Re: [PHP] need real expert (geting outer files) *english/german*

2001-08-16 Thread Tribun

OK... here are more details...

my trying was to get the content from this url :
http://www29.gmx.net/v4/register?FILE_POS_OLD=0&ADDR_CHECK=&t=&COMPANY=&TITL
E=Herr&FIRSTNAME=Aaaa&MIDINITIAL=A&LASTNAME=Aaaa&STREET=Strandener Str.
1&ZIPCODE=51079&CITY=koeln&COUNTRYISO=DE&STATE=Nordrhein-Westfalen&LANGUAGES
=,de&PHONE=&MOBILEPHONE=&FAX=&HOMEPAGE=&GENDER=M&BIRTHDAY=01&BIRTHMONTH=1&BI
RTHYEAR=1901&MARRISTAT=S&HOUSEHOLDPERS=1&INCOME=0&EDUCATIONLEVEL=HSA&EMPLOYS
TAT=SC&COMPUTEROWN=0&INTERNETUSE=Private&MPHONE=0

(one line!) into a variable.


every other link succeed, but NOT this one.

I've tried to do that with fopen and fsockopen.


may be, i've made something wrong...

I HOPE, u know an answer, how to do that...

and please test it out, what you mean, and if it doesnt work, report anyway
your tryings.


;)

thanks!

Tribun (Patrick Lehnen)

PS: I've tried to solve this problem the hole day... I would like to, but I
cant believe, that someone knows the right solution lets hope ;)





"Richard Lynch" <[EMAIL PROTECTED]> schrieb im Newsbeitrag
00a801c12603$0ccb6c20$6401a8c0@Lynchux100">news:00a801c12603$0ccb6c20$6401a8c0@Lynchux100...
> Subject: [PHP] need real expert (geting outer files) *english/german*
>
>
> > the problem is, that this is very good restricted by serverside.
>
> If you've worked around that, you're probably now seeing something silly
in
> your fread() code...
>
> > But now I already get the file, and no more the error-message,
> > but the problem is, that the file will not completly load.
> >
> > this means, I receive the file, but only the first 4188 bytes from
> > 11988 bytes.
>
> You'd have to show us your source code for how you're dynamically
> downloading only half the file.
>
> We can't just guess at what you've done to make it stop...
>
> It's extremely unliked for the server to decide halfway through a file
> download that you were not a valid user and to quit sending you stuff...
>
> --
> WARNING [EMAIL PROTECTED] address is an endangered species -- Use
> [EMAIL PROTECTED]
> Wanna help me out?  Like Music?  Buy a CD: http://l-i-e.com/artists.htm
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Re: [PHP] to set file tye at apache module using htaccess

2001-08-16 Thread Jack

In response to Maxim and Rasmus, I got it work out now. Many thanks for this
open source code community :-)
Jack
[EMAIL PROTECTED]
"Love your enemies, it will drive them nuts"
- Original Message -
From: Maxim Maletsky <[EMAIL PROTECTED]>
To: 'Jack' <[EMAIL PROTECTED]>
Cc: <[EMAIL PROTECTED]>
Sent: Thursday, August 16, 2001 2:01 AM
Subject: RE: [PHP] to set file tye at apache module using htaccess


