[PHP] Ok then, here is a test
On 10/12/2012 11:42 AM, Daniel Brown wrote: Well, as the adage goes, you'll catch more flies with honey than with vinegar. And considering this is the very first message I've ever seen from you, it sounds like either (a) you didn't follow the proper protocol, or (b) there's something in the process we need to review. If you think the issue lies on our end, you can submit a bug at https://bugs.php.net/ and detail the steps to reproduce the issue. If it is indeed something we need to correct, believe me, we will. We don't deliberately attempt to mislead or frustrate people, despite how it might have seemed. Well, with that said, here is a test. I have found, in the past, that when I enable all the SPAM filtering that I want, that 76.75.200.58/pb1.pair.com/lists.php.net mail server gets blocked by my mail server. It has been a while so I don't remember what the reason was it got blocked, but I have enabled all the filtering again, and this is my test email with the full set of filtering enabled. Lets see if the server still gets blocked. I will post the logs if and when it gets blocked. -- Jim Lucas -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Ok then, here is a test
On 10/13/2012 10:42 PM, Jim Lucas wrote: On 10/12/2012 11:42 AM, Daniel Brown wrote: Well, as the adage goes, you'll catch more flies with honey than with vinegar. And considering this is the very first message I've ever seen from you, it sounds like either (a) you didn't follow the proper protocol, or (b) there's something in the process we need to review. If you think the issue lies on our end, you can submit a bug at https://bugs.php.net/ and detail the steps to reproduce the issue. If it is indeed something we need to correct, believe me, we will. We don't deliberately attempt to mislead or frustrate people, despite how it might have seemed. Well, with that said, here is a test. I have found, in the past, that when I enable all the SPAM filtering that I want, that 76.75.200.58/pb1.pair.com/lists.php.net mail server gets blocked by my mail server. It has been a while so I don't remember what the reason was it got blocked, but I have enabled all the filtering again, and this is my test email with the full set of filtering enabled. Lets see if the server still gets blocked. I will post the logs if and when it gets blocked. -- Jim Lucas Well, I got it. Seems the problem has gone away. Never mind then. -- Jim Lucas -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: [BULK] Re: [PHP] OK to have many files in one folder?
I have no clue how big the files are, but you might want to store them
in a database. That can speed up things, but don't ask me how much ;)
Tijnema
no dude, while database are convenient, files systems are faster, I mean
thats what they were designed for, serving files.
For lots of files I would store them in directories and sub directories.
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Clive.
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[PHP] Re: [BULK] Re: [PHP] OK to have many files in one folder?
clive wrote: I have no clue how big the files are, but you might want to store them in a database. That can speed up things, but don't ask me how much ;) Tijnema no dude, while database are convenient, files systems are faster, I mean thats what they were designed for, serving files. For lots of files I would store them in directories and sub directories. Yeah amen! I generally use a two character hex hash in my main folder to give 255 sub folders each containing files. In my case the hash is calculated from some known info - e.g. a database ID and then stored in a meta data table. Col -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Re: [BULK] Re: [PHP] OK to have many files in one folder?
On 6/18/07, Colin Guthrie [EMAIL PROTECTED] wrote: clive wrote: I have no clue how big the files are, but you might want to store them in a database. That can speed up things, but don't ask me how much ;) Tijnema no dude, while database are convenient, files systems are faster, I mean thats what they were designed for, serving files. For lots of files I would store them in directories and sub directories. Yeah amen! I generally use a two character hex hash in my main folder to give 255 sub folders each containing files. In my case the hash is calculated from some known info - e.g. a database ID and then stored in a meta data table. Col -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php Tij, Referring to one of my earlier posts in this thread, as a refresher, database information is stored in files. So to store files in a database means the following has to take place: 1.) Data is uploaded to the server. 2.) Data is processed by the database server. 3.) Data is compressed and encrypted. 4.) Data is written to disk. (4b. - optional) Data file is checked for integrity and correctness of write. Then, to serve the content, a similar reverse occurs: 1.) Request is sent to the server via a script. 2.) The script interfaces with the database to locate the desired data row. 3.) Once located, the data is pulled in raw form from the database file. 4.) The data is then decompressed and decrypted. 5.) The data is streamed back to the script. 6.) The script decides how to handle it, based upon hard-coded options. For a filesystem, it's simpler. Uploading: 1.) Data is uploaded. 2.) Data is written to disk. Serving: 1.) Request is sent via script, FTP, socket connection, or local request. 2.) File is served through via the method requested. So there are several pros and cons for each, but just to list three of each with regard to database storage: Pros: Can be stored centralized and portable, without needing to archive. Automatically encrypted and compressed upon storage. Easier and faster to search. Cons: Slower storage and retrieval Much greater risk of corruption Not always cross-compatible across platforms, versions, installations, etc. -- Daniel P. Brown [office] (570-) 587-7080 Ext. 272 [mobile] (570-) 766-8107 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Re: [BULK] Re: [PHP] OK to have many files in one folder?
On 6/18/07, Daniel Brown [EMAIL PROTECTED] wrote: On 6/18/07, Colin Guthrie [EMAIL PROTECTED] wrote: clive wrote: I have no clue how big the files are, but you might want to store them in a database. That can speed up things, but don't ask me how much ;) Tijnema no dude, while database are convenient, files systems are faster, I mean thats what they were designed for, serving files. For lots of files I would store them in directories and sub directories. Yeah amen! I generally use a two character hex hash in my main folder to give 255 sub folders each containing files. In my case the hash is calculated from some known info - e.g. a database ID and then stored in a meta data table. Col -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php Tij, Referring to one of my earlier posts in this thread, as a refresher, database information is stored in files. So to store files in a database means the following has to take place: 1.) Data is uploaded to the server. 2.) Data is processed by the database server. 3.) Data is compressed and encrypted. 4.) Data is written to disk. (4b. - optional) Data file is checked for integrity and correctness of write. Then, to serve the content, a similar reverse occurs: 1.) Request is sent to the server via a script. 2.) The script interfaces with the database to locate the desired data row. 3.) Once located, the data is pulled in raw form from the database file. 4.) The data is then decompressed and decrypted. 5.) The data is streamed back to the script. 6.) The script decides how to handle it, based upon hard-coded options. For a filesystem, it's simpler. Uploading: 1.) Data is uploaded. 2.) Data is written to disk. Serving: 1.) Request is sent via script, FTP, socket connection, or local request. 2.) File is served through via the method requested. So there are several pros and cons for each, but just to list three of each with regard to database storage: Pros: Can be stored centralized and portable, without needing to archive. Automatically encrypted and compressed upon storage. Easier and faster to search. Cons: Slower storage and retrieval Much greater risk of corruption Not always cross-compatible across platforms, versions, installations, etc. -- Daniel P. Brown How sure are you about all this? Benchmarks? What about search time for the harddrives etc? It needs to scan the inode table to find the file, etc.., then it needs to locate that file on the harddrive, while the second file might be on the other side of the disk Storing all files in one single filesystem means you have only 1 inode :) All data is stored at same place (atleast, it should be) Tijnema -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Re: [BULK] Re: [PHP] OK to have many files in one folder?
On 6/18/07, Tijnema [EMAIL PROTECTED] wrote: On 6/18/07, Daniel Brown [EMAIL PROTECTED] wrote: On 6/18/07, Colin Guthrie [EMAIL PROTECTED] wrote: clive wrote: I have no clue how big the files are, but you might want to store them in a database. That can speed up things, but don't ask me how much ;) Tijnema no dude, while database are convenient, files systems are faster, I mean thats what they were designed for, serving files. For lots of files I would store them in directories and sub directories. Yeah amen! I generally use a two character hex hash in my main folder to give 255 sub folders each containing files. In my case the hash is calculated from some known info - e.g. a database ID and then stored in a meta data table. Col -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php Tij, Referring to one of my earlier posts in this thread, as a refresher, database information is stored in files. So to store files in a database means the following has to take place: 1.) Data is uploaded to the server. 2.) Data is processed by the database server. 3.) Data is compressed and encrypted. 4.) Data is written to disk. (4b. - optional) Data file is checked for integrity and correctness of write. Then, to serve the content, a similar reverse occurs: 1.) Request is sent to the server via a script. 2.) The script interfaces with the database to locate the desired data row. 3.) Once located, the data is pulled in raw form from the database file. 4.) The data is then decompressed and decrypted. 5.) The data is streamed back to the script. 6.) The script decides how to handle it, based upon hard-coded options. For a filesystem, it's simpler. Uploading: 1.) Data is uploaded. 2.) Data is written to disk. Serving: 1.) Request is sent via script, FTP, socket connection, or local request. 2.) File is served through via the method requested. So there are several pros and cons for each, but just to list three of each with regard to database storage: Pros: Can be stored centralized and portable, without needing to archive. Automatically encrypted and compressed upon storage. Easier and faster to search. Cons: Slower storage and retrieval Much greater risk of corruption Not always cross-compatible across platforms, versions, installations, etc. -- Daniel P. Brown How sure are you about all this? Benchmarks? What about search time for the harddrives etc? It needs to scan the inode table to find the file, etc.., then it needs to locate that file on the harddrive, while the second file might be on the other side of the disk Storing all files in one single filesystem means you have only 1 inode :) All data is stored at same place (atleast, it should be) Tijnema Do I have benchmarks? No. Do I have the time to do them now? No. Do I feel confident enough that if you were to run those benchmark tests that it would prove me right? Damn straight. ;-P -- Daniel P. Brown [office] (570-) 587-7080 Ext. 272 [mobile] (570-) 766-8107 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Re: [BULK] Re: [PHP] OK to have many files in one folder?
On 6/18/07, Daniel Brown [EMAIL PROTECTED] wrote: On 6/18/07, Tijnema [EMAIL PROTECTED] wrote: On 6/18/07, Daniel Brown [EMAIL PROTECTED] wrote: On 6/18/07, Colin Guthrie [EMAIL PROTECTED] wrote: clive wrote: I have no clue how big the files are, but you might want to store them in a database. That can speed up things, but don't ask me how much ;) Tijnema no dude, while database are convenient, files systems are faster, I mean thats what they were designed for, serving files. For lots of files I would store them in directories and sub directories. Yeah amen! I generally use a two character hex hash in my main folder to give 255 sub folders each containing files. In my case the hash is calculated from some known info - e.g. a database ID and then stored in a meta data table. Col -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php Tij, Referring to one of my earlier posts in this thread, as a refresher, database information is stored in files. So to store files in a database means the following has to take place: 1.) Data is uploaded to the server. 2.) Data is processed by the database server. 3.) Data is compressed and encrypted. 4.) Data is written to disk. (4b. - optional) Data file is checked for integrity and correctness of write. Then, to serve the content, a similar reverse occurs: 1.) Request is sent to the server via a script. 2.) The script interfaces with the database to locate the desired data row. 3.) Once located, the data is pulled in raw form from the database file. 4.) The data is then decompressed and decrypted. 5.) The data is streamed back to the script. 6.) The script decides how to handle it, based upon hard-coded options. For a filesystem, it's simpler. Uploading: 1.) Data is uploaded. 2.) Data is written to disk. Serving: 1.) Request is sent via script, FTP, socket connection, or local request. 2.) File is served through via the method requested. So there are several pros and cons for each, but just to list three of each with regard to database storage: Pros: Can be stored centralized and portable, without needing to archive. Automatically encrypted and compressed upon storage. Easier and faster to search. Cons: Slower storage and retrieval Much greater risk of corruption Not always cross-compatible across platforms, versions, installations, etc. -- Daniel P. Brown How sure are you about all this? Benchmarks? What about search time for the harddrives etc? It needs to scan the inode table to find the file, etc.., then it needs to locate that file on the harddrive, while the second file might be on the other side of the disk Storing all files in one single filesystem means you have only 1 inode :) All data is stored at same place (atleast, it should be) Tijnema Do I have benchmarks? No. Do I have the time to do them now? No. Do I feel confident enough that if you were to run those benchmark tests that it would prove me right? Damn straight. ;-P -- Daniel P. Brown I think I have some time to write a simple script in a few hours, I'd like to see what the performance difference is :) Tijnema -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Re: [BULK] Re: [PHP] OK to have many files in one folder?
On 6/18/07, Tijnema [EMAIL PROTECTED] wrote: On 6/18/07, Daniel Brown [EMAIL PROTECTED] wrote: On 6/18/07, Tijnema [EMAIL PROTECTED] wrote: On 6/18/07, Daniel Brown [EMAIL PROTECTED] wrote: On 6/18/07, Colin Guthrie [EMAIL PROTECTED] wrote: clive wrote: I have no clue how big the files are, but you might want to store them in a database. That can speed up things, but don't ask me how much ;) Tijnema no dude, while database are convenient, files systems are faster, I mean thats what they were designed for, serving files. For lots of files I would store them in directories and sub directories. Yeah amen! I generally use a two character hex hash in my main folder to give 255 sub folders each containing files. In my case the hash is calculated from some known info - e.g. a database ID and then stored in a meta data table. Col -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php Tij, Referring to one of my earlier posts in this thread, as a refresher, database information is stored in files. So to store files in a database means the following has to take place: 1.) Data is uploaded to the server. 2.) Data is processed by the database server. 3.) Data is compressed and encrypted. 4.) Data is written to disk. (4b. - optional) Data file is checked for integrity and correctness of write. Then, to serve the content, a similar reverse occurs: 1.) Request is sent to the server via a script. 2.) The script interfaces with the database to locate the desired data row. 3.) Once located, the data is pulled in raw form from the database file. 4.) The data is then decompressed and decrypted. 5.) The data is streamed back to the script. 6.) The script decides how to handle it, based upon hard-coded options. For a filesystem, it's simpler. Uploading: 1.) Data is uploaded. 2.) Data is written to disk. Serving: 1.) Request is sent via script, FTP, socket connection, or local request. 2.) File is served through via the method requested. So there are several pros and cons for each, but just to list three of each with regard to database storage: Pros: Can be stored centralized and portable, without needing to archive. Automatically encrypted and compressed upon storage. Easier and faster to search. Cons: Slower storage and retrieval Much greater risk of corruption Not always cross-compatible across platforms, versions, installations, etc. -- Daniel P. Brown How sure are you about all this? Benchmarks? What about search time for the harddrives etc? It needs to scan the inode table to find the file, etc.., then it needs to locate that file on the harddrive, while the second file might be on the other side of the disk Storing all files in one single filesystem means you have only 1 inode :) All data is stored at same place (atleast, it should be) Tijnema Do I have benchmarks? No. Do I have the time to do them now? No. Do I feel confident enough that if you were to run those benchmark tests that it would prove me right? Damn straight. ;-P -- Daniel P. Brown I think I have some time to write a simple script in a few hours, I'd like to see what the performance difference is :) Tijnema Well, keep in mind that I don't expect that you'd see much difference at all with a single file, but try doing multiple files of ASCII and binary, various sizes, and also several simultaneous connections. Two other things I forgot to mention with database storage are a pro and con, respectively - caching and accessibility. -- Daniel P. Brown [office] (570-) 587-7080 Ext. 272 [mobile] (570-) 766-8107 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Re: [BULK] Re: [PHP] OK to have many files in one folder?
