See the date function
Http://www.php.net/date
Bastien
Sent from my iPod
On Apr 8, 2009, at 21:41, Jack Lauman wrote:
I need to reformat the output of the 'dates' field from '2009-04-08'
to 'Wed. Apr. 8th'. Any help would be appreciated.
Thanks.
---
for ($counter = 0; $counter < mysql_n
Jack Lauman wrote:
I need to reformat the output of the 'dates' field from '2009-04-08' to
'Wed. Apr. 8th'. Any help would be appreciated.
You can either do it using mysql date formats (see
http://dev.mysql.com/doc/refman/5.0/en/date-and-time-functions.html#function_date-format)
or something
On Tue, Aug 5, 2008 at 4:33 PM, Ben Miller <[EMAIL PROTECTED]>wrote:
> Figured there had to be an easier way. Thank you so much.
>
> -Original Message-
> From: Simcha Younger [mailto:[EMAIL PROTECTED]
> Sent: Tuesday, August 05, 2008 2:48 PM
> To: php-db@lists.php
Figured there had to be an easier way. Thank you so much.
-Original Message-
From: Simcha Younger [mailto:[EMAIL PROTECTED]
Sent: Tuesday, August 05, 2008 2:48 PM
To: php-db@lists.php.net
Subject: RE: [PHP-DB] Date Translation in MySQL
Select * FROM ... WHERE DAYOFWEEK(datecol)=7
Select * FROM ... WHERE DAYOFWEEK(datecol)=7
-Original Message-
From: Ben Miller [mailto:[EMAIL PROTECTED]
Sent: Tuesday, August 05, 2008 8:10 PM
To: PHP. DB Mail List
Subject: [PHP-DB] Date Translation in MySQL
I'm looking for a quick and simple way to query a MySQL database by date, or
Something like this should work.
$today = mktime(0, 0, 0, date("m"), date("d"), date("Y"));
$tomorrow = mktime(0, 0, 0, date("m"), date("d") + 1, date("Y"));
$sql = "SELECT COUNT(*) FROM table WHERE regdate BETWEEN {$today} AND
{$tomorrow}";
$thismonth = mktime(0, 0, 0, date("m"), 1, date("Y")
www.php.net/date will show you all the possibilities of formatting the date
bastien
> Date: Sat, 22 Dec 2007 17:54:07 +0600
> From: [EMAIL PROTECTED]
> To: php-db@lists.php.net
> Subject: [PHP-DB] date format problem
>
> my problem is with date format
>
you can mimic the old behaviour like so:
select TS, 1*TS as OldStyle;
(TS being your timestamp filed)
TS |OldStyle
2007-09-03 15:03:02 | 20070903150302
rDubya wrote:
>
> WOW!! Thanks for all the help guys!! And Instruct ICC.. you're
> solution for pulling the events did work.. but.. i
WOW!! Thanks for all the help guys!! And Instruct ICC.. you're
solution for pulling the events did work.. but.. it turns out that
the solution was actually much simpler than I thought:
The old mysql database (once again, not sure what version) stored the
date as MMDDHHMMSS. The new databas
"This DID work, but I recently switched hosting companies..."
Is the new server in a different country with a different date format
/ time zone?
Just a thought ;-\
On 9/7/07, Instruct ICC <[EMAIL PROTECTED]> wrote:
> >From: "Instruct ICC" <[EMAIL PROTECTED]>
> >And while not trusting your index
From: "Instruct ICC" <[EMAIL PROTECTED]>
And while not trusting your indexing, rewrite short_date as:
My short_date rewrite was also wrong. So it looks like you will have to
learn those offsets for this function if you do it on the PHP side. But you
could also do it on the MySQL side.
__
From: rDubya <[EMAIL PROTECTED]>
Thanks for the help so far guys!!
Not helping though. I have the date contained in the database as timestamp
(-MM-DD HH:MM:SS).
Do you really need to pull events from the database which are not in your
range of interest? This will only slow down your pro
Thanks for the help so far guys!!
Not helping though. I have the date contained in the database as timestamp
(-MM-DD HH:MM:SS). The problem is that not only is it not displaying
events, but if I alter my code so that it displays ALL events, it shows the
events for the last year, and those up
Argh, make sure you add the closing paren for the date_add since I
forgot it.
Mike...