> Yes, you can.
>
> Maxim Maletsky
>
>
> -Original Message-
> From: Jack [mailto:[EMAIL PROTECTED]]
> Sent: Friday, August 17, 2001 3:33 AM
> Cc: [EMAIL PROTECTED]
> Subject: Re: [PHP] to set file tye at apache module using htaccess
>
>
> In response to Rasmus again, please bare with me a sec, where can I find
the
> file https.conf? I am only able to log in to server viw ftp at this stage,
> so I am not sure if I will have access to that file yet. Alternatively,
can
> I do the same to .htaccess?
> Jack
> [EMAIL PROTECTED]
> "Love your enemies, it will drive them nuts"
> - Original Message -
> From: Rasmus Lerdorf <[EMAIL PROTECTED]>
> To: Jack <[EMAIL PROTECTED]>
> Cc: <[EMAIL PROTECTED]>
> Sent: Thursday, August 16, 2001 1:34 AM
> Subject: Re: [PHP] to set file tye at apache module using htaccess
>
>
> > > In response to Rasmus, I need to make this for all html files under a
> > > domain, not just one file. Is there anyway to do this?
> >
> > Sure, in your httpd.conf file look for your  block for the
> > dmain and add:
> >
> >  AddType application/x-httpd-php .html
> >
> > -Rasmus
> >
> >
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Re: [PHP] Eval error

2001-08-16 Thread Pavel Jartsev

Felipe Coury wrote:
> 
> Hi,
> 
> I am a beginner in PHP and I am trying to do the following: I have a form in
> a page that has 3 fields: email_1, email_2 and email_3. I am trying to send
> e-mail to those people, if the fields are filled. Relevant part of code:
> 
>  for ($i = 1; $i <= 6; $i++) {
> $eval = '\$email = \$email_' + $i + ';';
> eval( $eval );
> echo $email;
> }
> ?>
> 
> The code complains about an error in line eval( $eval );:
> 
> Parse error: parse error in
> /home/httpd/htdocs/hthcombr/cgi-local/envia.php(19) : eval()'d code on line
> 1
> 
> Can anyone please help me?
> 

Use arrays, it's much easier. Set name of fields like this: email[0],
email[1] and email[2].
Now after submitting the form you have array $email. And for-loop will
be:


Hope this helps.

-- 
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Re: [PHP] could i get a clue?

2001-08-16 Thread Renze Munnik

Robert V. Zwink wrote:
> This particular application is designed to assist someone working on data
> entry, and is currently in production.  She inputs 100's of mail-in reply
> cards into a database using a php webpage.  The first field of the form is
> for the email address listed on the reply card.  If the email address is
> already in the database, the person doing data entry will see an image of a
> red light, if the email address is not in the database the person doing data
> entry will see an image of a green light.  Kind of weird, true, but exactly
> what she wanted.  Why should the person doing data entry have to type in
> email address, mailing address, first name, last name, etc. just to get an
> error saying duplicate entry found?  This way she can choose to replace the
> record or just skip it depending on the results (red or green).  The
> changing image increases her productivty by decreasing time spent inputing
> duplicate data.
>
> And also is one possible answer to the question, "How do I access php from
> JavaScript".
>
> I fail to see how this is a "horrible construction".  Solves a problem with
> minimal input from user, quickly, and completely.  How is this horrible?
> Its a functional tool, that is used ever day with 0 complaints.
>
> Horrible?
> Inigo: "You keep using that word. I do not think it means what you think it
> means."



Michael Geier wrote:
> No it's not.
> First one is changing the address of the current window.
> Second one is a popup window leaving the first one intact.
>
> Just semantics.


A question for the both a you: Did either one of you actually _READ_
my message completely? No.

Michael... I said "same _KIND_OF_ construction". I didn't say it's
exactly the same. Kind of you to tell me thing I already know, but
it doesn't change anything. It still is the same _kind_of_
construction. Like I wrote before; you redirect someone to a
different page. And whether you do that in the same window or in a
window that pops up makes no change to that. The user still goes to
a different page for the result of the referenced PHP-script.

And Robert... Seems like a pretty cool application you got there and
for what you're doing there, the images _are_ a good solution. You
want the 'light' to switch from green to red depending on a db-query
in a different PHP-script. And it does, without the user having to
leave the page. Smart!
But like a wrote before; if you're not using any images on your
page, it's not a nice solution. Then one should put images on a page
where he/she doesn't want any images. And, like I wrote, then you
get the Sitestat/Nedstat kind of constructions where you have to put
a transparent image from 1x1 pixel on the page. That's not the way
to do it.
And why wouldn't I know what horrible means? Because I keep using
that word? Wow... then you must have absolutely no clue of what
words like 'is' and 'the' mean. Yes, I know... this doesn't make
sense... Neither does your remark (...)