On Mon, 2007-06-18 at 11:25 -0400, Daniel Brown wrote: On 6/18/07, Tijnema [EMAIL PROTECTED] wrote: On 6/18/07, Daniel Brown [EMAIL PROTECTED] wrote: Referring to one of my earlier posts in this thread, as a refresher, database information is stored in files. So to store files in a database means the following has to take place: 1.) Data is uploaded to the server. 2.) Data is processed by the database server. 3.) Data is compressed and encrypted. 4.) Data is written to disk. (4b. - optional) Data file is checked for integrity and correctness of write. Then, to serve the content, a similar reverse occurs: 1.) Request is sent to the server via a script. 2.) The script interfaces with the database to locate the desired data row. 3.) Once located, the data is pulled in raw form from the database file. 4.) The data is then decompressed and decrypted. 5.) The data is streamed back to the script. 6.) The script decides how to handle it, based upon hard-coded options. For a filesystem, it's simpler. Uploading: 1.) Data is uploaded. 2.) Data is written to disk. This isn't quite correct. There are numerous databases that allow you to assign a raw partition and they manage the filesystem themselves thus the intermediate OS dependence is eliminated. As such, the database probably wins in this situation since you also get rapid searching on any meta data fields and since you probably have to issue a query anyways (for either approach), this approach is superior since you no longer need to interact with the filesystem at all. The only negative is that writing to the database will be less efficient due to escaping of the data. But reading will be much faster. And in practice, I'd wager, it's rare that images are created more often than read. Cheers, Rob. -- .. | InterJinn Application Framework - http://www.interjinn.com | :: | An application and templating framework for PHP. Boasting | | a powerful, scalable system for accessing system services | | such as forms, properties, sessions, and caches. InterJinn | | also provides an extremely flexible architecture for | | creating re-usable components quickly and easily. | `' -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Re: [BULK] Re: [PHP] OK to have many files in one folder?
Daniel Brown wrote: On 6/18/07, Tijnema [EMAIL PROTECTED] wrote: On 6/18/07, Daniel Brown [EMAIL PROTECTED] wrote: On 6/18/07, Tijnema [EMAIL PROTECTED] wrote: On 6/18/07, Daniel Brown [EMAIL PROTECTED] wrote: On 6/18/07, Colin Guthrie [EMAIL PROTECTED] wrote: clive wrote: I have no clue how big the files are, but you might want to store them in a database. That can speed up things, but don't ask me how much ;) Tijnema no dude, while database are convenient, files systems are faster, I mean thats what they were designed for, serving files. For lots of files I would store them in directories and sub directories. Yeah amen! I generally use a two character hex hash in my main folder to give 255 sub folders each containing files. In my case the hash is calculated from some known info - e.g. a database ID and then stored in a meta data table. Col -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php Tij, Referring to one of my earlier posts in this thread, as a refresher, database information is stored in files. So to store files in a database means the following has to take place: 1.) Data is uploaded to the server. 2.) Data is processed by the database server. 3.) Data is compressed and encrypted. 4.) Data is written to disk. (4b. - optional) Data file is checked for integrity and correctness of write. Then, to serve the content, a similar reverse occurs: 1.) Request is sent to the server via a script. 2.) The script interfaces with the database to locate the desired data row. 3.) Once located, the data is pulled in raw form from the database file. 4.) The data is then decompressed and decrypted. 5.) The data is streamed back to the script. 6.) The script decides how to handle it, based upon hard-coded options. For a filesystem, it's simpler. Uploading: 1.) Data is uploaded. 2.) Data is written to disk. Serving: 1.) Request is sent via script, FTP, socket connection, or local request. 2.) File is served through via the method requested. So there are several pros and cons for each, but just to list three of each with regard to database storage: Pros: Can be stored centralized and portable, without needing to archive. Automatically encrypted and compressed upon storage. Easier and faster to search. Cons: Slower storage and retrieval Much greater risk of corruption Not always cross-compatible across platforms, versions, installations, etc. -- Daniel P. Brown How sure are you about all this? Benchmarks? What about search time for the harddrives etc? It needs to scan the inode table to find the file, etc.., then it needs to locate that file on the harddrive, while the second file might be on the other side of the disk Storing all files in one single filesystem means you have only 1 inode :) All data is stored at same place (atleast, it should be) Tijnema Do I have benchmarks? No. Do I have the time to do them now? No. Do I feel confident enough that if you were to run those benchmark tests that it would prove me right? Damn straight. ;-P -- Daniel P. Brown I think I have some time to write a simple script in a few hours, I'd like to see what the performance difference is :) Tijnema Well, keep in mind that I don't expect that you'd see much difference at all with a single file, but try doing multiple files of ASCII and binary, various sizes, and also several simultaneous connections. Two other things I forgot to mention with database storage are a pro and con, respectively - caching and accessibility. and the fact that a lot of hosting environments have a DB on a different machine. This would make for a much worse performance then the local filesystem. -- Jim Lucas Some men are born to greatness, some achieve greatness, and some have greatness thrust upon them. Twelfth Night, Act II, Scene V by William Shakespeare -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Re: [BULK] Re: [PHP] OK to have many files in one folder?
On Mon, 2007-06-18 at 08:41 -0700, Jim Lucas wrote: Daniel Brown wrote: On 6/18/07, Tijnema [EMAIL PROTECTED] wrote: On 6/18/07, Daniel Brown [EMAIL PROTECTED] wrote: On 6/18/07, Tijnema [EMAIL PROTECTED] wrote: On 6/18/07, Daniel Brown [EMAIL PROTECTED] wrote: On 6/18/07, Colin Guthrie [EMAIL PROTECTED] wrote: clive wrote: I have no clue how big the files are, but you might want to store them in a database. That can speed up things, but don't ask me how much ;) Tijnema no dude, while database are convenient, files systems are faster, I mean thats what they were designed for, serving files. For lots of files I would store them in directories and sub directories. Yeah amen! I generally use a two character hex hash in my main folder to give 255 sub folders each containing files. In my case the hash is calculated from some known info - e.g. a database ID and then stored in a meta data table. Col -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php Tij, Referring to one of my earlier posts in this thread, as a refresher, database information is stored in files. So to store files in a database means the following has to take place: 1.) Data is uploaded to the server. 2.) Data is processed by the database server. 3.) Data is compressed and encrypted. 4.) Data is written to disk. (4b. - optional) Data file is checked for integrity and correctness of write. Then, to serve the content, a similar reverse occurs: 1.) Request is sent to the server via a script. 2.) The script interfaces with the database to locate the desired data row. 3.) Once located, the data is pulled in raw form from the database file. 4.) The data is then decompressed and decrypted. 5.) The data is streamed back to the script. 6.) The script decides how to handle it, based upon hard-coded options. For a filesystem, it's simpler. Uploading: 1.) Data is uploaded. 2.) Data is written to disk. Serving: 1.) Request is sent via script, FTP, socket connection, or local request. 2.) File is served through via the method requested. So there are several pros and cons for each, but just to list three of each with regard to database storage: Pros: Can be stored centralized and portable, without needing to archive. Automatically encrypted and compressed upon storage. Easier and faster to search. Cons: Slower storage and retrieval Much greater risk of corruption Not always cross-compatible across platforms, versions, installations, etc. -- Daniel P. Brown How sure are you about all this? Benchmarks? What about search time for the harddrives etc? It needs to scan the inode table to find the file, etc.., then it needs to locate that file on the harddrive, while the second file might be on the other side of the disk Storing all files in one single filesystem means you have only 1 inode :) All data is stored at same place (atleast, it should be) Tijnema Do I have benchmarks? No. Do I have the time to do them now? No. Do I feel confident enough that if you were to run those benchmark tests that it would prove me right? Damn straight. ;-P -- Daniel P. Brown I think I have some time to write a simple script in a few hours, I'd like to see what the performance difference is :) Tijnema Well, keep in mind that I don't expect that you'd see much difference at all with a single file, but try doing multiple files of ASCII and binary, various sizes, and also several simultaneous connections. Two other things I forgot to mention with database storage are a pro and con, respectively - caching and accessibility. and the fact that a lot of hosting environments have a DB on a different machine. This would make for a much worse performance then the local filesystem. Maybe on the occasional hit. I use a technique where a 404 request of a specially formulated filename causes the file to be retrieved from the remote centralized database server. If found the 404 is changed to a 200 response and the file is served. Subsequent requests directly access the file from the webserver without PHP. Obviously this is a caching technique, but it eliminates much of the overhead of the database while still providing a centralized repository for all the images. And
Re: [PHP] OK to have many files in one folder?
For everyone who advised me to beware the inode, allow me to forward what the Rackspace admins told me. This is Greek to me, and I'm hoping one of you can translate. All I understood was where he said I appear to have more than enough. Yes? ---snip--- All of your slices on the disk are ext3. As this is the only file system that the Red Hat kernel provides support for. [EMAIL PROTECTED] ~]# df -hT Filesystem Type Size Used Avail Use% Mounted on /dev/hda5 ext3 227G 93G 123G 43% / /dev/hda1 ext3 99M 12M 83M 12% /boot none tmpfs 1.9G 0 1.9G 0% /dev/shm /dev/hda2 ext3 2.0G 36M 1.9G 2% /tmp As far as I am able to recall, there are only 2 limitations that you must be concerned with. There might be others, but these are the only ones I am aware of, which also appears to be true from the research I have done. 1. The number if i-nodes. You appear to have more than enough. [EMAIL PROTECTED] ~]# df -i Filesystem Inodes IUsed IFree IUse% Mounted on /dev/hda5 30130176 3729871 26400305 13% / /dev/hda1 26104 46 26058 1% /boot none 220613 1 220612 1% /dev/shm /dev/hda2 262144 18 262126 1% /tmp 2. The subdirectory limitation for the ext3 file system. You can only have 32000 subdirectories with in any directory. ---/snip--- -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] OK to have many files in one folder?
On 6/17/07, Brian Dunning [EMAIL PROTECTED] wrote: For everyone who advised me to beware the inode, allow me to forward what the Rackspace admins told me. This is Greek to me, and I'm hoping one of you can translate. All I understood was where he said I appear to have more than enough. Yes? ---snip--- All of your slices on the disk are ext3. As this is the only file system that the Red Hat kernel provides support for. [EMAIL PROTECTED] ~]# df -hT Filesystem Type Size Used Avail Use% Mounted on /dev/hda5 ext3 227G 93G 123G 43% / /dev/hda1 ext3 99M 12M 83M 12% /boot none tmpfs 1.9G 0 1.9G 0% /dev/shm /dev/hda2 ext3 2.0G 36M 1.9G 2% /tmp As far as I am able to recall, there are only 2 limitations that you must be concerned with. There might be others, but these are the only ones I am aware of, which also appears to be true from the research I have done. 1. The number if i-nodes. You appear to have more than enough. [EMAIL PROTECTED] ~]# df -i Filesystem Inodes IUsed IFree IUse% Mounted on /dev/hda5 30130176 3729871 26400305 13% / /dev/hda1 26104 46 26058 1% /boot none 220613 1 220612 1% /dev/shm /dev/hda2 262144 18 262126 1% /tmp 2. The subdirectory limitation for the ext3 file system. You can only have 32000 subdirectories with in any directory. Enough Inodes, and 32000 subdirectory's is quiet a lot, and definitly not a problem if you place all files in one directory ;) But, speed is a different story, so you might want to test how it works when you store the files in a database, it might be faster... Tijnema -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] OK to have many files in one folder?
Server is running Linux, and PHP is constantly creating and modifying images in a directory. Apache is constantly serving these same images. There are about 250,000 of them in the same directory. Seems to be running OK, no problematic CPU load, but I'm wondering if anyone knows whether I'm living dangerously having that many docs in one directory with that much activity. It is an extremely busy server. Sorry is this seems like more of a linux sysad question than a PHP question. Thanks... :) -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] OK to have many files in one folder?
[snip] Server is running Linux, and PHP is constantly creating and modifying images in a directory. Apache is constantly serving these same images. There are about 250,000 of them in the same directory. Seems to be running OK, no problematic CPU load, but I'm wondering if anyone knows whether I'm living dangerously having that many docs in one directory with that much activity. It is an extremely busy server. Sorry is this seems like more of a linux sysad question than a PHP question. Thanks... :) [/snip] Two words. Beware the inode. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] OK to have many files in one folder?
6/15/07, Jay Blanchard [EMAIL PROTECTED] wrote: [snip] Server is running Linux, and PHP is constantly creating and modifying images in a directory. Apache is constantly serving these same images. There are about 250,000 of them in the same directory. Seems to be running OK, no problematic CPU load, but I'm wondering if anyone knows whether I'm living dangerously having that many docs in one directory with that much activity. It is an extremely busy server. Sorry is this seems like more of a linux sysad question than a PHP question. Thanks... :) [/snip] Two words. Beware the inode. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php If that directory is all on one single partition, God help you if there's any corruption. Check into RAID 0+1/RAID 5 disk striping if you've got that many images. And remember, the fact that they're all in one directory doesn't matter at all to the system, as directories, folders, et cetera, are just representations for human readability and organization. In fact, those files reside on several sectors throughout the drive, and each file itself is probably fragmented many times. Just for fun, though, if you want to crash your server, you could always do: `while [ 1 = 1 ]; do ls -l;done` -- Daniel P. Brown [office] (570-) 587-7080 Ext. 272 [mobile] (570-) 766-8107 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] OK to have many files in one folder?