Mike Gohlke wrote:
It's much better to use add_date instead of to_days since mysql isn't
smart enough to do it for you.
Such as:
SELECT yourEventFields FROM theTable
WHERE theEventDate BETWEEN now() AND date
It's much better to use add_date instead of to_days since mysql isn't
smart enough to do it for you.
Such as:
SELECT yourEventFields FROM theTable
WHERE theEventDate BETWEEN now() AND date_add(now(), INTERVAL 21 DAYS;
This way mysql will calc the now() and date_add and will essentially
convert
From: rDubya <[EMAIL PROTECTED]>
My problem is that I have events dated for Sep 2007 and on, and yet
they all come up as being on Dec 7 to 9, 2006.. any ideas?
rDubya
How about having MySQL only return the events you are interested in?
SELECT yourEventFields FROM theTable
WHERE
TO_DAYS( theEv
At 12:26 PM 1/21/2007, Denis L. Menezes wrote:
Dear friends.
I have a date field in mysql called event_end .
I want to run a query to find all records where the event_and is greater
than today's date. I have written the following code. It does not work.
Please point out the mistake.
$today =
Manoj Singh wrote:
I am developing a site in php implementing the concept of rss feeds. For
that i want to convert the standard date into RFC822 format.
If any one have idea about it, please help me.
Go to http://php.net/date and search the page for RFC822. If you need
further help read the r
ph Brickley
-Original Message-
From: Ralph Brickley [mailto:[EMAIL PROTECTED]
Sent: Tuesday, May 16, 2006 1:29 PM
To: [EMAIL PROTECTED]; 'Php-Db'
Subject: RE: [PHP-DB] Date Conversion
A simple associate array would work as well, although not quite as elegent.
$months_arr = ar
A simple associate array would work as well, although not quite as elegent.
$months_arr = array("January"=>01, "February"=>02...);
-Original Message-
From: Mark Bomgardner [mailto:[EMAIL PROTECTED]
Sent: Tuesday, May 16, 2006 12:35 PM
To: Php-Db
Subject: [PHP-DB] Date Conversion
PHP 4.4/
Mark Bomgardner wrote:
PHP 4.4/MySQL 4.0
I am tying to convert a date to put into a database from a string (ie:
January, February) to a numeric value (ie: 01,02). I am taking the
value from a form, which is a drop down menu listing the months.
$sMonth1 = $_POST['Smonth']; returns the mon
This works perfect, Bastien!
Many thanks.
Gerry
On 3/13/06, Bastien Koert <[EMAIL PROTECTED]> wrote:
>
> select * from table where date_format(date_field, '%Y-%m') = '2006-02'
>
>
> bastien
>
>
> >From: "Gerry Danen" <[EMAIL PROTECTED]>
> >To: php-db@lists.php.net
> >CC: [EMAIL PROTECTED]
> >Sub
select * from table where date_format(date_field, '%Y-%m') = '2006-02'
bastien
From: "Gerry Danen" <[EMAIL PROTECTED]>
To: php-db@lists.php.net
CC: [EMAIL PROTECTED]
Subject: [PHP-DB] Date question
Date: Sun, 12 Mar 2006 20:44:13 -0700
While I am rebuilding my crashed laptop (the machine tha
Gerry Danen wrote:
While I am rebuilding my crashed laptop (the machine that had all my
intelligence), I started thinking about a select statement I need.
I have log info in a table and want to extract it on a monthly basis. The
date field is in -mm-dd format. What's a good way to select tho
For example, you have table `logs` with `datelog` field and you want to
select dates
that match 2006-02. You can try this select statement:
SELECT * FROM `logs` WHERE MONTH(datelog)='02' and YEAR(datelog)='2006'
Hope that helps.
LJ Regalado
Bastien's example is probably the quickest and easiest. I just wanted to point
out that you can use math within the mktime() function as well in case the
relative date/time you need isn't "right now".
$month = 1;
$day = 19;
$year = 2006;
$hour = 17;
$minute = 08;
$second = 05;
echo date("Y-m-d
$date_90_minutes_ago = date('m/d/Y',mktime()-(60*90));
$time_90_minutes_ago = date('h:i:s',mktime()-(60*90));
60 seconds * 90 minutes.
