Re: [PHP] Beginner question
On Mon, 2009-08-24 at 23:16 -0600, mike bode wrote: I am trying to use PHP on my web site I am developing now. I have installed Apache 2.2 and PHP 5.2. My problem is that I can execute PHP code embedded in my HTML code, but I can't execute the same cose when I put it into a separate .php file that i then call from within the html code. for example: I have a html file with body ?php echo Printing with php; ? ?body and it works fine. When I take out the php code and put it inot a file pp.php, and I call that file with my browser (localhost/pp.php), it works, too. But when I change the html code to: body script type=text/javascript src=pp.php/script /body I get a blank page. this is probably something really stupid, but I have been wrecking my head for days now, and I can't figure it out. anybody has an idea? Yes, this is not how you use PHP! PHP isn't embedded in HTML, it's actually the other way round. You should make the main page a .php page and from there you can include the necessary HTML parts like so: ?php include includes/header.html; // body code here include includes/footer.html; ? Thanks, Ash http://www.ashleysheridan.co.uk -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] Beginner question
To: php-general@lists.php.net From: mikebo...@hotmail.com Date: Mon, 24 Aug 2009 23:16:02 -0600 Subject: [PHP] Beginner question I am trying to use PHP on my web site I am developing now. I have installed Apache 2.2 and PHP 5.2. My problem is that I can execute PHP code embedded in my HTML code, but I can't execute the same cose when I put it into a separate .php file that i then call from within the html code. for example: I have a html file with body ?php echo Printing with php; ? ?body and it works fine. When I take out the php code and put it inot a file pp.php, and I call that file with my browser (localhost/pp.php), it works, too. But when I change the html code to: body script type=text/javascript src=pp.php/script /body I get a blank page. this is probably something really stupid, but I have been wrecking my head for days now, and I can't figure it out. anybody has an idea? Hello Bode, You obviously purposefully asked your browser not to parse you php code. You are linking to a javascript instead of a php file. It's this simple; if you are create a .php file and u wish to incorporate it in your html code, you should use a function called include();. Simply try something like: body ?php include(pp.php); ? /body Let me know what u get from that. Alugo Abdulazeez Serving you from Nigeria. http://www.frangeovic.com _ With Windows Live, you can organize, edit, and share your photos. http://www.microsoft.com/middleeast/windows/windowslive/products/photo-gallery-edit.aspx
Re: [PHP] Beginner question
Well, as I said: Beginner ... I am actually trying to implement some html code that I found on the web, which uses php (see: http://www.dynamicdrive.com/dynamicindex4/php-photoalbum.htm). They use the method I tried to call a function php and then display a photo album. Well, that doesn't work. I am just getting a blank page when I follow their instructions. So I thought I try to follow the trail and see where it ends. But how do I do that? I was attempting to do so with the script that I posted, but apparently that doesn't work. So, how do I find out why my installation does not process the html code that I have posted a link to above? How would I implement that on my web site? Thanks. Ashley Sheridan a...@ashleysheridan.co.uk wrote in message news:1251211648.2799.46.ca...@localhost... On Mon, 2009-08-24 at 23:16 -0600, mike bode wrote: I am trying to use PHP on my web site I am developing now. I have installed Apache 2.2 and PHP 5.2. My problem is that I can execute PHP code embedded in my HTML code, but I can't execute the same cose when I put it into a separate .php file that i then call from within the html code. for example: I have a html file with body ?php echo Printing with php; ? ?body and it works fine. When I take out the php code and put it inot a file pp.php, and I call that file with my browser (localhost/pp.php), it works, too. But when I change the html code to: body script type=text/javascript src=pp.php/script /body I get a blank page. this is probably something really stupid, but I have been wrecking my head for days now, and I can't figure it out. anybody has an idea? Yes, this is not how you use PHP! PHP isn't embedded in HTML, it's actually the other way round. You should make the main page a .php page and from there you can include the necessary HTML parts like so: ?php include includes/header.html; // body code here include includes/footer.html; ? Thanks, Ash http://www.ashleysheridan.co.uk -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] Beginner question