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[PHP] .htaccess username

2001-08-16 Thread Tribun

...hmmm, I would guess there is a way, but I dont know why...

Can I read out the active username, which has just logged in through a
.htaccess authentication???

Like the access data..
user: patrick
pass: linux

can PHP reads out the usersname "patrick" ??

(and if ,... how? ;)

10x 4 U'r time.

Patrick




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Re: [PHP] .htaccess username

2001-08-16 Thread Pavel Jartsev

Tribun wrote:
> 
> ...hmmm, I would guess there is a way, but I dont know why...
> 
> Can I read out the active username, which has just logged in through a
> .htaccess authentication???
> 
> Like the access data..
> user: patrick
> pass: linux
> 
> can PHP reads out the usersname "patrick" ??
> 
> (and if ,... how? ;)
> 

$PHP_AUTH_USER and $PHP_AUTH_PW.

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Re: [PHP] Addtype command in htaccess

2001-08-16 Thread Pavel Jartsev

Jack wrote:
> 
> Hi people
> this may be off this list a bit, But I want to make the apache webserver believe 
>that a "html" file is my server is actually a "php4" file, Is this syntax correct to 
>add in the .htaccess file?
> 
> AddType application/x-httpd-php4 .html

Just remove the '4' from this line and it's ok.

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[PHP] Fussy logic...

2001-08-16 Thread Tribun

Moin!

Has anybody already thought about the problematic conditional on adding an
automatic "BACK" Link?

It seems to be very easy... just Link to basename($HTTP_REFERER);

BUT if you CLICK on this Link, and come to a prior site, the BACK-Link THERE
appears NOT to the PAGE, witch was prior this, but is linked to the Site you
come from...
so the link should better be called "FORWARD".

Do U C the problem???

;)

Has someone an idea to solve it?


Sincerely yours,
Patrick Lehnen (alias: Tribun)



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Re: [PHP] .htaccess username

2001-08-16 Thread Stig-Ørjan Smelror

Pavel Jartsev wrote:
> Tribun wrote:
> 
>>...hmmm, I would guess there is a way, but I dont know why...
>>
>>Can I read out the active username, which has just logged in through a
>>.htaccess authentication???
>>
>>Like the access data..
>>user: patrick
>>pass: linux
>>
>>can PHP reads out the usersname "patrick" ??
>>
>>(and if ,... how? ;)
>>
>>
> 
> $PHP_AUTH_USER and $PHP_AUTH_PW.
> 
> 

It's also possible to use $REMOTE_USER. I don't know of any 
$REMOTE_PASS, so the suggestion above it good ;)



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RE: [PHP] Creating a javascript array from database data

2001-08-16 Thread Tim Ward

I'm not sure if this is the problem but it is an important point. print
"\"$text\""; does not output anything to screen, as with all prints and
echos it outputs it to html (in this case within a js function definition).
Try viewing the source produced.

Tim

--
From:  Neil Freeman [SMTP:[EMAIL PROTECTED]]
Sent:  15 August 2001 18:10
To:  Sheridan Saint-Michel
Cc:  php-general
Subject:  Re: [PHP] Creating a javascript array from database data

Thanks a lot for your help Sheridan,

This now appears to work ok :) but if I remove the:

print "\"$text\"";

line (as it is not required), I receive errors complaining about a
syntax
error (related to what?) and that 'text' is undefined. As this line
simply
outputs the value to screen why should this cause a problem if it is
removed?
Or could it be some other problem?