=C=
|
| Cal Evans
| http://www.calevans.com
|
| We get our best customers from referrals.
| We would appreciate you referring any of your
| friends or co-workers
bastien
From: "Ron Piggott (PHP)" <[EMAIL PROTECTED]>
Reply-To: [EMAIL PROTECTED]
To: PHP DB
Subject: [PHP-DB] Date & Time 90 minutes ago
Date: Thu, 19 Jan 2006 16:57:33 -0500
Would someone be able to help me with the DATE command syntax to know
what the date and time was 90 minutes ago? I
You got the right idea, but you're making it more complicated than it needs to
be.
your $sDate after using explode() is going to contain an array. strtotime
doesn't take an array, it takes a string.
$monthName = date("F", strtotime($row_events['Sdate']));
$monthNumber = date("m", strtotime($r
You need to use:
date('Y-m-d H:i:s');
It's in the comments at:
http://www.php.net/date
Jordan
On Sep 9, 2005, at 12:52 PM, Ron Piggott wrote:
Question:
I am trying to for the first time create a table with a column that is
defined as datetime
I wanted to populate that column with the dat
use timestamp column type and populate it by
$date = strtottime(date(r));
then when you want to display it
$date = date('r',$row['datefieldname']);
Bastien
From: "Ron Piggott" <[EMAIL PROTECTED]>
Reply-To: "Ron Piggott" <[EMAIL PROTECTED]>
To: "PHP DB"
Subject: [PHP-DB] DATE(r)
Date: Fri,
I suppose there is a " submit_time" field in your DB table, so you could:
"SELECT * FROM `tablename` WHERE `submit_time`>=".lastdays(3)
lastdays() is a function you could create using mktime(),time(), and date()
On Tue, 22 Mar 2005 16:28:39 -0500, Chris Payne <[EMAIL PROTECTED]> wrote:
> Hi ther
Interesting use of split().. don't think I've ever used that function but looks
like it'll do just as well and also allow multiple dividers. Thanks for
pointing that out.
As for this:
$mysqldate = $y.'-'.$m.'-'.$d;
The only problem I foresee is what happens when you have single digit days an
To view the terms under which this email is distributed, please go to
http://disclaimer.leedsmet.ac.uk/email.htm
On 16 December 2004 06:00, neil wrote:
> Hi
>
> I am needing to convert a d/m/y date such as 30/11/2004 into the
> format that mysql can use ie. 2004-11-20
>
> If I try the follow
Thank you for all your help.
Among all the variations I found this to be the clearest:
list($d,$m,$y) = explode("/",$testdate);
$mysqldate = date("Y-m-d", mktime(0,0,0,$m,$d,$y));
But I also thought the use of split instead of explode so you could nominate
multiple delimiters was good.
eg.
list
On Thursday 16 December 2004 14:00, neil wrote:
> I am needing to convert a d/m/y date such as 30/11/2004 into the format
> that mysql can use ie. 2004-11-20
>
> If I try the following:
>
> $testdate="30/11/2004";
> echo date("Y-m-d", strtotime($testdate));
>
> the result is - 2006-06-11
>
> I can
Yeah, this is my problem with relyinig on strtotime(). If you don't give it a
format that it knows, it's going to give you random results (well, not random,
but "undesireable"). Seems like more of a crutch that leaves too much chance
of error for my taste. I prefer to be a little more explici
Bomgardner, Mark A wrote:
I am having trouble converting a date from mm/dd/ to -mm-dd on a
user form. I know there was post about this, but I keep getting an
error message when I try to search the archives.
I have looked at the manual, but I am not finding what I am looking for.
echo date(
How are you trying to convert the date?
bastien
From: "Bomgardner, Mark A" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Subject: [PHP-DB] Date Question
Date: Wed, 27 Oct 2004 11:17:16 -0500
I am having trouble converting a date from mm/dd/ to -mm-dd on a
user form. I know there was post ab
-Original Message-
From: Karen Resplendo
To: [EMAIL PROTECTED]
Sent: 02/07/04 19:36
Subject: [PHP-DB] Date problem: data is current as of yesterday
The database queries all the sources at night after everyone has gone
home. That means the data was current as of yesterday. This little
snipp
accidentally replied only to karen.