On Saturday 16 June 2007 02:51, Daniel Brown wrote: And remember, the fact that they're all in one directory doesn't matter at all to the system, as directories, folders, et cetera, are just representations for human readability and organization. In fact, those files reside on several sectors throughout the drive, and each file itself is probably fragmented many times. Actually it does matter depending on the filesystem you use. If you're using ext2/ext3 then having several thousand files in a directory seriously slows things down. -- Crayon -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] OK to have many files in one folder?
Thanks for the replies but I'm not sure I know what to do with them. Is the problem with the number of files, or is the problem with the activity? Can you dumb down your answers at all for me? :) On Jun 15, 2007, at 11:51 AM, Daniel Brown wrote: 6/15/07, Jay Blanchard [EMAIL PROTECTED] wrote: [snip] Server is running Linux, and PHP is constantly creating and modifying images in a directory. Apache is constantly serving these same images. There are about 250,000 of them in the same directory. Seems to be running OK, no problematic CPU load, but I'm wondering if anyone knows whether I'm living dangerously having that many docs in one directory with that much activity. It is an extremely busy server. Sorry is this seems like more of a linux sysad question than a PHP question. Thanks... :) [/snip] Two words. Beware the inode. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php If that directory is all on one single partition, God help you if there's any corruption. Check into RAID 0+1/RAID 5 disk striping if you've got that many images. And remember, the fact that they're all in one directory doesn't matter at all to the system, as directories, folders, et cetera, are just representations for human readability and organization. In fact, those files reside on several sectors throughout the drive, and each file itself is probably fragmented many times. Just for fun, though, if you want to crash your server, you could always do: `while [ 1 = 1 ]; do ls -l;done` -- Daniel P. Brown [office] (570-) 587-7080 Ext. 272 [mobile] (570-) 766-8107 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] OK to have many files in one folder?
On 6/15/07, Crayon Shin Chan [EMAIL PROTECTED] wrote: On Saturday 16 June 2007 02:51, Daniel Brown wrote: And remember, the fact that they're all in one directory doesn't matter at all to the system, as directories, folders, et cetera, are just representations for human readability and organization. In fact, those files reside on several sectors throughout the drive, and each file itself is probably fragmented many times. Actually it does matter depending on the filesystem you use. If you're using ext2/ext3 then having several thousand files in a directory seriously slows things down. -- Crayon -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php Once again, this doesn't matter so much for per-directory (though listing will take longer, as I think I mentioned) as it does the filesystem mount. The ext2/ext3 filesystems were made for these reasons, especially with journaling like ReiserFS, XFS, et cetera (which is a completely different bag of nuts). -- Daniel P. Brown [office] (570-) 587-7080 Ext. 272 [mobile] (570-) 766-8107 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] OK to have many files in one folder?
I can easily break it up into 100 subdirectories, 2500 files in each, would that be good insurance against problems? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] OK to have many files in one folder?
[snip] I can easily break it up into 100 subdirectories, 2500 files in each, would that be good insurance against problems? [/snip] As someone mentioned, directories are just a human convenience. Each file will have an inode and is identified by an inode number in the file system where it resides. Inodes store information on files such as user and group ownership, access mode (read, write, execute permissions) and type of file. There is a fixed number of inodes, which indicates the maximum number of files each filesystem can hold. Hence, beware the inode. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] OK to have many files in one folder?
On 6/15/07, Brian Dunning [EMAIL PROTECTED] wrote: I can easily break it up into 100 subdirectories, 2500 files in each, would that be good insurance against problems? I have no clue how big the files are, but you might want to store them in a database. That can speed up things, but don't ask me how much ;) Tijnema -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] OK to have many files in one folder?
On 6/15/07, Brian Dunning [EMAIL PROTECTED] wrote: Thanks for the replies but I'm not sure I know what to do with them. Is the problem with the number of files, or is the problem with the activity? Can you dumb down your answers at all for me? :) On Jun 15, 2007, at 11:51 AM, Daniel Brown wrote: 6/15/07, Jay Blanchard [EMAIL PROTECTED] wrote: [snip] Server is running Linux, and PHP is constantly creating and modifying images in a directory. Apache is constantly serving these same images. There are about 250,000 of them in the same directory. Seems to be running OK, no problematic CPU load, but I'm wondering if anyone knows whether I'm living dangerously having that many docs in one directory with that much activity. It is an extremely busy server. Sorry is this seems like more of a linux sysad question than a PHP question. Thanks... :) [/snip] Two words. Beware the inode. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php If that directory is all on one single partition, God help you if there's any corruption. Check into RAID 0+1/RAID 5 disk striping if you've got that many images. And remember, the fact that they're all in one directory doesn't matter at all to the system, as directories, folders, et cetera, are just representations for human readability and organization. In fact, those files reside on several sectors throughout the drive, and each file itself is probably fragmented many times. Just for fun, though, if you want to crash your server, you could always do: `while [ 1 = 1 ]; do ls -l;done` -- Daniel P. Brown [office] (570-) 587-7080 Ext. 272 [mobile] (570-) 766-8107 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php Brian, I stand behind my suggestion, though I also suggest you take whatever everyone else says into consideration just as much as me. I have well over a decade of experience, but I'll be the first to admit that sometimes a teenage computer geek is more correct than I am. Yes, list, believe it or not, I'm not always correct. I'm just going to let that sink in a little bit. Okay, now that everyone is done laughing at me (well, mostly everyone), let's get on with it. I still think it's best to split the files across a RAID. Ask your datacenter to discuss the pros and cons of both RAID 0+1 and RAID 5 with you, and research it on the web. It would be better to split the files into different directories, as well, but *probably* is not necessary. Take that as you will. That said, one way of doing it that is very common is to create a minimum of 36 directories, from 0 - 9 and a - z. Each directory should contain only files where the first character is the same as the directory within which it resides. However, if you have a specific character that comes up much more frequently than others, or even all the time, this won't work, of course. The point is, in my experience, holding even a terabyte of data in smaller files within one directory is not a Bad Thing [tm], per se. I've administered MySQL databases on servers that were in the two-to-three terabyte range, and one of which had well over 3,000 separate tables. Each of those tables is three separate files (minimum) on disk, mind you: table.frm, table.MYD, table.MYI. Also, keep in mind that I didn't create the database structure, but was instead hired to ensure that it ran smoothly. In the four months and n-million queries that were run on it while it was in use, the server responded as if it were a standard 50MB database in under a dozen files (if memory serves, it was a Dual Xeon 2.6GHz with 4GB RAM) and only used for MySQL). After the project was completed, however, we did upgrade the systems to a distributed network for further expansion, but I think you get the point there. Bottom line, however, is that just because you're not experiencing problems now doesn't mean you won't soon in the future. Seriously consider, with that many separate files and that much data, how much it's worth to you in the long run, and if a RAID setup and directory-splitting is a Good Thing [tm] for your situation. -- Daniel P. Brown [office] (570-) 587-7080 Ext. 272 [mobile] (570-) 766-8107 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] OK to have many files in one folder?
On 6/15/07, Jay Blanchard [EMAIL PROTECTED] wrote: [snip] I can easily break it up into 100 subdirectories, 2500 files in each, would that be good insurance against problems? [/snip] As someone mentioned, directories are just a human convenience. Each file will have an inode and is identified by an inode number in the file system where it resides. Inodes store information on files such as user and group ownership, access mode (read, write, execute permissions) and type of file. There is a fixed number of inodes, which indicates the maximum number of files each filesystem can hold. Hence, beware the inode. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php Perfect, Jay. That's something I forgot to mention. Also, keep in mind that, while there are file byte size limits (4GB, 8GB, etc.), directories are NOT limited in byte size. -- Daniel P. Brown [office] (570-) 587-7080 Ext. 272 [mobile] (570-) 766-8107 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] OK to have many files in one folder?
Since it depends on many factors, some out of your control, some others that might vary over the lifetime of the application, one thing you might do, to be on the safe side is try to put files in different directories, for example, by breaking up their filenames every three characters and making each segment a folder but no more than three levels deep so that the file ./abcdefghijkl.jpg would be located at ./abc/def/ghijkl.jpg. This breakup would allow even to mount extra disk volumes for some of the folders, should they exceed certain capacity or to split the risk. Whether to break filenames every two, three or more characters might be a matter of optimization, but I would guess that around three (or four) for the first two segments and whatever is left for the filename would be a reasonable number. I wouldn't go more than three levels deep either, because jumping from one directory level to the next also takes some time, thus it is a compromise in between searching sequentially in a directory for a filename (for those filesystems that do so) and going deep into the directory tree. Satyam - Original Message - From: Brian Dunning [EMAIL PROTECTED] To: php-general@lists.php.net Sent: Friday, June 15, 2007 9:38 PM Subject: Re: [PHP] OK to have many files in one folder? Thanks for the replies but I'm not sure I know what to do with them. Is the problem with the number of files, or is the problem with the activity? Can you dumb down your answers at all for me? :) On Jun 15, 2007, at 11:51 AM, Daniel Brown wrote: 6/15/07, Jay Blanchard [EMAIL PROTECTED] wrote: [snip] Server is running Linux, and PHP is constantly creating and modifying images in a directory. Apache is constantly serving these same images. There are about 250,000 of them in the same directory. Seems to be running OK, no problematic CPU load, but I'm wondering if anyone knows whether I'm living dangerously having that many docs in one directory with that much activity. It is an extremely busy server. Sorry is this seems like more of a linux sysad question than a PHP question. Thanks... :) [/snip] Two words. Beware the inode. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php If that directory is all on one single partition, God help you if there's any corruption. Check into RAID 0+1/RAID 5 disk striping if you've got that many images. And remember, the fact that they're all in one directory doesn't matter at all to the system, as directories, folders, et cetera, are just representations for human readability and organization. In fact, those files reside on several sectors throughout the drive, and each file itself is probably fragmented many times. Just for fun, though, if you want to crash your server, you could always do: `while [ 1 = 1 ]; do ls -l;done` -- Daniel P. Brown [office] (570-) 587-7080 Ext. 272 [mobile] (570-) 766-8107 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- No virus found in this incoming message. Checked by AVG Free Edition. Version: 7.5.472 / Virus Database: 269.8.16/849 - Release Date: 14/06/2007 12:44 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] OK to have many files in one folder?
On Saturday 16 June 2007 03:47, Daniel Brown wrote: Once again, this doesn't matter so much for per-directory (though listing will take longer, as I think I mentioned) as it does the filesystem mount. Several years ago, having say 3000+ files in single directory on ext2 would mean that a simple 'ls -al' takes several orders of magnitude longer to perform than on a directory with just several hundred files. As I haven't used ext2/3 for ages I don't know whether the same is still true today. The ext2/ext3 filesystems were made for these reasons, especially with journaling like ReiserFS, XFS, et cetera (which is a completely different bag of nuts). Not sure what point you're trying to make here, but, of the common filesystems for linux, ext2/3 is the absolute slowest (by far) when you have a large number of files in a directory. -- Crayon -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] OK to have many files in one folder?
Jay Blanchard wrote: [snip] Server is running Linux, and PHP is constantly creating and modifying images in a directory. Apache is constantly serving these same images. There are about 250,000 of them in the same directory. Seems to be running OK, no problematic CPU load, but I'm wondering if anyone knows whether I'm living dangerously having that many docs in one directory with that much activity. It is an extremely busy server. Sorry is this seems like more of a linux sysad question than a PHP question. Thanks... :) [/snip] Two words. Beware the inode. ^^ ^^^ ^ 1 23 Here endeth the lesson. -Stut -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] OK to have many files in one folder?
[snip] Two words. Beware the inode. ^^ ^^^ ^ 1 23 Here endeth the lesson. [/snip] Can I get an Admin brotha'!? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Ok next php problem
I got the previous question answered, Now here's my next problem.
With the numbers displaying correctly again I got:
1
2
3
4
5
6
7
10
11
12
13
14
15
16
17
18
19
20
21
22
25
listed in that order in the database
Now i'm trying to figure out how to write a syntax saying that if like number 8
isnt listed, display it.
I've tried doing a
if ($count != $data) {
echo $data;
}
$count++;
But when I get to like id number 9 it dont work right because the next entrie
is displayed as 10 in the db. So that's my problem is to try and display only
them numbers that are not in there. I have also tried putting the numbers in to
an array and matching from there but it still come's up as the same as above.
- Rob
Re: [PHP] Ok next php problem
Rob W. wrote: I got the previous question answered, Now here's my next problem. With the numbers displaying correctly again I got: 1 2 3 4 5 6 7 10 11 12 13 14 15 16 17 18 19 20 21 22 25 listed in that order in the database Now i'm trying to figure out how to write a syntax saying that if like number 8 isnt listed, display it. Get them both into arrays and compare: $good_list = range(1,10); $db_list = array(4,7,10); $missing = array_diff($good_list, $db_list); http://php.net/array_diff -- Postgresql php tutorials http://www.designmagick.com/ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Ok next php problem
Ok but my problem is is that in the process of doing that, numbers can be released so they pretty much haft to be dynamic. Any idea how I do it with that. IE: 1 2 3 6 9 10 ... So if them numbers change, which they can, because they are assigned port numbers for servers, How do I make it so they are not scripted statically. - Original Message - From: Chris [EMAIL PROTECTED] To: Rob W. [EMAIL PROTECTED] Cc: php-general@lists.php.net Sent: Sunday, June 18, 2006 8:38 PM Subject: Re: [PHP] Ok next php problem Rob W. wrote: I got the previous question answered, Now here's my next problem. With the numbers displaying correctly again I got: 1 2 3 4 5 6 7 10 11 12 13 14 15 16 17 18 19 20 21 22 25 listed in that order in the database Now i'm trying to figure out how to write a syntax saying that if like number 8 isnt listed, display it. Get them both into arrays and compare: $good_list = range(1,10); $db_list = array(4,7,10); $missing = array_diff($good_list, $db_list); http://php.net/array_diff -- Postgresql php tutorials http://www.designmagick.com/ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Ok next php problem
At 7:21 PM -0500 6/18/06, Rob W. wrote:
I got the previous question answered, Now here's my next problem.
