Re: [PHP] Array help.
On Wed, Oct 24, 2012 at 2:40 PM, Samuel Lopes Grigolato
samuel.grigol...@gmail.com wrote:
Could you try changing this:
if($groupTest != FALSE) {
to this:
if($groupTest !== FALSE) {
?
Hah. Perfect! Thanks.
-Mensagem original-
De: Paul Halliday [mailto:paul.halli...@gmail.com]
Enviada em: quarta-feira, 24 de outubro de 2012 15:38
Para: PHP-General
Assunto: [PHP] Array help.
I am processing v4IP's and what I want to do is a prefix substitution if the
3rd octet matches a predefined list $groupMappings. I went down this path
and it isn't working as expected. Drawing a blank on this one. Why does 40
miss the comparison?
$hostname = Z;
$ips = array('10.1.40.1','10.1.41.1','10.1.1.1','10.1.40.1','10.9.1.1');
foreach ($ips as $ip) {
$groupMappings = array('40' ='A','41' ='B','1' ='C');
$ocTest = explode(., $ip);
$groupKeys = array_keys($groupMappings);
$groupTest = array_search($ocTest[2], $groupKeys);
if($groupTest != FALSE) {
$hostGroup = $groupMappings[$groupKeys[$groupTest]];
echo Hit! $ip : $hostname : $hostGroup\n;
} else {
$hostGroup = substr($hostname, 0,2);
echo Miss! $ip : $hostname : $hostGroup\n;
}
}
Miss! 10.1.40.1 : Z : Z
Hit! 10.1.41.1 : Z : B
Hit! 10.1.1.1 : