[zbmethod] Re: Motivation and balance

2005-11-24 Thread Doug Lee
Correction: +mirrors only, I counted inverses separately.

I can generate the algs and give an average move statistic on this 
using ACube. It would take ACube less than 1 minute on my newest 
machine to generate. It would take me like 5-10 minutes all together 
to report on my findings.

Right now I'm at home for Thanksgiving, and besides my computer on 
campus has a busted chipset fan. I'll get on it over the weekend.

This seems like something I am used to doing though. I recently 
generated a huge alg set for the sq-1, this type of stuff is right up 
my alley.


-Doug


--- In zbmethod@yahoogroups.com, "Mike Bennett" <[EMAIL PROTECTED]> 
wrote:
> That's a lot better than my quick guesstimate.  Thanks.  Now, any
> ideas on how to find the algs for the exact cases, or the average 
move
> count for them?  If it's really only 31 cases+inverses and mirrors, I
> would be very interested in learning them.  Especially considering 
how
> many of those I know already, like the 3 PLL's and the 3 cases
> permuting M slice pieces only.  Thanks for your help.
> 
> -Mike
> team [zb]
>






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[zbmethod] progress!!

2005-11-24 Thread cmhardw
Hey everyone,

I've been working on just transformation solves lately, and have not
been timing myself.  I'm trying to learn to recognize the T cases
without having to AUF.  It's awesome, I'm actually getting to the
point where I can recognize fairly quickly cases 5 and 6 without
evening having to AUF.  I haven't timed myself yet, but I think my
delays are getting shorter.

I'm also getting more comfortable at recognizing the cases I'm already
comfortable with, but without AUF at first.

Once I can comfortably identify without having to adjust the U face,
I'm going top get started with the U algs again.

I was getting discouraged at how hard this might be, but with more
practice it is getting easier!

Heh heh ZB is such a roller coaster sometimes, but it's still fun!

Chris
Team [ZB]





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[zbmethod] Re: A database

2005-11-24 Thread Mike Bennett
--- In zbmethod@yahoogroups.com, "cmhardw" <[EMAIL PROTECTED]> wrote:

> I can go back through and count the cases I know instead.  For this
> database are you guys more interested in the percentage of cases
> known, or the chance for a 1 look LL?
> 
> Chris

I suppose it probably makes more sense to list the probability for a 1
look LL, as opposed to the percentage of algs known, because the
probability has some practical application.  I just ammended my entry.
 The only real problem is that I'm not really certain the
probabilities on some of them.  I think my new entry more accurately
reflects the probabilities now.  I have a 6% or so chance for just a
PLL after my F2L, based on some corner orientation.  This will be a
good way to track everyone's progress.  I suppose I should go learn
some more ZBF2L...

-Mike
team [zb]





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[zbmethod] Re: Motivation and balance

2005-11-24 Thread Mike Bennett
--- In zbmethod@yahoogroups.com, "Doug Lee" <[EMAIL PROTECTED]> wrote:
>
> Ignoring the solved case and counting mirrors together but inverses 
> distinct...
> 
> First off, I looked at the number of totally distinct cases, that'd be 
> 6!/2 = 360. Exploiting two planes of symmetry that gives 90 cases 
> while exploiting 4 planes of symmetry gives 15 cases.
> 
> But that was just to get a rough estimate so that I know that my 
> answer is going to be between 14 and 79. Some cases are self-mirrors 
> that shouldn't be counted twice and some cases have more or less 
> symmetry than others... a bit of a mess trying to apply Burnside's 
> Lemma on.
> 
> So then I broke it up into categories:
> There are 8 cases involving a 5-edge cycle.
> There are 7 cases involving a 4-edge cycle and a 2-edge cycle.
> There are 6 cases involving two disjoint 3-edge cycles.
> There are 4 cases involving a single 3-edge cycle.
> There are 6 cases involving two disjoint 2-edge cycles.
> There is the solved case.
> 
> Thus I conclude that there are 31 cases not counting the solved case. 
> Also 3 of the algs needed are from PLL, so it's really only 28 algs to 
> memorize, some of which maybe inverse of each other.
> 
> That is a quick count, nothing rigorous... see if you can find any 
> flaws in my reasoning.
> 
> 
> -Doug

That's a lot better than my quick guesstimate.  Thanks.  Now, any
ideas on how to find the algs for the exact cases, or the average move
count for them?  If it's really only 31 cases+inverses and mirrors, I
would be very interested in learning them.  Especially considering how
many of those I know already, like the 3 PLL's and the 3 cases
permuting M slice pieces only.  Thanks for your help.

-Mike
team [zb]






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[zbmethod] Weird dream

2005-11-24 Thread Bob Burton
Hey all...

I actually had this weird dream in which somebody suggested to me that
I slow down because I'm learning too much too fast and that my times
will slow down too much if I continue to learn.  I thought this was
very very strange, but I am going to keep on learning anyway. ;)

~ Bob





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[zbmethod] Re: A database

2005-11-24 Thread Bob Burton
For the VHF2L column, that is knowing the 32 "tricks" on Dan Harris'
site.  This is some sort of intermediate for ZBF2L.