-Original Message- From: mike bode [mailto:mikebo...@hotmail.com] Sent: 25 August 2009 07:16 AM To: php-general@lists.php.net Subject: [PHP] Beginner question I am trying to use PHP on my web site I am developing now. I have installed Apache 2.2 and PHP 5.2. My problem is that I can execute PHP code embedded in my HTML code, but I can't execute the same cose when I put it into a separate .php file that i then call from within the html code. for example: I have a html file with body ?php echo Printing with php; ? ?body and it works fine. When I take out the php code and put it inot a file pp.php, and I call that file with my browser (localhost/pp.php), it works, too. But when I change the html code to: body script type=text/javascript src=pp.php/script /body I get a blank page. this is probably something really stupid, but I have been wrecking my head for days now, and I can't figure it out. anybody has an idea? -- I presume your html/php code is in a file with a .php extension? If not then change the extension to php because most other webservers won't parse php code in a html file. If you have a .php file you can mix html and php the way you described, and you can put your php code between the ?php and ? tags. The php script you're trying to include in your html code with javascript script type=text/javascript src=pp.php/script would presumably echo out the javascript code that ends up in your html page, but if you don't know php then you're trying to run before you can walk. If possible try to see what javascript code is being generated (echoed) by the php script and put it in a normal .js file (e.g. pp.js) and then use it like any other javascript file script type=text/javascript src=pp.js/script This isn't always possible because often php is used to decide what javascript to output (otherwise why bother). If you have to use php to generate your javascript code then start with small steps - try echoing some simple js code in your pp.php (like an alert) just so you can see how it works. Once you get that working you can move on to more useful things. To illustrate, what's actually happening with the code you have at the moment is this: The browser parses the initial html code and finds script type=text/javascript src=pp.php/script And sends a request back to the server for pp.php The server runs pp.php and send the output generated by the php script back to the browser, so effectively the browser ends up with script type=text/javascriptPrinting with php/script Obviously that isn't going to work. Hopefully you can now see what the problem is and how to fix it. Cheers Arno -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Beginner question
At 11:16 PM -0600 8/24/09, mike bode wrote: I get a blank page. this is probably something really stupid, but I have been wrecking my head for days now, and I can't figure it out. anybody has an idea? Mike: Here's an idea -- try this: http://sperling.com/examples/include-demo/ If you complete that (a hour or so, not days), you'll have a much better idea of what this is all about. Cheers, tedd -- --- http://sperling.com http://ancientstones.com http://earthstones.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Beginner question
Thanks. I will surely do that. In the meantime I have found out that it really is not a problem with the code. I uploaded the (non-functioning code) from my PC to a public web server, and lo and behold, the code works. It thus appears that there is something wrong with my php-apache setup. Now that's a whole other issue that I now need to try to solve. Any suggestions where to start? Thanks. tedd tedd.sperl...@gmail.com wrote in message news:p06240806c6b9e3571...@[192.168.1.102]... At 11:16 PM -0600 8/24/09, mike bode wrote: I get a blank page. this is probably something really stupid, but I have been wrecking my head for days now, and I can't figure it out. anybody has an idea? Mike: Here's an idea -- try this: http://sperling.com/examples/include-demo/ If you complete that (a hour or so, not days), you'll have a much better idea of what this is all about. Cheers, tedd -- --- http://sperling.com http://ancientstones.com http://earthstones.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Beginner question
I see. PHP runs on the server and cannot directly interact with my browser, only through Javascript. So I can use javascript to trigger a php script, which does something on the server, and returns something to javascript on my machine, which can then be used to do something on my browser. However, as I just said in this thread, I found out that the code is actually working, just not on my machine. I uploaded the code to a public web server (www.bestrmvacation.com/album.htm, if you want to check it out), and it works there. But not on my computer. There must be something broken with my PHP or Apache Installation. However, when I run a PHP script that calls phpinfo(), it works fine. Any idea where this might go wrong? BTW, I am using Expression Web to develop the web site. Could that have anything to do with it? Thanks. Arno Kuhl ak...@telkomsa.net wrote in message news:a6c65a0610f9485787e31f7161cb7...@point01... -Original Message- From: mike bode [mailto:mikebo...