> The database queries all the sources at night after everyone has gone
home. That means the data was current as of yesterday. This little snippet
below returns yesterday's date, except that the first day of the month
returns "0" for > the day. Now, I know why
Use strtotime() instead..
http://us2.php.net/manual/en/function.strtotime.php
Regards,
Neal Carmine
Nine Systems Corporation
-Original Message-
From: Karen Resplendo [mailto:[EMAIL PROTECTED]
Sent: Friday, July 02, 2004 12:36 PM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] Date problem: dat
Hi Neil,
I would actually like to get a sample of this code as well if you don't
mind
K-
-Original Message-
From: Neil Smith [MVP, Digital media]
[mailto:[EMAIL PROTECTED]
Sent: 25 June 2004 16:22
To: [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Subject: Re: [PHP-DB] Date help neede
0
Content-Type: text/plain;
charset="us-ascii"
Content-Transfer-Encoding: 7bit
Subject: RE: [PHP-DB] Date help needed
One thing he wanted which I didn't know how to do (Javascript I guess which
I don't know much about) was to preload a database of email address, and as
EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
Sent: 25 June 2004 12:15
To: Tom Chubb
Cc: [EMAIL PROTECTED]; [EMAIL PROTECTED]
Subject: Re: [PHP-DB] Date Select
>How can I query a MySQL table to get the latest results from a date field?
>Basically, I am inserting several records at a time at the
>How can I query a MySQL table to get the latest results from a date field?
>Basically, I am inserting several records at a time at the end of each
week.
>I want to have a page that displays the results for the last week only.
>The date format in the field is -MM-DD
if you want the latest
Hi there,
>A drop down with 365 days !?!? Isn't that a "little" big?
Actually it's Fridays, Sundays and Tuesdays for 2 years (365 was an example)
it's for an Admin for a client, and he asked that it be in a dropdown box
and he's the boss, so he gets what he wants :-)
One thing he wanted which
A drop down with 365 days !?!? Isn't that a "little" big?
> I have a problem, I currently have some code which populates a dropdown
> box
> - this code gives me every day for the next x amount of days (EG: a years
> worth of days), however what I really need to be able to do, is to find a
> way
Hi there,
Just got back and tried it and it works perfectly, thank you so much for
your help, you've got me out of a bind here ;-)
Chris
You could loop through the weeks and put those 3 specifically in:
$days = array();
for($i = 0; $i < 365; $i +=7) {
$days[] = strtotime('next Monday', strtoti
You could loop through the weeks and put those 3 specifically in:
$days = array();
for($i = 0; $i < 365; $i +=7) {
$days[] = strtotime('next Monday', strtotime('+ '.$i.' days'));
$days[] = strtotime('next Friday', strtotime('+ '.$i.' days'));
$days[] = strtotime('next Sunday', strtotime('+ '.
Kim Jacobs - MWEB wrote:
I have a script which pulls a date(date default NULL) and a time (time default NULL)
from a MySQL database, now I would like to display that date and time in a 'pretty'
format.
I've been able to show the date nicely with the help of this:
$ntime=strtotime(
try the WHERE clause.
SELECT name, address, phone, date FROM usertable WHERE date =
'-00-00'
And please, look at the mysql documentation, or at least the tutorial.
--
Marcjon
--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
SELECT
IF( B.Booking_End_Date != "-00-00",
DATE_FORMAT( B.Booking_End_Date, "%Y-%m-%d" ),
"N/A"
) AS Booking_End_Date
FROM Bookings AS B, etc.
HTH
Ignatius
_
- Original Message -
From: "Shaun" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
S
Shannon Doyle wrote:
My question, how do I get the date entered into the form add 35days to it
and then include that into the same sql query as the first one. Or do I have
to use a second sql query? If the second query how would I get the date and
add 35days??
INSERT INTO table (date1, date2) VALU
Brett King wrote:
Hi Angelo
Yes you will have to reformat and he is something that may help you.
Hope it does
function dateCheckMysql ($date) {
list($dateDay, $dateMonth, $dateYear) = explode("/", $date);
if ((is_numeric($dateDay)) && (is_numeric($dateMonth)) &&
Hi Angelo
Yes you will have to reformat and he is something that may help you.
Hope it does
function dateCheckMysql ($date) {
list($dateDay, $dateMonth, $dateYear) = explode("/", $date);
if ((is_numeric($dateDay)) && (is_numeric($dateMonth)) &&
(is_numer
From: "Angelo Zanetti" <[EMAIL PROTECTED]>
> This might be slightly off topic but hopefully someone can help.
