[PHP] Re: Need To Find A php Person

2003-02-11 Thread rija
Hello,
I'm likely the person you're looking for.
My name's Rija
I live in Vanuatu, and I teach IT and computer science for the MontMartre
High School.

I'll give you some of the best website I've done:
- trano-bongo.com
- evelyneproducts.com
- vanua2.com
- madeinpacific.com

Also, I've done plenty static websites.
For further information
contact me at this e.mail address : [EMAIL PROTECTED]



Michael McGlaughlin [EMAIL PROTECTED] a écrit dans le message :
[EMAIL PROTECTED]
 Hello,

 I am looking for someone well versed and established who understands the
php language and who can support a product that I have that I cannot receive
support from by the original developer.

 What would be the best way for me to go about finding someone? We paid the
developer by making a donation to him for his script, then paid him for some
further customizations, which he completed, but now he does not appear
interested in additional cusomization work on our system and I am left in a
bit of a lurch.

 Any help you can give would be greatly appreciated.

 Sincerely,
 Michael


 _
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[PHP] Test

2003-02-10 Thread rija
test



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[PHP] How can I install PHP 4.2.3 and Apache on WIN98 ?

2003-02-10 Thread rija
I want to run php 4.2.3 on Windows 98 2nd edition using apache server, but
after installing apache on it, I've got the following message, No service
installed.
So how can I install it? Then, I also cannot install php.

Any thought?



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Re: [PHP] http_get_var and isset() not working with script generated includes.

2002-11-18 Thread rija
Yep,
You need make global every variable used in yout include.
Maybe, you should declare-
GLOBAL $_GET ;

or do not call function to include your include
just do simply like this,

 foreach ($sections as $key = $value)  include mod.section. . $value .
.php;

- Original Message -
From: Moo [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Friday, November 15, 2002 7:55 AM
Subject: [PHP] http_get_var and isset() not working with script generated
includes.


 I wrote a bug report but [EMAIL PROTECTED] bogusified my report without the
 least bit of information.
 My script uses multiple includes and the file names all have the same
 syntax. So instead of writing each individual include, I created an
 array which contains all the filenames

 function LoadSections($sections)
 {
  foreach ($sections as $key = $value)
  {
   include mod.section. . $value . .php;
  }
 }
 instead of writing
 include file_x;
 include file_y;
 and so on

 All the files load well except that I cannot access HTTP_GET_VARS and
 the isset() function always return false (when they are inside the
included
 files).

 NB My includes work fine when loaded individually



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Re: [PHP] is this not possible?

2002-11-18 Thread rija

- Original Message -
From: Jeff Bluemel [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Tuesday, November 19, 2002 8:39 AM
Subject: [PHP] is this not possible?


 I'm been ignored on this question for 4-5 days now.  even if it is not
 possible could somebody please verify this?

 is it possible to pass a variable from javascript directly to php WITHOUT
 using either a link, or a form submit to pass the variables?  I've gotten
a
 work around to call an image that's actually a php file, but run my
script,
 and then return an image file.

Try Header refresh or some java applet to send javascript variable without
user click something.


 is this the only way?



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[PHP] IMAP_mailboxcreate problem

2002-11-18 Thread rija
What does this imap_errors()  mean : mailbox is empty 
I tried to create new mailbox using this simple script:

if (!imap_createmailbox($mbox, 
imap_utf7_encode({192.168.0.1:110/pop3}INBOX.$newname)))
echo Impossible de créer une nouvelle boîte aux lettres 
:.implode(br\n,imap_errors() ) ;

Thanks in advance.



[PHP] PHP 4.2.3 on Apache 2.0.39

2002-11-17 Thread rija
Hi Guys

I'm installing PHP 4.2.3 on Apache Server 2.0.41.
If I try localhost or localhost/manual it work perfectly,

Now I want to run my php program, I developed on IIS 5.0 environment, on my new Apache 
server
I get the message below , and my browser display HTTP 400 - BAD request page, which 
means The page cannot be found although all the files are there.


[Mon Nov 18 11:04:28 2002] [error] [client 127.0.0.1] Invalid URI in request GET 
/domains/home.php HTTP/1.1, referer: http://localhost/domains/

I put these few line in my httpd.conf
  a.. ScriptAlias /php/ c:/php/ 

  b.. AddType application/x-httpd-php .php .phtml 

  c.. Action application/x-httpd-php /php/php.exe





Re: [PHP] Write file can't work ?!? :-(

2002-11-17 Thread rija
Try to change write permission doing like the following:
- Right click on the folder
- Select proprieties
- Click on security icon
- And allow everyone to write, read, execute

If you cannot access this tools, ask your administrator to allow you to do
this work.


- Original Message -
From: Ivan Marenic [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Monday, November 18, 2002 7:21 AM
Subject: Re: [PHP] Write file can't work ?!? :-(


 Here is IIS permisin setting. Watch attachment.

 Thanks for help!


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Re: [PHP] returning unique values in columns

2002-11-14 Thread rija
GROUP BY column ???

For example if you want the count(*) of each value
do like this
SELECT column, count(*) from 'tablename' GROUP BY column ;

- Original Message - 
From: [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Friday, November 15, 2002 8:17 AM
Subject: [PHP] returning unique values in columns


 Is there any way to run a query in mysql that retuns unique values in a
 column?  For example, say i had this colum:
 
 Column:
 -
 Fashion
 -
 Basics
 -
 Fashion
 -
 Plus
 
 Plus
 -
 
 but I only want it to return unique values - in this case I would only
 want Fashion, Basics, Plus - instead of the Fashion, Basics, Fashion,
 Plus, Plus I would get if I had run: SELECT column FROM tblname;
 
 any help would be greatly appreciated...
 



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Re: [PHP] Removing duplicates in multi-dimensional array

2002-11-14 Thread rija
You can also create new uni dimensional array
with key like this '0-1' and run array_unique
and after come back to myarray

for example
[UNTESTED]

foreach ($myarray as $key1 = $value)
foreach($value as $key2 = $value2) $new_array[$key1-$key2] = $value2
;
unset($myarray) ;

$new_array = array_unique($new_array) ;
foreach($new_array as $key = $value)
 if (ereg(([0-9])-([0-9]), $key, $reg) $myarray[$reg[1]][$reg[2]] = $value
;

- Original Message -
From: René Fournier [EMAIL PROTECTED]
To: php [EMAIL PROTECTED]
Sent: Friday, November 15, 2002 7:31 AM
Subject: [PHP] Removing duplicates in multi-dimensional array


I'm finding this one hard to approach...

I have a two-dimensional array, containing customer contact
information. Looks like:

$myarray[0][0] = Microsoft;
$myarray[0][1] = Bill;
$myarray[0][2] = 123-1234;

$myarray[1][0] = Apple;
$myarray[1][1] = Steve;
$myarray[1][2] = 456-1234; 

$myarray[2][0] = Oracle;
$myarray[2][1] = Larry;
$myarray[2][2] = 987-4321;

$myarray[3][0] = Pixar;
$myarray[3][1] = Steve;
$myarray[3][2] = 456-1234; 

What I want to do is remove records that have the same fax number, so
that each fax number occurs only once. For example,  $myarray[1][2] and
$myarray[3][2] are the same--I would like to remove/unset one of them.

I know that array_unique() will do this for one-dimensional arrays, but
I'm kinda stuck here, since the repeating element is in the second
dimension. Any ideas how I might do this?

Thanks.

...Rene

---
René Fournier,
[EMAIL PROTECTED]

Toll-free +1.888.886.2754
Tel +1.403.291.3601
Fax +1.403.250.5228
www.smartslitters.com

SmartSlitters International
#33, 1339 - 40th Ave NE
Calgary AB  T2E 8N6
Canada


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Re: [PHP] PROBLEMS

2002-11-14 Thread rija
Try to put this at the top of your script-
?php
file://require comun.inc; para llamar a la conexion mejor poner include
file://include array.inc para funciones de array
$conexion = mysql_connect(localhost, root);
mysql_select_db(bd1, $conexion);
?

///  SCRIPT  ///
html
headtitle/title/head


- Original Message -
From: Ysrael Guzmán [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Friday, November 15, 2002 9:00 AM
Subject: [PHP] PROBLEMS


THIS IS MY SCRIPT:
AND THE ERROR IS
Warning: Cannot send session cache limiter - headers already sent
(output started at
c:\foxserv\www\t-demo1\pedidos\prod_mostrar_tipo.php:4) in
c:\foxserv\www\t-demo1\pedidos\prod_mostrar_tipo.php on line 5


///  SCRIPT  ///
html
headtitle/title/head
body topmargin=0 leftmargin=0
?php
session_start();
if(!session_is_registered(camion))
   DIE(error);
?
target=tipo
p
?php
file://require comun.inc; para llamar a la conexion mejor poner include
file://include array.inc para funciones de array
$conexion = mysql_connect(localhost, root);
mysql_select_db(bd1, $conexion);
?
div align=left
table width=350 border=1 bordercolor=white
tr
td
table width=350 border=1 bordercolor=white
?php
echo $codigo;
// función que determina si un determinado valor coincide con
// un elemento que pertenece al array que se pasa como parámetro
//
file://function esta_en_array($objetos, $elemento)
//   {
//   $i = 0;
//   $encontrado = false;
//   while (($i  count($objetos))  !$encontrado)
//  {
//  while($elemento = each($objetos[$i]))
//  {
//  $encontrado = ($objetos[$i] == $elemento);
//  $i++;
// }
//  }
//   return $encontrado;
//   }
//
$consulta = select * from productos where prod_cod = '$codigo';
$rta = mysql_query($consulta, $conexion);
$num_filas = mysql_num_rows($rta);
$num_campos = mysql_num_fields($rta);
file://echo $num_filas;
while($filas = mysql_fetch_array($rta))
{
$codigo = $filas['prod_cod'];
$nombre = $filas['prod_descripcion'];
$precio = $filas['prod_precio'];
 echo tr;
   echo td bgcolor='red';
echo bfont color='white'
face='verdana' size=2, $filas['prod_descripcion'], /b;
echo /font/td;
echo /tr
td;
echo FORM METHOD='Post'
ACTION='guardar_array.php'\n;
echo tr;
echo td bgcolor='white';
 file://echo INPUT TYPE='Checkbox' NAME=tabla[]
VALUE='$filas['prod_cod']';
 echo INPUT TYPE='text' NAME='cantidad';
 // if (esta_en_array($camion, $cantidad))
  //   {
//   echo VALUE='$cantidad' size='15';
  //  }
//else
  //