@hotmail.com] Sent: 25 August 2009 07:16 AM To: php-general@lists.php.net Subject: [PHP] Beginner question I am trying to use PHP on my web site I am developing now. I have installed Apache 2.2 and PHP 5.2. My problem is that I can execute PHP code embedded in my HTML code, but I can't execute the same cose when I put it into a separate .php file that i then call from within the html code. for example: I have a html file with body ?php echo Printing with php; ? ?body and it works fine. When I take out the php code and put it inot a file pp.php, and I call that file with my browser (localhost/pp.php), it works, too. But when I change the html code to: body script type=text/javascript src=pp.php/script /body I get a blank page. this is probably something really stupid, but I have been wrecking my head for days now, and I can't figure it out. anybody has an idea? -- I presume your html/php code is in a file with a .php extension? If not then change the extension to php because most other webservers won't parse php code in a html file. If you have a .php file you can mix html and php the way you described, and you can put your php code between the ?php and ? tags. The php script you're trying to include in your html code with javascript script type=text/javascript src=pp.php/script would presumably echo out the javascript code that ends up in your html page, but if you don't know php then you're trying to run before you can walk. If possible try to see what javascript code is being generated (echoed) by the php script and put it in a normal .js file (e.g. pp.js) and then use it like any other javascript file script type=text/javascript src=pp.js/script This isn't always possible because often php is used to decide what javascript to output (otherwise why bother). If you have to use php to generate your javascript code then start with small steps - try echoing some simple js code in your pp.php (like an alert) just so you can see how it works. Once you get that working you can move on to more useful things. To illustrate, what's actually happening with the code you have at the moment is this: The browser parses the initial html code and finds script type=text/javascript src=pp.php/script And sends a request back to the server for pp.php The server runs pp.php and send the output generated by the php script back to the browser, so effectively the browser ends up with script type=text/javascriptPrinting with php/script Obviously that isn't going to work. Hopefully you can now see what the problem is and how to fix it. Cheers Arno -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Beginner question
At 2:45 PM -0600 8/25/09, mike bode wrote: I see. PHP runs on the server and cannot directly interact with my browser, only through Javascript. Kind of. PHP runs on the server and can create html, css, javascript et al. However, PHP will complete it's task before the browser see's anything. Once the browser see's the code, it's up to the browser to interpret and run html, css, and javascript. If your html is a form (i.e., submit), or you have javascript running, then either of those can trigger a php script on the server to run which can repeat the process in generating new html, css, and javascript (if needed). Normally, javascript is not generated by PHP, but it can be. Using javascript to trigger an event certainly works IF javascript is turned on by the user's browser. However, this is something that you have absolutely no control over. A user can turn javascript ON/OFF at their discretion. You see, many people turn javascript off because of security concerns -- and those concerns are not without foundation. Cheers, tedd -- --- http://sperling.com http://ancientstones.com http://earthstones.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Beginner Question
On Fri, 2007-01-19 at 19:21 +0100, Delta Storm wrote: Hi, I have learned as lot about PHP but I still dont know how do they build PHP based web sites. Obviously you haven't learned enough ;) I need to build a complete PHP site with a lot of content and integrate CSS,javaScript and a lot of other stuff (for the school) Woohooo, a good way to learn, though hopefully you get the security right the first time :) (Complete site for example. www.domain1.com/index.php or www.domain2.co/about?set=p1) I want to know how are the sites built, do they build for each page a PHP script or do they build just a couple of scripts and a database full of content and just retrieve and delete,edit,show database information? Depends on who builds it, what they use, and personal preference. For instance most Drupal sites are mostly database driven. But other sites may be file based. Some use a front end controller pattern so you access a single page that determines what you see via the URL's parameters, others use real files. Others use URL rewriting tricks via the web server to make it the front end controller pattern look like real files. I know that when I see in the sites url php? that means that site has a database, right...? Nope, that generally means it's using PHP, but not always. Anyone can set their webserver to invoke whatever server side language they want to use regardless of file extension. Some common PHP extensions though are, .php, .php3, .phtml, .html Either way I would be