page then all that is displayed is This is an HTML line. Nothing else whatsoever. I am fairly confused. I've tried a couple of different web page creators (Webplus 10 and Web page maker) and get the same result. Sorry if I sound extremely naive but it's bugging me now and I want to understand. Cheers Shreyas Agasthya shreya...@gmail.com wrote in message news:aanlkti=4ke1stf8tan7+ecjo-ux5cj=t9-0qctcfk...@mail.gmail.com... Col, Can you let us know what exactly you see when you say http://localhost:/phptest.php ? Regards, Shreyas On Tue, Oct 5, 2010 at 4:20 PM, Col Day colind...@aol.com wrote: Col Day colind...@aol.com wrote in message news:23.81.45586.2820b...@pb1.pair.com... Hi all, After my escapades with the real basics and realizing my laptop wasn't logged on as Administrator, I now am trying to work out why this script works sometimes but not others. html head titlePHP Test/title /head body pThis is an HTML line ?php echo pThis is a PHP line/p; phpinfo(); ? /body /html If I save this as phptest.php and open IE pointing it to localhost/phptest.php it works fine. Get both lines of text followed by the pages of gumpf about php. However if I paste this into a That was weird! I was saying, If I paste this into a webpage I only get the HTML line as before. Anyone have any ideas? PHP is obviously working as is apache. Just don't understand why they don't show up in web pages. Cheers again all! -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- Regards, Shreyas Agasthya -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: Fw: [PHP] Connecting to MySql with PHP
Hello, remember that for windows, you must also copy the library (libmysql.dll) to window's system32 directory in addition to un-commenting the extension=php_mysql.dll line in php.ini. Also, just in case, ensure that php.ini also has the proper extension directory set, typically c:\php\ext but depends on where you installed php. -- From: Steve Staples sstap...@mnsi.net Sent: Tuesday, October 05, 2010 9:08 AM To: 'php-general' php-general@lists.php.net Subject: RE: Fw: [PHP] Connecting to MySql with PHP On Tue, 2010-10-05 at 14:02 +0100, Jason wrote: -Original Message- From: Steve Staples [mailto:sstap...@mnsi.net] Sent: 05 October 2010 13:55 To: php-general Subject: Re: Fw: [PHP] Connecting to MySql with PHP On Tue, 2010-10-05 at 13:35 +0100, sueandant wrote: - Original Message - From: sueandant To: a...@ashleysheridan.co.uk Sent: Monday, October 04, 2010 10:29 PM Subject: Re: [PHP] Connecting to MySql with PHP Thanks Ash Where do I find the PHP mysql module? I have uncommented both the extensions php-mysql.dll and php-mysqli.dll; do I need to do more? Just curious... BUT Did you restart apache (or your webserver software) ? Also, did you configure the windows firewall to allow connections into the MySQL server? J Jason: if you're using it via localhost, does the firewall come into play here? All: Also, the BIND-ADDRESS in the my.cnf, it may not be set properly (usually they say to comment that line out) Steve. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] Re: Continuance of the struggle (trying to understand)
-Original Message- From: Col Day [mailto:colind...@aol.com] Sent: 05 October 2010 12:55 To: php-general@lists.php.net Subject: Re: [PHP] Re: Continuance of the struggle (trying to understand) Hi Shreyas, Ok, as far as I can tell the script should show This is an HTML line reflecting that I am seeing the HTML part of the script followed by This is a PHP line to show that PHP is installed and working fine. If I view the script directly in IE by going to http://localhost/phptest.php I get the output: This is an HTML line This is a PHP line followed by a large and detailed list of the PHP install which includes things like compiler language etc. If I paste the script into a web page then all that is displayed is What on earth does this mean? http://localhost/phptest.php *is* a web page -- especially as you have structured it as PHP within HTML -- so why would you want to paste the code anywhere else? I think your concepts are a little skew-whiff, and you need to explain what it is you think you're trying to do in more detail so that we can spot where it is that your understanding is wrong. Cheers! Mike -- Mike Ford, Electronic Information Developer, Libraries and Learning Innovation, Leeds Metropolitan University, C507 City Campus, Woodhouse Lane, LEEDS, LS1 3HE, United Kingdom Email: m.f...@leedsmet.ac.uk Tel: +44 113 812 4730 To view the terms under which this email is distributed, please go to http://disclaimer.leedsmet.ac.uk/email.htm -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] i wanna join
-- Ngô Xuân Huy
Re: [PHP] file_get_contents() failing on CentOS.