//   $cantidad = 0;
  // echo VALUE='$cantidad' size='15';
//}
 // echo ;


  echo INPUT TYPE='Hidden' NAME='codigo'
VALUE='$codigo'\n;
  echo INPUT TYPE='Hidden' NAME='nombre'
VALUE='$nombre'\n;
  echo INPUT TYPE='Hidden' NAME='precio'
VALUE='$precio'\n;



 // echo INPUT TYPE='Hidden' NAME=' , session_name() ,
 //' VALUE=' , session_id() , ';
 // echo /td;

  echo td bgcolor='white';
  echo INPUT TYPE='Submit' VALUE='Añadir'\n;
  echo /td;

  echo /tr;
  echo /FORM;





echo tr;
echo td bgcolor='white';
echo centerimg src=,
$filas['prod_ruta_foto_l'], /center;
echo /td;
echo /tr;

echo tr;
echo td bgcolor='#cc'
width='100%'font face='verdana' size=2;
echo BCODIGO: /B/fontfont
color='red' face='verdana' size=2, $filas['prod_cod'], br\n;
echo /font/td;
echo /tr;

echo tr;
echo td bgcolor='#f3f3f3'
width='100%'font face='verdana' size=2;
echo BPRESENTACION: /B/fontfont
color='red' face='verdana' size=2, $filas['prod_presentacion'],
br\n;
echo /font/td;
echo /tr;

echo tr;
echo td bgcolor='#cc'
width='100%'font face='verdana' size=2;
echo BFABRICANTE: /B/fontfont
color='red' face='verdana' size=2, $filas['prod_fabricante'],
br\n;

echo tr;
echo td bgcolor='#f3f3f3'
width='100%'font color='black' face='verdana' size=2;
echo BDESCRIPCION: /B/fontfont
color='red' face='verdana' size=2, $filas['prod_propiedades'],
br\n;
echo /font/td;
echo /tr;
}

echo /table;
?
/td

/tr
/table


/div

?php

mysql_free_result($rta);
mysql_close($conexion);
?

/body

Ysrael Guzmán Meza


-Mensaje original-
De: BigDog [mailto:bigdog;venticon.com]
Enviado el: Jueves, 14 de Noviembre de 2002 09:54 a.m.
Para: [EMAIL PROTECTED]
Asunto: RE: [PHP] PHP Auth with Apache


You are sending the header information to the browser before the session
stuff begins...


make sure that you call session_start(); right after your ?php start
tag...



On Thu, 2002-11-14 at 21:50, Ysrael Guzmán wrote:
 I have a problem, i'm new in PHP

 It is the problem in my browsegive me the solution please

 Warning: Cannot send session cache limiter - headers already sent
 (output started at 

Re: [PHP] Drop down list with date

2002-11-12 Thread rija
Try this one:
echo select ;

for ($d=0 ; $d 7 ; $d++)
echo option
onchange=\javascript:document.location.href='link'\.date(d/m/y,
strtotime(+$d day)).\n  ;
echo /option
/select ;

- Original Message -
From: Miguel Brás [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Wednesday, November 13, 2002 4:15 AM
Subject: [PHP] Drop down list with date


 Hello guys,

 I have a question:

 How can I create a drop down menu where the choices are the days of the
 month, displaying always the next 7 days?

 What I mean is, create a drop down menu and show the today's date, next
day,
 and next...

 Example: Today is 12th, then the menu shows the following option to be
 choosen
 12/11/02
 13/11/02
 14/11/02
 15/11/02
 16/11/02
 17/11/02
 18/11/02

 Tomorrow 13th will display
 13/11/02
 14/11/02
 15/11/02
 16/11/02
 17/11/02
 18/11/02
 19/11/02

 and so on...

 Thx
 Regards
 Miguel



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Re: [PHP] Query problem

2002-11-12 Thread rija
$query = INSERT INTO mararegistro (visitorid, fname, lname, borndate,
address, city, country, phone, how) VALUES (null, 'c', 'c', '12', 'c', 'c',
'c', '12', 'c');

I think you should put quotes around all of these values 12 exept null or
change null to '' ///


- Original Message -
From: Cesar Aracena [EMAIL PROTECTED]
To: PHP General [EMAIL PROTECTED]
Sent: Wednesday, November 13, 2002 8:27 AM
Subject: [PHP] Query problem


 Hi all,

 I came back from vacations and forgot some things about queries... can
 anyone tell me what is wrong with this? of all the error messages I set up
 in the script, none comes back on the page but the record is not saved...

 ?

 $db = mysql_connect(www.icaam.com.ar, icaam, );
 if (!$db)
 {
  die(No se pudo abrir la base de datos);
 }

 $ok = mysql_select_db(icaam);
 if(!$ok)
 {
  die(No se pudo acceder a la base de datos);
 }

 $borndate = $bornd . $bornm . $borny;
 $phonenumber = $phone;

 $query = INSERT INTO mararegistro (visitorid, fname, lname, borndate,
 address, city, country, phone, how) VALUES (null, 'c', 'c', 12, 'c', 'c',
 'c', 12, 'c');
 $result = mysql_query($query) or die (mysql_errno());
 if (mysql_affected_rows() != 1)
 {
  die(Fallo al guardar datos);
 }

 echo Gracias por administrarnos su información.;

 ?

 Any thiughts? Thanks in advance,

 Cesar



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Re: [PHP] Query problem

2002-11-12 Thread rija
error_reporting() ;

  1 E_ERROR
  2 E_WARNING
  4 E_PARSE
  8 E_NOTICE
  16 E_CORE_ERROR
  32 E_CORE_WARNING
  64 E_COMPILE_ERROR
  128 E_COMPILE_WARNING
  256 E_USER_ERROR
  512 E_USER_WARNING
  1024 E_USER_NOTICE


- Original Message -
From: Cesar Aracena [EMAIL PROTECTED]
To: PHP General [EMAIL PROTECTED]
Sent: Wednesday, November 13, 2002 9:35 AM
Subject: Re: [PHP] Query problem


 The problem is that I have a remote rented server and I don't have
access
 to these configurations

 any other ideas are welcome. Thanks

 any ot

 - Original Message -
 From: BigDog [EMAIL PROTECTED]
 To: Cesar Aracena [EMAIL PROTECTED]
 Cc: PHP General [EMAIL PROTECTED]
 Sent: Tuesday, November 12, 2002 11:51 AM
 Subject: Re: [PHP] Query problem


  In your php.ini file you can turn on all the errors have have them
  displayed...
 
  I would suggest doing that and you should see some errors if there are
  any.
 
  Have you verified that dates in the database via mysql command line or
  gui application.
 
 
  On Tue, 2002-11-12 at 21:27, Cesar Aracena wrote:
   Hi all,
  
   I came back from vacations and forgot some things about queries... can
   anyone tell me what is wrong with this? of all the error messages I
set
 up
   in the script, none comes back on the page but the record is not
 saved...
  
   ?
  
   $db = mysql_connect(www.icaam.com.ar, icaam, );
   if (!$db)
   {
die(No se pudo abrir la base de datos);
   }
  
   $ok = mysql_select_db(icaam);
   if(!$ok)
   {
die(No se pudo acceder a la base de datos);
   }
  
   $borndate = $bornd . $bornm . $borny;
   $phonenumber = $phone;
  
   $query = INSERT INTO mararegistro (visitorid, fname, lname, borndate,
   address, city, country, phone, how) VALUES (null, 'c', 'c', 12, 'c',
 'c',
   'c', 12, 'c');
   $result = mysql_query($query) or die (mysql_errno());
   if (mysql_affected_rows() != 1)
   {
die(Fallo al guardar datos);
   }
  
   echo Gracias por administrarnos su información.;
  
   ?
  
   Any thiughts? Thanks in advance,
  
   Cesar
  --
  .: B i g D o g :.
 
 
 


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Re: [PHP] Problem with sessions

2002-11-12 Thread rija
maybe you should remove the dot before the session path or do like this :

session.save_path = C:\PHP\sessions\tmp

- Original Message -
From: Charlie Fowler [EMAIL PROTECTED]
To: [EMAIL PROTECTED]; [EMAIL PROTECTED];
[EMAIL PROTECTED]
Sent: Wednesday, November 13, 2002 10:19 AM
Subject: [PHP] Problem with sessions


 Hi all,,

 Can some one help me with this little issue ... I am trying out some
 prewritten scripts curtesy of SAMS PHP and MYSQL Web Development, Ch24 -
 User Authenication  Personalisation on my server setup

 The Configuartion for my development environment is Apache 2.39, Win
 2000, PHP 4.2.3

 The Ini file has the following session settings (as taken from
PHPInfo.php):


 session

 Session Support enabled


 Directive Local Value Master Value
 session.auto_start
 Off Off
 session.cache_expire
 180 180
 session.cache_limiter
 nocache nocache
 session.cookie_domain
 no value no value
 session.cookie_lifetime
 0 0
 session.cookie_path
 / /
 session.cookie_secure
 Off Off
 session.entropy_file
 no value no value
 session.entropy_length
 0 0
 session.gc_maxlifetime
 1440 1440
 session.gc_probability
 1 1
 session.name
 PHPSESSID PHPSESSID
 session.referer_check
 no value no value
 session.save_handler
 files files
 session.save_path
 .c:/php/sessions/tmp .c:/php/sessions/tmp
 session.serialize_handler
 php php
 session.use_cookies
 On On
 session.use_trans_sid
 0 0


 The error occurs after the registration page is submitted with the
 following using the function session_start() on the register page.:

 Warning:
 open(.c:/php/sessions/tmp\sess_fa42372dcdbde0e457309f134d71827f, O_RDWR)
 failed: Invalid argument (22) in C:\Program Files\Apache
 Group\Apache2\htdocs\SAMS\Chapter24\member.php on line 5

 I believe the problem is in my PHP setup and not the script. The Invalid
 arguement is the trigger for the config error to be initaited but I am
 not sure how to edit the php.ini file. I want to ensure that session are
 started when the server is started. I am also unsure of  the function
 and terminology of

 session.save_handler
 files files


 with the use of files. Is this the correct default. Also is this the
 correct session save path:

 session.save_path
 .c:/php/sessions/tmp .c:/php/sessions/tmp


 What is wrong, please help.

 Charlie




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Re: [PHP] Trying to e-mail password

2002-11-12 Thread rija
You should do like this:

$password = $row['password'];
This return weird crypted value of your password.