very gratefull if you could you give me a detailed explanation of the process of building a PHP/MySQL site (I know to write scripts in PHP so im not a total beginner). You'll need a webserver, I recommend Apache: http://httpd.apache.org/ You will probably want to install PHP as amodule for use by the webserver. You should check out the PHP website, it explains how to set things up: http://www.php.net/manual/en/install.general.php I suggest installing on a *nix system versus crappy Windows. But feel free to use Windows if you're just a noobie. You don't need a database to learn the basics, mostly you just need to know how to set up the webserver, where to place your files, how to retrieve form posts and URL parametets, and how to output HTML. The PHP website is a goldmine of information. The comments can be quite helpful also. Cheers, Rob. -- .. | InterJinn Application Framework - http://www.interjinn.com | :: | An application and templating framework for PHP. Boasting | | a powerful, scalable system for accessing system services | | such as forms, properties, sessions, and caches. InterJinn | | also provides an extremely flexible architecture for | | creating re-usable components quickly and easily. | `' -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] Beginner Question
Doesn't the Apple Developer Tools disk have all that stuff? http://developer.apple.com/tools/ -- jon --- jon roig web developer email: [EMAIL PROTECTED] phone: 888.230.7557 -Original Message- From: rob [mailto:[EMAIL PROTECTED] Sent: Thursday, April 08, 2004 10:31 PM To: [EMAIL PROTECTED] Subject: [PHP] Beginner Question I am a newcomer to PHP and I am looking for an intsallation package similar to to FoxPro for MAC OSX 10.2.(Ie intsall appache, MY SQL and Latest version of PHP) Does anyone know where I may find one? Thanks RB -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php --- Incoming mail is certified Virus Free. Checked by AVG anti-virus system (http://www.grisoft.com). Version: 6.0.644 / Virus Database: 412 - Release Date: 3/26/2004 --- Outgoing mail is certified Virus Free. Checked by AVG anti-virus system (http://www.grisoft.com). Version: 6.0.644 / Virus Database: 412 - Release Date: 3/26/2004 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Beginner Question
On Thu, 2004-04-08 at 22:30, rob wrote: I am a newcomer to PHP and I am looking for an intsallation package similar to to FoxPro for MAC OSX 10.2.(Ie intsall appache, MY SQL and Latest version of PHP) Does anyone know where I may find one? Thanks RB Try http://www.serverlogistics.com They have packaged installers for Apache, MySQL and PHP with Preference Panes you can drop in to control the Apache and MySQL processes if you want them. Kris -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Beginner Question-Solution-packages
On 10/4/04 1:37 AM, jon roig [EMAIL PROTECTED] wrote: Thank you for your help! Php and mysql ship on MAC OSX servers but not on on the normal machines. Apple provides support for these two at http://developer.apple.com/internet/opensource/osdb.html for help on MySQL on MAC OSX including step by step instructions on how to install it. Assistance with PHP is found at http://developer.apple.com/internet/opensource/php.html including help on how to install it. I have not found integrated packages for Macs like FoxPro but the above links will get you up and running. Marc Linnage has a standalone installer for the latest release of PHP for OSX at http://www.entropy.ch/software/macosx/php/- very easy to install for beginners. I had trouble installing MySQL(from MySQL.com) but found the server logistics package a breeze at http://www.serverlogistics.com/mysql.php Once again thks for pointing me to the developer section at Apple RB -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] beginner question about while loops
Paul,
the warning that John refers to does occur - whether you see it
depends on the error reporting level, PHP will create the array for you
if you have not already initialized it but a warning will be generated
in such cases. - errors that may not display on one machine might be
visible on another due to differences in the error reporting level.
error reporting level is set in the php.ini file (it can also be set in
your script see http://nl2.php.net/ini_set), you probably have a line in
your php.ini that looks like:
error_reporting = E_ALL ~E_WARNING ~E_NOTICE
which means: log all errors except warning level and notice level errors
I recommend you try to set the error reporting level to:
error_reporting = E_ALL
in this way all errors are logged (and possibly displayed) - if you can
write bug/error free code with error reporting set to E_ALL then you
will have made a good start towards more professional/better coding
practices.
there is another php.ini line:
display_errors = On
this line determines if errors are output to the browser window. for web
development this should be definitely on. (productions server often have
it Off for speed and 'niceness' reasons - i.e. not many users are
interested in seeing PHP errors, for whatever reason!)