On Tue, Oct 5, 2010 at 6:56 AM, Richard Quadling rquadl...@gmail.comwrote: The issue _WAS_ the firewall. All sorted. Thank you. Glad he got it working. Adam -- Nephtali: PHP web framework that functions beautifully http://nephtaliproject.com
[PHP] Re: Is it possible to create a global namespace alias?
I'm assuming there is no way to make a global alias. Can anyone confirm/deny this? Matt Palermo wrote in message news:5e7b8989448b45dbbeeb6fb89b3f3...@rachet... Is it possible to create a global namespace alias in PHP or does the alias have to be defined in EVERY file that I use? Here is an example: file: main.php ?php use \this\is\my\custom\namespace\Item as nsItem; ? file: index.php ?php require_once “main.php”; // Attempt to use namespace alias defined in main.php file nsItem::test(); ? The above code doesn’t work for me. The namespace alias defined in the main.php file isn’t accessible in the index.php file. Is there a way to make the “nsItem” alias a “global” one, so that I don’t have to define it in EVERY file that I want to use? -Matt -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Re: Is it possible to create a global namespace alias?
On Tue, Oct 5, 2010 at 8:41 AM, Matt Palermo palermom...@gmail.com wrote: I'm assuming there is no way to make a global alias. Can anyone confirm/deny this? I reread the documentation on namespaces, and from what I can tell this is no way to do it. Each file maintains its own active namespace *at compile time*. This means you can't even get around it with eval() or including another script to set it. I can't say I'm positive someone won't find a way around it, but short of an extension I don't see one. David
Re: [PHP] Re: Continuance of the struggle (trying to understand)
At 12:54 PM +0100 10/5/10, Col Day wrote: Hi Shreyas, Ok, as far as I can tell the script should show This is an HTML line reflecting that I am seeing the HTML part of the script followed by This is a PHP line to show that PHP is installed and working fine. Col: Do this: 1. Create a file and entitle it index.php (without quotes) 2. Enter ?php phpinfo();? (without quotes) 3. Save the file. 4. Upload the file to your host. 5. Open a browser and enter the url (i.e., http://yourdomain.com/index.php) What do you see? Cheers, tedd -- --- http://sperling.com/ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Re: Continuance of the struggle (trying to understand)
At 1:56 PM -0400 10/5/10, tedd wrote: At 12:54 PM +0100 10/5/10, Col Day wrote: Hi Shreyas, Ok, as far as I can tell the script should show This is an HTML line reflecting that I am seeing the HTML part of the script followed by This is a PHP line to show that PHP is installed and working fine. Col: Do this: 1. Create a file and entitle it index.php (without quotes) 2. Enter ?php phpinfo();? (without quotes) 3. Save the file. 4. Upload the file to your host. 5. Open a browser and enter the url (i.e., http://yourdomain.com/index.php) What do you see? Cheers, tedd Col: You don't have to tell what you see, but rather do you see anything? Cheers, tedd -- --- http://sperling.com/ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Re: Continuance of the struggle (trying to understand)
On Tue, 2010-10-05 at 14:32 -0400, tedd wrote: At 1:56 PM -0400 10/5/10, tedd wrote: At 12:54 PM +0100 10/5/10, Col Day wrote: Hi Shreyas, Ok, as far as I can tell the script should show This is an HTML line reflecting that I am seeing the HTML part of the script followed by This is a PHP line to show that PHP is installed and working fine. Col: Do this: 1. Create a file and entitle it index.php (without quotes) 2. Enter ?php phpinfo();? (without quotes) 3. Save the file. 4. Upload the file to your host. 5. Open a browser and enter the url (i.e., http://yourdomain.com/index.php) What do you see? Cheers, tedd Col: You don't have to tell what you see, but rather do you see anything? Cheers, tedd -- --- http://sperling.com/ Tedd: He is working off his localhost, running on vista... so what it seems (to me at least) is that he is getting the php to work when he uses the localhost, but when he tries to open a php file from say his desktop, he doesn't see the php stuff... which is exactly as designed since running form your desktop, php does not execute the code... i am guessing that he just needs to use his localhost directory. Steve. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] which one is faster
$a = 'hey'; $b = 'done'; $c = $a.$b; $c = $a$b; which one is faster for echo $c.
Re: [PHP] which one is faster
Benchmark and find out! :) What are you using this for? Unless you are doing something crazy it probably doesn't matter, and you should pick whichever you feel looks nicer / is easier to code in / etc. Chris H. On Tue, Oct 5, 2010 at 3:23 PM, saeed ahmed saeed@gmail.com wrote: $a = 'hey'; $b = 'done'; $c = $a.$b; $c = $a$b; which one is faster for echo $c.
Re: [PHP] which one is faster
On Tue, 2010-10-05 at 15:28 -0400, chris h wrote: Benchmark and find out! :) What are you using this for? Unless you are doing something crazy it probably doesn't matter, and you should pick whichever you feel looks nicer / is easier to code in / etc. Chris H. On Tue, Oct 5, 2010 at 3:23 PM, saeed ahmed saeed@gmail.com wrote: $a = 'hey'; $b = 'done'; $c = $a.$b; $c = $a$b; which one is faster for echo $c. As far as I'm aware, the first of the two will be faster, but only just. As Saeed mentioned, the difference will be negligible, and unless you plan to run a line like that in a loop or something hundreds of thousands of times, you probably won't notice any difference. Thanks, Ash http://www.ashleysheridan.co.uk
Re: [PHP] which one is faster
Saeed here's a quick (and dirty) test I ran:
$tests = 100;
$start = microtime(true);
for ($i=0; $i$tests; $i++) {
$a = md5( rand() );
$b = md5( rand() );
$c = $a.$b;
}
var_dump( By concat op:\t. (microtime(true) - $start) );
$start = microtime(true);
for ($i=0; $i$tests; $i++) {
$a = md5( rand() );
$b = md5( rand() );
$c = $a$b;
}
var_dump( By string:\t\t. (microtime(true) - $start) );
Sample results:
string(30) By concat op: 2.1713118553162
string(27) By string: 2.2525599002838
string(30) By concat op: 2.2123351097107
string(27) By string: 2.2798750400543
string(29) By concat op: 2.1521489620209
string(27) By string: 2.2470209598541
string(29) By concat op: 2.1347990036011
string(27) By string: 2.1982681751251
I would say that under virtually all cases that difference is less
then negligible.
Chris H.
On Tue, Oct 5, 2010 at 3:35 PM, Ashley Sheridan
a...@ashleysheridan.co.ukwrote:
On Tue, 2010-10-05 at 15:28 -0400, chris h wrote:
Benchmark and find out! :)
What are you using this for? Unless you are doing something crazy it
probably doesn't matter, and you should pick whichever you feel looks nicer
/ is easier to code in / etc.
Chris H.
On Tue, Oct 5, 2010 at 3:23 PM, saeed ahmed saeed@gmail.com wrote:
$a = 'hey';
$b = 'done';
$c = $a.$b;
$c = $a$b;
which one is faster for echo $c.
As far as I'm aware, the first of the two will be faster, but only just. As
Saeed mentioned, the difference will be negligible, and unless you plan to
run a line like that in a loop or something hundreds of thousands of times,
you probably won't notice any difference.
Thanks,
Ash
http://www.ashleysheridan.co.uk
Re: [PHP] which one is faster
On Tue, 2010-10-05 at 20:35 +0100, Ashley Sheridan wrote:
On Tue, 2010-10-05 at 15:28 -0400, chris h wrote:
Benchmark and find out! :)
What are you using this for? Unless you are doing something crazy it
probably doesn't matter, and you should pick whichever you feel looks nicer
/ is easier to code in / etc.
Chris H.
On Tue, Oct 5, 2010 at 3:23 PM, saeed ahmed saeed@gmail.com wrote:
$a = 'hey';
$b = 'done';
$c = $a.$b;
$c = $a$b;
which one is faster for echo $c.
As far as I'm aware, the first of the two will be faster, but only just.
As Saeed mentioned, the difference will be negligible, and unless you
plan to run a line like that in a loop or something hundreds of
thousands of times, you probably won't notice any difference.
Thanks,
Ash
http://www.ashleysheridan.co.uk
to be proper, shouldn't it technically be
$c = {$a}{$b};
??
Steve.
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[PHP] Variable (Class instantiation) collision
I am running into a variable collision. The project I'm developing is NOT guaranteed to be operating on PHP5. Any solution I find should (hopefully) be able to run on PHP4 (yes, I know PHP4 is deprecated). I am building a bridge between two third-party applications. Both instantiate their respective database class assigning it to $db and I cannot change that. So, I am interested in solutions to this. I found a reference to a Packager class and will be looking at it shortly. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] which one is faster
On Tue, 2010-10-05 at 15:46 -0400, Steve Staples wrote:
On Tue, 2010-10-05 at 20:35 +0100, Ashley Sheridan wrote:
On Tue, 2010-10-05 at 15:28 -0400, chris h wrote:
Benchmark and find out! :)
What are you using this for? Unless you are doing something crazy it
probably doesn't matter, and you should pick whichever you feel looks
nicer
/ is easier to code in / etc.
Chris H.
On Tue, Oct 5, 2010 at 3:23 PM, saeed ahmed saeed@gmail.com wrote:
$a = 'hey';
$b = 'done';
$c = $a.$b;
$c = $a$b;
which one is faster for echo $c.
As far as I'm aware, the first of the two will be faster, but only just.
As Saeed mentioned, the difference will be negligible, and unless you
plan to run a line like that in a loop or something hundreds of
thousands of times, you probably won't notice any difference.
Thanks,
Ash
http://www.ashleysheridan.co.uk
to be proper, shouldn't it technically be
$c = {$a}{$b};
??
Steve.
It doesn't have to use the braces. The braces only tell PHP exactly
where to stop parsing the current variable name. The following examples
wouldn't work without them:
$var = 'hello ';
$arr = array('msg 1'='hello','msg 2'='world');
echo {$var}world;
echo {$arr['msg 1']}{$arr['msg 2']};
Without the braces, in the first example PHP would look for a variable
called $varworld, and in the second it would be looking for a simple
scaler called $arr, not the array value you wanted.
Thanks,
Ash
http://www.ashleysheridan.co.uk
Re: [PHP] which one is faster
On Tue, Oct 5, 2010 at 3:53 PM, Ashley Sheridan
a...@ashleysheridan.co.ukwrote:
On Tue, 2010-10-05 at 15:46 -0400, Steve Staples wrote:
On Tue, 2010-10-05 at 20:35 +0100, Ashley Sheridan wrote:
On Tue, 2010-10-05 at 15:28 -0400, chris h wrote:
Benchmark and find out! :)
What are you using this for? Unless you are doing something crazy it
probably doesn't matter, and you should pick whichever you feel looks
nicer
/ is easier to code in / etc.
Chris H.
On Tue, Oct 5, 2010 at 3:23 PM, saeed ahmed saeed@gmail.com
wrote:
$a = 'hey';
$b = 'done';
$c = $a.$b;
$c = $a$b;
which one is faster for echo $c.
As far as I'm aware, the first of the two will be faster, but only
just.
As Saeed mentioned, the difference will be negligible, and unless you
plan to run a line like that in a loop or something hundreds of
thousands of times, you probably won't notice any difference.
Thanks,
Ash
http://www.ashleysheridan.co.uk
to be proper, shouldn't it technically be
$c = {$a}{$b};
??
Steve.
It doesn't have to use the braces. The braces only tell PHP exactly
where to stop parsing the current variable name. The following examples
wouldn't work without them:
$var = 'hello ';
$arr = array('msg 1'='hello','msg 2'='world');
echo {$var}world;
echo {$arr['msg 1']}{$arr['msg 2']};
Without the braces, in the first example PHP would look for a variable
called $varworld, and in the second it would be looking for a simple
scaler called $arr, not the array value you wanted.
Thanks,
Ash
http://www.ashleysheridan.co.uk
Just to add in here, they are also required when calling an object's
properties, if - ready for this? - that object is itself a property of
another object.
so while this would work,
$circle-circumference
this would NOT work
$circle-circumference-inches
The later would be injecting the $circle-circumference property, followed
by string literal -inches. So to get it to work you would need to use
curlys.
{$circle-circumference-inches}
Chris H.
Re: [PHP] which one is faster
On Oct 5, 2010, at 3:23 PM, saeed ahmed wrote: $a = 'hey'; $b = 'done'; $c = $a.$b; $c = $a$b; which one is faster for echo $c. Depends upon the platform its running on. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] which one is faster
On Tue, 2010-10-05 at 20:53 +0100, Ashley Sheridan wrote:
On Tue, 2010-10-05 at 15:46 -0400, Steve Staples wrote:
On Tue, 2010-10-05 at 20:35 +0100, Ashley Sheridan wrote:
On Tue, 2010-10-05 at 15:28 -0400, chris h wrote:
Benchmark and find out! :)
What are you using this for? Unless you are doing something crazy it
probably doesn't matter, and you should pick whichever you feel looks
nicer
/ is easier to code in / etc.
Chris H.
On Tue, Oct 5, 2010 at 3:23 PM, saeed ahmed saeed@gmail.com wrote:
$a = 'hey';
$b = 'done';
$c = $a.$b;
$c = $a$b;
which one is faster for echo $c.
As far as I'm aware, the first of the two will be faster, but only just.
As Saeed mentioned, the difference will be negligible, and unless you
plan to run a line like that in a loop or something hundreds of
thousands of times, you probably won't notice any difference.
Thanks,
Ash
http://www.ashleysheridan.co.uk
to be proper, shouldn't it technically be
$c = {$a}{$b};
??
Steve.
It doesn't have to use the braces. The braces only tell PHP exactly
where to stop parsing the current variable name. The following examples
wouldn't work without them:
$var = 'hello ';
$arr = array('msg 1'='hello','msg 2'='world');
echo {$var}world;
echo {$arr['msg 1']}{$arr['msg 2']};
Without the braces, in the first example PHP would look for a variable
called $varworld, and in the second it would be looking for a simple
scaler called $arr, not the array value you wanted.
Thanks,
Ash
http://www.ashleysheridan.co.uk
Ash:
I understand what the {} does, but just like in HTML, it is more proper
to use lower case for the attributes/elements, and use (double quotes)
when wrapping the attributes... but is it not REQUIRED to write it in
that manner... just like it is not required to wrap the variables in {}
when inside the ...
that's just me, I tend to try and do that every time...
Steve.
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Re: [PHP] Variable (Class instantiation) collision
Just to clarify, both packages are instantiating and calling their respective database classes from the $db var, which is in the global scope. Is this correct? This is why I hate the global scope, I hate it, I hate it! On Tue, Oct 5, 2010 at 3:47 PM, Brian Smither bhsmit...@gmail.com wrote: I am running into a variable collision. The project I'm developing is NOT guaranteed to be operating on PHP5. Any solution I find should (hopefully) be able to run on PHP4 (yes, I know PHP4 is deprecated). I am building a bridge between two third-party applications. Both instantiate their respective database class assigning it to $db and I cannot change that. So, I am interested in solutions to this. I found a reference to a Packager class and will be looking at it shortly. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] which one is faster
On Tue, 2010-10-05 at 15:58 -0400, Steve Staples wrote:
On Tue, 2010-10-05 at 20:53 +0100, Ashley Sheridan wrote:
On Tue, 2010-10-05 at 15:46 -0400, Steve Staples wrote:
On Tue, 2010-10-05 at 20:35 +0100, Ashley Sheridan wrote:
On Tue, 2010-10-05 at 15:28 -0400, chris h wrote:
Benchmark and find out! :)
What are you using this for? Unless you are doing something crazy it
probably doesn't matter, and you should pick whichever you feel looks
nicer
/ is easier to code in / etc.
Chris H.
On Tue, Oct 5, 2010 at 3:23 PM, saeed ahmed saeed@gmail.com
wrote:
$a = 'hey';
$b = 'done';
$c = $a.$b;
$c = $a$b;
which one is faster for echo $c.
As far as I'm aware, the first of the two will be faster, but only just.
As Saeed mentioned, the difference will be negligible, and unless you
plan to run a line like that in a loop or something hundreds of
thousands of times, you probably won't notice any difference.
Thanks,
Ash
http://www.ashleysheridan.co.uk
to be proper, shouldn't it technically be
$c = {$a}{$b};
??
Steve.
It doesn't have to use the braces. The braces only tell PHP exactly
where to stop parsing the current variable name. The following examples
wouldn't work without them:
$var = 'hello ';
$arr = array('msg 1'='hello','msg 2'='world');
echo {$var}world;
echo {$arr['msg 1']}{$arr['msg 2']};
Without the braces, in the first example PHP would look for a variable
called $varworld, and in the second it would be looking for a simple
scaler called $arr, not the array value you wanted.
Thanks,
Ash
http://www.ashleysheridan.co.uk
Ash:
I understand what the {} does, but just like in HTML, it is more proper
to use lower case for the attributes/elements, and use (double quotes)
when wrapping the attributes... but is it not REQUIRED to write it in
that manner... just like it is not required to wrap the variables in {}
when inside the ...
that's just me, I tend to try and do that every time...
Steve.
Not really, it's no more proper than the difference between:
echo 'text' . $var;
or
echo text$var;
And in some cases, it is required. It is down to preference if you use
them when you don't have to, but personally I'd avoid typing what is
essentially useless fluff.
Thanks,
Ash
http://www.ashleysheridan.co.uk
Re: [PHP] which one is faster
On Tue, Oct 5, 2010 at 3:58 PM, Steve Staples sstap...@mnsi.net wrote:
On Tue, 2010-10-05 at 20:53 +0100, Ashley Sheridan wrote:
On Tue, 2010-10-05 at 15:46 -0400, Steve Staples wrote:
On Tue, 2010-10-05 at 20:35 +0100, Ashley Sheridan wrote:
On Tue, 2010-10-05 at 15:28 -0400, chris h wrote:
Benchmark and find out! :)
What are you using this for? Unless you are doing something crazy
it
probably doesn't matter, and you should pick whichever you feel
looks nicer
/ is easier to code in / etc.
Chris H.
On Tue, Oct 5, 2010 at 3:23 PM, saeed ahmed saeed@gmail.com
wrote:
$a = 'hey';
$b = 'done';
$c = $a.$b;
$c = $a$b;
which one is faster for echo $c.
As far as I'm aware, the first of the two will be faster, but only
just.
As Saeed mentioned, the difference will be negligible, and unless you
plan to run a line like that in a loop or something hundreds of
thousands of times, you probably won't notice any difference.
Thanks,
Ash
http://www.ashleysheridan.co.uk
to be proper, shouldn't it technically be
$c = {$a}{$b};
??
Steve.