With the numbers displaying correctly again I got:
1
2
3
4
5
6
7
10
11
12
13
14
15
16
17
18
19
20
21
22
25
listed in that order in the database
Now i'm trying to figure out how to write a syntax saying that if like number
8 isnt listed, display it.
I've tried doing a
if ($count != $data) {
echo $data;
}
$count++;
But when I get to like id number 9 it dont work right because the next entrie
is displayed as 10 in the db. So that's my problem is to try and display only
them numbers that are not in there. I have also tried putting the numbers in
to an array and matching from there but it still come's up as the same as
above.
- Rob
Rob:
Why?
If you want to show the number of records in your dB, then just show them. If
you want a counter, then add a counter but don't list the id number. Besides,
why would you want to anyway?
tedd
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Re: [PHP] Ok next php problem
Rob W. wrote: Ok but my problem is is that in the process of doing that, numbers can be released so they pretty much haft to be dynamic. Any idea how I do it with that. IE: 1 2 3 6 9 10 ... So if them numbers change, which they can, because they are assigned port numbers for servers, How do I make it so they are not scripted statically. That was an example only. See my next reply for an example of how to get the port from the db and go from there. Since we don't know your db structure, table names, field names I made it generic and you'll have to modify to suit your needs. -- Postgresql php tutorials http://www.designmagick.com/ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] GD text proc via php OK for local strings, but NOT for SESSION-passed strings. why?
On Fri, April 28, 2006 4:54 pm, OpenMacNews wrote: -BEGIN PGP SIGNED MESSAGE- in a given php file, this returns an image as expected: ... $word=blah; imagefttext($im, ... other params ... , $word); ... header (Content-type: image/png); imagepng($im); ... however, if rather than defining $word locally in the script, i $_SESSION['test']=blah; elsewhere, then: $word=$_SESSION['test']=blah; imagefttext($im, ... other params ... , $word); imagepng($im); i simply get a blank image. NO error in either the browser or my apache logs. a simple test with: echo $word; outputs blah as expected; i.e, the _SESSION var *is* passed. QUESTION: what's different about the string passed via SESSION? Just for fun, try it with imagestring. And, really, show us the image creation and whatnot. You've trimmed so much out, and we're going to have to second-guess you and think you just messed up creating the image in the second script, or that you got the arguments to the imagefttext() wrong, which is easy to do, since there are so many paramters on those image functions. And the bits you've trimmed out wouldn't make your post THAT much longer. A handful of lines more, if you keep it to a minimum. TIP: I always copy and paste the prototype line from the reference manual as a comment the line before my call to those image functions with many arguments -- Then I can better track what I'm typing. Yeah, those fancy IDEs can help too, but I'm an old-school vi kind of guy -- The IDEs with all the bells and whistles just get in my way more than they help. It's pretty hard to see how the string coming from the SESSION could matter... Though there WAS one RC version where, as I recall, SESSION strings were being passed out as, errr, references to strings, even though no such beast actually exists in PHP User Land... Altering the string would also alter the session data, which was very disconcerting. I don't see how that would apply here, mind you, but you could try this: $word = ''; $word .= $_SESSION['test']; The point being that by appending to an existing string, you can be sure it's a fresh string, and not a reference to the string. The bug I refer to was easily spotted by doing a var_dump on the data string. It showed string rather than just string, as I recall. (Or maybe it was string ) -- Like Music? http://l-i-e.com/artists.htm -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] GD text proc via php OK for local strings, but NOT for SESSION-passed strings. why?
-BEGIN PGP SIGNED MESSAGE- Hash: RIPEMD160 hi all, php-5.1.2 built from src on OSX 10.4.6. GD-2.0.33 + libpng-1.2.10 are built/enabled. GD is working fine ... locally. in a given php file, this returns an image as expected: ... $word=blah; imagefttext($im, ... other params ... , $word); ... header (Content-type: image/png); imagepng($im); ... however, if rather than defining $word locally in the script, i $_SESSION['test']=blah; elsewhere, then: $word=$_SESSION['test']=blah; imagefttext($im, ... other params ... , $word); imagepng($im); i simply get a blank image. NO error in either the browser or my apache logs. a simple test with: echo $word; outputs blah as expected; i.e, the _SESSION var *is* passed. QUESTION: what's different about the string passed via SESSION? thx! richard - -- /\ \ / ASCII Ribbon Campaign X against HTML email, vCards / \ micro$oft attachments [GPG] OpenMacNews at gmail dot com fingerprint: 50C9 1C46 2F8F DE42 2EDB D460 95F7 DDBD 3671 08C6 -BEGIN PGP SIGNATURE- Version: GnuPG v1.4.3 (Darwin) iEYEAREDAAYFAkRSjyEACgkQlffdvTZxCMZz/ACgvI60Zm6JfUDnczpOl3gpNLjj ObMAoLOobf7h7CGuD6dX7Rz2KRV/9vsf =Znuf -END PGP SIGNATURE- -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Ok, why is this happening...
On Tue, July 19, 2005 10:26 am, John Nichel said:
There's some freaky math going on there or something. I added a couple
of other echos in to see and for some reason it seems to be losing
single digit value (subtracting, rounding down, I don't know).
$calculatedGross = $originalNet + ( $originalNet * $commissionPct * 0.01
);
echo ( Gross : . (int)$calculatedGross . = . $originalNet . + ( .
$originalNet . * . $commissionPct . *.01 )br /\n );
$calculatedNet= $calculatedGross / ( 1 + ( $commissionPct * 0.01 ));
echo ( Net : . (int)$calculatedNet. = . (int)$calculatedGross .
/ ( 1 + ( . $commissionPct . * .01 ) )br /\n );
Floating point mathematics is inherently unreliable in computers.
Consider, for example, 1/3 in decimal notation:
1.33...
PHP can only write so many digits down in a 32-bit floating point
representation, just as you can only write down so many digits before your
hand cramps up or you run out of paper or you get lazy and put ... on
the end. :-)
Now, the thing to remember is, the problem won't appear where you expect
it to from your experience with DECIMAL numbers all your life because
floating point numbers are being stored in a binary/hexidecimal notation.
If you are feeling particularly masochistic, you can Google for floating
point internal representation mantissa exponent and you're gonna find out
EXACTLY how those numbers get stored. Set aside a good chunk of time to
absorb it all... :-)
Even something as simple as:
?php
$foo = (float) 2;
echo $foo;
?
could, in theory, print out something like:
1.
and be correct as far as Computer Science is concerned.
If you need PRECISE mathematics, you should use integer and count pennies
instead of dollars -- or even 1/10th of pennies or whatever resolution you
need.
Of course, every step you take on the right, you can only store 1/10th as
large a number of dollars as your maximum amount. But you are starting
with 2 billion as your max, so that's a lot of room to play with.
If you *need* float numbers and precision out to decimal point N, look
into BC_MATH and that new-fangled Math package PHP has for this very
reason. You'll still be dealing with this issue, but you'll know your
numbers are accurate to the Nth decimal point, and it will be painfully
obvious in your code that it is so. [It will also be SLOWER than just
plain float numbers.]
If you just don't care about the damn penny, but want your code to work,
something like:
if (1.00 = $x $x = 1.01){
// $x == 1, really
}
may suffice for your everyday work-a-day computing needs...
Though that can also turn into a lot more problems than you think, down
the line...
Remember 2nd Grade when long division was tricky? Yeah, well, computers
are a hell of a lot more stupid than 2nd Graders, any day of the week.
Note that there *ARE* computer languages where are prefectly happy to work
in fractions (Lisp is one such language) because somebody has programmed
the algebraic rules of fraction arithmetic into the language:
(let ((x 1/3)
(y 2/3))
(print (+ x y))
will cheefully and with 100% accuracy print out 1 every single time.
[Apologies to Guy Steele if my 10-years-unused Lisp syntax is not spot on.]
Lisp stores fractions as 2 integers, not as floating point numbers.
[Though of course you can ask it to convert and round off if you like.]
You could, if you so desired, whip up a PHP class fraction { code-base,
or even just store fractions as 2-element arrays (numerator, denominator)
and write some procedural functions to work with them.
It's not exactly Rocket Science to do that.
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[PHP] Ok, why is this happening...
Consider the following test script:
script language=php
set_time_limit( 0 );
echo 'html';
echo 'headtitleTest Rounding Net Premium/title/head';
echo 'body';
echo 'Running test...br';
flush();
echo 'table';
echo 'tr';
echo 'tdOriginal Net/td';
echo 'tdCommission %/td';
echo 'tdCalculated Gross/td';
echo 'tdCalculated Net/td';
echo '/tr';
$numberOfFailures = 0;
for( $originalNet = 1; $originalNet = 10005; $originalNet++ ) {
for( $commissionPct = 1; $commissionPct = 20; ( $commissionPct += .1 ))
{
$calculatedGross = $originalNet + ( $originalNet * $commissionPct *
.01 );
$calculatedNet= $calculatedGross / ( 1 + ( $commissionPct *
.01 ));
echo if( $originalNet != $calculatedNet ) = . ( (int)$originalNet !==
(int)$calculatedNet ) . br\n;
if( (int)$originalNet !== (int)$calculatedNet ) {
$numberOfFailures++;
echo 'tr';
echo 'td' . $originalNet . '/td';
echo 'td' . $commissionPct . '%/td';
echo 'td' . $calculatedGross . '/td';
echo 'td' . $calculatedNet . '/td';
echo '/tr';
flush();
}
}
}
echo '/table';
if( 0 $numberOfFailures ) {
echo number_format( $numberOfFailures ) . ' calculations failed to match
the original net premium.br';
}
echo '/body';
echo '/html';
/script
Why is the if( (int)$originalNet !== (int)$calculatedNet ) failing some
times even though they are the exact same value? I've tried using just
the != comparison operator, I've tried casting the values (as seen above)
I've tried testing to see if the values are either less than or greater than
one another (as a test for inequality). I just can't figure out why in the
world the IF is showing the values are inequal when you can view the
output and see they are exactly equal. What's going on?
thnx,
Chris
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Re: [PHP] Ok, why is this happening...
Chris Boget wrote: snip echo if( $originalNet != $calculatedNet ) = . ( (int)$originalNet !== (int)$calculatedNet ) . br\n; /snip Change this to echo out what you're comparing... echo if( . (int)$originalNet . != . (int)$calculatedNet . ) = . ( (int)$originalNet !== (int)$calculatedNet ) . br\n; That'll show what numbers is actually trying to match. -- John C. Nichel ÜberGeek KegWorks.com 716.856.9675 [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Ok, why is this happening...
Chris Boget wrote: snip echo if( $originalNet != $calculatedNet ) = . ( (int)$originalNet !== (int)$calculatedNet ) . br\n; /snip Change this to echo out what you're comparing... echo if( . (int)$originalNet . != . (int)$calculatedNet . ) = . ( (int)$originalNet !== (int)$calculatedNet ) . br\n; That'll show what numbers is actually trying to match. Ok, then that begs the following questions: If I don't cast any of the values, why do they display as being identicle? Additionally, why does every IF check fail in that case? thnx, Chris -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Ok, why is this happening...
Chris Boget wrote: Chris Boget wrote: snip echo if( $originalNet != $calculatedNet ) = . ( (int)$originalNet !== (int)$calculatedNet ) . br\n; /snip Change this to echo out what you're comparing... echo if( . (int)$originalNet . != . (int)$calculatedNet . ) = . ( (int)$originalNet !== (int)$calculatedNet ) . br\n; That'll show what numbers is actually trying to match. Ok, then that begs the following questions: If I don't cast any of the values, why do they display as being identicle? Additionally, why does every IF check fail in that case? There's some freaky math going on there or something. I added a couple of other echos in to see and for some reason it seems to be losing single digit value (subtracting, rounding down, I don't know). $calculatedGross = $originalNet + ( $originalNet * $commissionPct * 0.01 ); echo ( Gross : . (int)$calculatedGross . = . $originalNet . + ( . $originalNet . * . $commissionPct . *.01 )br /\n ); $calculatedNet= $calculatedGross / ( 1 + ( $commissionPct * 0.01 )); echo ( Net : . (int)$calculatedNet. = . (int)$calculatedGross . / ( 1 + ( . $commissionPct . * .01 ) )br /\n ); -- John C. Nichel ÜberGeek KegWorks.com 716.856.9675 [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Ok, why is this happening...
Hi I admit not gone trough all of your code, but mostly this happens when mixing the string concatenation operator (.) with the addition (+) or substraction (-) operator. HTH With kind regards Andy On Tuesday 19 July 2005 19:26, John Nichel wrote: Chris Boget wrote: Chris Boget wrote: snip echo if( $originalNet != $calculatedNet ) = . ( (int)$originalNet !== (int)$calculatedNet ) . br\n; /snip Change this to echo out what you're comparing... echo if( . (int)$originalNet . != . (int)$calculatedNet . ) = . ( (int)$originalNet !== (int)$calculatedNet ) . br\n; That'll show what numbers is actually trying to match. Ok, then that begs the following questions: If I don't cast any of the values, why do they display as being identicle? Additionally, why does every IF check fail in that case? There's some freaky math going on there or something. I added a couple of other echos in to see and for some reason it seems to be losing single digit value (subtracting, rounding down, I don't know). $calculatedGross = $originalNet + ( $originalNet * $commissionPct * 0.01 ); echo ( Gross : . (int)$calculatedGross . = . $originalNet . + ( . $originalNet . * . $commissionPct . *.01 )br /\n ); $calculatedNet= $calculatedGross / ( 1 + ( $commissionPct * 0.01 )); echo ( Net : . (int)$calculatedNet. = . (int)$calculatedGross . / ( 1 + ( . $commissionPct . * .01 ) )br /\n ); -- John C. Nichel ÜberGeek KegWorks.com 716.856.9675 [EMAIL PROTECTED] -- Registered Linux User Number 379093 Cockroaches and socialites are the only things that can stay up all night and eat anything. Herb Caen -- -- --BEGIN GEEK CODE BLOCK- Version: 3.1 GAT/O/E$ d-(---)+ s:(+): a--(-)? C$(+++) UL$ P-(+)++ L+++$ E---(-)@ W++$ !N@ o? !K? W--(---) !O !M- V-- PS++(+++) PE--(-) Y+ PGP++(+++) t+(++) 5-- X++ R*(+)@ !tv b-() DI(+) D+(+++) G(+) e$@ h++(*) r--++ y--() -- ---END GEEK CODE BLOCK-- -- Check out these few php utilities that I released under the GPL2 and that are meant for use with a php cli binary: http://www.vlaamse-kern.com/sas/ -- -- pgptzLlv5o2r7.pgp Description: PGP signature
RE: [PHP] OK ... WHY does this work ?????