~ Bob

--- In zbmethod@yahoogroups.com, "cmhardw" <[EMAIL PROTECTED]> wrote:
>
> I also didn't know what to do about the VHF2L column, as I never
> really learned exactly how it works.  I just put 0%, since I figure if
> I don't even know how exactly one uses it, then I don't know it.
> 
> I guess I should change my ZBLL %, since that's not really the number
> of cases I know, but my chance for a 1 look LL, and even then it's
> only an estimate.
> 
> I count the chance for a PLL skip after COLL as a "ZBLL" case, but I
> don't count all the cases where I know whether to use the L or R
> reflection of an alg on the same RL symmetric COLL case to be more
> likely to get a ZBLL solve.
> 
> I can go back through and count the cases I know instead.  For this
> database are you guys more interested in the percentage of cases
> known, or the chance for a 1 look LL?
> 
> Chris
> 
> --- In zbmethod@yahoogroups.com, "Doug Lee" <[EMAIL PROTECTED]> wrote:
> >
> > Thanks Bob!
> > 
> > Made me sit down and count up the cases I know w.r.t the 
> > probabilities. I was ONE case away from knowing more than Chris (at 
> > least on paper) for ZBLL. I was a bit suprised at the high
percentages 
> > here. So anyhow I decided to learn one more case: "T1 with edges H".
> > 
> > That did the trick and tipped the scale :).
> > 
> > Anything to bring out our competitive natures.
> > 
> > Not sure how VHF2L would be defined so I'm not sure what that column 
> > really means.
> > 
> > I hope everybody did the case counts with factoring in the 
> > probabilities of occurance. I think that would be a better comparison 
> > value.
> > 
> > 
> > -Doug
> > 
> > 
> >
>






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[zbmethod] Re: A database

2005-11-24 Thread cmhardw
I also didn't know what to do about the VHF2L column, as I never
really learned exactly how it works.  I just put 0%, since I figure if
I don't even know how exactly one uses it, then I don't know it.

I guess I should change my ZBLL %, since that's not really the number
of cases I know, but my chance for a 1 look LL, and even then it's
only an estimate.

I count the chance for a PLL skip after COLL as a "ZBLL" case, but I
don't count all the cases where I know whether to use the L or R
reflection of an alg on the same RL symmetric COLL case to be more
likely to get a ZBLL solve.

I can go back through and count the cases I know instead.  For this
database are you guys more interested in the percentage of cases
known, or the chance for a 1 look LL?

Chris

--- In zbmethod@yahoogroups.com, "Doug Lee" <[EMAIL PROTECTED]> wrote:
>
> Thanks Bob!
> 
> Made me sit down and count up the cases I know w.r.t the 
> probabilities. I was ONE case away from knowing more than Chris (at 
> least on paper) for ZBLL. I was a bit suprised at the high percentages 
> here. So anyhow I decided to learn one more case: "T1 with edges H".
> 
> That did the trick and tipped the scale :).
> 
> Anything to bring out our competitive natures.
> 
> Not sure how VHF2L would be defined so I'm not sure what that column 
> really means.
> 
> I hope everybody did the case counts with factoring in the 
> probabilities of occurance. I think that would be a better comparison 
> value.
> 
> 
> -Doug
> 
> 
> 







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[zbmethod] Re: A database

2005-11-24 Thread Doug Lee
Thanks Bob!

Made me sit down and count up the cases I know w.r.t the 
probabilities. I was ONE case away from knowing more than Chris (at 
least on paper) for ZBLL. I was a bit suprised at the high percentages 
here. So anyhow I decided to learn one more case: "T1 with edges H".

That did the trick and tipped the scale :).

Anything to bring out our competitive natures.

Not sure how VHF2L would be defined so I'm not sure what that column 
really means.

I hope everybody did the case counts with factoring in the 
probabilities of occurance. I think that would be a better comparison 
value.


-Doug



--- In zbmethod@yahoogroups.com, "Bob Burton" <[EMAIL PROTECTED]> wrote:
>
> Hey all,
> 
> I created a database for people to update their progress in learning
> ZB by showing how much they know for certain aspects of ZB.
> 
> ~ Bob
> Team [zb]
>






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[zbmethod] Re: Motivation and balance

2005-11-24 Thread Doug Lee
Ignoring the solved case and counting mirrors together but inverses 
distinct...

First off, I looked at the number of totally distinct cases, that'd be 
6!/2 = 360. Exploiting two planes of symmetry that gives 90 cases 
while exploiting 4 planes of symmetry gives 15 cases.

But that was just to get a rough estimate so that I know that my 
answer is going to be between 14 and 79. Some cases are self-mirrors 
that shouldn't be counted twice and some cases have more or less 
symmetry than others... a bit of a mess trying to apply Burnside's 
Lemma on.

So then I broke it up into categories:
There are 8 cases involving a 5-edge cycle.
There are 7 cases involving a 4-edge cycle and a 2-edge cycle.
There are 6 cases involving two disjoint 3-edge cycles.
There are 4 cases involving a single 3-edge cycle.
There are 6 cases involving two disjoint 2-edge cycles.
There is the solved case.

Thus I conclude that there are 31 cases not counting the solved case. 
Also 3 of the algs needed are from PLL, so it's really only 28 algs to 
memorize, some of which maybe inverse of each other.

That is a quick count, nothing rigorous... see if you can find any 
flaws in my reasoning.


-Doug


--- In zbmethod@yahoogroups.com, "Mike Bennett" <[EMAIL PROTECTED]> 
wrote:
> Can someone help me work out the number of possible combinations for
> when there are 1x3x4 blocks on the sides, all four U layer corners
> correct, and the final 6 edges and centers oriented?  I'd really like
> to know, to see if this is a strategy worth pursuing.






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