> I have a field that is a varchar and I stored dates in it. But now I want
to
> change the type of the column to date, but I have a problem that the
formats
> differ:
>
> my format: mm/dd
1) Why do you send this to a DB list?
2) Try seeing the Date class of PEAR (PEAR::Date).
El Dom 02 Nov 2003 19:13, OpenSource escribió:
> Hi guys,
>
> This might not be the best place for this but here goes.
>
> I want to create a dropdown list with a date range of
>
have a look at the PEAR date package.
http://pear.php.net/package/Date
_
- Original Message -
From: "OpenSource" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Sunday, November 02, 2003 11:13 PM
Subject: [PHP-DB] date function
Hi guys,
This might not be the be
This might not be the best place for this but here goes.
You are correct. At the very least, you should probably be using the
general PHP list, not the database one.
I want to create a dropdown list with a date range of
Not to be obstinate, but it looks like you already have. But, assuming
t
On Saturday 06 September 2003 06:01, Darryl wrote:
> I have some php code that pulls from the mysql database. Here it is:
>
> mysql_connect("wildcat.osborneindustries.com", "webuser",
> "webpass");
>$mymonth = date('n');
>$cyear = date('Y');
> $query = "SELECT name,hdat
>
> I have a field in my mysql db wich is a timestamp with the format
>
> mmddhhmmss
>
> and I would like to display it like:
>
> dd/mm/
>
http://www.mysql.com/doc/en/Date_and_time_functions.html#IDX1333
SELECT DATE_FORMAT(timestamp_col_name, '%d/%m/%Y') FROM table_name
--
PHP Datab
> // Do some number crunching here //
>
> $newnow = $now-$numweeks;
>
> echo $now;
>
> $converted_date = date("d-m-y",$now);
>
> echo "$converted_date";
You should be running your $convewrted_date on $newnow, not $now
Gary Every
Sr. UNIX Administrator
Ingram Entertainment
(615) 287-4876
you could change mysql to a few different date formats, but i don't _think_
that is one of them.
Why not just take care of a format change on the way out with DATE_FORMAT.
Also, if you store the date as one of the defualt date[time] values then
you have tons of functions that you can run against
This worked perfectly, is very simple for me to use, and I would never have
come upon it in 10,000 years of trying. Thanks!
Thanks also to everyone who offered ideas.
> $f_date = date('F d, Y',strtotime($db_date));
--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: htt
> I have a simple need to reformat a variable coming in as $DatePick,
brought
> forward from a MySQL select in the format:
>
> 2003-11-18
>
> I need to convert it to the format
>
> November 18, 2003
$f_date = date('F d, Y',strtotime($db_date));
---John Holmes...
--
PHP Database Mailing
At 05:23 PM 6/10/2003 -0400, David Shugarts wrote:
I have a simple need to reformat a variable coming in as $DatePick, brought
forward from a MySQL select in the format:
2003-11-18
I need to convert it to the format
November 18, 2003
try the "dice-n-slice" method. use substr and concat
Hi David,
Try this one:
Regards,
Frank
- Original Message -
From: "David Shugarts" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Tuesday, June 10, 2003 11:23 PM
Subject: [PHP-DB] Date Formatting in PHP
>
>
>
> I have a simple need to reformat a variable coming in as $DatePick,
b
ehmmm what kind of dates do you use, maybe dates of birth?
when using date of unix timestamp you can't have dates befor 1970 so if
those timestamps represents an older date you can't use timestamps!
-mark-
-Oorspronkelijk bericht-
Van: David Rice [mailto:[EMAIL PROTECTED]
Verzonden
> function datetoymd($date){
> $dateymd = date('Y-m-d',$date);
>
> return $dateymd;
> }
>
> this function when output gives me the date 1970-01-01 (date of the unix
> timestamp start) so, ehm, why!?
Because you're not passing a valid Unix timestamp or whatever your passing
is empty.