Read over some of the examples at:
http://us4.php.net/types.array
If you don't set a key, PHP starts with '0' and increments as you add
more elements to the array.
If you have NOTICEs turned on, I believe you'll get a notice saying
that $arrlevels[99] doesn't exist. It's not a fatal error, so PHP just
passes over it and doesn't say anything unless you tell it to.
# One dimensional array
$arrlevels = array(1,2,3);
# Three dimensional array. $lvl_guest is a key and 'levelname' is a key
$arrlevels[$lvl_guest]['levelname'];
-TG
On Tue, 14 Sep 2004 22:32:54 +0200, -{ Rene Brehmer }-
[EMAIL PROTECTED] wrote:
Unless I misunderstand how PHP make unspecified arrays (and
I probably do
since this works), when you have an array of 3 elements on the first
dimenstion like I do, and then ask for
$arrlevels[$lvl_guest]['levelname'],
which in this case actually means it asks for
$arrlevels[99]['levelname']
how come it pick the correct element, and not error
out that element
99 don't exist ??
My only conclusion (based on the fact that this actually
works) is that PHP
makes the key the same as the value if the key isn't
specified. But is this
actually correct Or is there something going on that
I don't know
about ???
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[PHP] OK ... WHY does this work ?????
This is some experimental code I did to try and find a way to recycle the
same query multiple times as efficient as possible. With the purpose of
efficiently comparing the results of 2 queries where the resultset from
both queries won't match in the size (in this sample test it coincidently
does, but I've tried with a variant where it doesn't, and it works just as
beautiful). Although it's nice that it actually works like intended, I'm a
little baffled to exactly WHY it works (this being why the 2 dimensional
array I build actually works like intended). I tried looking through the
manual to find how PHP build the associate arrays when no key is specified,
but came out empty. So if anyone can explain how this come to function like
intended despite immediate logic dictating it shouldn't, I'd really
appreciate it ... I hate when I get the code to work, but don't get why it
works...
This is the code (pieced together from much larger script ... that does
lots more than this in between:
?php
// global data pull of base configuration
$config_query = SELECT setting,value FROM hf_config;
$config = mysql_query($config_query) or die('Unable to get base
configurationbr'.mysql_error());
while ($config_data = mysql_fetch_array($config)) {
if ($config_data['setting'] == 'admin_level') {
$lvl_admin = $config_data['value'];
} elseif ($config_data['setting'] == 'new_member_level') {
$lvl_new = $config_data['value'];
} elseif ($config_data['setting'] == 'guest_level') {
$lvl_guest = $config_data['value'];
}
}
// load levels and build array
$level_query = SELECT levelID,levelname,description FROM hf_levels ORDER
BY `levelorder` ASC;
$levels = mysql_query($level_query);
while ($leveldata = mysql_fetch_array($levels)) {
$arrlevels[$leveldata['levelID']] = array('levelname' =
$leveldata['levelname'],
'description' = $leveldata['description']);
}
?
table
tr
td colspan=3 class=adm_titleGeneral configuration/td
/trtr
td class=adm_subtitleAdministrator level/td
td class=adm_regular?php echo($lvl_admin.' -
'.$arrlevels[$lvl_admin]['levelname']); ?/td
td/td
/trtr
td class=adm_subtitleNew member level/td
td class=adm_regular?php echo($lvl_new.' -
'.$arrlevels[$lvl_new]['levelname']); ?/td
/trtr
td class=adm_subtitleGuest level/td
td class=adm_regular?php echo($lvl_guest.' -
'.$arrlevels[$lvl_guest]['levelname']); ?/td
/tr
/table
The query results look like this:
mysql SELECT setting,value FROM hf_config;
+--+---+
| setting | value |
+--+---+
| admin_level | 1 |
| new_member_level | 50|
| guest_level | 99|
+--+---+
3 rows in set (0.00 sec)
mysql SELECT levelID,levelname,description FROM hf_levels ORDER BY
`levelorder`
ASC;
+-++---+
| levelID | levelname | description |
+-++---+
| 1 | Admin | System administrators |
| 50 | New member | new members |
| 99 | Guest | Guest users |
+-++---+
3 rows in set (0.00 sec)
Output of the script looks like this:
General configuration
Administrator level 1 - Admin
New member level 50 - New member
Guest level 99 - Guest
Unless I misunderstand how PHP make unspecified arrays (and I probably do
since this works), when you have an array of 3 elements on the first
dimenstion like I do, and then ask for $arrlevels[$lvl_guest]['levelname'],
which in this case actually means it asks for $arrlevels[99]['levelname']
how come it pick the correct element, and not error out that element
99 don't exist ??
My only conclusion (based on the fact that this actually works) is that PHP
makes the key the same as the value if the key isn't specified. But is this
actually correct Or is there something going on that I don't know
about ???
I've got another sample, that uses the same query recycling method, but
with much, much more complex database queries, and it works just as
perfectly well
I really just wanna understand why this actually work, and how ... it can
be rather confusing to stumble across a useful functionality and solution
when you're still learning how to do the more complex things in PHP.
--
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aka Metalbunny
If your life was a dream, would you wake up from a nightmare, dripping of
sweat, hoping it was over? Or would you wake up happy and pleased, ready to
take on the day with a smile?
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Check out the new Metalbunny forums at http://forums.metalbunny.net/
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Re: [PHP] OK ... WHY does this work ?????
On Tue, 14 Sep 2004 22:32:54 +0200, -{ Rene Brehmer }-
[EMAIL PROTECTED] wrote:
Unless I misunderstand how PHP make unspecified arrays (and I probably do
since this works), when you have an array of 3 elements on the first
dimenstion like I do, and then ask for $arrlevels[$lvl_guest]['levelname'],
which in this case actually means it asks for $arrlevels[99]['levelname']
how come it pick the correct element, and not error out that element
99 don't exist ??
My only conclusion (based on the fact that this actually works) is that PHP
makes the key the same as the value if the key isn't specified. But is this
actually correct Or is there something going on that I don't know
about ???
Yes, that is what's happening, a simple test shows this:
#!/usr/bin/php
?php
$a = array(1, 2, 3);
print_r($a);
?
output:
Array
(
[0] = 1
[1] = 2
[2] = 3
)
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Re: [PHP] OK SQL experts...
I think you want to remove the single quotes around the field names.
SELECT * FROM my_table WHERE (field_1 LIKE '%$keyword%' OR
field_2 LIKE '%$keyword%' OR field_3 LIKE '%$keyword%') AND
status = 'active';
I STFW and RTFM and I still can't figure out why this returns a 1064
parse error:
SELECT * FROM 'my_table' WHERE ('field_1' LIKE '%$keyword%' OR
'field_2' LIKE '%$keyword%' OR 'field_3' LIKE '%$keyword%') AND
'status' = 'active';
Anyone? TIA!
- B1ff Lamer
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Re: [PHP] OK SQL experts...
The parenthesis are OK. The query might take a long time to run with 3 LIKE
statements.
Backticks, single quotes, or nothing at all makes no difference. I
believe the parsing error is due to my parentheses or AND/OR structure.
Any thoughts on that?
On Apr 23, 2004, at 8:32 AM, John W. Holmes wrote:
From: Brian Dunning [EMAIL PROTECTED]
I STFW and RTFM and I still can't figure out why this returns a 1064
parse error:
SELECT * FROM 'my_table' WHERE ('field_1' LIKE '%$keyword%' OR
'field_2' LIKE '%$keyword%' OR 'field_3' LIKE '%$keyword%') AND
'status' = 'active';
[PHP] OK SQL experts...
I STFW and RTFM and I still can't figure out why this returns a 1064
parse error:
SELECT * FROM 'my_table' WHERE ('field_1' LIKE '%$keyword%' OR
'field_2' LIKE '%$keyword%' OR 'field_3' LIKE '%$keyword%') AND
'status' = 'active';
Anyone? TIA!
- B1ff Lamer
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RE: [PHP] OK SQL experts...
why are the table and field names surrounded by single quotes?
-Original Message-
From: Brian Dunning [mailto:[EMAIL PROTECTED]
Sent: Friday, April 23, 2004 11:19 AM
To: [EMAIL PROTECTED]
Subject: [PHP] OK SQL experts...
I STFW and RTFM and I still can't figure out why this returns a 1064
parse error:
SELECT * FROM 'my_table' WHERE ('field_1' LIKE '%$keyword%' OR
'field_2' LIKE '%$keyword%' OR 'field_3' LIKE '%$keyword%') AND
'status' = 'active';
Anyone? TIA!
- B1ff Lamer
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Re: [PHP] OK SQL experts...
I tried it both ways - didn't make any difference (phpmyadmin adds the
single quotes when I was trying to use its sql function to debug, so I
figured what the hell)...
On Apr 23, 2004, at 8:27 AM, Edward Peloke wrote:
why are the table and field names surrounded by single quotes?
-Original Message-
From: Brian Dunning [mailto:[EMAIL PROTECTED]
Sent: Friday, April 23, 2004 11:19 AM
To: [EMAIL PROTECTED]
Subject: [PHP] OK SQL experts...
I STFW and RTFM and I still can't figure out why this returns a 1064
parse error:
SELECT * FROM 'my_table' WHERE ('field_1' LIKE '%$keyword%' OR
'field_2' LIKE '%$keyword%' OR 'field_3' LIKE '%$keyword%') AND
'status' = 'active';
Anyone? TIA!
- B1ff Lamer
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- Brian
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RE: [PHP] OK SQL experts...
[snip] I tried it both ways - didn't make any difference (phpmyadmin adds the single quotes when I was trying to use its sql function to debug, so I figured what the hell)... [/snip] Those aren't single quotes it adds to table and column names...those are back tics (on the same key as the tilde) If you chnage those you should be OK. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] OK SQL experts...
does it just return the error when running in the php page? If you pull it
out can you run it in mysql without errors?
-Original Message-
From: Brian Dunning [mailto:[EMAIL PROTECTED]
Sent: Friday, April 23, 2004 11:23 AM
To: [EMAIL PROTECTED]
Subject: Re: [PHP] OK SQL experts...
I tried it both ways - didn't make any difference (phpmyadmin adds the
single quotes when I was trying to use its sql function to debug, so I
figured what the hell)...
On Apr 23, 2004, at 8:27 AM, Edward Peloke wrote:
why are the table and field names surrounded by single quotes?
-Original Message-
From: Brian Dunning [mailto:[EMAIL PROTECTED]
Sent: Friday, April 23, 2004 11:19 AM
To: [EMAIL PROTECTED]
Subject: [PHP] OK SQL experts...
I STFW and RTFM and I still can't figure out why this returns a 1064
parse error:
SELECT * FROM 'my_table' WHERE ('field_1' LIKE '%$keyword%' OR
'field_2' LIKE '%$keyword%' OR 'field_3' LIKE '%$keyword%') AND
'status' = 'active';
Anyone? TIA!
- B1ff Lamer
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- Brian
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Re: [PHP] OK SQL experts...
It gives the same error when I run it in phpmyadmin.
On Apr 23, 2004, at 8:34 AM, Edward Peloke wrote:
does it just return the error when running in the php page? If you
pull it
out can you run it in mysql without errors?
-Original Message-
From: Brian Dunning [mailto:[EMAIL PROTECTED]
Sent: Friday, April 23, 2004 11:23 AM
To: [EMAIL PROTECTED]
Subject: Re: [PHP] OK SQL experts...
I tried it both ways - didn't make any difference (phpmyadmin adds the
single quotes when I was trying to use its sql function to debug, so I
figured what the hell)...
On Apr 23, 2004, at 8:27 AM, Edward Peloke wrote:
why are the table and field names surrounded by single quotes?
-Original Message-
From: Brian Dunning [mailto:[EMAIL PROTECTED]
Sent: Friday, April 23, 2004 11:19 AM
To: [EMAIL PROTECTED]
Subject: [PHP] OK SQL experts...
I STFW and RTFM and I still can't figure out why this returns a 1064
parse error:
SELECT * FROM 'my_table' WHERE ('field_1' LIKE '%$keyword%' OR
'field_2' LIKE '%$keyword%' OR 'field_3' LIKE '%$keyword%') AND
'status' = 'active';
Anyone? TIA!
- B1ff Lamer
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Re: [PHP] OK SQL experts...
AFAIK phpMyAdmin uses backticks for table/field names, not single
quotes ...
Friday, April 23, 2004, 5:22:35 PM, thus was written:
I tried it both ways - didn't make any difference (phpmyadmin adds the
single quotes when I was trying to use its sql function to debug, so I
figured what the hell)...
On Apr 23, 2004, at 8:27 AM, Edward Peloke wrote:
why are the table and field names surrounded by single quotes?
-Original Message-
From: Brian Dunning [mailto:[EMAIL PROTECTED]
Sent: Friday, April 23, 2004 11:19 AM
To: [EMAIL PROTECTED]
Subject: [PHP] OK SQL experts...
I STFW and RTFM and I still can't figure out why this returns a 1064
parse error:
SELECT * FROM 'my_table' WHERE ('field_1' LIKE '%$keyword%' OR
'field_2' LIKE '%$keyword%' OR 'field_3' LIKE '%$keyword%') AND
'status' = 'active';
Anyone? TIA!
- B1ff Lamer
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Re: [PHP] OK SQL experts...
From: Brian Dunning [EMAIL PROTECTED]
I STFW and RTFM and I still can't figure out why this returns a 1064
parse error:
SELECT * FROM 'my_table' WHERE ('field_1' LIKE '%$keyword%' OR
'field_2' LIKE '%$keyword%' OR 'field_3' LIKE '%$keyword%') AND
'status' = 'active';
Use backticks around table and column names, not single quotes.
