I think this is related to WSGI.
On Oct 6, 7:17 pm, Merrick <[EMAIL PROTECTED]> wrote:
> That is the approach I took and how I resolved the original problem
> with the 404. It led me to find that "AllowEncodedSlashes On" in
> Apache is needed for encoded slashes to be allowed in the pathname
>
That is the approach I took and how I resolved the original problem
with the 404. It led me to find that "AllowEncodedSlashes On" in
Apache is needed for encoded slashes to be allowed in the pathname
information following the filename.
The problem now is that
http%3A%2F%2F prints http:/ in my
On Mon, 2008-10-06 at 16:10 -0700, Merrick wrote:
> keith, thanks for trying.
>
> %2f is the encoded value of /, but urls contain other characters as
> well not just alphanumeric.
I think you're debugging the wrong piece of the problem here. Your
original regular expression must have been
While I have not found the complete solution, I am closer. I added
this to my apache settings for the virtual host:
AllowEncodedSlashes On
I am no longer getting a 404. But even though the url has two
instances of %2f to represent two slashes:
keith, thanks for trying.
%2f is the encoded value of /, but urls contain other characters as
well not just alphanumeric.
I suspect this issue may have to do with apache or WSGI but not sure
what.
On Oct 6, 4:06 pm, "Keith Eberle" <[EMAIL PROTECTED]> wrote:
> quick solution, i think you could
quick solution, i think you could add the % to the regex (i'm hardly a
regex master):
r'^find/(?P[%-\w]+)$
keith
On Mon, Oct 6, 2008 at 7:05 PM, Merrick <[EMAIL PROTECTED]> wrote:
>
> I have narrowed down the problem to %2F in my url, anyone?
>
>
>
> On Oct 6, 2:55 pm, Merrick <[EMAIL
I have narrowed down the problem to %2F in my url, anyone?
On Oct 6, 2:55 pm, Merrick <[EMAIL PROTECTED]> wrote:
> \w will only match alphanumeric characters, I need to match anything
> and will let my modelform verify that it is indeed a URL.
>
> On Oct 6, 2:43 pm, Merrick <[EMAIL PROTECTED]>
Thank you, I meant urls.py. APPEND_SLASH = False so I omitted the
trailing slash from the regex line:
r'^find/(?P[-\w]+)$
and if I pull up the address:
http://mydomain.com/find/http%3A%2F%2Fwww.wired.com%2F
I still get
Not Found
The requested URL /find/http://www.wired.com/ was not found on
\w will only match alphanumeric characters, I need to match anything
and will let my modelform verify that it is indeed a URL.
On Oct 6, 2:43 pm, Merrick <[EMAIL PROTECTED]> wrote:
> Thank you, I meant urls.py. APPEND_SLASH = False so I omitted the
> trailing slash from the regex line:
>
>
it looks like you have mismatched parens, and no trailing slash, which will
matter if APPEND_SLASH = True. the regex should look like:
r'^find/(?P[-\w]+)/$'
should be urls.py too, not views.py.
keith
On Mon, Oct 6, 2008 at 1:17 PM, Merrick <[EMAIL PROTECTED]> wrote:
>
> I am trying to
I am trying to figure out how to match / capture a URL.
views.py
===
urlpatterns = patterns('',
url(r'^find/(?P(.*)$',
view = 'myapp.views.find',
name = 'find'
),
when I enter in this address:
mydomain.com/find/www.wired.com
my view / template are executed, but if
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