---John Holme
Hi there,
Thank you John, you are a lifesaver :-)
Chris
> > I have a form which displays 3 dropdowns, day, month and year, I have
> it
> > displaying the default of the dropdown for month no problem, but how
> can I
> > get it to select the current date (day) in the dropdown, but show 31
> days
> I have a form which displays 3 dropdowns, day, month and year, I have
it
> displaying the default of the dropdown for month no problem, but how
can I
> get it to select the current date (day) in the dropdown, but show 31
days
> nomatter how many days are in the month? This is important even
thou
t - A monthly magazine for PHP Professionals. Get your copy
today. http://www.phparch.com/
> -Original Message-
> From: David Rice [mailto:[EMAIL PROTECTED]
> Sent: Wednesday, March 05, 2003 12:34 PM
> To: [EMAIL PROTECTED]; [EMAIL PROTECTED]
> Subject: Re: [PHP-DB] date funct
Sorry, I forgot to add the part at the bottom where I am calling the
function
=
$start = date('Ymd',strtotime($weekstart));
$query = "SELECT * FROM Rota WHERE date >= $start and date <= ($start +
INTERVAL 6 DAY) ORDER BY staff
> Here is the whole code of my function
>
> Whenever i run it, it say's there is a parse error on line 6, can't see
what
> is the problem
> the format of $weekstart (as it is stored in the Database) is -MM-DD
>
> =
> function tips
Here is the whole code of my function
Whenever i run it, it say's there is a parse error on line 6, can't see what
is the problem
the format of $weekstart (as it is stored in the Database) is -MM-DD
=
$start = date('Ymd',strto
> I want to use it in this function that i am creating (it's for a
resteraunt
> automated tips system, to work out how much tips each staff member is
> entitled to.
>
>
> function tips($weekstart){
> /* JUST BELOW HERE IS WHER
Good stuff here.
http://www.mysql.com/doc/en/Date_and_time_functions.html
Check out the SELECT DATE_ADD section. That might be what you're looking
for.
HTH,
Rich
> -Original Message-
> From: David Rice [mailto:[EMAIL PROTECTED]
> Sent: Tuesday, March 04, 2003 9:36 AM
> To: [EMAIL PROTEC
> I am looking for a way to take a date stored in a mysql database... and
find
> out the date seven days later.
>
> how would i do this?!
too easy...
SELECT date_column + INTERVAL 7 DAY FROM your_table ...
---John Holmes...
--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, vi
go to mysql.com en look for date
-Original Message-
From: Jorge Miguel Fonseca Martins [mailto:[EMAIL PROTECTED]
Sent: vrijdag 28 februari 2003 16:23
To: [EMAIL PROTECTED]
Subject: [PHP-DB] Date
How can a make a query that lists all the fields where a datefield as
the date of tomorow?
t the difference of 2 or 3 days?
-Original Message-
From: 1LT John W. Holmes [mailto:[EMAIL PROTECTED]]
Sent: Tuesday, February 04, 2003 10:04 AM
To: NIPP, SCOTT V (SBCSI); [EMAIL PROTECTED]
Subject: Re: [PHP-DB] Date Range Question...
> I am working on an app that needs to post informat
> I am working on an app that needs to post information to a website
> based on date. The tricky part for me is that the date is a range that
> spans either 2 or 3 days. I want the web page to dynamically populate
this
> information based on a query. The query will look something like this:
> my
thank you... this worked. best, addison
Simple MySQL.
After your ORDER BY clause use either ASC (I think this is the default) or
DESC. I'm pretty sure this'll work on date fields to produce the results you
want.
Your query will end up looking like:
"...order by createdate DESC"
-Original
Simple MySQL.
After your ORDER BY clause use either ASC (I think this is the default) or
DESC. I'm pretty sure this'll work on date fields to produce the results you
want.
Your query will end up looking like:
"...order by createdate DESC"
> -Original Message-
> From: Addison Ellis [mailt
> when retrieving data from the db and displaying it on the
> page by creation date how can i reverse the order so that the most
> recent entry appears first? here's what i have now:
>
> require("config.php");
>
> $obj = mysql_db_query($dbname,"select * from ads order by
createdate");
> ?
$query = mysql_query("SELECT UNIX_TIMESTAMP(fieldname) AS date WHERE id = '1';");
$array = mysql_fetch_array($query);
$mydate = date("j F, Y",$array[date]);
Change fieldname and the where clause, and that should work.
If you want to further munipulate how it looks, just look at the
dat
ewson
s.utk.edu>cc: "'[EMAIL PROTECTED]'"
<[EMAIL PROTECTED]>
Subjec
strftime()
offers a lot of formatting options for dates.