---John Holmes...
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Re: [PHP] OK SQL experts...
Backticks, single quotes, or nothing at all makes no difference. I
believe the parsing error is due to my parentheses or AND/OR structure.
Any thoughts on that?
On Apr 23, 2004, at 8:32 AM, John W. Holmes wrote:
From: Brian Dunning [EMAIL PROTECTED]
I STFW and RTFM and I still can't figure out why this returns a 1064
parse error:
SELECT * FROM 'my_table' WHERE ('field_1' LIKE '%$keyword%' OR
'field_2' LIKE '%$keyword%' OR 'field_3' LIKE '%$keyword%') AND
'status' = 'active';
Use backticks around table and column names, not single quotes.
---John Holmes...
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RE: [PHP] OK SQL experts...
SELECT * FROM 'my_table' WHERE ('field_1' LIKE '%$keyword%' OR
'field_2' LIKE '%$keyword%' OR 'field_3' LIKE '%$keyword%') AND
'status' = 'active';
Longshot but try to remove the ' ' from around the field names in the
where statement..
Or
SELECT * FROM My_Table
WHERE field_1 like '%$keyword%' status = 'active'
|| field_2 like '%$keyword%' status = 'active'
|| field_3 like '%$keyword%' status = 'active'
Jeff
-Original Message-
From: Brian Dunning [mailto:[EMAIL PROTECTED]
Sent: Friday, April 23, 2004 11:30 AM
To: [EMAIL PROTECTED]
Subject: Re: [PHP] OK SQL experts...
It gives the same error when I run it in phpmyadmin.
On Apr 23, 2004, at 8:34 AM, Edward Peloke wrote:
does it just return the error when running in the php page? If you
pull it
out can you run it in mysql without errors?
-Original Message-
From: Brian Dunning [mailto:[EMAIL PROTECTED]
Sent: Friday, April 23, 2004 11:23 AM
To: [EMAIL PROTECTED]
Subject: Re: [PHP] OK SQL experts...
I tried it both ways - didn't make any difference
(phpmyadmin adds the
single quotes when I was trying to use its sql function to
debug, so I
figured what the hell)...
On Apr 23, 2004, at 8:27 AM, Edward Peloke wrote:
why are the table and field names surrounded by single quotes?
-Original Message-
From: Brian Dunning [mailto:[EMAIL PROTECTED]
Sent: Friday, April 23, 2004 11:19 AM
To: [EMAIL PROTECTED]
Subject: [PHP] OK SQL experts...
I STFW and RTFM and I still can't figure out why this
returns a 1064
parse error:
SELECT * FROM 'my_table' WHERE ('field_1' LIKE '%$keyword%' OR
'field_2' LIKE '%$keyword%' OR 'field_3' LIKE '%$keyword%') AND
'status' = 'active';
Anyone? TIA!
- B1ff Lamer
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RE: [PHP] OK SQL experts...
[snip]
SELECT * FROM 'my_table' WHERE ('field_1' LIKE '%$keyword%' OR
'field_2' LIKE '%$keyword%' OR 'field_3' LIKE '%$keyword%') AND
'status' = 'active';
[/snip]
How about this?
SELECT * FROM my_table WHERE (field_1 LIKE '%$keyword%' OR
field_2 LIKE '%$keyword%' OR field_3 LIKE '%$keyword%') AND
status = 'active';
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RE: [PHP] OK SQL experts...
what value is being put in the $keyword variable? You are sure all these
columns exist?
-Original Message-
From: Brian Dunning [mailto:[EMAIL PROTECTED]
Sent: Friday, April 23, 2004 11:36 AM
To: [EMAIL PROTECTED]
Subject: Re: [PHP] OK SQL experts...
Backticks, single quotes, or nothing at all makes no difference. I
believe the parsing error is due to my parentheses or AND/OR structure.
Any thoughts on that?
On Apr 23, 2004, at 8:32 AM, John W. Holmes wrote:
From: Brian Dunning [EMAIL PROTECTED]
I STFW and RTFM and I still can't figure out why this returns a 1064
parse error:
SELECT * FROM 'my_table' WHERE ('field_1' LIKE '%$keyword%' OR
'field_2' LIKE '%$keyword%' OR 'field_3' LIKE '%$keyword%') AND
'status' = 'active';
Use backticks around table and column names, not single quotes.
---John Holmes...
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RE: [PHP] OK SQL experts...
if you echo out the query..what is the output?
-Original Message-
From: Brian Dunning [mailto:[EMAIL PROTECTED]
Sent: Friday, April 23, 2004 11:36 AM
To: [EMAIL PROTECTED]
Subject: Re: [PHP] OK SQL experts...
Backticks, single quotes, or nothing at all makes no difference. I
believe the parsing error is due to my parentheses or AND/OR structure.
Any thoughts on that?
On Apr 23, 2004, at 8:32 AM, John W. Holmes wrote:
From: Brian Dunning [EMAIL PROTECTED]
I STFW and RTFM and I still can't figure out why this returns a 1064
parse error:
SELECT * FROM 'my_table' WHERE ('field_1' LIKE '%$keyword%' OR
'field_2' LIKE '%$keyword%' OR 'field_3' LIKE '%$keyword%') AND
'status' = 'active';
Use backticks around table and column names, not single quotes.
---John Holmes...
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Re: [PHP] OK SQL experts...
Yes, I've checked and rechecked the spelling on everything. I've been
testing with a word that I know appears in at least one of the fields.
On Apr 23, 2004, at 8:54 AM, Edward Peloke wrote:
what value is being put in the $keyword variable? You are sure all
these
columns exist?
-Original Message-
From: Brian Dunning [mailto:[EMAIL PROTECTED]
Sent: Friday, April 23, 2004 11:36 AM
To: [EMAIL PROTECTED]
Subject: Re: [PHP] OK SQL experts...
Backticks, single quotes, or nothing at all makes no difference. I
believe the parsing error is due to my parentheses or AND/OR structure.
Any thoughts on that?
On Apr 23, 2004, at 8:32 AM, John W. Holmes wrote:
From: Brian Dunning [EMAIL PROTECTED]
I STFW and RTFM and I still can't figure out why this returns a 1064
parse error:
SELECT * FROM 'my_table' WHERE ('field_1' LIKE '%$keyword%' OR
'field_2' LIKE '%$keyword%' OR 'field_3' LIKE '%$keyword%') AND
'status' = 'active';
Use backticks around table and column names, not single quotes.
---John Holmes...
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Re: [PHP] OK SQL experts...
phpmyadmin echoes it out exactly as I copied pasted into my first
post.
On Apr 23, 2004, at 8:56 AM, Edward Peloke wrote:
if you echo out the query..what is the output?
-Original Message-
From: Brian Dunning [mailto:[EMAIL PROTECTED]
Sent: Friday, April 23, 2004 11:36 AM
To: [EMAIL PROTECTED]
Subject: Re: [PHP] OK SQL experts...
Backticks, single quotes, or nothing at all makes no difference. I
believe the parsing error is due to my parentheses or AND/OR structure.
Any thoughts on that?
On Apr 23, 2004, at 8:32 AM, John W. Holmes wrote:
From: Brian Dunning [EMAIL PROTECTED]
I STFW and RTFM and I still can't figure out why this returns a 1064
parse error:
SELECT * FROM 'my_table' WHERE ('field_1' LIKE '%$keyword%' OR
'field_2' LIKE '%$keyword%' OR 'field_3' LIKE '%$keyword%') AND
'status' = 'active';
Use backticks around table and column names, not single quotes.
---John Holmes...
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Re: [PHP] OK SQL experts...
--- Brian Dunning [EMAIL PROTECTED] wrote:
Yes, I've checked and rechecked the spelling on everything. I've
been
testing with a word that I know appears in at least one of the
fields.
I'm coming in a bit late, but have you tried echoing out the query
variable contents and copying and pasting that to the MySQL command
line?
Also, any chance you could post the table decription?
On Apr 23, 2004, at 8:54 AM, Edward Peloke wrote:
what value is being put in the $keyword variable? You are sure
all
these
columns exist?
-Original Message-
From: Brian Dunning [mailto:[EMAIL PROTECTED]
Sent: Friday, April 23, 2004 11:36 AM
To: [EMAIL PROTECTED]
Subject: Re: [PHP] OK SQL experts...
Backticks, single quotes, or nothing at all makes no difference.
I
believe the parsing error is due to my parentheses or AND/OR
structure.
Any thoughts on that?
On Apr 23, 2004, at 8:32 AM, John W. Holmes wrote:
From: Brian Dunning [EMAIL PROTECTED]
I STFW and RTFM and I still can't figure out why this returns a
1064
parse error:
SELECT * FROM 'my_table' WHERE ('field_1' LIKE '%$keyword%' OR
'field_2' LIKE '%$keyword%' OR 'field_3' LIKE '%$keyword%') AND
'status' = 'active';
Use backticks around table and column names, not single quotes.
---John Holmes...
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=
Mark Weinstock
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defend everyone else's right to the same thing.
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RE: [PHP] OK SQL experts...
I STFW and RTFM and I still can't figure out why this returns a 1064
parse error:
SELECT * FROM 'my_table' WHERE ('field_1' LIKE '%$keyword%' OR
'field_2' LIKE '%$keyword%' OR 'field_3' LIKE '%$keyword%') AND
'status' = 'active';
Why don't you try rebuilding the query. I mean go into phpmyadmin and
issue select * from `my_table` if that works. Then add on one where
clause
Select * FROM `my_table` WHERE (`field_1 LIKE '%key%' ) , and just put
it back together piece by piece until it breaks. That should at least
help narrow down what is breaking.
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RE: [PHP] OK SQL experts...
[snip]
SELECT * FROM 'my_table' WHERE ('field_1' LIKE '%$keyword%' OR
'field_2' LIKE '%$keyword%' OR 'field_3' LIKE '%$keyword%') AND
'status' = 'active';
[/snip]
*slaps forehead*
SELECT * FROM my_table WHERE (field_1 LIKE '% . $keyword . %' OR
field_2 LIKE '% . $keyword . %' OR field_3 LIKE '% . $keyword . %')
AND
status = 'active';
The single quoted variables do not get parsed
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Re: [PHP] OK SQL experts...
I don't have access to the MySQL command line; it's hosted at my ISP.
:(
On Apr 23, 2004, at 8:54 AM, Mark wrote:
--- Brian Dunning [EMAIL PROTECTED] wrote:
Yes, I've checked and rechecked the spelling on everything. I've
been
testing with a word that I know appears in at least one of the
fields.
I'm coming in a bit late, but have you tried echoing out the query
variable contents and copying and pasting that to the MySQL command
line?
Also, any chance you could post the table decription?
On Apr 23, 2004, at 8:54 AM, Edward Peloke wrote:
what value is being put in the $keyword variable? You are sure
all
these
columns exist?
-Original Message-
From: Brian Dunning [mailto:[EMAIL PROTECTED]
Sent: Friday, April 23, 2004 11:36 AM
To: [EMAIL PROTECTED]
Subject: Re: [PHP] OK SQL experts...
Backticks, single quotes, or nothing at all makes no difference.
I
believe the parsing error is due to my parentheses or AND/OR
structure.
Any thoughts on that?
On Apr 23, 2004, at 8:32 AM, John W. Holmes wrote:
From: Brian Dunning [EMAIL PROTECTED]
I STFW and RTFM and I still can't figure out why this returns a
1064
parse error:
SELECT * FROM 'my_table' WHERE ('field_1' LIKE '%$keyword%' OR
'field_2' LIKE '%$keyword%' OR 'field_3' LIKE '%$keyword%') AND
'status' = 'active';
Use backticks around table and column names, not single quotes.
---John Holmes...
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RE: [PHP] OK SQL experts...
Brian Dunning mailto:[EMAIL PROTECTED]
on Friday, April 23, 2004 8:19 AM said:
SELECT * FROM 'my_table' WHERE ('field_1' LIKE '%$keyword%' OR
'field_2' LIKE '%$keyword%' OR 'field_3' LIKE '%$keyword%') AND
'status' = 'active';
have you tried simply:
SELECT * FROM my_table WHERE status = 'active';
??
if that works move up into:
SELECT * FROM my_table WHERE (field_1 LIKE '%$keyword%') AND status =
'active';
if that works continue until you get an error.
chris.
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RE: [PHP] OK SQL experts...
[snip] SELECT * FROM my_table WHERE (field_1 LIKE '%$keyword%') AND status = 'active'; if that works continue until you get an error. [/snip] That'll give you an error right there. That old single quoted variable will get you every time. :) WHERE (field_1 LIKE '%$keyword%') WHERE (field_1 LIKE '% . $keyword . %') -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re[2]: [PHP] OK SQL experts...
Hi,
Saturday, April 24, 2004, 1:55:36 AM, you wrote:
JB [snip]
JB SELECT * FROM 'my_table' WHERE ('field_1' LIKE '%$keyword%' OR
JB 'field_2' LIKE '%$keyword%' OR 'field_3' LIKE '%$keyword%') AND
JB 'status' = 'active';
JB [/snip]
JB *slaps forehead*
JB SELECT * FROM my_table WHERE (field_1 LIKE '% . $keyword . %' OR
JB field_2 LIKE '% . $keyword . %' OR field_3 LIKE '% . $keyword . %')
JB AND
JB status = 'active';
JB The single quoted variables do not get parsed
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They do if they are themselves inside double quotes :)
echo '$var'; will get parsed ok
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Re: [PHP] OK SQL experts...
if that works move up into:
SELECT * FROM my_table WHERE (field_1 LIKE '%$keyword%') AND status =
'active';
Yes, I actually did exactly that. Everything works until I have more
than one statement inside the (x LIKE x OR x LIKE x) parens. That's why
I figured there has to be something wrong with my paren structure. When
I RTFM I saw someplace to use {}+ instead of () but it gave a different
error.
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RE: Re[2]: [PHP] OK SQL experts...
[snip] They do if they are themselves inside double quotes :) echo '$var'; will get parsed ok [/snip] I know, but since I saw no double quotes I had to go for the obvious. :) -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re[4]: [PHP] OK SQL experts...