---
as a rule of thumb it is better to initialize variable before you use them.
e.g. $pictures = array();
otherwise, in your case, if no files are present in the directory (or
none have a 'jpg' extension) referencing the $pictures array the while
loop will cause another error.
---
Side Note:
for beginners often RTFM only leads to more confusion because the
contents of many technical manuals often assume that the reader has
knowledge which a beginner does not yet have. I don't feel that this is
very much the case of the PHP manual - my feeling is that is very
accessible. I recommend taking the time to read all of it - the parts
you don't yet understand often become clear with continued reading. The
time invested in reading the manual is quickly regained!
Paul Furman wrote:
OK thanks again for helping through the stumbling blocks... I'm rolling
again now.
John W. Holmes wrote:
Just make sure $pictures is defined as an array before you try to push a
value onto it (even using the method you have now), otherwise you'll
get a
warning.
It seems to be working fine this way without defining it as an array but
I guess other languages would not accept that approach.
while ($file = readdir($dh)){
if (strstr ($file, '.jpg')){
$pictures[] = $file;
}
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Re: [PHP] beginner question about while loops
Jochem Maas wrote: Paul, the warning that John refers to does occur - whether you see it depends on the error reporting level, PHP will create the array for you if you have not already initialized it but a warning will be generated in such cases. ... error_reporting = E_ALL ... display_errors = On ... as a rule of thumb it is better to initialize variable before you use them. e.g. $pictures = array(); otherwise, in your case, if no files are present in the directory (or none have a 'jpg' extension) referencing the $pictures array the while loop will cause another error. Thanks for the advice. I do think the manual is pretty good and I'll spend more time with it. But... I do have error reporting set to all. I think they may have changed the behavior on newer versions of PHP. I have indeed experienced the non-existant array eerror you describe. Lots of debugging to do! PS here's my results from a voracious weekend of coding: http://hills.ccsf.edu/~pfurma02/index.php?SCREEN=ecards.php Thanks for all your help! -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] beginner question about while loops
At 11:41 AM -0800 2/6/04, Paul Furman wrote:
while ($file = readdir($dh)){
if (strstr ($file, '.jpg')){
$pictures[] = $file;
}
Spotted this problem when staring at your code.
Number of open braces: 2
Number of close braces: 1
You need to close off your while loop.
Should I set up a counter for loops $integer++ or if I'm going
through something
You can if you like, but it is not necessary in this case.
the while function knows to just go through those and fills in array
numbers accordingly?
The while function has nothing to do with it. Using the syntex
$array[] simply adds an element onto the _end_ of the array and PHP
picks the next logical, numerical index.
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RE: [PHP] beginner question about while loops
You didn't close your loop;
while ($file = readdir($dh)){
if (strstr ($file, '.jpg')){
$pictures[] = $file;
}
#vardump ($pictures[]);
} = here
?
instead of;
while ($file = readdir($dh)){
if (strstr ($file, '.jpg')){
$pictures[] = $file;
}
#vardump ($pictures[]);
?
alex
-Original Message-
From: Paul Furman [mailto:[EMAIL PROTECTED]
Sent: Friday, February 06, 2004 1:41 PM
To: [EMAIL PROTECTED]
Subject: [PHP] beginner question about while loops
Totally ignorant need for clarification... Should I set up a counter for
loops $integer++ or if I'm going through something, the while function
knows to just go through those and fills in array numbers accordingly?
Below is my project (while loop at the bottom):
I'm getting unexpected $end on line 18 but the file only has 17 lines!
?php
if (isset ($_REQUEST ['IMGDIR'])){
$imagedir=$_REQUEST ['IMG_DIR'];
} else {
$imagedir = PUB_DIR . '/grasses';
#PUB_DIR coordinates my public htm location at home school
}
if (!(chdir ($imagedir))){
print invalid directory;
}
$fh=opendir($imagedir);
while ($file = readdir($dh)){
if (strstr ($file, '.jpg')){
$pictures[] = $file;
}
#vardump ($pictures[]);
?
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Re: [PHP] beginner question about while loops
Eric Gorr wrote:
the while function knows to just go through those and fills in array
numbers accordingly?
The while function has nothing to do with it. Using the syntax $array[]
simply adds an element onto the _end_ of the array and PHP picks the
next logical, numerical index.
OK thanks guys, I got the missing curly brace some other messes.
So when assigning values to an array inside a loop, it knows to advance
to the next but then if I want to print those out at the same time, it's
complaining
while ($file = readdir($fh)){
if (strstr ($file, '.jpg')){
$pictures[] = $file;
#print $pictures[]; #Fatal error: Cannot use [] for reading
}
var_dump ($pictures[]); #Fatal error: Cannot use [] for reading
}
This one works but complains about Undefined variable: pictures NULL
array (but it dumps the contents of $pictures[]:
while ($file = readdir($fh)){
if (strstr ($file, '.jpg')){
$pictures[] = $file;
}
var_dump ($pictures);
}
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Re: [PHP] beginner question about while loops
Paul Furman [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
Eric Gorr wrote:
[snip]
while ($file = readdir($fh)){
if (strstr ($file, '.jpg')){
$pictures[] = $file;
#print $pictures[]; #Fatal error: Cannot use [] for reading
Which element are you trying to print? I'm guessing the current one, so
just use:
print $file;
}
var_dump ($pictures[]); #Fatal error: Cannot use [] for reading
}
This one works but complains about Undefined variable: pictures NULL
array (but it dumps the contents of $pictures[]:
while ($file = readdir($fh)){
if (strstr ($file, '.jpg')){
$pictures[] = $file;
}
var_dump ($pictures);
}
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RE: [PHP] beginner question about while loops
1. Using [] creates a new array element. Hence the error. You can try this
piece of code inside the loop
[code]
if (strstr ($file, '.jpg')){
$refPictures = $pictures[];
$refPictures = $file;
print $refPictures;
}
[/code]
$refPictures holds a reference to the newly created element of the $pictures
array. Therefore, by assigning $file to $refPictures, $file is actually
getting assigned to the newly created element of the $pictures array. The
same logic applies in the print statement
2. Again, using [] in the var_dump indicates that you are trying to create a
new element of the $pictures array. If dumping the contents of the entire
array along with their data types and such is what you are trying to
achieve, the correct syntax is
[code]
var_dump($pictures);
[/code]
-Original Message-
From: Paul Furman [mailto:[EMAIL PROTECTED]
Sent: Friday, February 06, 2004 3:09 PM
To: [EMAIL PROTECTED]
Subject: Re: [PHP] beginner question about while loops
Eric Gorr wrote:
the while function knows to just go through those and fills in array
numbers accordingly?
The while function has nothing to do with it. Using the syntax $array[]
simply adds an element onto the _end_ of the array and PHP picks the
next logical, numerical index.
OK thanks guys, I got the missing curly brace some other messes.
So when assigning values to an array inside a loop, it knows to advance
to the next but then if I want to print those out at the same time, it's
complaining
while ($file = readdir($fh)){
if (strstr ($file, '.jpg')){
$pictures[] = $file;
#print $pictures[]; #Fatal error: Cannot use [] for reading
}
var_dump ($pictures[]); #Fatal error: Cannot use [] for reading
}
This one works but complains about Undefined variable: pictures NULL
array (but it dumps the contents of $pictures[]:
while ($file = readdir($fh)){
if (strstr ($file, '.jpg')){
$pictures[] = $file;
}
var_dump ($pictures);
}
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Re: [PHP] beginner question about while loops
- Original Message -
From: Paul Furman [EMAIL PROTECTED]
Totally ignorant need for clarification... Should I set up a counter for
loops $integer++ or if I'm going through something, the while function
knows to just go through those and fills in array numbers accordingly?
[snip]
while ($file = readdir($dh)){
if (strstr ($file, '.jpg')){
$pictures[] = $file;
}
With this syntax, you do not need to keep an $integer variable for the array
key. When you use $array[] = something, it just assigns that value to the
next available numeric key.
while ($file = readdir($dh)){
if (strstr ($file, '.jpg')){
$pictures[$int++] = $file;
}
Would also be correct, if you wanted to keep the count yourself. You could
also use array_push().
Just make sure $pictures is defined as an array before you try to push a
value onto it (even using the method you have now), otherwise you'll get a
warning.
---John Holmes...
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Re: [PHP] beginner question about while loops
OK thanks again for helping through the stumbling blocks... I'm rolling
again now.
John W. Holmes wrote:
Just make sure $pictures is defined as an array before you try to push a
value onto it (even using the method you have now), otherwise you'll get a
warning.
It seems to be working fine this way without defining it as an array but
I guess other languages would not accept that approach.
while ($file = readdir($dh)){
if (strstr ($file, '.jpg')){
$pictures[] = $file;
}
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Re: [PHP] beginner question about while loops
From: Paul Furman [EMAIL PROTECTED]
So when assigning values to an array inside a loop, it knows to advance
to the next but then if I want to print those out at the same time, it's
complaining
while ($file = readdir($fh)){
if (strstr ($file, '.jpg')){
$pictures[] = $file;
#print $pictures[]; #Fatal error: Cannot use [] for reading
}
var_dump ($pictures[]); #Fatal error: Cannot use [] for reading
}
Can't do that, like it says. You just assigned $file to $print.. so just
display the value of $file.
---John Holmes...
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Re: [PHP] Beginner question : Removing spaces in forms
you could start with something like: $old_string=44 55 99 111; $new_string=ereg_replace( ,,$old_string); echo $new_string; should display 445599111 There are other regular expression aids listed on the page at: http://www.php.net/manual/en/function.ereg-replace.php Hope this helps, Hugh - Original Message - From: Andrew Wilson [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent: Thursday, December 12, 2002 7:19 PM Subject: [PHP] Beginner question : Removing spaces in forms Hay guys i was wondering if there was a form parameter of something equivalent for input text boxes that when a user enters a number or series of numbers that it removes the spaces. If there is no alternative how would you go about solving this issue. Your help is appreciated. Thanks. Netway Networks Pty Ltd (T) 8920 8877 (F) 8920 8866 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Beginner question?
At 01:59 AM 12/21/2001 -0500, jtjohnston wrote:
Michael,
$fp = fopen (./users.txt, r);
while (!feof ($fp)) {
$buffer = fgets($fp, 4096);
echo $buffer;
}
fclose($fp);
Ok. But $buffer is not an array, is it? Why/what is 4096? What is !feof ?
Don't you have access to the WWW? You need to follow the link I gave you
and actually READ it. Your first two questions are answered here:
http://www.php.net/manual/en/function.fgets.php
And your next one here:
http://www.php.net/manual/en/function.feof.php
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Re: [PHP] Beginner question?
Can anyone show me how to split() each line and parse to see if $user
exists?
// get contents of a file into a string
$filename = ./users.txt;
$fd = fopen ($filename, r);
$contents = fread ($fd, filesize ($filename));
fclose ($fd);
// seperate the string into an array of lines
$linebreak = \n;
$lines = explode($linebreak,$contents);
// seperate each line into an array of words
for ($i=0;$icount($lines);$i++){
$words[$i]=explode( ,$lines[$i]);
}
- Original Message -
From: jtjohnston [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Thursday, December 20, 2001 10:59 PM
Subject: Re: [PHP] Beginner question?
Michael,
$fp = fopen (./users.txt, r);
while (!feof ($fp)) {
$buffer = fgets($fp, 4096);
echo $buffer;
}
fclose($fp);
Ok. But $buffer is not an array, is it? Why/what is 4096? What is !feof ?
Can anyone show me how to split() each line and parse to see if $user
exists?
Here's what I'm upto. I want to use users.txt as a user:password text
database
file.
I want to read users.txt into an array.
I want to parse each line splitting for :
user:pass
john:help
michael:thanks
$fp = fopen (./users.txt, r);
while (!feof ($fp)) {
$buffer = fgets($fp, 4096);
echo $buffer;
}
fclose($fp);
$user = john;
$num_fields = count($buffer);
for ($i = 0; $i $num_fields; $i++)
{
if ?? = $user then echo ??
}
Can anyone show me how to split() each line and parse to see if $user
exists?
?php
$fp = fopen (./info.txt, r);
print $fp;
fclose($fp);
?
$fp is just a file pointer, not the actual contents of the file. You need
to use fgets() (or something similar) to actually get the contents out.
http://www.php.net/manual/en/function.fgets.php
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RE: [PHP] Beginner question?
?php
//$fp = fopen (C:/Program Files/localhost/info.txt, r);
//$fp = fopen (http://compcanlit.ca/;, r);
$fp = fopen (./info.txt, r);
while (!foef($fp))
{
$line = fgets($fp, 1024);
echo $line;
}
fclose($fp);
?
what you were doing was opening a file ready for reading and then printing
the pointer to the file, and not the file itself...
-Original Message-
From: jtjohnston [mailto:[EMAIL PROTECTED]]
Sent: Friday, December 21, 2001 4:13 PM
To: [EMAIL PROTECTED]
Subject: [PHP] Beginner question?
This seems newbie. So what am I doing wrong? I want to print the
contents of the file. I get resource id #1 instead. Do I need to add a
header or what?
?php
//$fp = fopen (C:/Program Files/localhost/info.txt, r);
//$fp = fopen (http://compcanlit.ca/;, r);
$fp = fopen (./info.txt, r);
print $fp;
fclose($fp);
?
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Re: [PHP] Beginner question?
At 12:13 AM 12/21/2001 -0500, jtjohnston wrote: This seems newbie. So what am I doing wrong? I want to print the contents of the file. I get resource id #1 instead. Do I need to add a header or what? ?php //$fp = fopen (C:/Program Files/localhost/info.txt, r); //$fp = fopen (http://compcanlit.ca/;, r); $fp = fopen (./info.txt, r); print $fp; fclose($fp); ? $fp is just a file pointer, not the actual contents of the file. You need to use fgets() (or something similar) to actually get the contents out. http://www.php.net/manual/en/function.fgets.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
Re: [PHP] Beginner question?
Michael,
$fp = fopen (./users.txt, r);
while (!feof ($fp)) {
$buffer = fgets($fp, 4096);
echo $buffer;
}
fclose($fp);
Ok. But $buffer is not an array, is it? Why/what is 4096? What is !feof ?
Can anyone show me how to split() each line and parse to see if $user exists?
Here's what I'm upto. I want to use users.txt as a user:password text database
file.
I want to read users.txt into an array.
I want to parse each line splitting for :
user:pass
john:help
michael:thanks
$fp = fopen (./users.txt, r);
while (!feof ($fp)) {
$buffer = fgets($fp, 4096);
echo $buffer;
}
fclose($fp);
$user = john;
$num_fields = count($buffer);
for ($i = 0; $i $num_fields; $i++)
{
if ?? = $user then echo ??
}
Can anyone show me how to split() each line and parse to see if $user exists?
?php
$fp = fopen (./info.txt, r);
print $fp;
fclose($fp);
?
$fp is just a file pointer, not the actual contents of the file. You need
to use fgets() (or something similar) to actually get the contents out.
http://www.php.net/manual/en/function.fgets.php
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Re: [PHP] Beginner question?
:) Again why 1024? or 4096 or ... ?
while (!foef($fp))
{
$line = fgets($fp, 1024);
echo $line;
}
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