Unless you want send the this weird password. The function mysql_password is
irreversible, you cannot get back the value crypted by password. Use ENCODE
and DECODE instead,



- Original Message -
From: Ben C. [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Wednesday, November 13, 2002 11:09 AM
Subject: [PHP] Trying to e-mail password


 I am trying to have a form that send a user their email and password to
login.  I am using the following:

 while ($row = mysql_fetch_array($result)) {
 $email = $row['email'];
 $password = $row['password(password)'];

 When I use the mail() function to send both $email and $password I receive
an e-mail with a blank password.

 What am I doing wrong.  Please help!


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Re: [PHP] Trying to e-mail password

2002-11-12 Thread rija
ENCODE(value, 'secret code')
DECODE(field name, 'secret code')

to record
 ... VALUES ( ... blahblah, ENCODE('$passord', 'secret code', ... BLAH
BHAL) ;

and to read the value
do like this
MYSQL_QUERY(SELECT DECODE(password, 'secret code') as password, id, BLAH
BLAH


- Original Message -
From: Ben C. [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Wednesday, November 13, 2002 12:07 PM
Subject: Re: [PHP] Trying to e-mail password


 Is there not any way to reverse the crypted password before e-mailing??

 If not, how do I use ENCODE / DECODE?


 
  From: rija [EMAIL PROTECTED]
  Date: 2002/11/12 Tue PM 07:32:28 EST
  To: php [EMAIL PROTECTED],
  Ben C. [EMAIL PROTECTED]
  Subject: Re: [PHP] Trying to e-mail password
 
  You should do like this:
 
  $password = $row['password'];
  This return weird crypted value of your password.
 
  Unless you want send the this weird password. The function
mysql_password is
  irreversible, you cannot get back the value crypted by password. Use
ENCODE
  and DECODE instead,
 
 
 
  - Original Message -
  From: Ben C. [EMAIL PROTECTED]
  To: [EMAIL PROTECTED]
  Sent: Wednesday, November 13, 2002 11:09 AM
  Subject: [PHP] Trying to e-mail password
 
 
   I am trying to have a form that send a user their email and password
to
  login.  I am using the following:
  
   while ($row = mysql_fetch_array($result)) {
   $email = $row['email'];
   $password = $row['password(password)'];
  
   When I use the mail() function to send both $email and $password I
receive
  an e-mail with a blank password.
  
   What am I doing wrong.  Please help!
  
  
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Re: [PHP] Trying to e-mail password

2002-11-12 Thread rija
I don't think so,
data stored as plain text is almost stored intact in the file system.

Using stupid windows for example,
you can easily open mysql file table.MYD in the folder database with
NotePad, and you can read everything. Which means, everybody without any
hacking knowledge can access to user's password and mailbox stored in your
site, since he had access to the system folder. And if you have rented
server it is recommanded to crypt strategic data.



- Original Message -
From: John W. Holmes [EMAIL PROTECTED]
To: [EMAIL PROTECTED]; 'php' [EMAIL PROTECTED]; 'Ben C.'
[EMAIL PROTECTED]
Sent: Wednesday, November 13, 2002 2:05 PM
Subject: RE: [PHP] Trying to e-mail password


 If you want an email password feature, then just store it as plain text.
 If someone is able to get access to your database, that means they more
 than likely have access to the rest of your box, so your 'secret code'
 is worthless.

 ---John Holmes...

  -Original Message-
  From: rija [mailto:rija;vatu.com]
  Sent: Tuesday, November 12, 2002 9:37 PM
  To: php; Ben C.
  Subject: Re: [PHP] Trying to e-mail password
 
  ENCODE(value, 'secret code')
  DECODE(field name, 'secret code')
 
  to record
   ... VALUES ( ... blahblah, ENCODE('$passord', 'secret code', ...
 BLAH
  BHAL) ;
 
  and to read the value
  do like this
  MYSQL_QUERY(SELECT DECODE(password, 'secret code') as password, id,
 BLAH
  BLAH
 
 
  - Original Message -
  From: Ben C. [EMAIL PROTECTED]
  To: [EMAIL PROTECTED]
  Sent: Wednesday, November 13, 2002 12:07 PM
  Subject: Re: [PHP] Trying to e-mail password
 
 
   Is there not any way to reverse the crypted password before
 e-mailing??
  
   If not, how do I use ENCODE / DECODE?
  
  



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Re: [PHP] Trying to e-mail password

2002-11-12 Thread rija


 Okay, so why are you giving users read access to the mysql data folder?
 They can also open up your .php file and find your secret code.

I think, it is good discussion, so I try to go deeper to it, because we need
improve security. And I hope another people to join this.

Since I don't have my own server, I have to buy external hosting service
maybe in Costa Rica or in Panama or in South Africa, so I don't know who are
going to administrate my site first? Whoelse can have access to the system.
I don't know how safe is it? I just bought it because it was cheap, or
simply it was in my way.

And suppose some hacker is entered to the server, because he would like hack
the server not my user's mailbox. Surprise, he found plenty of address email
with its password. Really cool

Using ENCODE and DECODE with protected 'secret code' help you to improve
your security and user's security. And you don't lost anything doing this,
on the contrary, it is a good marketing arguments, like as your system
(site) is more safe than other and user could fell in.





 It won't hurt anything to encode it in the database, but just don't get
 this overwhelming sense of security and think everything is safe.

---John Holmes...




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Re: [PHP] form with two actions

2002-11-12 Thread rija
If you want php to do it in the remote server (your case),
of course, you do not have to use javascript //

Just do like this

if (isset($_POST['submit'])) // to verify that browser are sending something
correctly
{
// -- record posted data into database

and after
// -- send mail
}

But if you want 2 actions in the client-side browser, you should use
javascript, for example you want first to check data and simultaneously,
display progress bar (animated gif),

like this
onsubmit=return(send_data(document.form));
and the on the function send_data() you have
1. do action 1
2. do action 2
3. return true

- Original Message -
From: Scott [EMAIL PROTECTED]
To: php-general [EMAIL PROTECTED]
Sent: Wednesday, November 13, 2002 4:05 PM
Subject: [PHP] form with two actions


 Hello
 I would like to know if it is possible to use Php to make a form perform 2
 actions by having the user click on a single submit button. For instance,
 send data to a database and email it simultaneously.  I would prefer not
to
 use javascript.  If someone could point me to an example I would
appreciate it

 Thanks,
 S.W.

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[PHP] Submit hitting enter problem

2002-11-10 Thread rija
What am I missing?

My form does not submit when I hit enter in the text box.
I do something approximately like this :

form action=index.php?s=add method=post

input type=text name=bongabe value=something 
...
input type=submit value=submit name=submit

//

Thanks in advance.



Re: [PHP] mysql DECODE question

2002-11-10 Thread rija
SELECT DECODE(ENCODE('password', 'sec'), SUBSTRING(secret,1,3));
if you put quotes around substring function, mysql considere it as a string,
so I think you shouldn't.

After, are you sure that the correct table field name is the weirdthing
encoded by this function : ENCODE('password', 'sec') ???
if so, show us, the script that allow you to record the password ?


- Original Message -
From: Donahue Ben [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Monday, November 11, 2002 11:13 AM
Subject: [PHP] mysql DECODE question


 SELECT DECODE(ENCODE('password', 'sec'), 'sec') -
 password

 When I try:
 SELECT DECODE(ENCODE('password', 'sec'),
 'SUBSTRING(secret,1,3)'); or without quotes around
 SUBSTRING function

 This does not produce the same output, i am not sure
 what the problem is.

 Ben

 __
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Re: [PHP] Submit hitting enter problem

2002-11-10 Thread rija
Thanks for your quick answer,

But it doesn't change anything.
textarea change my text box into big text area-

So I always have to click on submit button to submit the form.



- Original Message - 
From: Justin French [EMAIL PROTECTED]
To: [EMAIL PROTECTED]; php [EMAIL PROTECTED]
Sent: Monday, November 11, 2002 3:45 PM
Subject: Re: [PHP] Submit hitting enter problem


 on 11/11/02 12:44 PM, rija ([EMAIL PROTECTED]) wrote:
 
  input type=text name=bongabe value=something
 
 I think you need to use a textarea if you wish for the returns to be
 submitted.
 
 Cheers
 
 
 Justin French
 
 Creative Director
 http://Indent.com.au
 Web Developent  
 Graphic Design
 
 
 



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Re: [PHP] Submit hitting enter problem

2002-11-10 Thread rija
Sure !

But just simple question?
Is it necessary to put quotes around these attributes values?
Because I think quotes increase the site size, and using IE4, IE5, IE6, NS4,
OPERA, quotes don't change anything.


Of course if I have somethings with space, for value's attribute, It is
important to put quote because sometimes users enter space.


- Original Message -
From: Jason Wong [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Monday, November 11, 2002 3:33 PM
Subject: Re: [PHP] Submit hitting enter problem

 What happens when ENTER is pressed depends on what browser you're using.
 Different browsers exhibit different behaviours, eg the old versions of
 Netscape (v4 and before) does not submit on ENTER. Also, put quotes around
 your attribute values eg:

 input type=text name=bongabe value=something

 --
 Jason Wong - Gremlins Associates - www.gremlins.com.hk
 Open Source Software Systems Integrators
 * Web Design  Hosting * Internet  Intranet Applications Development *

 /*
 The more I know men the more I like my horse.
 */


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Re: [PHP] Submit hitting enter problem

2002-11-10 Thread rija
Really big thank to everybody,

But, now, I know what happening, because I check form submit using
isset($_POST['submit']), so if user don't press submit button,
$_POST['submit'] stay null even the rest is already sent. Then my script
send me back to the first page.


- Original Message -
From: Justin French [EMAIL PROTECTED]
To: [EMAIL PROTECTED]; php [EMAIL PROTECTED]
Sent: Monday, November 11, 2002 4:28 PM
Subject: Re: [PHP] Submit hitting enter problem


 on 11/11/02 2:16 PM, rija ([EMAIL PROTECTED]) wrote:


 Actually, I miss-read your question... do you WANT the form to be
submitted
 when hitting return/enter???

 And you find that this is not happening when you are in a text field???

 Correct?


 This is a browser thing... I don't *think* there's anything in the
standards
 to say when hitting enter should/shouldn't work -- i think it's something
 that each browser will do differently.

 There may be something you can do with javascript.


 Perhaps check out:
 http://www.w3.org/TR/1998/REC-html40-19980424/interact/forms.html


 Or find a similar form example on another site, and dig around thru the
code
 to have a look how they did it.


 Justin





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Re: [PHP] regular expression and exact word search...