Hi, Saturday, April 24, 2004, 2:03:36 AM, you wrote: JB [snip] JB They do if they are themselves inside double quotes :) JB echo '$var'; will get parsed ok JB [/snip] JB I know, but since I saw no double quotes I had to go for the obvious. :) Yes I would like to see the whole truth as well :) including the mysterious search word. -- regards, Tom -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re[2]: [PHP] OK SQL experts...
Hello Brian,
Friday, April 23, 2004, 5:02:00 PM, you wrote:
BD Yes, I actually did exactly that. Everything works until I have more
BD than one statement inside the (x LIKE x OR x LIKE x) parens. That's why
BD I figured there has to be something wrong with my paren structure. When
BD I RTFM I saw someplace to use {}+ instead of () but it gave a different
BD error.
I don't think it's anything to do with your () placement, I just
tested and the follow 3 queries all bring back the same results:
SELECT * FROM table WHERE (field LIKE '%var%') OR (field2 LIKE
'%var%') AND field3 = 'condition'
SELECT * FROM table WHERE (field LIKE '%var%' OR field2 LIKE
'%var%') AND field3 = 'condition'
SELECT * FROM table WHERE field LIKE '%var%' OR field2 LIKE
'%var%' AND field3 = 'condition'
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Re: [PHP] OK SQL experts...
How are you manipulating the whole SQL string??
$sql = SELECT...; ???
or
$sql = 'SELECT...'; ???
In this case you will have to use double quotes because PHP won't parse
single quote strings for searching embedded PHP variables.
May be this is the problem.
-William
El vie, 23-04-2004 a las 11:02, Brian Dunning escribió:
if that works move up into:
SELECT * FROM my_table WHERE (field_1 LIKE '%$keyword%') AND status =
'active';
Yes, I actually did exactly that. Everything works until I have more
than one statement inside the (x LIKE x OR x LIKE x) parens. That's why
I figured there has to be something wrong with my paren structure. When
I RTFM I saw someplace to use {}+ instead of () but it gave a different
error.
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Re: [PHP] OK SQL experts...
* Thus wrote Brian Dunning ([EMAIL PROTECTED]):
I STFW and RTFM and I still can't figure out why this returns a 1064
parse error:
SELECT * FROM 'my_table' WHERE ('field_1' LIKE '%$keyword%' OR
'field_2' LIKE '%$keyword%' OR 'field_3' LIKE '%$keyword%') AND
'status' = 'active';
You might want to change your subject to 'mind reading experts'. A
lot of things can be wrong with this, as per the whole discussion
on this topic has shown.
All you need to do is echo mysql_error() and echo the actual string
that you are passing to mysql_query(). You're problem will be
solved rather quickly if you do that.
Curt
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Re: [PHP] OK SQL experts...
Brian Dunning wrote:
I STFW and RTFM and I still can't figure out why this returns a 1064
parse error:
SELECT * FROM 'my_table' WHERE ('field_1' LIKE '%$keyword%' OR 'field_2'
LIKE '%$keyword%' OR 'field_3' LIKE '%$keyword%') AND 'status' = 'active';
Anyone? TIA!
- B1ff Lamer
What does mysql_error() tell you?
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* _ __ __ __ _ * John Nichel *
* | |/ /___ __ \ \/ /__ _ _| |__ ___ __ ___ _ __ * 716.856.9675 *
* | ' / -_) _` \ \/\/ / _ \ '_| / /(_-_/ _/ _ \ ' \ * 737 Main St. *
* |_|\_\___\__, |\_/\_/\___/_| |_\_\/__(_)__\___/_|_|_|* Suite #150 *
* |___/ * Buffalo, NY *
* http://www.KegWorks.com[EMAIL PROTECTED] * 14203 - 1321 *
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Re: [PHP] OK SQL experts...
On Apr 23, 2004, at 10:13 AM, John Nichel wrote:
Brian Dunning wrote:
I STFW and RTFM and I still can't figure out why this returns a 1064
parse error:
SELECT * FROM 'my_table' WHERE ('field_1' LIKE '%$keyword%' OR
'field_2' LIKE '%$keyword%' OR 'field_3' LIKE '%$keyword%') AND
'status' = 'active';
Anyone? TIA!
- B1ff Lamer
What does mysql_error() tell you?
You have an error in your SQL syntax. Check the manual that corresponds
to your MySQL server version for the right syntax to use near
''my_table' WHERE ('field_1' LIKE '%%' OR 'field2'
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RE: [PHP] OK SQL experts...
doesn't look like your $keyword value contains anything.
-Original Message-
From: Brian Dunning [mailto:[EMAIL PROTECTED]
Sent: Friday, April 23, 2004 1:19 PM
To: [EMAIL PROTECTED]
Subject: Re: [PHP] OK SQL experts...
On Apr 23, 2004, at 10:13 AM, John Nichel wrote:
Brian Dunning wrote:
I STFW and RTFM and I still can't figure out why this returns a 1064
parse error:
SELECT * FROM 'my_table' WHERE ('field_1' LIKE '%$keyword%' OR
'field_2' LIKE '%$keyword%' OR 'field_3' LIKE '%$keyword%') AND
'status' = 'active';
Anyone? TIA!
- B1ff Lamer
What does mysql_error() tell you?
You have an error in your SQL syntax. Check the manual that corresponds
to your MySQL server version for the right syntax to use near
''my_table' WHERE ('field_1' LIKE '%%' OR 'field2'
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Re: [PHP] OK SQL experts...
On Apr 23, 2004, at 10:27 AM, Edward Peloke wrote:
doesn't look like your $keyword value contains anything.
My error. Here is the actual return:
You have an error in your SQL syntax. Check the manual that corresponds
to your MySQL server version for the right syntax to use near
''my_table' WHERE ('field_1' LIKE '%custom%' OR 'field_
I am searching for the word custom, which I put in at least one of
the fields in several records, so the search SHOULD find something.
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Re: [PHP] OK SQL experts...
* Thus wrote Brian Dunning ([EMAIL PROTECTED]):
On Apr 23, 2004, at 10:13 AM, John Nichel wrote:
Brian Dunning wrote:
I STFW and RTFM and I still can't figure out why this returns a 1064
parse error:
SELECT * FROM 'my_table' WHERE ('field_1' LIKE '%$keyword%' OR
'field_2' LIKE '%$keyword%' OR 'field_3' LIKE '%$keyword%') AND
'status' = 'active';
Anyone? TIA!
- B1ff Lamer
What does mysql_error() tell you?
You have an error in your SQL syntax. Check the manual that corresponds
to your MySQL server version for the right syntax to use near
''my_table' WHERE ('field_1' LIKE '%%' OR 'field2'
Because you are using a single quotes around your table/field
names. Remove them or use ` (back tick). As suggested earlier.
Curt
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Re[2]: [PHP] OK SQL experts...
Hello Brian,
Friday, April 23, 2004, 6:18:43 PM, you wrote:
BD You have an error in your SQL syntax. Check the manual that corresponds
BD to your MySQL server version for the right syntax to use near
BD ''my_table' WHERE ('field_1' LIKE '%%' OR 'field2'
my_table should NOT be quoted in this instance and it causes the mysql
error above. I just tried a query on a table and put the table name in
quotes and it generated the exact same error. You can use back-ticks:
` but not the ' character which is what was in your post above.
Also - wrapping field_1 in ' quotes ' DOES effect the outcome of the
query, it should not have anything around it. If you wrap the field
name in back-ticks that is fine.
Unless the back-ticks have been converted to quotes by your email
client automatically, that is most definitely the root of the problem.
If PHPMyAdmin offers the ability to enter an execute a standard SQL
statement - try it for yourself and you'll see what I mean.
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http://www.phpcommunity.org/wiki/296.html
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Re: [PHP] OK SQL experts...
You have an error in your SQL syntax. Check the manual that
corresponds
to your MySQL server version for the right syntax to use near
''my_table' WHERE ('field_1' LIKE '%%' OR 'field2'
Because you are using a single quotes around your table/field
names. Remove them or use ` (back tick). As suggested earlier.
NOW IT WORKS!! I thought I had tried back ticks and nothing - I did try
it, must have made a typo. But all is well now. THANKS VERY MUCH
- B1ff Lamer
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Re: [PHP] OK SQL experts...
From: Brian Dunning [EMAIL PROTECTED]
My error. Here is the actual return:
You have an error in your SQL syntax. Check the manual that corresponds
to your MySQL server version for the right syntax to use near
''my_table' WHERE ('field_1' LIKE '%custom%' OR 'field_
I am searching for the word custom, which I put in at least one of
the fields in several records, so the search SHOULD find something.
Take out the single quotes around your table name! If you must, use
backticks, but even they aren't necessary. Then tell us what the new error
is.
---John Holmes...
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Re: [PHP] OK SQL experts...
You have an error in your SQL syntax. Check the manual that
corresponds
to your MySQL server version for the right syntax to use near
''my_table' WHERE ('field_1' LIKE '%%' OR 'field2'
Because you are using a single quotes around your table/field
names. Remove them or use ` (back tick). As suggested earlier.
NOW IT WORKS!! I thought I had tried back ticks and nothing - I did try
it, must have made a typo. But all is well now. THANKS VERY MUCH
- B1ff Lamer
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Re: [PHP] OK SQL experts...
Brian Dunning wrote:
On Apr 23, 2004, at 10:13 AM, John Nichel wrote:
Brian Dunning wrote:
I STFW and RTFM and I still can't figure out why this returns a 1064
parse error:
SELECT * FROM 'my_table' WHERE ('field_1' LIKE '%$keyword%' OR
'field_2' LIKE '%$keyword%' OR 'field_3' LIKE '%$keyword%') AND
'status' = 'active';
Anyone? TIA!
- B1ff Lamer
What does mysql_error() tell you?
You have an error in your SQL syntax. Check the manual that corresponds
to your MySQL server version for the right syntax to use near
''my_table' WHERE ('field_1' LIKE '%%' OR 'field2'
I think this has been mentioned already, but your field names shouldn't
have quotes around them. You should be using back ticks.
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* | |/ /___ __ \ \/ /__ _ _| |__ ___ __ ___ _ __ * 716.856.9675 *
* | ' / -_) _` \ \/\/ / _ \ '_| / /(_-_/ _/ _ \ ' \ * 737 Main St. *
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[PHP] OK
Sorry, i didn't itent to be a spam, believe me. But i don't know how to do this aplication
Re: [PHP] OK
On Jul 22, 2003, Rausch Alexandru claimed that: |Sorry, i didn't itent to be a spam, believe me. But i don't know how to |do this aplication | In that case, you might want to start with something a bit less ambitious, maybe learning to wrap your mail, and some tutorials? http://www.devshed.com/Server_Side/PHP/PHP101/PHP101_1/page1.html Maybe a web search to see if what you want to do has already been done? -- Registered Linux user #304026. lynx -source http://jharris.rallycentral.us/jharris.asc | gpg --import Key fingerprint = 52FC 20BD 025A 8C13 5FC6 68C6 9CF9 46C2 B089 0FED Responses to this message should conform to RFC 1855. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] OK, So I am new to these List. Win2000 help!
John A. Thomason wrote: Thanks, that did it. And yes, I am trying to run this as a shell script. Thank you very much. John. - Original Message - From: John Nichel [EMAIL PROTECTED] To: John A. Thomason [EMAIL PROTECTED] Cc: [EMAIL PROTECTED] Sent: Saturday, July 12, 2003 10:01 PM Subject: Re: [PHP] OK, So I am new to these List. Win2000 help! John A. Thomason wrote: The following is my output in the command prompt window(DOS Prompt?) C:\PHPhello.php Content-type: text/html X-Powered-By: PHP/4.3.2 !#C:\php\; echoHello World!; if ($foo): echo yep\n; elseif ($bar): echo almost\n; else: echo nope\n; endif; phpinfo(); C:\PHP And the following is the PHP code to generate it. !#C:\php\; echoHello World!; if ($foo): echo yep\n; elseif ($bar): echo almost\n; else: echo nope\n; endif; phpinfo(); Now, I know that the variables are not set, so they should be false, but the output just displays a listing of the code and doesn't process it. In the documentation, it states that PHP can be run from the command prompt, like a batch file. Now what am I doing wrong. I do have it working correctly with an Apache server, that I am using backend. and my install dir is C:\php, and it is listed first in the path. John A. Thomason [EMAIL PROTECTED] Looks like you're trying to run it as a shell script, or a cgi program. Replace the sh-bang on the first line with ?php and make sure the last line of the script is ? eg: ?php echoHello World!; if ($foo): echo yep\n; elseif ($bar): echo almost\n; else: echo nope\n; endif; phpinfo(); ? Yeah, you just need to enclose the actual script in the opening/closing php tags (?php and ?). And to run it as a shell script, you can either call the script as... c:\path\to\php\php.exe filename.php (or just 'php filename.php' if the php interperter is in your path), or put the sh-bang as the first line (before the opening php tag). -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] OK, So I am new to these List. Win2000 help!
The following is my output in the command prompt window(DOS Prompt?) C:\PHPhello.php Content-type: text/html X-Powered-By: PHP/4.3.2 !#C:\php\; echoHello World!; if ($foo): echo yep\n; elseif ($bar): echo almost\n; else: echo nope\n; endif; phpinfo(); C:\PHP And the following is the PHP code to generate it. !#C:\php\; echoHello World!; if ($foo): echo yep\n; elseif ($bar): echo almost\n; else: echo nope\n; endif; phpinfo(); Now, I know that the variables are not set, so they should be false, but the output just displays a listing of the code and doesn't process it. In the documentation, it states that PHP can be run from the command prompt, like a batch file. Now what am I doing wrong. I do have it working correctly with an Apache server, that I am using backend. and my install dir is C:\php, and it is listed first in the path. John A. Thomason [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] OK, So I am new to these List. Win2000 help!