Hope it helps.
RUBANOWICZ Lisa wrote:
Hi All, I have a date format of -MM-DD in MySQL and am showing it on a PHP page. However I want to show it as
"2 February, 2003"
or "2 February"
Can someone please help me. The date will not ne
> > > mysql("$DBName","UPDATE Balances SET CompEarned=CompTaken+8 WHERE
> > > said='$said'") or die(mysql_error());
> > > mysql("$DBName","INSERT INTO Log VALUES(DATE_ADD($StopDate,
> > > INTERVAL 1 DAY,'',1,2,'$CalendarDetailsID')") or die(mysql_error());
> Actually this is generating another err
On Thursday 16 January 2003 00:55, NIPP, SCOTT V (SBCSI) wrote:
> Actually this is generating another error. Now, without the single
> quotes I am getting the following error:
>
> Column 'StartDate' cannot be null
>
> It looks like for some reason the DATE_ADD is returning a NULL
> val
: 1LT John W. Holmes [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, January 15, 2003 10:32 AM
To: 1LT John W. Holmes; NIPP, SCOTT V (SBCSI); [EMAIL PROTECTED]
Subject: Re: [PHP-DB] Date math functions...
> [snip]
> > if ($dateDiff == 3) {
> > mysql("$DBName","UPDATE B
]
Subject: Re: [PHP-DB] Date math functions...
> [snip]
> > if ($dateDiff == 3) {
> > mysql("$DBName","UPDATE Balances SET CompEarned=CompTaken+8 WHERE
> > said='$said'") or die(mysql_error());
> > mysql("$DBName","INSERT INTO Log VA
> [snip]
> > if ($dateDiff == 3) {
> > mysql("$DBName","UPDATE Balances SET CompEarned=CompTaken+8 WHERE
> > said='$said'") or die(mysql_error());
> > mysql("$DBName","INSERT INTO Log VALUES('DATE_ADD($StopDate,
> > INTERVAL 1 DAY','',1,2,'$CalendarDetailsID')") or die(mysql_error());
> >
> > My bi
[snip]
> if ($dateDiff == 3) {
> mysql("$DBName","UPDATE Balances SET CompEarned=CompTaken+8 WHERE
> said='$said'") or die(mysql_error());
> mysql("$DBName","INSERT INTO Log VALUES('DATE_ADD($StopDate,
> INTERVAL 1 DAY','',1,2,'$CalendarDetailsID')") or die(mysql_error());
>
> My big question is ab
On Saturday 30 November 2002 12:30, Chris Payne wrote:
> Hi there everyone,
>
> I've never really used the date functions beyond getting it to store the
> current date in a db.
>
> I have a dilema in that I need to get all the days in the current month and
> all the days in the next month (whatever
@Keane.com To: "'Edward Peloke'"
<[EMAIL PROTECTED]>
cc: "'Php-Db'" <[EMAIL PROTECTED]>
toredDate) as date FROM SomeTable where blah
blah"
Should work like that?
Aaron
-Original Message-
From: Edward Peloke [mailto:[EMAIL PROTECTED]]
Sent: November 18, 2002 2:50 PM
To: 'Php-Db'
Subject: RE: [PHP-DB] date()
it is just a datetime field and the clients use a ja
On Tuesday 19 November 2002 03:26, Aaron Wolski wrote:
> Hmm.. I would get it into a unix_timestamp (unless someone can suggest a
> reasoning for now doing so).
It really depends on where you want to manipulate the dates. If mostly from
within MySQL then store with DATE, DATETIME & TIMESTAMP, if
Sent: November 18, 2002 2:50 PM
To: 'Php-Db'
Subject: RE: [PHP-DB] date()
it is just a datetime field and the clients use a javascript calander to
pick the date, here is the exact date as it appears in the db.
2002-11-08 00:00:00
Eddie
-Original Message-
From: Aaron Wolski [mailto:[
eloke'; 'Php-Db'
Subject: RE: [PHP-DB] date()
Ok..
I guess it depends on how your date is stored. I always use
unix_timestamps.
If you are too.. then the format I supplied should work as indicated.
Aaron
-Original Message-
From: Edward Peloke [mailto:[EMAIL PROTECTED]]
Sen
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