2002-11-07 Thread rija
How about this one,
$word_search = 'blablabla' ;

echo eregi_replace(($word_search),b\\1/b,$html) ;
//


- Original Message -
From: BAROILLER Pierre-Emmanuel [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Friday, November 08, 2002 2:42 AM
Subject: [PHP] regular expression and exact word search...


 Hi!

 does someone know how to find an exact word in a content with html tags ?
 I'm using a regexp like this :

 $searchRegEx = '\b.$word_search.\b'msi;

 to get boundary word results, but... if the searched word is  like 'word
or
 word. or anything else, the
 regular expression doesn't work..

 if I remove the \b , I've got all words ( but without bound...)

 Any idea?
 (the big problem is I'm higlighting found sentences, and .. if the
searched
 word is part of an html tag, it's very auwfull... )



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Re: [PHP] MYSQL and PHP Storing and retrieving images getting corrupted

2002-11-05 Thread rija
Have you tried out mysql function load_file() to upload directly your file
into the database without passing through php variable ?

Like this:

$result=MYSQL_QUERY(INSERT INTO master_products
(image_thumbnail,image_thumbnail_name,image_thumbnail_size,image_thumbnail_t
ype) VALUES

(load_file('$form_data'),'$form_data_name','$form_data_size','$form_data_typ
e'));

If you are not allowed to upload directly $form_data using mysql
load_file(), move first the file $form_data into another allowed directory
with valid filename and try again.

Finally, storing image or binary file into database is not good, put them
into directory instead.

- Original Message -
From: Darren McPhee [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Tuesday, November 05, 2002 11:24 PM
Subject: [PHP] MYSQL and PHP Storing and retrieving images getting corrupted


 I have written 2 programs (which are very common PHP
 programs) that A) Allows me to upload image files into a MYSQL database
 using a simple form.  And B) Allows me to retrieve and display the image
 using a PHP script.  This is my problem:-

 I can upload the images ok.  I store the binary code, image type, name,
and
 size within the MYSQL database.  On checking the database directly using
 DBTools, I can see that the files have uploaded.  The file sizes reflect
 exactly what was originally on the hard disk of my PC (not sure if this is
a
 correct gauge).

 When I run my PHP program to display the images, maybe only 1 out of 10
 actually displays correctly.  The rest are broken up or non displayable
 images.  One image even made a prompt window appear and somehow now causes
 Windows paint to load the image instead of the browser.  God only knows
how
 that occurred !!

 Below are my (designed by others) 2 programs.  The first program is the
 upload form.  This seems to work ok.



 HTML
 HEADTITLEStore binary data into SQL Database/TITLE/HEAD
 BODY

 ?php
 // code that will be executed if the form has been submitted:

 if ($submit) {

 // connect to the database

 require_once('../../Connections/TestServer.php');
 mysql_select_db($database_TestServer, $TestServer);

 $data = addslashes(fread(fopen($form_data, r),
filesize($form_data)));

 $result=MYSQL_QUERY(INSERT INTO master_products

(image_thumbnail,image_thumbnail_name,image_thumbnail_size,image_thumbnail_t
 ype) .
 VALUES
 ('$data','$form_data_name','$form_data_size','$form_data_type'));

 $id= mysql_insert_id();
 print pThis file has the following Database ID: b$id/b;

 MYSQL_CLOSE();

 } else {

 // else show the form to submit new data:
 ?

 form method=post action=?php echo $PHP_SELF; ?
 enctype=multipart/form-data
   INPUT TYPE=hidden name=MAX_FILE_SIZE value=100
 brFile to upload/store in database:br
 input type=file name=form_data  size=40
 pinput type=submit name=submit value=submit
 /form

 ?php

 }

 ?

 /BODY
 /HTML

 Here is the code to display the image:-

 ?php
 if($id) {
 require_once('../Connections/TestServer.php');
 mysql_select_db($database_TestServer, $TestServer);
 $query = select image_thumbnail,image_thumbnail_type from
 master_products where item_id=$id;
 $result = @MYSQL_QUERY($query);
 $data = @MYSQL_RESULT($result,0,image_thumbnail);
 $type = @MYSQL_RESULT($result,0,image_thumbnail_type);
 Header( Content-type: $type);
 echo $data;
 };
 ?

 I run the above program in the following way:
 http://192.168.0.11/htdocs/displayimage2.php?id=9  The ID is the item_id
 primary key field for whichever record I want to display.

 I have tried these programs on a test server here in my room to a test
 Apache server and MYSQL test database, and also from my ISP to a MYSQL
 database at a server at my ISP.  I get exactly the same problem.  When I
run
 the display image program, the images being displayed are always being
 displayed the same.  Which points the problem towards the upload process
 (maybe).  If anybody can tell me what the heck is wrong here, I'll give
them
 a medal !!  There is basically some kind of binary corruption going on (it
 looks like)

 For added information, below is my database table structure.  At the
moment,
 the only part I am actually using relates to the image_thumbnail sections.

 Darren.



 CREATE TABLE master_products (
  item_id SMALLINT UNSIGNED NOT NULL PRIMARY KEY AUTO_INCREMENT,
  item_code VARCHAR (10) UNIQUE,
  item_dateadded DATETIME DEFAULT '-00-00 00:00:00',
  item_datemodified DATETIME DEFAULT '-00-00 00:00:00',

  category ENUM (none,single herbs,general
 vitality,ageing,arthritis,eyesite,prostate,ahlzheimers,
  weight
 loss,menopause,depression,fatigue,headaches,insomnia,colds and
 flues,allergies,
  healthy heart,cancer prevention,aphrodisiacs,sexual herbs,for
 women,for men,books),

  name VARCHAR (30),
  name_dateadded DATETIME DEFAULT '-00-00 00:00:00',
  name_datemodified DATETIME DEFAULT '-00-00 00:00:00',
  INDEX idx_name (name),

  

Re: [PHP] Problem with is_dir function

2002-11-05 Thread rija
I cannot explain your error message,
are you sure that the following error message provide from these lines ?

If not, I think your machine is blasted, so find out an exorcist or a witch.
Good luck !

- Original Message -
From: Roger Lewis [EMAIL PROTECTED]
To: Roger Lewis [EMAIL PROTECTED]; Php-General
[EMAIL PROTECTED]
Sent: Wednesday, November 06, 2002 3:41 AM
Subject: RE: [PHP] Problem with is_dir function



 On Saturday, November 02, 2002 11:07 AM, I wrote

 *  I'm having a problem with the is_dir function, or maybe I don't
 understand
  how it supposed to work.  I'm using the following code to check whether
or
  not a directory called $user_dir exists.  If it exists, I am returned
the
  proper message.  But if it doesn't exist, I get the following error
 message
  that says that it doesn't exist. (I already knew that!)


  ERROR Number=8 Description=Error: quot;stat failed for
  /home/sites/home/users/demodocs/web/userforum/user
  (errno=2 - No such file or directory)quot; on line 175 of
  /home/sites/home/users/demo/web/user_forum/messages.php./


  Can someone please explain what I am doing wrong here, and how to return
a
  usable value if the directory doesn't exist.


  $test = is_dir($user_dir);
  if($test){echo You have a user directory.  It is $user_dir;}
  else{echo Your user directory doesn't exist;
  return;}


  Thanks a lot.

  Roger Lewis


 This is a follow-up to my original posting.
 * I did not get an answer as to why is_dir does not return a false
value;
 however, file_exists does the job nicely.  Thanks for all the suggestions.
 * Roger

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Re: [PHP] File download + HTTP auth problem.

2002-11-05 Thread rija
Simply, HTTP Authentification
Header(WWW-Authenticate: Basic realm='something')
does not work with microsoft product, so you need to buy Microsoft
authentification from Microsoft to do  something like it.

- Original Message -
From: Rodolfo Gonzalez [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Wednesday, November 06, 2002 6:29 AM
Subject: [PHP] File download + HTTP auth problem.


 Hello,

 I have this simple script called index.php in a directory protected with
 HTTP auth (require valid-user):

 ?php
   $archivo = '/somewhere/out/docroot/registro.csv';
   header('Content-Type: application/octect-stream');
   header('Content-Length: '.filesize($archivo));
   header('Content-Disposition: attachment; filename=registro.csv');
   @readfile($archivo);
 ?

 When I access the directory with Netscape/Mozilla/Galeon it works fine,
 Apache asks the login and password and the script sends the file. But
 with MSIE 6.x (from Windows XP) it does not work: it presents the download
 dialog asking to save or open the file, but then MSIE reports an error
 and does not download the file. I discovered later that Konqueror asks for
 the login and password again when the download starts. What could be
 causing this?. Thanks in advance.

 Rodolfo.




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Re: [PHP] session cache limiter

2002-11-05 Thread rija
I bit you are sending something like as an blank_space before your are
sending your header.
Show us first your code.


- Original Message -
From: ROBERT MCPEAK [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Wednesday, November 06, 2002 6:34 AM
Subject: [PHP] session cache limiter


Could somebody shed some light on this error message I'm getting.  Could you
point me at the appropriate docs or clue me in somehow.

PHP Warning:  Cannot send session cache limiter - headers already sent
(output started at /usr/local/httpd/htdocs/mmc/results.php:79) in
/usr/local/httpd/htdocs/mmc/includes/display_options.php on line 115

Thanks!


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Re: [PHP] uploading

2002-11-05 Thread rija
Either you put references into your variables
$_FILES['userfile']['tmp_name'][0] :
move_uploaded_file($_FILES['userfile']['tmp_name'][0], \ufiles) ;

or don't put bracket in your variable userfile from your input form
like this : input type=file name=userfile


- Original Message -
From: Edward Peloke [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Wednesday, November 06, 2002 7:03 AM
Subject: [PHP] uploading


 I am playing with uploading files (hence the array question).  I have a
 simple form:

 form action=upload.php method=post enctype=multipart/form-data
   Send these files:br
   input name=userfile[] type=filebr
 input type=submit value=Send files
 /form

 Which calls a php file that just contains this:
 copy($_FILES['userfile']['tmp_name'], \ufiles\);

  This ufiles folder is under my htdocs folder in apache.  I have looked
 through the help files in php.net but am just not getting it today.  How
do
 I simply upload the file?  I tried to move uploaded file function but
can't
 seem to get that to work alsoany ideas would be greatly appreciated!

