Re: [PHP] Making thumbs same size
Morning :o)
This is what I am using
--- SNIP
?php
// The file
$filename = $_GET['filename'];
$file = $_GET['filename'];
$target_path= ../_images/news/;
$filename = $target_path.$filename;
// Set a maximum height and width
$width = 250;
$height = 250;
// Content type
header('Content-type: image/jpeg');
// Get new dimensions
list($width_orig, $height_orig) = getimagesize($filename);
$ratio_orig = $width_orig/$height_orig;
if ($width/$height $ratio_orig) {
$width = $height*$ratio_orig;
} else {
$height = $width/$ratio_orig;
}
// Resample
$image_p = imagecreatetruecolor($width, $height);
$image = imagecreatefromjpeg($filename);
$dest_path = ../_images/news/;
imagecopyresampled($image_p, $image, 0, 0, 0, 0, $width, $height,
$width_orig, $height_orig);
$dest_file = $dest_path.thumb_.$file;
// Output
imagejpeg($image_p, $dest_file, 100);
?
- SNAP ---
If I read it now, I must admit that it might be hard to understand (even I
am having a hard time reading it... I guess there is some useless stuff in
there, too)... but I haven't had coffee yet, so I might be able to explain
that stuff to you a bot late. But maybe this code example does help you...
if not, please ask. :o) I will try my best then ... hopefully you just
needed the calculation part :oP
Cheerio mate
Chris
- Original Message -
From: Humani Power [EMAIL PROTECTED]
To: php-general@lists.php.net
Sent: Monday, June 04, 2007 8:44 AM
Subject: [PHP] Making thumbs same size
Hey hi!!.
I have a few pages that uploads images to the apache server and makes a
registry on a mysql database. Everything is going well just for a few
details.
When I make the upload for an image, it creates me a thumb image, but not
as
I want. For example, if I have an image that its of 2000 x 2000 px, the
thumb created is 200 x 200, If I upload another with 300x300 px, my thumb
will be 30x30 px, making look the gallery pretty bad. The only thing that
I
need is that all my thumbs were on the same size.
I've tried to modify the thumb width and height size, but doesnt work..
Probably I am not undersatnding hoy to use the resampling() tool.
here is my code.
?php
include(connection.php);
//make variables avaliable
$image_caption = $_POST['image_caption'];
$image_username = $_POST['image_username'];
$image_tempname = $_FILES['image_filename']['name'];
$image_date = date($_POST['image_date']);
$today= date(Y-m-d);
//upload image and check for image type
$ImageDir=/var/www/apache2-default/images/;
$Imagethumb=$ImageDir.thumbs/;
$ImageName=$ImageDir . $image_tempname;
if (move_uploaded_file($_FILES['image_filename']['tmp_name'],
$ImageName)) {
//get info about the image being uploaded
list($width, $height, $type, $attr)= getimagesize($ImageName);
//insert info into the table
$insert= insert into rsiis_images
(image_caption,image_username,image_date,image_date_upload)
values
('$image_caption','$image_username','$image_date','$today');
$insertresults=mysql_query($insert)
or die(mysql_error());
$lastpicid=mysql_insert_id();
$newfilename=$ImageDir . $lastpicid ..jpg;
if($type==2){
rename($ImageName, $newfilename);
} else {
if ($type==1){
$image_old=imagecreatefromgif($ImageName);
}elseif ($type==3){
$image_old=imagecreatefrompng($ImageName);
}
//convert the image to JPG
$image_jpg=imagecreatetruecolor($width,$height);
imagecopyresampled($image_jpg,$image_old, 0, 0, 0, 0, $width,
$height,$width,$height);
imagejpeg($image_jpg,$newfilename);
imagedestroy($image_old);
imagedestroy($image_jpg);
}
$newthumbname=$Imagethumb.$lastpicid..jpg;
//get dimensions of the thumbnail
$thumb_width=$width*0.10;
$thumb_height=$height*.10;
//Create thumbnail
$largeimage=imagecreatefromjpeg($newfilename);
$thumb=imagecreatetruecolor($thumb_width,$thumb_height);
imagecopy($thumb, $largeimage, 0, 0, 0, 0,$width,$height);
imagecopyresampled($thumb, $largeimage, 0, 0, 0, 0,
$thumb_width,$thumb_height,$width,$height);
imagejpeg($thumb,$newthumbname);
imagedestroy($largeimage);
imagedestroy($thumb);
$url=location:showimage.php?id=.$lastpicid;
header($url);
}
?
thanks for your help
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Re: [PHP] Database error: Invalid SQL:
Usually you need to specify the type: inner join, left join, right join, straight join etc. OTThat sounds like the good old times when we did air-to-air refueling :oP /OT Sorry, had to :P - Original Message - From: Chris [EMAIL PROTECTED] To: wisuttorn [EMAIL PROTECTED] Cc: php-general@lists.php.net Sent: Thursday, May 24, 2007 7:34 AM Subject: Re: [PHP] Database error: Invalid SQL: wisuttorn wrote: I have a problem please help me when i loged in to egroup this show Database error: Invalid SQL: SELECT DISTINCT egw_cal_repeats.*,egw_cal.*,cal_start,cal_end,cal_recur_date FROM egw_cal JOIN egw_cal_dates ON egw_cal.cal_id=egw_cal_dates.cal_id JOIN egw_cal_user ON egw_cal.cal_id=egw_cal_user.cal_id LEFT JOIN egw_cal_repeats ON egw_cal.cal_id=egw_cal_repeats.cal_id WHERE (cal_user_type='u' AND cal_user_id IN (6,-1)) AND cal_status != 'R' AND 1179939600 cal_end AND cal_start 1180025999 AND (recur_type IS NULL AND cal_recur_date=0 OR cal_recur_date=cal_start) ORDER BY cal_start mysql Error: 1064 (You have an error in your SQL syntax near 'ON egw_cal.cal_id=egw_cal_dates.cal_id JOIN egw_cal_user ON egw_cal.cal_id=egw_c' at line 1) I guess that whatever database you are using doesn't allow 'JOIN' as a join type. Usually you need to specify the type: inner join, left join, right join, straight join etc. Ask your specific database list about it. -- Postgresql php tutorials http://www.designmagick.com/ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Project Management
Morning guys, this is not exactly a PHP question, but as I am sure that I am talking to more or less professional developers, I thought I might ask you. As I am working on some... well, for my standards... huge project, I thought that some kind of project management software would / could be helpful to keep track of my ideas, tasks and so on. Right now I am using a huge chunk of papers to keep track (as good as I can). Has any of you any experience with good project management software? Best would be OpenSource, of course :o) My boss doesn't want to spend a lot of money ;o) Cheers guys, Chris from sunny germany -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Project Management
Hi Edward, thanks for your comment. I use a lab book too... And already fille two of them in the last 8 weeks I just wanna use the project management thing to collect my ideas, and write a howto for future generation developers who may have to deal with this thing once I am gone. Stut, yes sir, I've used google and had a look at those things. What I wanted was to know what you guys use. There is nothing more valuable than the opinions of other developers and to know what they use in their day to day job. Anyhow, my arse is still on... so I better bugger off :oP Cheers for your comments! Chris - Original Message - From: Edward Kay [EMAIL PROTECTED] To: php-general@lists.php.net Sent: Thursday, May 24, 2007 12:00 PM Subject: RE: [PHP] Project Management -Original Message- From: Christian Haensel [mailto:[EMAIL PROTECTED] Sent: 24 May 2007 10:27 To: php-general@lists.php.net Subject: [PHP] Project Management Morning guys, this is not exactly a PHP question, but as I am sure that I am talking to more or less professional developers, I thought I might ask you. As I am working on some... well, for my standards... huge project, I thought that some kind of project management software would / could be helpful to keep track of my ideas, tasks and so on. Right now I am using a huge chunk of papers to keep track (as good as I can). Has any of you any experience with good project management software? Best would be OpenSource, of course :o) My boss doesn't want to spend a lot of money ;o) Cheers guys, Chris from sunny germany If you're working on your own, I would think realistically about how much you would use such software. I've used Basecamp, Trac, MS Project and others in the past and find them a waste of time. My favourite tool is simply an A4 lab book. (I know this doesn't scale, but it fits the bill perfectly for now). For initial brainstorming/idea tracking, I do use FreeMind though. http://freemind.sf.net HTH, Edward -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] PHP MySQL Problem
Good morning friends, I have a script that collects data from a form and puts together a mysql query to search a database. Now, everything worked fine until I added a few new form fields... now the $_POST['var'] don't reach the script... I have about 20 to 25 form fields which are all taken into the query... Now my question: is there a limit in the fields that I can use in the query string to query the database? Somehow the script doesn't even output the value of the POST data anymore... been using this stuff for years now, and i'm feeling really silly at the moment. I'd appreciate any help. Cheers! Chris -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] PHP MySQL Problem
Right, here we go... this page has about 1000 lines of code, so here the
relevant stuff.
$s_query = SELECT * FROM database WHERE
kategorie LIKE '$s_cat' AND
marke LIKE '$s_marke' AND
leistung_kw = '$kw_von' AND leistung_kw = '$kw_bis' AND
preis = '$s_preis_von' AND
preis = '$s_preis_bis'.$checkboxes.$sort_str;
I get the $checkboxes from the POST checkboxes, which looks like this (an
example):
$kraftstoffart = $_POST['fueltype'];
if($kraftstoffart == 3) {
$checkboxes .= ;
}elseif($kraftstoffart == 2) {
$checkboxes .= AND kraftstoffart = '2';
}elseif($kraftstoffart == 1) {
$checkboxes .= AND kraftstoffart = '1';
}
and the $sort_str comes in like
$sort_by = $_POST['sort_by'];
$desc_asc = $_POST['desc_asc'];
$sort_str = ORDER BY .$sort_by. .$desc_asc;
The query then just goes like
$do_q = mysql_query($s_query) or die(mysql_error());
and that's it... no errors shown, just the regular output which I had
before I put the new fields in there. So no changes to what I've had
before... but there should be changes *g*
I hope anybody can find some sense in what I'm writing here... hardly makes
sense to me :oP
Cheers!
- Original Message -
From: Zoltán Németh [EMAIL PROTECTED]
To: Christian Haensel [EMAIL PROTECTED]
Cc: php-general@lists.php.net
Sent: Monday, May 21, 2007 9:36 AM
Subject: Re: [PHP] PHP MySQL Problem
2007. 05. 21, hétfő keltezéssel 09.26-kor Christian Haensel ezt írta:
Good morning friends,
I have a script that collects data from a form and puts together a mysql
query to search a database.
Now, everything worked fine until I added a few new form fields... now
the
$_POST['var'] don't reach the script...
I have about 20 to 25 form fields which are all taken into the query...
Now my question: is there a limit in the fields that I can use in the
query
string to query the database? Somehow the script doesn't even output the
value of the POST data anymore... been using this stuff for years now,
and
i'm feeling really silly at the moment.
AFAIK there is no limit in the number of fields in a query...
post some code please, otherwise I don't think anyone will be able to
help you
greets
Zoltán Németh
I'd appreciate any help.
Cheers!
Chris
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Re: [PHP] PHP MySQL Problem
I thought so, too. But the part where it receives the data is this:
$s_marke = $_POST['marke'];
$s_modell = $_POST['modell'];
$s_preis_von = $_POST['preis_von'];
$s_preis_bis = $_POST['preis_bis'];
$s_mileage_von = $_POST['mileage_from'];
$s_mileage_bis = $_POST['mileage_to'];
$s_ez_von = $_POST['ez_from'];
$s_ez_bis = $_POST['ez_bis'];
$s_search_text = $_POST['search_text'];
$s_cat = $_POST['cat'];
$kw_von = $_POST['kw_von'];
$kw_bis = $_POST['kw_bis'];
(part of it)
And this is the relevant part of the form
select name=kw_von
option selected=selected value=0***/option
option value=/60/option
option value=/75/option
option value=/90/option
option value=8181/110/option
option value=9292/125/option
option value=110110/150/option
option value=147147/200/option
option value=184184/250/option
option value=220220/300/option
option value=257257/350/option
/select
The funny thing is that all vars are being received except for the last two:
$kw_von = $_POST['kw_von'];
$kw_bis = $_POST['kw_bis'];
I am s stuck here, it ain't even funny anymore *g* And my boss is, of
course, waiting for a result. Howcome people don't get that programming
sometimes really IS leaning back and closing your eyes *gr* :oP
Thanks for trying to help me :o)
Chris
- Original Message -
From: Zoltán Németh [EMAIL PROTECTED]
To: Christian Haensel [EMAIL PROTECTED]
Cc: php-general@lists.php.net
Sent: Monday, May 21, 2007 9:58 AM
Subject: Re: [PHP] PHP MySQL Problem
2007. 05. 21, hétfő keltezéssel 09.43-kor Christian Haensel ezt írta:
Right, here we go... this page has about 1000 lines of code, so here the
relevant stuff.
$s_query = SELECT * FROM database WHERE
kategorie LIKE '$s_cat' AND
marke LIKE '$s_marke' AND
leistung_kw = '$kw_von' AND leistung_kw = '$kw_bis' AND
preis = '$s_preis_von' AND
preis = '$s_preis_bis'.$checkboxes.$sort_str;
I get the $checkboxes from the POST checkboxes, which looks like this (an
example):
$kraftstoffart = $_POST['fueltype'];
if($kraftstoffart == 3) {
$checkboxes .= ;
}elseif($kraftstoffart == 2) {
$checkboxes .= AND kraftstoffart = '2';
}elseif($kraftstoffart == 1) {
$checkboxes .= AND kraftstoffart = '1';
}
and the $sort_str comes in like
$sort_by = $_POST['sort_by'];
$desc_asc = $_POST['desc_asc'];
$sort_str = ORDER BY .$sort_by. .$desc_asc;
The query then just goes like
$do_q = mysql_query($s_query) or die(mysql_error());
and that's it... no errors shown, just the regular output which I had
before I put the new fields in there. So no changes to what I've had
before... but there should be changes *g*
actually there seems to be no problem with your query (besides that you
should check posted values first in order to avoid SQL injection)
you said in your first letter that $_POST['var'] don't reach the
script - I would guess the relevant part is not the query but rather
the form itself...
greets
Zoltán Németh
I hope anybody can find some sense in what I'm writing here... hardly
makes
sense to me :oP
Cheers!
- Original Message -
From: Zoltán Németh [EMAIL PROTECTED]
To: Christian Haensel [EMAIL PROTECTED]
Cc: php-general@lists.php.net
Sent: Monday, May 21, 2007 9:36 AM
Subject: Re: [PHP] PHP MySQL Problem
2007. 05. 21, hétfő keltezéssel 09.26-kor Christian Haensel ezt írta:
Good morning friends,
I have a script that collects data from a form and puts together a
mysql
query to search a database.
Now, everything worked fine until I added a few new form fields... now
the
$_POST['var'] don't reach the script...
I have about 20 to 25 form fields which are all taken into the
query...
Now my question: is there a limit in the fields that I can use in the
query
string to query the database? Somehow the script doesn't even output
the
value of the POST data anymore... been using this stuff for years now,
and
i'm feeling really silly at the moment.
AFAIK there is no limit in the number of fields in a query...
post some code please, otherwise I don't think anyone will be able to
help you
greets
Zoltán Németh
I'd appreciate any help.
Cheers!
Chris
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Re: [PHP] PHP MySQL Problem
Guys
nevermind... stupid moron that I am I put a hidden action in the form whích
I totally (!!) forgot... All my code is fine so far, and all is working
perfectly... now that bloddy thing cost me 3 DAYS of work... sometimes I
wonder if I should rather sell shoes than calling myself a webdeveloper and
work at that job all day long... geez!
Anyhow, thanks for your help guys... time for Aspirin over here... laterz!
Chris
- Original Message -
From: Zoltán Németh [EMAIL PROTECTED]
To: Christian Haensel [EMAIL PROTECTED]
Cc: php-general@lists.php.net
Sent: Monday, May 21, 2007 10:16 AM
Subject: Re: [PHP] PHP MySQL Problem
2007. 05. 21, hétfő keltezéssel 10.04-kor Christian Haensel ezt írta:
I thought so, too. But the part where it receives the data is this:
$s_marke = $_POST['marke'];
$s_modell = $_POST['modell'];
$s_preis_von = $_POST['preis_von'];
$s_preis_bis = $_POST['preis_bis'];
$s_mileage_von = $_POST['mileage_from'];
$s_mileage_bis = $_POST['mileage_to'];
$s_ez_von = $_POST['ez_from'];
$s_ez_bis = $_POST['ez_bis'];
$s_search_text = $_POST['search_text'];
$s_cat = $_POST['cat'];
$kw_von = $_POST['kw_von'];
$kw_bis = $_POST['kw_bis'];
(part of it)
And this is the relevant part of the form
select name=kw_von
option selected=selected value=0***/option
option value=/60/option
option value=/75/option
option value=/90/option
option value=8181/110/option
option value=9292/125/option
option value=110110/150/option
option value=147147/200/option
option value=184184/250/option
option value=220220/300/option
option value=257257/350/option
/select
The funny thing is that all vars are being received except for the last
two:
$kw_von = $_POST['kw_von'];
$kw_bis = $_POST['kw_bis'];
and if you do a var_dump($_POST) what do you get?
are these values not showing up at all?
if so, then you should check whether they are within the form and
/form tags... I made that mistake once...
greets
Zoltán Németh
I am s stuck here, it ain't even funny anymore *g* And my boss is, of
course, waiting for a result. Howcome people don't get that programming
sometimes really IS leaning back and closing your eyes *gr* :oP
Thanks for trying to help me :o)
Chris
- Original Message -
From: Zoltán Németh [EMAIL PROTECTED]
To: Christian Haensel [EMAIL PROTECTED]
Cc: php-general@lists.php.net
Sent: Monday, May 21, 2007 9:58 AM
Subject: Re: [PHP] PHP MySQL Problem
2007. 05. 21, hétfő keltezéssel 09.43-kor Christian Haensel ezt írta:
Right, here we go... this page has about 1000 lines of code, so here
the
relevant stuff.
$s_query = SELECT * FROM database WHERE
kategorie LIKE '$s_cat' AND
marke LIKE '$s_marke' AND
leistung_kw = '$kw_von' AND leistung_kw = '$kw_bis' AND
preis = '$s_preis_von' AND
preis = '$s_preis_bis'.$checkboxes.$sort_str;
I get the $checkboxes from the POST checkboxes, which looks like this
(an
example):
$kraftstoffart = $_POST['fueltype'];
if($kraftstoffart == 3) {
$checkboxes .= ;
}elseif($kraftstoffart == 2) {
$checkboxes .= AND kraftstoffart = '2';
}elseif($kraftstoffart == 1) {
$checkboxes .= AND kraftstoffart = '1';
}
and the $sort_str comes in like
$sort_by = $_POST['sort_by'];
$desc_asc = $_POST['desc_asc'];
$sort_str = ORDER BY .$sort_by. .$desc_asc;
The query then just goes like
$do_q = mysql_query($s_query) or die(mysql_error());
and that's it... no errors shown, just the regular output which I had
before I put the new fields in there. So no changes to what I've had
before... but there should be changes *g*
actually there seems to be no problem with your query (besides that you
should check posted values first in order to avoid SQL injection)
you said in your first letter that $_POST['var'] don't reach the
script - I would guess the relevant part is not the query but rather
the form itself...
greets
Zoltán Németh
I hope anybody can find some sense in what I'm writing here... hardly
makes
sense to me :oP
Cheers!
- Original Message -
From: Zoltán Németh [EMAIL PROTECTED]
To: Christian Haensel [EMAIL PROTECTED]
Cc: php-general@lists.php.net
Sent: Monday, May 21, 2007 9:36 AM
Subject: Re: [PHP] PHP MySQL Problem
2007. 05. 21, hétfő keltezéssel 09.26-kor Christian Haensel ezt
írta:
Good morning friends,
I have a script that collects data from a form and puts together a
mysql
query to search a database.
Now, everything worked fine until I added a few new form fields...
now
the
$_POST['var'] don't reach the script...
I have about 20 to 25 form fields which are all taken into the
query...
Now my question: is there a limit in the fields that I can use in
the
query
string to query the database? Somehow the script doesn't even
output
the
value of the POST data anymore... been using this stuff for years
now,
and
i'm feeling really silly at the moment.
AFAIK
Re: [PHP] PHP MySQL Problem
Hi there, good morning, as posted yesterday (I guess it kind of got overlooked by the nmber of posts here), I was such a dirk that I put a hidden action in my form that redirected the test page to another (currently running) form which didn't have the changes in it. So my test page showed me data of a live page... dumb me, I know. But after hours and hours of coding, I bet this even happens to the best out there :oP Little piece of code sticking somewhere and you don't even remember that it is there... that reminds me to continue writing the handbook to this website *g* Have a great coding-day :o)) Chris - Original Message - From: Richard Lynch [EMAIL PROTECTED] To: Christian Haensel [EMAIL PROTECTED] Cc: php-general@lists.php.net Sent: Tuesday, May 22, 2007 2:42 AM Subject: Re: [PHP] PHP MySQL Problem On Mon, May 21, 2007 2:26 am, Christian Haensel wrote: Good morning friends, I have a script that collects data from a form and puts together a mysql query to search a database. Now, everything worked fine until I added a few new form fields... now the $_POST['var'] don't reach the script... I have about 20 to 25 form fields which are all taken into the query... Now my question: is there a limit in the fields that I can use in the query string to query the database? Somehow the script doesn't even output the value of the POST data anymore... been using this stuff for years now, and i'm feeling really silly at the moment. I'd appreciate any help. POST data *does* have a limit, possibly, based on your selection of browser/server software... It's a ridiculously high limit however, so it seems more likely that you just added a typo to your code. Show us code to get an answer. And estimate for us the size of the POST data as well. Without those bits of info, our answers will be: Maybe. -- Some people have a gift link here. Know what I want? I want you to buy a CD from some indie artist. http://cdbaby.com/browse/from/lynch Yeah, I get a buck. So? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Re: showing source
Why don't you use:
highlight_file(__FILE__) ?
OMG
I have been coding that thing for MONTHS now... just to get syntax
highlighting for my tutorial blog... maybe I shouldn't write tutorials...
maybe I should rather read them *g*
Thanks for this short, but awesome answer :o) I wasn't the one asking the
question, but nonetheless you have just wrecked my weekend :oP If I could
kick my own rear end, I would do so´for the next two days...
Cheers mate, and have a great weekend!
Chris
- tul
James Lockie wrote:
This almost works but all my and are replaced with .
// open this file to show the source
if (($fh = fopen( __FILE__, 'r' )) === FALSE){
die ('Failed to open source file (' . $_FILE_ . ') for
reading!');
} else {
$tags = array( , );
$safe_tags = array( \\, \\ );
print pre\n;
// read the file line by line
while (! feof( $fh )) {
$currentLine = fgets( $fh, 255 );
$noTags = str_replace( $tags, $safeTags, $currentLine );
print $noTags;
}
fclose( $fh );
print /pre\n;
}
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Re: [PHP] using preg_match
Hi Ed,
did you try the backslash as escape character?
?
$path = testing/realtors/userdata/;
if(preg_match(/\/realtors/, $path)) {
echo 'Success';
}
?
Works for me :o)
Maybe try http://de3.php.net/manual/en/function.preg-match.php too see some
examples.
Good luck
Chris
- Original Message -
From: Ed Curtis [EMAIL PROTECTED]
To: php-general@lists.php.net
Sent: Wednesday, May 16, 2007 2:12 PM
Subject: [PHP] using preg_match
I'm trying to use preg_match to find a string in a system path.
What I need to do is see if the string '/realtors' exists in a variable
named '$path'.
I know '/' is used as a container within the command itself. How do I
escape it to find the string '/realtors'?
Thanks,
Ed
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Re: [PHP] RE: Bounty FYI
You forgot one: Don't spam! Regards, Chris - Original Message - From: Brad Sumrall [EMAIL PROTECTED] To: php-general@lists.php.net Sent: Tuesday, May 15, 2007 8:55 AM Subject: [PHP] RE: Bounty FYI Food for thought! Respect the freedom. Respect the Internet! We all benefit! Never abuse! -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] RE: Bounty FYI
ROFL... you really made my day... it's about 9am, been working for 2 hours now, and the day is great already! Worked for the DoD and stuff like that, and still doesn't know how to behave. You remind me of a 14 years old guy I knew from Bahrain... always trying to mess with the big boys. Go play outside :o) Mr DoD *ROFL* - Original Message - From: Brad Sumrall [EMAIL PROTECTED] To: 'Christian Haensel' [EMAIL PROTECTED] Sent: Tuesday, May 15, 2007 9:06 AM Subject: RE: [PHP] RE: Bounty FYI When did I request money? Go hit your Webster's schmuck! -Original Message- From: Christian Haensel [mailto:[EMAIL PROTECTED] Sent: Tuesday, May 15, 2007 3:01 AM To: Brad Sumrall; php-general@lists.php.net Subject: Re: [PHP] RE: Bounty FYI You forgot one: Don't spam! Regards, Chris - Original Message - From: Brad Sumrall [EMAIL PROTECTED] To: php-general@lists.php.net Sent: Tuesday, May 15, 2007 8:55 AM Subject: [PHP] RE: Bounty FYI Food for thought! Respect the freedom. Respect the Internet! We all benefit! Never abuse! -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Image Resize with LibGD
Good morning, I am using imagecreatetruecolor() and imagecopyresampled() to resize oversized images and am overlaying them with an transparent PNG to add a watermark. That works just well for oversized images. Now, let's say I have a small image and would like to stretch it by 50 to 100% of its original size... I know there will be a loss of quality. But maybe someone out there has had to deal with the same before and knows the best way to do that? Any suggestion would be very much appreciated :o) Greetings from germany, Chris -- Chriatian Haensel Fulltime WebSlave http://www.chftp.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] PHP MySQL - Field Title
Hi Oliver,
below is what I used.
?
mysql_con();
$insert_q = INSERT INTO DB1 VALUES(;
$query = SELECT * FROM vorlauf WHERE satz_nr = '$fzg_id' LIMIT 1;
$doit = mysql_query($query);
$data = mysql_fetch_assoc($doit);
for($i=0; $i=126; $i++) {
$fieldname = mysql_field_name($doit, $i);
$value = $data[$fieldname];
if($value == ) {
$value=0;
}
if($fieldname == lfd_id) {
$value=;
}
echo $fieldname. -- .$value.br;
$titel = $fieldname;
$insert_q .= ,'$value';
}
$insert_q = $insert_q.')';
$insert_q = eregi_replace(\(,,(, $insert_q);
echo p;
echo $insert_q;
mysql_query($insert_q) or die(mysql_error());
echo Yup;
$del_q = DELETE FROM vorlauf WHERE satz_nr = '$fzg_id' LIMIT 1;
$do_del = mysql_uery($del_q);
?
I'm sure there are better ways to do the whole thing :o) But as long as I
need to cpy one record at a time, I don't really care much for speed. I just
put all the stuff into a string and then use that string as query for the
insertion into the second database.
Scripts like that make me feel good when I say You can be dumb as heck, ás
long as you find a way to resolve your problems :o) It works, and it took
me just about 10 minutes of research and another 10 of writing :o)
Hope your weather is just as good as ours here...
All the best!
Chris
- Original Message -
From: Oliver Block [EMAIL PROTECTED]
To: php-general@lists.php.net
Cc: Christian Haensel [EMAIL PROTECTED]
Sent: Monday, April 30, 2007 1:11 PM
Subject: Re: [PHP] PHP MySQL - Field Title
Am Montag, 30. April 2007 07:47 schrieb Christian Haensel:
but now I have the problem with the field names and all... can someone
point me into the right direction?
http://www.php.net/manual/de/ref.mysql.php
php-db at lists.php.net
If you need to use an assoc array, use the following SQL Syntax:
INSERT INTO new_table SET key0=value0, key2=value2, ...,
Regards,
Oliver
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[PHP] PHP MySQL - Field Title
Good Morning guys and girls
As I am rather lazy, I don't wanna do a data readout on my MySQL table in
the following way with mysql_fetch_assoc()
$data_item1=$data['xitem1'];
$data_item2=$data['yitem2];
I am trying to do the following:
I have the correct number of fields in the table, which is 116. Now I want
to use a for-loop and read teh data into a string, then shove it into
another table, which has the exact same layout. I was thinking about
something like
for($i=0; $i= 115; $i++) {
$data_item[$i]=$data[$i];
}
but now I have the problem with the field names and all... can someone point
me into the right direction? All I have to so is move the contents of one
field to the second database wich has the same layout as the first DB.
Would be thankful for any help :o)
Cheers!
Chris
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[PHP] echo or print ?
Good morning fellow coders
I've been working with PHP for a little over 5 years now, and it even got me
a cute office and a good salary... but even though I can make a living off
of it, I am still wondering about a few little things.
Whenever I see people put their code up for review, I realize they mostly
use print instead of echo, while I am using echo 99% of the time. Actually,
I can't even remember when I last used the regular print.
What do you guys use, and what is the advantage (if ther is any) of print
over echo? And I am not talking about print_r or anything, just the regular
print. :o)
All the best!
Chris
Christian Haensel
/voodoo.css
#GeorgeWBush { position:absolute; bottom:-6ft; }
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Re: [PHP] echo or print ?
Thanks mate, that clarifies that. And now I know why I use echo all the time *g* Have a great day,... greetings from sunny germany :o) Chris - Original Message - From: Dimiter Ivanov [EMAIL PROTECTED] To: Christian Haensel [EMAIL PROTECTED] Cc: php-general@lists.php.net Sent: Tuesday, April 17, 2007 9:48 AM Subject: Re: [PHP] echo or print ? On 4/17/07, Christian Haensel [EMAIL PROTECTED] wrote: Good morning fellow coders I've been working with PHP for a little over 5 years now, and it even got me a cute office and a good salary... but even though I can make a living off of it, I am still wondering about a few little things. Whenever I see people put their code up for review, I realize they mostly use print instead of echo, while I am using echo 99% of the time. Actually, I can't even remember when I last used the regular print. What do you guys use, and what is the advantage (if ther is any) of print over echo? And I am not talking about print_r or anything, just the regular print. :o) There is a link in the manual about the difference between those two: http://www.faqts.com/knowledge_base/view.phtml/aid/1/fid/40 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