It doesn't have to use the braces. The braces only tell PHP exactly
where to stop parsing the current variable name. The following examples
wouldn't work without them:
$var = 'hello ';
$arr = array('msg 1'='hello','msg 2'='world');
echo {$var}world;
echo {$arr['msg 1']}{$arr['msg 2']};
Without the braces, in the first example PHP would look for a variable
called $varworld, and in the second it would be looking for a simple
scaler called $arr, not the array value you wanted.
Thanks,
Ash
http://www.ashleysheridan.co.uk
Ash:
I understand what the {} does, but just like in HTML, it is more proper
to use lower case for the attributes/elements, and use (double quotes)
when wrapping the attributes... but is it not REQUIRED to write it in
that manner... just like it is not required to wrap the variables in {}
when inside the ...
that's just me, I tend to try and do that every time...
Steve.
Unlike HTML, PHP interpretation doesn't have various browsers to contend
with. And even if it was not proper I have a doubt that not using {} would
become deprecated anytime soon.
Also laziness is a trait of a good programmer! :)
http://c2.com/cgi/wiki?LazinessImpatienceHubris
Chris H.
[PHP] Re: which one is faster
As I can see, it´d be too much faster to decide by yourself than reading all theese answers and understanding their differences and taking people´s time for nothing. -- João Cândido de Souza Neto saeed ahmed saeed@gmail.com escreveu na mensagem news:aanlktikh6g5ilsz3hkxatg=h1wzobgoko7byngo0p...@mail.gmail.com... $a = 'hey'; $b = 'done'; $c = $a.$b; $c = $a$b; which one is faster for echo $c. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Variable (Class instantiation) collision
Just to clarify, both packages are instantiating and calling their
respective classes from the $db var, which is in the global scope.
Is this correct?
I would say yes to the way you are asking. Take the following two applications.
The four respective statements are in each their respective script.
Application A:
?php
class foo {}
$db = new foo();
$outA = barA();
function barA() { global $db; include(Application B); }
?
Application B:
?php
class bar {}
$db = new bar();
$outB = barB();
function barB() { global $db; }
?
The bridge project is operating in A and include()'ing the script that is B (as
I have not found an API for B). $db in B is colliding with $db in A.
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Re: [PHP] Variable (Class instantiation) collision
Short of refactoring ApplicationB, can you set it up as a SOAP/REST service
that AppA calls?
On Tue, Oct 5, 2010 at 5:02 PM, Brian Smither bhsmit...@gmail.com wrote:
Just to clarify, both packages are instantiating and calling their
respective classes from the $db var, which is in the global scope.
Is this correct?
I would say yes to the way you are asking. Take the following two
applications. The four respective statements are in each their respective
script.
Application A:
?php
class foo {}
$db = new foo();
$outA = barA();
function barA() { global $db; include(Application B); }
?
Application B:
?php
class bar {}
$db = new bar();
$outB = barB();
function barB() { global $db; }
?
The bridge project is operating in A and include()'ing the script that is B
(as I have not found an API for B). $db in B is colliding with $db in A.
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Re: [PHP] Variable (Class instantiation) collision
If you have total control over application A which contains the bridge code,
the easiest is to change it to use a different global variable, $dbA. This
must not be doable or you wouldn't have asked.
If you have control over the bridge code, and it alone calls A and B, then
you could swap the $db variables between calls:
$db = null;
$dbA = null;
$dbB = null;
function copyPersons() {
useA();
$persons = loadPersonsFromA();
useB();
savePersonsInB($persons);
}
function connect() {
global $db, $dbA, $dbB;
connectToA();
$dbA = $db;
unset($db);
connectToB();
$dbB = $db;
unset($db);
}
function useA() {
global $db, $dbA;
$db = $dbA;
}
function useB() {
global $db, $dbB;
$db = $dbB;
}
This is the simplest implementation. You could get trickier by tracking
which system is in use and only swapping them as-needed, writing a facade
around the APIs to A and B. It's ugly, but it works.
David