John A. Thomason wrote: The following is my output in the command prompt window(DOS Prompt?) C:\PHPhello.php Content-type: text/html X-Powered-By: PHP/4.3.2 !#C:\php\; echoHello World!; if ($foo): echo yep\n; elseif ($bar): echo almost\n; else: echo nope\n; endif; phpinfo(); C:\PHP And the following is the PHP code to generate it. !#C:\php\; echoHello World!; if ($foo): echo yep\n; elseif ($bar): echo almost\n; else: echo nope\n; endif; phpinfo(); Now, I know that the variables are not set, so they should be false, but the output just displays a listing of the code and doesn't process it. In the documentation, it states that PHP can be run from the command prompt, like a batch file. Now what am I doing wrong. I do have it working correctly with an Apache server, that I am using backend. and my install dir is C:\php, and it is listed first in the path. John A. Thomason [EMAIL PROTECTED] Looks like you're trying to run it as a shell script, or a cgi program. Replace the sh-bang on the first line with ?php and make sure the last line of the script is ? eg: ?php echoHello World!; if ($foo): echo yep\n; elseif ($bar): echo almost\n; else: echo nope\n; endif; phpinfo(); ? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] OK guys, thank you so far
Now my code is
extract ($_GET);
if ($_GET['printout'] != yeah) { include(header.php); }
but I still get the following error:
Undefined index: printout
I understand nothing
Jonathan Wilkes [EMAIL PROTECTED] skrev i meddelandet
news:[EMAIL PROTECTED]
Hi,
What he means is that with register_globals=off you cannot do this:
echo $path
you need to do this (if the variable is sent by POST action)
echo _POST('path')
and through GET
echo _GET('path')
-Original Message-
From: Øystein Håland [mailto:[EMAIL PROTECTED]
Sent: 03 June 2003 17:02
To: [EMAIL PROTECTED]
Subject: [PHP] Re: Migration from register_globals=on to
register_globals=off
I'm not sure what you mean. To give ONE example:
Earlier I could use this code on top of every page:
if ($printout != yeah) { include(header.php); }
This code gives an error today. The variable $printout is set if the visitor
choose to click on the 'print_page_image', otherwise the variable has no
value.
Esteban FernáNdez [EMAIL PROTECTED] skrev i meddelandet
news:[EMAIL PROTECTED]
When you recivied that error ?, in a form ?, if is in a Form just put in
the
top of .php files this code
$HTTP_GET_VARS[variable2];
$HTTP_GET_VARS[variable3];
Of course if you send with other method (post) change the GET for POST
$HTTP_POS_VARS[variable2];
$HTTP_POS_VARS[variable3];
Regards.
Esteban.
ØYstein HåLand [EMAIL PROTECTED] escribió en el mensaje
news:[EMAIL PROTECTED]
None of my old scripts worx nowadays and the most common error message
is
'undefined variable'. What is the best/simplest way to work around this
situation?
if !isset($myvar) {
do this
blah blah
}
?
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RE: [PHP] OK guys, thank you so far
can you try if ($HTTP_GET_VARS['printout']!=yeah) {include(header.php);}
does that work?
-Original Message-
From: Øystein Håland [mailto:[EMAIL PROTECTED]
Sent: Tuesday, June 03, 2003 1:17 PM
To: [EMAIL PROTECTED]
Subject: [PHP] OK guys, thank you so far
Now my code is
extract ($_GET);
if ($_GET['printout'] != yeah) { include(header.php); }
but I still get the following error:
Undefined index: printout
I understand nothing
Jonathan Wilkes [EMAIL PROTECTED] skrev i meddelandet
news:[EMAIL PROTECTED]
Hi,
What he means is that with register_globals=off you cannot do this:
echo $path
you need to do this (if the variable is sent by POST action)
echo _POST('path')
and through GET
echo _GET('path')
-Original Message-
From: Øystein Håland [mailto:[EMAIL PROTECTED]
Sent: 03 June 2003 17:02
To: [EMAIL PROTECTED]
Subject: [PHP] Re: Migration from register_globals=on to
register_globals=off
I'm not sure what you mean. To give ONE example:
Earlier I could use this code on top of every page:
if ($printout != yeah) { include(header.php); }
This code gives an error today. The variable $printout is set if the visitor
choose to click on the 'print_page_image', otherwise the variable has no
value.
Esteban FernáNdez [EMAIL PROTECTED] skrev i meddelandet
news:[EMAIL PROTECTED]
When you recivied that error ?, in a form ?, if is in a Form just put in
the
top of .php files this code
$HTTP_GET_VARS[variable2];
$HTTP_GET_VARS[variable3];
Of course if you send with other method (post) change the GET for POST
$HTTP_POS_VARS[variable2];
$HTTP_POS_VARS[variable3];
Regards.
Esteban.
ØYstein HåLand [EMAIL PROTECTED] escribió en el mensaje
news:[EMAIL PROTECTED]
None of my old scripts worx nowadays and the most common error message
is
'undefined variable'. What is the best/simplest way to work around this
situation?
if !isset($myvar) {
do this
blah blah
}
?
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Re: [PHP] OK guys, thank you so far
On Tue, 3 Jun 2003 19:16:30 +0200, +ystein Hland wrote:
Now my code is
extract ($_GET);
if ($_GET['printout'] != yeah) { include(header.php); }
but I still get the following error:
Undefined index: printout
I understand nothing
Ok, it looks like you are mixing your metaphors ;)
If you use extract( $_GET ); -- you should have a $printout variable
available (assuming you aren't doing a POST form and you are on a
version of PHP that supports $_GET). At least two of the following
should work...
--- Option 1 --- GET method - New PHP
extract($_GET);
if ($printout != yeah) { include(header.php); }
--- Option 2 --- POST method - New PHP
extract($_POST);
if ($printout != yeah) { include(header.php); }
--- Option 3 --- GET method - Older PHP
extract($HTTP_GET_VARS);
if ($printout != yeah) { include(header.php); }
--- Option 4 --- POST method - Older PHP
extract($HTTP_POST_VARS);
if ($printout != yeah) { include(header.php); }
--- Option 5 --- GET method - new php - No extract
if ( $_GET[ 'printout' ] != yeah) { include(header.php); }
--- Option 6 --- POST method - new php - No extract
if ( $_POST[ 'printout' ] != yeah) { include(header.php); }
--- Option 7 --- GET method - older php - No extract
if ( $HTTP_GET_VARS[ 'printout' ] != yeah) { include(header.php); }
--- Option 8 --- POST method - older php - No extract
if ( $HTTP_POST_VARS[ 'printout' ] != yeah) { include(header.php);
}
End ---
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Re: [PHP] OK guys, thank you so far
I've tried and here's the output:
Undefined index: input
if ($HTTP_GET_VARS['printout'] != yeah) { include(header.php); }
Edward Peloke [EMAIL PROTECTED] skrev i meddelandet
news:[EMAIL PROTECTED]
can you try if ($HTTP_GET_VARS['printout']!=yeah)
{include(header.php);}
does that work?
-Original Message-
From: Øystein Håland [mailto:[EMAIL PROTECTED]
Sent: Tuesday, June 03, 2003 1:17 PM
To: [EMAIL PROTECTED]
Subject: [PHP] OK guys, thank you so far
Now my code is
extract ($_GET);
if ($_GET['printout'] != yeah) { include(header.php); }
but I still get the following error:
Undefined index: printout
I understand nothing
Jonathan Wilkes [EMAIL PROTECTED] skrev i meddelandet
news:[EMAIL PROTECTED]
Hi,
What he means is that with register_globals=off you cannot do this:
echo $path
you need to do this (if the variable is sent by POST action)
echo _POST('path')
and through GET
echo _GET('path')
-Original Message-
From: Øystein Håland [mailto:[EMAIL PROTECTED]
Sent: 03 June 2003 17:02
To: [EMAIL PROTECTED]
Subject: [PHP] Re: Migration from register_globals=on to
register_globals=off
I'm not sure what you mean. To give ONE example:
Earlier I could use this code on top of every page:
if ($printout != yeah) { include(header.php); }
This code gives an error today. The variable $printout is set if the
visitor
choose to click on the 'print_page_image', otherwise the variable has no
value.
Esteban FernáNdez [EMAIL PROTECTED] skrev i meddelandet
news:[EMAIL PROTECTED]
When you recivied that error ?, in a form ?, if is in a Form just put in
the
top of .php files this code
$HTTP_GET_VARS[variable2];
$HTTP_GET_VARS[variable3];
Of course if you send with other method (post) change the GET for POST
$HTTP_POS_VARS[variable2];
$HTTP_POS_VARS[variable3];
Regards.
Esteban.
ØYstein HåLand [EMAIL PROTECTED] escribió en el mensaje
news:[EMAIL PROTECTED]
None of my old scripts worx nowadays and the most common error message
is
'undefined variable'. What is the best/simplest way to work around
this
situation?
if !isset($myvar) {
do this
blah blah
}
?
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Re: [PHP] OK guys, thank you so far
Hello,
This is a reply to an e-mail that you wrote on Tue, 3 Jun 2003 at 20:04,
lines prefixed by '' were originally written by you.
I've tried and here's the output:
Undefined index: input
if ($HTTP_GET_VARS['printout'] != yeah) { include(header.php); }
You have error reporting set to E_ALL, turn it down a bit.
More information at:
http://uk2.php.net/error_reporting
David.
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Re: [PHP] OK guys, thank you so far
On Tue, 2003-06-03 at 13:20, David Nicholson wrote:
Hello,
This is a reply to an e-mail that you wrote on Tue, 3 Jun 2003 at 20:04,
lines prefixed by '' were originally written by you.
I've tried and here's the output:
Undefined index: input
if ($HTTP_GET_VARS['printout'] != yeah) { include(header.php); }
You have error reporting set to E_ALL, turn it down a bit.
More information at:
http://uk2.php.net/error_reporting
David.
This is a good idea for a production machine, but for your development
environment, turning down error reporting is not a good idea. :) You
will kill yourself trying to track down subtle errors when they aren't
displayed.
Try checking your variables before using them:
if (isset($_GET['printout']) $_GET['printout'] != 'yeah') {
// . . .
}
Torben
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Re: [PHP] Ok, problem found, but that makes way for another...
ok, now where in that heck can i find the php entry in that file? i cant seem to find it anywhere. would it be with the CGI entry or in a different place? Marek Kilimajer[EMAIL PROTECTED] 04/03/03 04:37AM The old installation is likely in /usr, and you installed in /usr/local. Simply remove the old installation (man rm ;-) and change httpd.conf to look for php in the new place Ryan Vennell wrote: ok, my last post stated that i've tried reconfigureing.making/makeinstalling php 4.3.1 a tons of times. well, today when i typed php -v it told me that version 4.2.2 was the one that was installed. so apparently my installing has not been taking the place of the old one. The original root is that the original compile of php (not done by me) was installed w/out mysql and i need mysql for what i'm working on. now that i know the problem here, any suggestions? I'm running apache for what i'm working on, tomcat for other things that this server does, and the latest version of mysql now how do i get rid of hte old php and make sure this new one goes into its place? P.S.- i'm not a total linux newb but i'm not, NOT a newb either. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Ok, problem found, but that makes way for another...
The old installation is likely in /usr, and you installed in /usr/local. Simply remove the old installation (man rm ;-) and change httpd.conf to look for php in the new place Ryan Vennell wrote: ok, my last post stated that i've tried reconfigureing.making/makeinstalling php 4.3.1 a tons of times. well, today when i typed php -v it told me that version 4.2.2 was the one that was installed. so apparently my installing has not been taking the place of the old one. The original root is that the original compile of php (not done by me) was installed w/out mysql and i need mysql for what i'm working on. now that i know the problem here, any suggestions? I'm running apache for what i'm working on, tomcat for other things that this server does, and the latest version of mysql now how do i get rid of hte old php and make sure this new one goes into its place? P.S.- i'm not a total linux newb but i'm not, NOT a newb either. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Ok, problem found, but that makes way for another...
ok, my last post stated that i've tried reconfigureing.making/makeinstalling php 4.3.1 a tons of times. well, today when i typed php -v it told me that version 4.2.2 was the one that was installed. so apparently my installing has not been taking the place of the old one. The original root is that the original compile of php (not done by me) was installed w/out mysql and i need mysql for what i'm working on. now that i know the problem here, any suggestions? I'm running apache for what i'm working on, tomcat for other things that this server does, and the latest version of mysql now how do i get rid of hte old php and make sure this new one goes into its place? P.S.- i'm not a total linux newb but i'm not, NOT a newb either. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] ok now my sessions are *not* timing out
before my problem was that my sessions were being terminated spontaneously. it looks
like i've managed to fix that problem - so far i haven't been randomly logged off my
application. the problem is, according to my php.ini settings, my session should have
been terminated after 2 hours, it's been almost 5 hours now...
my php.ini:
snip
; Lifetime in seconds of cookie or, if 0, until browser is restarted.
session.cookie_lifetime =0
; Percentual probability that the 'garbage collection' process is started
; on every session initialization.
session.gc_probability =100
; After this number of seconds, stored data will be seen as 'garbage' and
; cleaned up by the garbage collection process.
session.gc_maxlifetime =7200
/snip
after making the above changes in my php.ini, it looks like the javascript timer i
have in the headers of my authenticated pages does not work anymore. this javascript
is supposed to popup a warning message at 18 minutes of inactivity, and at 20 minutes,
redirect the user to the logout page, which calls session_destroy().
the js looks like:
snip
script language=JavaScript
!--
function timeout_2MinuteAlert()
{if(confirm('Warning: You are about to time out. As a security measure, we log you out
after 20 minutes of inactivity. You have been inactive for 18 minutes. Click Ok
within the next 2 minutes to continue with your application, otherwise you will be
logged out. If you are logged out, you will need to log in again to continue your
session.'))
{
history.go(0)
}
}
function timeout_FinalAlert()
{
if(confirm('Warning: You have timed out. As a security measure, you have been logged
out after 20 minutes of inactivity. Click Ok again to return to log in again to
continue your session.'))
{
history.go(0)
}
}
setTimeout('timeout_2MinuteAlert()', 108); // = 18 minutes
setTimeout('timeout_FinalAlert()', 1212000); // = 20 minutes
//--
/snip
what happens is that the javascript gets to the 18 minute warning, but never gets to
the 20 minute warning, the user is not redirected to the logout page. ideally, i would
like to have this work. i would like the user to be able to click around on the site
without their session expiring indefinitely, but at 18 minutes of inactivity, have
this javascript pop up a warning message, and at 20 mins of inactivity have them be
automatically redirected to the logout page and their session destroyed.
what am i doing wrong?
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