 Thanks,
 Eddie





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Re: [PHP] Using info from a MySQL Query

2002-11-05 Thread rija
Put your variables into {} like this '{$_POST['email'] }',

 $sql =SELECT company, name, email FROM $table_name
  WHERE email = '{$_POST[email]}' AND password =
password('{$_POST[password]}');

- Original Message -
From: Ben C. [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Wednesday, November 06, 2002 12:09 PM
Subject: [PHP] Using info from a MySQL Query


 I am using the following query:

 $sql =SELECT company, name, email FROM $table_name
WHERE email = '$_POST[email]' AND password =
password('$_POST[password]');

 Then I am echoing the $email on my form (it works because the person has
posted their e-mail name when logging in).  How can I echo the company and
email on to my form as well.  Please help.


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Re: [PHP] Using info from a MySQL Query

2002-11-05 Thread rija
Sorry, I didn't read correctly the question-
There are plenty way to do it
for example :

$query = mysql_query($sql) ;
$ligne=mysql_fetch_array($query) ;
echo $ligne['company'] ;
echo $ligne['email'] ;

or
echo mysql_result($query,0,1);


- Original Message -
From: rija [EMAIL PROTECTED]
To: php [EMAIL PROTECTED]; Ben C. [EMAIL PROTECTED]
Sent: Wednesday, November 06, 2002 1:34 PM
Subject: Re: [PHP] Using info from a MySQL Query


 Put your variables into {} like this '{$_POST['email'] }',

  $sql =SELECT company, name, email FROM $table_name
   WHERE email = '{$_POST[email]}' AND password =
 password('{$_POST[password]}');

 - Original Message -
 From: Ben C. [EMAIL PROTECTED]
 To: [EMAIL PROTECTED]
 Sent: Wednesday, November 06, 2002 12:09 PM
 Subject: [PHP] Using info from a MySQL Query


  I am using the following query:
 
  $sql =SELECT company, name, email FROM $table_name
 WHERE email = '$_POST[email]' AND password =
 password('$_POST[password]');
 
  Then I am echoing the $email on my form (it works because the person has
 posted their e-mail name when logging in).  How can I echo the company and
 email on to my form as well.  Please help.
 
 
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[PHP] Regular expression problem

2002-11-05 Thread rija
Hi Guy and Gay ?

I have the following code supposed to transform date format like this 04 desambra 1975 
into 1975-12-04.
User can use whatever language he want like french, english, malagasy even Bichlamar-
for example : 04, otis 1975 = 04 aout 1975 = 04 aogositra 1975 = 04-août 1975 = 04 
august 1975 = 04 aug 1975 and the function must return 1975-08-04

It work perfectly and I'm really happy while I don't use minus (-) and If I use it, 
the function stop working. 

So how can I use minus in the regular expression ?

function my_date($birthday) {

$birthday = strtolower($birthday) ;
$array_search2 = array(
'[âäàåÄÅáæÆ]'i,
'[éêëèÉ]'i,
'[üûùÜú]'i,
'[ïîìí]'i,
'[ôöòÖó]'i) ;
$array_replace2 = array(a, e, u, i, o) ;
 
$array_search = array('jan[a-zA-Z]{0,10}'i,
'fe[vb]{1}[a-zA-Z]{0,10}'i,
'm[a]{1,2}r[a-zA-Z]{0,10}'i,
'a[vp]{1}r[a-zA-Z]{0,10}'i,   
'ma[iy]{1}[a-zA-Z]{0,10}'i,
'j[ou]{1}n[a-zA-Z]{0,10}'i,
'j[uo]{1}l[a-zA-Z]{0,10}'i,
'[ao]{1}[out]{1}[a-zA-Z]{0,10}'i,
'sept[a-zA-Z]{0,10}'i,
'o[ck]{1}t[a-zA-Z]{0,10}'i,
'n[o]{1,2}v[a-zA-Z]{0,10}'i,
'de[sc]{1}[a-zA-Z]{0,10}'i
) ;

$array_replace = array( 01, 02, 03, 04, 05, 06,
 07,08,09,10, 11, 12 ) ;
$birthday = preg_replace($array_search2, $array_replace2, $birthday) ;
$birthday = eregi_replace(([0-9]{1,2})[\-_:\|/, ]+([a-zA-Z0-9]{1,})[\-_:\|/, 
]+([0-9]{2,4}),\\3-\\2-\\1, $birthday) ;
$birthday = preg_replace($array_search, $array_replace, $birthday) ;
return $birthday ;
}

echo my_date(12, janoary- 2001) ;
// return 12, 01- 2001 (bad)

and
echo my_date(12, januaari,\\__ 2001) ;

return exactly what I want ie 2001-01-12



Re: [PHP] How do I convert an array into a mask?

2002-11-05 Thread rija
Why don't you ask Jim Carrey ???
He knew more that whoever here about The MASK !!!

Good luck.
- Original Message - 
From: Daevid Vincent [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Wednesday, November 06, 2002 3:56 PM
Subject: [PHP] How do I convert an array into a mask?


 Does anyone know of a nice efficient way to convert an array of values
 into a mask...
 
 Here's the deal. Given an array such that:
 
 $purchitem[0] = 1;
 $purchitem[1] = 3;
 $purchitem[2] = 4;
 
 I want to end up with a variable like this:
 
 $mask = 10110;
 
 Additionally, my theory is that then the person purchases another book
 later
 
 $purchitem[0] = 2;
 
 My new mask should be $purchmask = 01000;
 
 Then I can load their previous mask from the database and boolean OR it
 with the new mask to set the correct permissions. i.e.
 
 $newmask = $mask | $purchmask;
 
 Or ideally = 0
 
 Can I boolean OR strings like that in the way I 'hope' it will work? Do
 I need to convert it to an intermediate stage or cast it or anything?
 
 Does this make sense? It's for an online book shopping cart. I have the
 reverse working, where I can split the mask into what books. And I also
 have the $purchitem[] working.
 
 
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Re: [PHP] PHP/Flash

2002-11-04 Thread rija
Me :-)
I wonder if you can post me these scripts

- Original Message - 
From: Clint Tredway [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Tuesday, November 05, 2002 8:46 AM
Subject: [PHP] PHP/Flash


 I have a small example of using Flash/PHP if anyone wants it..
 
 Clint
 
 
 
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Re: [PHP] randomly select file

2002-11-04 Thread rija
Why don't you cope with opendir / readdir () and array_rand ()
I tried it and I look ok-

But, I wonder if there are noble another way to do it?


- Original Message -
From: ROBERT MCPEAK [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Tuesday, November 05, 2002 8:40 AM
Subject: [PHP] randomly select file


Could someone suggest some php for randomly selecting a file from a
directory and then displaying the contents of the file?

Thanks in advance!


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Re: [PHP] Does anyone know if this is possible?

2002-11-04 Thread rija
It depends on where the textfile are going to be store
If you store them into unauthorized directory that php does not have the
right (or permission) to write in, I think it cannot be done, but if you put
down the file into allowed directory, why not?

to make column into your text file I think \t is good-

- Original Message -
From: Raymond Lilleodegard [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Tuesday, November 05, 2002 5:28 AM
Subject: [PHP] Does anyone know if this is possible?


 Hi!

 I have made a website with a webshop and the orders are written down in
 txtfiles and a faxserver is scanning a directory for txtfiles and sends
them
 as faxes.

 So I am trying to write the txtfile like I should have written the order
in
 a table. Or you can say I am trying to make some columns in the txtfile.

 Something like this:

 1pizzacheese, beef, tomato,5,-
   ham, bacon etc
 2burgerscheese, bacon2,-

 Best regards Raymond



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Re: [PHP] Battling with highlighting search criteria

2002-11-04 Thread rija
$result = eregi_replace(($search),span
class=hightlight\\0/span,$result) ;

I use it, and I work fine for me.


- Original Message -
From: David Russell [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Monday, November 04, 2002 7:27 PM
Subject: [PHP] Battling with highlighting search criteria


 Hi there,

 My brain has just gone very fuzzy...

 I have a search string ($search) and a result ($result). I need to
 highlight every occurance of $search in $result.

 I know that it means that I need to change (for example)

 $result = This is a test, isn't it?
 $search = is

 Into

 $result = thspan class=highlightis/span span
 class=highlightis/span a test, span class=highlightis/span'nt
 it

 Now I can easily see how to change the FIRST occurrence of the word, but
 how can I change every occurance?

 Thanks



 David Russell
 IT Support Manager
 Barloworld Optimus (Pty) Ltd
 Tel: +2711 444-7250
 Fax: +2711 444-7256
 e-mail: [EMAIL PROTECTED]
 web: www.BarloworldOptimus.com




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Re: [PHP] Upload permission on a web_user space...

2002-11-04 Thread rija
Hi Ben,
I am not sure to understand exactly what do you want to do.
But I am going to try to answer you about something,
First, If you need to create your own ftp software using php, check out ftp library 
(http://www.faqs.org/rfcs/rfc959.html)
there are several  function about it, and you can allow visitors to
upload, download, rename, delete, move files, create directory, rename directory chop 
directory etc... through 2 differents webservers using ftp parameters
like domain (ip), username, password, int port etc...

You can also create your own php software to allow user to view, upload,
modify and delete files in your webserver from their browser, and you don't
need activating ftp library, but you should set up (php.ini):
file_uploads to on
upload_tmp_dir to your upload directory
upload_max_size = 2M or I don't know. -- check out the documentary
(Documentary is also available in french.)

If you want allow people to see some file from their browser and download
it right_clicking and save target as to their computer, there are several
possibility, first you can set it up through your webhosting setting (for
example for IIS/Windows 2000) you can check on button browse directory- So when 
visitors write your directory URL, the browser shows every files in your webserver.

Secondly, you can also use your own php file to do it using function such as
dir(), opendir(), readdir()-- check out the documentary.
and it is better to use HEADER() to download files into visitors browser.

Well, I hope helping you as I can.

- Original Message -
From: Benjamin Trépanier [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Tuesday, November 05, 2002 12:55 PM
Subject: [PHP] Upload permission on a web_user space...


 Hello, I'm trying again to ask you that question because I was not
 understand.

 I have a unix server hosting service, my hosting service allow me to
create
 web_server. Those are create for my client who have to upload differents
 things. So when people are connecting to my ftp (example  on IE...) they
can
 see any folder in their web_user space and can upload stuff in any folder
of
 their level... So the set upload permission is not working... What can I
do

 Is it possible to create a upload page (php) that allow user to see every
 folder of his web_user space??

 Thanks!


 Ben


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Re: [PHP] checkboxes and selection lists

2002-11-04 Thread rija
If you have hundred thousand elements for example if you rob up for some
country select within tierce code-

I thinks doing like the following is better

echo select
optiona
optionb
...
optionzz
option selected$value
/option
/select ;

And I don't care if it could have 2 same value in the select case...