Neil

PS: Here is my updated code:

--


Menus test




 0)
{
   echo "\n";
   echo "text = new Array(";
   while ($i < $number)
   {
  $text = mysql_result($result, $i, "name");

   $i++;

   if ($i < $number)
print ",";
  else
print ")\n";
  }
  echo "\n";
}

mysql_free_result($result);
mysql_close();
?>



--

Sheridan Saint-Michel wrote:

> ***
>  This message was virus checked with: SAVI 3.48
>  last updated 14th August 2001
> ***
>
> The thing to ALWAYS remember when working with both PHP and
> JavaScript is that PHP is Server-Side and JavaScript is
Client-Side.
>
> What this mean is practical terms is that when going from
JavaScript
> to PHP you have to submit or redirect back to the server... and
when
> going from PHP to JavaScript (Like you are trying to do here) you
> have to make sure your PHP outputs JavaScript.
>
> So instead of printing $text you need to actually print the
JavaScript...
>
> So in your case change the middle of your script to something
like:
>
> $number = mysql_numrows($result);
>
>  $i = 0;
>
>  if ($number == 0)
> print "Error - No records found";
> else
> {
>   echo "\n";
>   echo "text = new Array(";
>   while ($i < $number)
>   {
>  $text = mysql_result($result, $i, "name");
>  print "\"$text\"";
> $i++;
> if ($i < $number)
>   print ",";
> else
>   print ")\n";
>}
>   echo "\n";
> }
>
> }
>
> Note:  This is my quick *untested* fix done by modifying
> your code as little as possible.  I would suggest you use
> mysql_fetch_row and use your loop to parse it rather than
> making several calls to mysql_result (especially if you are
> ever going to have more than a few entries in the DB).
>
> Sheridan Saint-Michel
> Website Administrator
> FoxJet, an ITW Company
> www.foxjet.com
>
> - Original Message -
> From: Neil Freeman <[EMAIL PROTECTED]>
> To: PHP General <[EMAIL PROTECTED]>
> Sent: Wednesday, August 15, 2001 11:16 AM
> Subject: [PHP] Creating a javascript array from database data
>
> > Hi there,
> >
> > Well after a few hours roaming around various websites I am at a
loss.
> > Here is what I am trying to do:
> >
> > 1) Access a MySQL database which contains 1 table
> > 2) Read the records from this table
> > 3) Store the values returned from this table into javascript
array
> > elements, ie, if I get the values "dog", "cat" and "cow" back I
want
> > these stored in an array as such:
> > myArray[0] = valueReturned1
> > myArray[1] = valueReturned2
> > myArray[2] = valueReturned3
> >
> > You get the idea.
> >
> > Problem being that I cannot work out how to implement the
javascript
> > section of this. At the moment my php script writes the values
returned
> > from the database to screen but I require these to be stored in
a
> > javascript array. Please can someone help me before I go mad :)
> >
> > Here is my current .php script:
> >
> > --
> > 
> > 
> > Menus test
   

Re: [PHP] Creating a javascript array from database data (Off-List)

2001-08-16 Thread Neil Freeman

Thanks for the clarification Sheridan - I think it must have been end of day
madness on my part :) I see what's going on now with the 'print' line.

Cheers,

Neil

Sheridan Saint-Michel wrote:

> ***
>  This message was virus checked with: SAVI 3.48
>  last updated 14th August 2001
> ***
>
> Think in terms of output...  The JavaScript is literally going to
> try and run the output of the PHP (It doesn't even know PHP
> exists).  PHP is outputting the source code for the HTML and
> JavaScript.  So what you are trying to do is get PHP to take
> dog,cat,cow from MySQL and output:
>
> 
> text = new Array("dog","cat","cow")
> 
>
> This block of code does exactly that, with the print"\"$text\"";
> filling in dog cat and cow.  I've added comments so you can
> see how each line produces the above (I am using C-Style
> comments as the // gets mucked up in e-mail)
>
> The parts in [] are comments within comments to show flow
> control and are not output.
>
> else
> {
> /*  */
>   echo "