And if there aren't many value, I think the following  sounds better:

echo 
SELECT CLASS=select NAME=qual
OPTION .($qual==A? SELECTED:).A
OPTION .($qual==B? SELECTED:).B
OPTION .($qual==C? SELECTED:). C/OPTION
/SELECT ;



- Original Message -
From: [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Tuesday, November 05, 2002 5:06 PM
Subject: [PHP] checkboxes and selection lists


Hi, as a beginner I find the way you declare variables through HTML-forms
quite straightforward. But the reverse, to put the same variables back into
a form field is not so obvious for selection lists and checkboxes. Would for
instance this be the best way:

SELECT CLASS=select NAME=qual
OPTION VALUE=A ?=if($qual=='A'){return 'SELECTED'}?A/OPTION
OPTION VALUE=B ?=if($qual=='B'){return 'SELECTED'}?B/OPTION
OPTION VALUE=C ?=if($qual=='C'){return 'SELECTED'}?C/OPTION
/SELECT

or would there be something more elegant?

Thanks, Marco




Internet wordt pas leuk als je mee kunt doen. Ga naar http://www.hetnet.nl

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Re: [PHP] fread() fails with large files

2002-11-03 Thread rija
Use readfile instead fread() if you've got some problem with, it looks
better!

Header(Content-Type: $type);
Header(Content-Disposition: attachment; filename=$downloadname);
header(Content-Length: $size);
header(Content-Transfer-Encoding: binary);
readfile($file);


- Original Message -
From: Sora B. Harbater [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Monday, November 04, 2002 12:44 AM
Subject: [PHP] fread() fails with large files


 Hi.  I am using Linux/Apache with PHP 4.1.2.  I have been experiencing
this
 problem since upgrading from an earlier version of PHP 4.

 My script forces a download of a PDF file after looking up some info in a
 database.  The code looks like this:


 $file=/path/to/file;
 $fp = fopen($file, r);
 $size=filesize($file);
 $contents = fread($fp, $size);
 fclose($fp);

 Header(Content-Type: $type);
 Header(Content-Disposition: attachment; filename=$downloadname);
 header(Content-Length: $size);
 header(Content-Transfer-Encoding: binary);
 echo $contents;

 filesize() is reporting the size properly. The code works perfectly for
 smaller files, but the fread() fails for files larger than 19 MB or so and
 I got a page cannot be displayed error. I know that it is fread() which is
 causing the problem because I commented out all the code that follows it
 and still get the error.  All the files being downloaded are PDF files.

 Can anyone shed some light on this?



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[PHP] re:[PHP] uploading help please again

2002-11-03 Thread rija
You might receive 2 files throught upload,
then the first file name should be $_FILES['origem'] ;
and the second file name $_FILES['origem2'] ;

To use the different variables you can use, peer John Holmes's answer, there
aren't no full answer like this anywhere?

to ask if file uploaded is ok
uploaded_file() is better than you are doing
and use move_uploaded_file() instead copy() and unset() ;
like this :

if (is_uploaded_file($_FILES['origem']) )
move_uploaded_file($_FILES['origem'], $dest) ;

/*
$path=(dirname($PATH_TRANSLATED))./primeirapagina/;
$origem_name=fdx.jpg;
$dest= $path.$origem_name;

if (($origem  none)  ($origem  )){
   if (copy($origem,$dest)){;

 } else {
  echo directoria sem direitos de escrita br;
  }
unlink ($origem);
}




- Original Message -
From: 'marcelo' [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Monday, November 04, 2002 12:46 PM
Subject: RE: [PHP] uploading help please again

Ok I'm back

This script is to upload 2 image files

Whit register_globals = on it Works fine



script A

p.php

titleJornal O Leme/title
meta http-equiv=Content-Type content=text/html; charset=iso-8859-1
/head

body bgcolor=#006699
table width=100% border=0 cellpadding=0 cellspacing=0
  !--DWLayoutTable--
  tr
td width=100% height=70 valign=topimg src=test.jpg
width=600 height=120
/td
  /tr
  tr
td height=262 valign=toppnbsp;/p
  form method=post  action=pi.php  enctype=multipart/form-data
table width=75% border=0 align=center bgcolor=#FF
  tr
td width=23%div align=centerfont face=BankGothic Md
BT
/font/div/td
td width=77% bgcolor=#FFnbsp; /td
  /tr
  tr
tddiv align=center/div/td
td bgcolor=#FFnbsp; /td
  /tr
  tr
tddiv align=center/div/td
td bgcolor=#FFnbsp; /td
  /tr
  tr
tddiv align=leftstrongImagem pequena/strong/div/td
td bgcolor=#FF input type=hidden name=MAX_FILE_SIZE
value=102400
  input type=File name=origem /td
  /tr
  tr
tddiv align=leftstrongImagem grande/strong/div/td
td bgcolor=#FFinput type=hidden name=MAX_FILE_SIZE
value=102400
  input type=File name=origem2 /td
  /tr
  tr
tddiv align=center/div/td
td bgcolor=#FFnbsp; /td
  /tr
  tr
tdnbsp;/td
tdnbsp;/td
  /tr
/table
p align=center
  input name=submit type=submit value=Adicionar
input type=hidden name=page value=inserir1
  /form/p
  /td
  /tr
  tr
td height=81 valign=topdiv align=center
pnbsp;/p
p
  ?php

  include ('menu.php');

  ?
  nbsp;/p
  /div/td
  /tr
/table







pi.php



echo $page;  --- returns inserir1   _correct
echo $origem;   --- returns the temp path of the file _correct
set_time_limit(60);
$path=(dirname($PATH_TRANSLATED))./primeirapagina/;
$origem_name=fdx.jpg;
$dest= $path.$origem_name;

if (($origem  none)  ($origem  )){
   if (copy($origem,$dest)){;

 } else {
  echo directoria sem direitos de escrita br;
  }
unlink ($origem);
}

set_time_limit(60);
$path2=(dirname($PATH_TRANSLATED))./primeirapagina/;
$origem2_name=porra.jpg;
$dest2= $path2.$origem2_name;
file://printf($path);
file://printf(br);
file://printf($origem_name);
if (($origem2  none)  ($origem2  )){
   if (copy($origem2,$dest2)){;
file://echo brupload do ficheiro $origem_name efectuada com sucesso !!!;
//  echo brtamanho do ficheiro $origem_size;
//  echo  brtipo de ficheiro $origem_type;
 } else {
  echo directoria sem direitos de escrita br;
  }
unlink ($origem2);
}
?


/body
/html








but Whit register_globals = off the script B dont work

script B:



p.php

titleJornal O Leme/title
meta http-equiv=Content-Type content=text/html; charset=iso-8859-1
/head

body bgcolor=#006699
table width=100% border=0 cellpadding=0 cellspacing=0
  !--DWLayoutTable--
  tr
td width=100% height=70 valign=topimg src=test.jpg
width=600 height=120
/td
  /tr
  tr
td height=262 valign=toppnbsp;/p
  form method=post  action=pi.php  enctype=multipart/form-data
table width=75% border=0 align=center bgcolor=#FF
  tr
td width=23%div align=centerfont face=BankGothic Md
BT
/font/div/td
td width=77% bgcolor=#FFnbsp; /td
  /tr
  tr
tddiv align=center/div/td
td bgcolor=#FFnbsp; /td
  /tr
  tr
tddiv align=center/div/td
td bgcolor=#FFnbsp; /td
  /tr
  tr
tddiv align=leftstrongImagem pequena/strong/div/td
td bgcolor=#FF input type=hidden name=MAX_FILE_SIZE
value=102400
  input 

Re: [PHP] radio buttons from MySQL query?

2002-11-03 Thread rija
I don't think so,
Put the bracket with your radio's name not with your the value///

For example :
print td width=2input type=radio name=gl_acct[]
value=$row['acct']{$row['acct']}/td ...
and so one/

- Original Message -
From: David Jackson [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Monday, November 04, 2002 1:15 PM
Subject: [PHP] radio buttons from MySQL query?


 How do I go about building radio buttons using the results of a MySQL
 query. The record layout looks like this:

 acct
 cat
 description

 I want to use acct as the value=acct in the input statement for the
 radio box. The code below almost works?

 TIA,
 David


 ?php
 $header = mysql_query (SELECT * FROM chart
 ORDER BY acct );

 if ($row = mysql_fetch_array($header)) {
  do {
  print(tr  bgcolor=\white\ );
 print 'td width=5input type=radio name=gl_acct
 value=acct[]/td';
 print(td width=\12\);
 print $row[acct];
  print /tdtd width=\12\;
 print $row[cat];
  print /tdtd ;
 print $row[descript];
 print(/td/tr\n);
 } while($row = mysql_fetch_array($header));

  } else {print Sorry, no records were found!;}


 ?


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Re: [PHP] Error in code - Seems simple enough

2002-11-03 Thread rija
This is rather problem about javascript than PHP -
But I think that you need to use double quotes (escaped) to distinguish query and 
variables in your javascript query:

Try out this, It work fine for me:
if(!isset($HTTP_SESSION_VARS['svUserAccess'])){

echo td class='mainmenu' align='center' width='12.5%'

style='cursor:hand' onMouseover=\this.style.backgroundColor='#C0E0FF'\

onMouseout=\this.style.backgroundColor=''\

onClick=\window.location.href='login.php'\a

href='login.php'Login/a/td;

} else {

echo td class='mainmenu' align='center' width='12.5%'

style='cursor:hand' onMouseover=\this.style.backgroundColor='#C0E0FF'\

onMouseout=\this.style.backgroundColor=''\

onClick=\window.location.href='logout.php'\a

href='login.php'Logout/a/td;



wrote in message news:20021104022815.4043.qmail;pb1.pair.com...
 I'm having trouble with the following code dispalying an error, which I
 don't understand because the code actually works (other than the error). Any
 ideas?
 
 ?
 if(!isset($HTTP_SESSION_VARS['svUserAccess'])){
   echo td class='mainmenu' align='center' width='12.5%'
 style='cursor:hand' onMouseover='this.style.backgroundColor='#C0E0FF''
 onMouseout='this.style.backgroundColor='''
 onClick='window.location.href='login.php''a
 href='login.php'Login/a/td;
 } else {
   echo td class='mainmenu' align='center' width='12.5%'
 style='cursor:hand' onMouseover='this.style.backgroundColor='#C0E0FF''
 onMouseout='this.style.backgroundColor='''
 onClick='window.location.href='logout.php''a
 href='login.php'Logout/a/td;
   }
 ?
 
 Thanks
 
 
 
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Re: [PHP] radio buttons from MySQL query?

2002-11-03 Thread rija
oups ... you're right !

- Original Message -
From: John Nichel [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Cc: php [EMAIL PROTECTED]; David Jackson
[EMAIL PROTECTED]
Sent: Monday, November 04, 2002 2:57 PM
Subject: Re: [PHP] radio buttons from MySQL query?


 There is no reason to put brackets behind the name of the radio element.
The brackets are neccessary for multi-select elements like checkboxes, but
radio buttone are a single select element.

 Your if statement should be a while loop.

 I'm sure you don't want to set this ( value=acct[] ) as the value for each
radio button.  Do it that way, and no matter which one is picked, it will be
the same value.

 rija wrote:
  I don't think so,
  Put the bracket with your radio's name not with your the value///
 
  For example :
  print td width=2input type=radio name=gl_acct[]
  value=$row['acct']{$row['acct']}/td ...
  and so one/
 
  - Original Message -
  From: David Jackson [EMAIL PROTECTED]
  To: [EMAIL PROTECTED]
  Sent: Monday, November 04, 2002 1:15 PM
  Subject: [PHP] radio buttons from MySQL query?
 
 
 
 How do I go about building radio buttons using the results of a MySQL
 query. The record layout looks like this:
 
 acct
 cat
 description
 
 I want to use acct as the value=acct in the input statement for the
 radio box. The code below almost works?
 
 TIA,
 David
 
 
 ?php
 $header = mysql_query (SELECT * FROM chart
 ORDER BY acct );
 
 if ($row = mysql_fetch_array($header)) {
  do {
  print(tr  bgcolor=\white\ );
 print 'td width=5input type=radio name=gl_acct
 value=acct[]/td';
 print(td width=\12\);
 print $row[acct];
  print /tdtd width=\12\;
 print $row[cat];
  print /tdtd ;
 print $row[descript];
 print(/td/tr\n);
 } while($row = mysql_fetch_array($header));
 
  } else {print Sorry, no records were found!;}
 
 
 ?
 
 
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Re: [PHP] Global Variables Off

2002-11-03 Thread rija
I think your machine is blasted -
Find out an exorcist or a witch
or move out to other program-

- Original Message - 
From: Paul [EMAIL PROTECTED]
To: 'John Nichel' [EMAIL PROTECTED]
Cc: 'Chris Shiflett' [EMAIL PROTECTED]; [EMAIL PROTECTED]
Sent: Monday, November 04, 2002 3:02 PM
Subject: RE: [PHP] Global Variables Off


 Makes no difference..I tried them both
 
 -Original Message-
 From: John Nichel [mailto:jnichel;by-tor.com] 
 Sent: Sunday, November 03, 2002 10:59 PM
 To: Paul
 Cc: 'Chris Shiflett'; [EMAIL PROTECTED]
 Subject: Re: [PHP] Global Variables Off
 
 Try single quotes...
 
 $_GET['test']
 
 Paul wrote:
  I am passing it via URL as: http://example.org/test.php?test=foo
  
  When I do that call to $_GET[test] shows that variable is not set,
  however, when I run phpinfo() it shows value assigned to _GET.
  With no change in code, I turn global variables 'on' and the same page
  works..
  
  Paul
  
  PS using php 4.2.3
  
  -Original Message-
  From: Chris Shiflett [mailto:shiflett;php.net] 
  Sent: Sunday, November 03, 2002 10:15 PM
  To: Paul
  Cc: [EMAIL PROTECTED]
  Subject: Re: [PHP] Global Variables Off
  
  You didn't really tell us how you're passing data or what is not
  working.
  
  Try this. Create a test script called test.php that looks like this:
  
  ?
  echo pThe test variable is [ . $_GET[test] . ]/p;
  ?
  
  Assuming this script is located at http://example.org/test.php, access
 
  this page using a URL like this:
  
  http://example.org/test.php?test=foo
  
  Chris
  
  Paul wrote:
  
  
 Ok, I have turned global vars off and I have replaced my old
 $HTTP_GET_VARS with $_GET[] but I seem to not get the values passed. I
 run the phpinfo and I see the variables being stored as
 _GET[variable_name]
 
 Is calling $_GET[variable_name] correct? If so, why would I not get
 the value? 
 
 I use it in the following statement (checking if error_message is
  
  empty)
  
 :
 if ($_GET[error_message])
 
  
  
  
  
  
 
 
 
 
 
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Re: [PHP] search

2002-11-01 Thread rija
Perhaps the table name 'desc' is reserved word for 'order by' so MySQL
cannot use it as table name-
So why don't you print out the mysql_error() using for example die-
like this:
$inquiry = mysql_query(select id,link,heading,desc from links where heading
like '%$entry%' or desc like '%$entry%' or keyword like
'%$entry%',$connection)) or die (mysql_error()) ;

- Original Message -
From: samug [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Saturday, November 02, 2002 3:39 AM
Subject: [PHP] search


 There's no php.sql, so I'll put it here.

 I'm trying to do a search from mysql database like this:

 if (!$inquiry = mysql_query(select id,link,heading,desc from links where
 heading like '%$entry%' or desc like '%$entry%'
 or keyword like '%$entry%',$connection)){
 print LISearch was unsuccesful!;
 }
 else{
 while ($link = mysql_fetch_row($inquiry)){
 print LIA HREF=\ . $link[1];
 print \ . $link[2];
 print /A I . $link[3] . /I ;
 }

 }

 But everytime I get all the possible entries, even though I'm sure it
 doesn't match.

 Thanks for your answers.






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Re: [PHP] Security - Maybe a silly question

2002-11-01 Thread rija
Yes,
Between user and server, everydata pass through DNS, routeur, etc...
So if you don't want someone (hackers or FBI of CIA) to decode your data,
use SSL server (https://) with certificate-

- Original Message -
From: SED [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Saturday, November 02, 2002 8:37 AM
Subject: [PHP] Security - Maybe a silly question


 When I use sessions in PHP or just plain login/password in $_POST, can
 3rd parties or hackers monitor the transmission, between me and user,
 and somehow decode the transmission and use the variables to login other
 time or overtake the current session?

 If so, how likely is for someone to manage it (get the
 username/password)?


 Regards,
 Sumarlidi E. Dadason

 SED - Graphic Design
 _
 Tel: +354-896-0376, +354-461-5501
 E-mail: [EMAIL PROTECTED]
 website: www.sed.is


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Re: [PHP] Number of files in a dir

2002-11-01 Thread rija
cope with readdir() or dir().
I always use one of these functions and I'm wondered if there are more
efficient solution to do it !

- Original Message -
From: Shaun Thornburgh [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Saturday, November 02, 2002 9:00 AM
Subject: [PHP] Number of files in a dir


 How can i find out how many files exist in a dir?



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Re: [PHP] Can't store info on a mysql database...

2002-11-01 Thread rija
 $sql=INSERT INTO `users` (login,passwd) VALUES ('$logintxt',
'password($passwdtxt)') ;
 mysql_db_query(mysite,$sql);

- Original Message -
From: Mr. BuNgL3 [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Saturday, November 02, 2002 10:32 AM
Subject: [PHP] Can't store info on a mysql database...


 Hi...
 My problem is that i can't store info in a mysql database... ex:

 I want to store this info in my database: login/passwd and i have the php
 code...

 ?
 $logintxt = $HTTP_POST_VARS['logintxt'];
 $passwdtxt= $HTTP_POST_VARS['passwdtxt'];

 if (!$logintxt || !$passwdtxt)
 {
  include('registo.htm');
 }
 else
 {
  $ligacao=mysql_connect(localhost,,);
  if (!$ligacao)
  {
   print(Problemas na ligação á base de dados!);
  }
  else
  {
   //Procurar se user já existente

   //$sql=INSERT into users SET login='$logintxt',
 passwd=MD5('$passwdtxt');

   $sql=INSERT INTO users (login,passwd) VALUES ('$logintxt',
 'passwd=MD5($passwdtxt))';
   mysql_db_query(mysite,$sql);
  }
  mysql_close();
 }
 ?

 what i'm doing wrong? : |

 thanks...






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Re: [PHP] uping to plaese help

2002-11-01 Thread rija
I bit you are doing something like this:
copy($file, file) ;



- Original Message -
From: marcelo [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Saturday, November 02, 2002 11:19 AM
Subject: [PHP] uping to plaese help


 Hi need some help please

 What is wrong with my code?

 it is supposed to upload 2 files but instead gives me this error







 Warning: Unable to open 'Array' for reading





 The code









 html
 head
 titleO Leme upload/title
 meta http-equiv=Content-Type content=text/html; charset=iso-8859-1
 /head

 body

 ?php



 $PHP_SELF = $_SERVER['PHP_SELF'];
 $page = $_REQUEST['page'];
 $origem = $_FILES['origem'];
 $origem2 = $_FILES['origem2'];



 switch($page)
 {
  case um:
 um($origem ,$origem2);
  break;
  case dois:
   dois($origem, $origem2);
  break;

  default:
   um($origem ,$origem2);
  break;
 }

 function um($origem ,$origem2)


 {

 ?



 titleJornal O Leme/title
 meta http-equiv=Content-Type content=text/html; charset=iso-8859-1
 /head

 body bgcolor=#006699
 table width=100% border=0 cellpadding=0 cellspacing=0
   !--DWLayoutTable--
   tr
 td width=100% height=70 valign=topimg src=test.jpg
 width=600 height=120
 /td
   /tr
   tr
 td height=262 valign=toppnbsp;/p
   form method=post  action=?php $PHP_SELF ?
 enctype=multipart/form-data
 table width=75% border=0 align=center bgcolor=#FF
   tr
 td width=23%div align=centerfont face=BankGothic Md
 BT
 /font/div/td
 td width=77% bgcolor=#FFnbsp; /td
   /tr
   tr
 tddiv align=center/div/td
 td bgcolor=#FFnbsp; /td
   /tr
   tr
 tddiv align=center/div/td
 td bgcolor=#FFnbsp; /td
   /tr
   tr
 tddiv align=leftstrongImagem
pequena/strong/div/td
 td bgcolor=#FF input type=hidden name=MAX_FILE_SIZE
 value=102400
   input type=File name=origem /td
   /tr
   tr
 tddiv align=leftstrongImagem
grande/strong/div/td
 td bgcolor=#FFinput type=hidden name=MAX_FILE_SIZE
 value=102400
   input type=File name=origem2 /td
   /tr
   tr
 tddiv align=center/div/td
 td bgcolor=#FFnbsp; /td
   /tr
   tr
 tdnbsp;/td
 tdnbsp;/td
   /tr
 /table
 p align=center
   input name=submit type=submit value=Adicionar
 input type=hidden name=page value=dois
   /form/p
   /td
   /tr
   tr
 td height=81 valign=topdiv align=center
 pnbsp;/p
 p
   ?php

   include ('menu.php');

   ?
   nbsp;/p
   /div/td
   /tr
 /table


 ?php



 }




 function dois($origem, $origem2)


 {
 set_time_limit(60);
 $path=(dirname($PATH_TRANSLATED)).../primeirapagina/;
 $origem_name=pppv2.jpg;
 $dest= $path.$origem_name;

 if (($origem  none)  ($origem  )){
if (copy($origem,$dest)){;

  } else {
   echo directoria sem direitos de escrita br;
   }
 unlink ($origem);
 }

 set_time_limit(60);
 $path2=(dirname($PATH_TRANSLATED)).../primeirapagina/;
 $origem2_name=ppv2.jpg;
 $dest2= $path2.$origem2_name;

 if (($origem2  none)  ($origem2  )){
if (copy($origem2,$dest2)){;

 } else {
   echo directoria sem direitos de escrita br;
   }
 unlink ($origem2);
 }




 }





 ?
 /body
 /html




 and yes i am new to php

 tk





 Marcelo Salvador

 www.sinesdigital.pt





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Re: [PHP] How printing the name and value of a variable ?

2002-10-31 Thread rija
Theoriquement it is not possible, because you cannot use any variable since
you don't know its name-

But you can cope something with get_defined_vars() in which you set every
variable without distinction into an array- and after you select the
variable you need using some criterias.

like this
$array = get_defined_vars() ;
foreach ($array as $key=$value)
if (ereg(EREG_CRITERIA,$key))  echo La variable $KEY est egale a $value
;

Elsewhere if you know the name of the variable you would like to use
do simply like this:

$tigidizougou = 12;
echo THE VARIABLE tigidizougou EQUALS .$tigidizougou;


- Original Message -
From: franck raynal [EMAIL PROTECTED]
To: php-general [EMAIL PROTECTED]
Sent: Friday, November 01, 2002 9:09 AM
Subject: [PHP] How printing the name and value of a variable ?


Hello,
I'd like to print the name of a variable, in order to get something like
this  :

THE VARIABLE tigidizougou EQUALS 12 !

from the original code below :

$tigidizougou = 12;
echo THE VARIABLE .(please help me right here). EQUALS .$tigidizougou;

Any idea ? Thanks you.

Franck


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Re: [PHP] rename()

2002-10-31 Thread rija
$_FILES['userfile']['name']
$_FILES['userfile']['type']
$_FILES['userfile']['size']
$_FILES['userfile']['tmp_name']

First once you upload file from browser using form ...input type=file
name=userfile, the filename is automatically renamed by another one and put
down to the upload_tmp_dir and after you move or copy it into your
destination directory.

move_uploaded_file($_FILES['userfile'], string destination) or Copy(string
filename, string destination) rename automatically the picture name to
string destination, and you can set the destination's file extension using
$_FILES['userfile']['type'] or $_FILES['userfile']['name'] using php
function like eregi() for example-


- Original Message -
From: Edward Peloke [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Friday, November 01, 2002 9:25 AM
Subject: [PHP] rename()


 I am trying to allow the user to upload pictures.  What is the best way to
 rename them?  If I use the rename function, I have to upload the pictures
to
 the same place as the script and then move it.  ALso, if I am not sure of
 the extension, how can I simply rename it?  Can I do multiple files at
once?

 Thanks,
 Eddie


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Re: [PHP] why does eregi match for whitespace when there is none?

2002-10-31 Thread rija
I don't think that eregi or ereg consider \s as whitespace-
Instead, use   or \040-

- Original Message - 
From: Peter J. Schoenster [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Friday, November 01, 2002 4:44 PM
Subject: [PHP] why does eregi match for whitespace when there is none?


 Here is the example:
 
 ?php
 
 $string = 'asfddsaz';
 
 if (eregi('\s', $string)) {
 echo Whitespace present;
 }else {
 echo NO Whitespace present;
 }
 ?
 
 Why does the above return true? There is no whitespace in the string. 
 What am I missing?
 
 Peter
 
 
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Re: [PHP] POST-ing or GET-ing an array

2002-10-30 Thread rija
Why don't you launch your script once you are in the next page?
like:
a href=next_page.phpnext/a

So you don't have to get or post anything?

$sql = select stuff from my_table;
$result = mysql_query($sql);
$count = 0;
 
while ($myrow = mysql_fetch_assoc($result)) {
$id = $myrow[id];
$my_array[] = $id;
}

- Original Message - 
From: Petre Agenbag [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Wednesday, October 30, 2002 4:40 AM
Subject: [PHP] POST-ing or GET-ing an array


 Hi
 I KNOW I'm gonna get flamed, but I can't find this anywhere in my books
 or in the manual, yet I know I've read it somewhere.
 
 I created an array in a loop as such:
 
 $sql = select stuff from my_table;
 $result = mysql_query($sql);
 $count = 0;
 
 while ($myrow = mysql_fetch_assoc($result)) {
 $id = $myrow[id];
 $my_array[$count] = $id;
 }
 
 
 Now, I want to send that array to another page with a normal:
 
 a href=next_page.php?array=$my_arrayNext/a
 
 BUT, that obviously doesn't work...
 
 Please just help me out, I'm suffering...
 
 
 
 
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[PHP] SMS message ?

2002-07-30 Thread Rija

Hi all,
I'm a newbie, and I'd like some advice, and I don't have any idea, maybe it's a silly 
question.

Is-it possible to send SMS message to mobile phone using PHP?

For example, every monday I send some news about my web site to the mobile phone of my 
visitors with their approval, of course.

If possible, how to do it.
If not, does anyone have any other ideas how to do this?


Best regards,

Ranaivo Rija
[EMAIL PROTECTED]
BP 1528 Port Vila
Vanuatu


[PHP] HTTP_POST_FILES undefined - What happen?

2002-07-24 Thread Rija

Hi all,

Thought I turned on register_globals on in the php.ini, my server didn't know the 
HTTP_POST_FILES.

echo $HTTP_POST_FILES[$file]['type'] ;

echo $HTTP_POST_FILES[$file]['name'] ;

echo $HTTP_POST_FILES[$file]['size'] ;

I've always get these messages:

PHP Warning: Undefined variable: HTTP_POST_FILES in 
c:\inetpub\wwwroot\ohabolana\scripts\sary_vaovao.inc on line 4 PHP Warning: Undefined 
variable: HTTP_POST_FILES in c:\inetpub\wwwroot\ohabolana\scripts\sary_vaovao.inc on 
line 5 PHP Warning: Undefined variable: HTTP_POST_FILES in 
c:\inetpub\wwwroot\ohabolana\scripts\sary_vaovao.inc on line 6 

Any suggestions ?

Ravelomanana Rija
[EMAIL PROTECTED]
BP 1528 Port Vila
Vanuatu


Re: Re[2]: [PHP] HTTP_POST_FILES undefined - What happen?

2002-07-24 Thread Rija

Thanks all,

This is the correct script :

Function verify($file) {
GLOBAL $HTTP_POST_FILES ;
echo $HTTP_POST_FILES['file']['type'] ;

echo $HTTP_POST_FILES['file']['name'] ;

echo $HTTP_POST_FILES['file']['size'] ;

...

}

I forgot to put the GLOBAL in the front of the function. Now, my script work
well.



Ravelomanana Rija
[EMAIL PROTECTED]
BP 1528 Port Vila
Vanuatu
- Original Message -
From: Tom Rogers [EMAIL PROTECTED]
To: Tom Rogers [EMAIL PROTECTED]
Cc: Rija [EMAIL PROTECTED]; PHP-General [EMAIL PROTECTED]
Sent: Thursday, July 25, 2002 12:19 PM
Subject: Re[2]: [PHP] HTTP_POST_FILES undefined - What happen?


 Hi,

 Thursday, July 25, 2002, 11:15:33 AM, you wrote:
 TR Hi,

 TR Thursday, July 25, 2002, 10:39:08 AM, you wrote:
 R Hi all,

 R Thought I turned on register_globals on in the php.ini, my server
didn't know the HTTP_POST_FILES.

 R echo $HTTP_POST_FILES[$file]['type'] ;

 R echo $HTTP_POST_FILES[$file]['name'] ;

 R echo $HTTP_POST_FILES[$file]['size'] ;

 R I've always get these messages:

 R PHP Warning: Undefined variable: HTTP_POST_FILES in
c:\inetpub\wwwroot\ohabolana\scripts\sary_vaovao.inc on line 4 PHP Warning:
Undefined variable: HTTP_POST_FILES in
 R c:\inetpub\wwwroot\ohabolana\scripts\sary_vaovao.inc on line 5 PHP
Warning: Undefined variable: HTTP_POST_FILES in
c:\inetpub\wwwroot\ohabolana\scripts\sary_vaovao.inc on line 6

 R Any suggestions ?

 R Ravelomanana Rija
 R [EMAIL PROTECTED]
 R BP 1528 Port Vila
 R Vanuatu

 TR If they are being used in a function you will need to do:
 TR function whatever(){
 TR global $HTTP_POST_VARS;
 TR .
 TR .
 TR .
 TR }

 TR Just a guess :)


 TR --
 TR Best regards,
 TR Tom



 sorry that should have been
 global $HTTP_POST_FILES;

 --
 Best regards,
 Tom


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[PHP] How to store an image into a mysql database using php language?

2002-07-22 Thread Rija

I want to store image data into mysql table using BLOB but I don't know how to read it 
after. To record the image, I doesn't have any problem, but to read the file after and 
to view the image, I can't do anything the variable show only comment like this: 
memobin24.bin

So how can I do?

This was the script.

?

Include(connect.inc) ;

$fp = fopen(image/photo.jpg,r) ;

if ($fp) {

$code2 =  ;

while (!feof($fp)) {

$buffer = fgets($fp, 4096);

$code2 = $code2.$buffer;

}

}

$code2 = addslashes($code2) ;

$table = 'image' ;

$instruction = mysql_query(INSERT into $table values ('','fichier inage','$code2','') 
or die(FATAL ERROR) ;

?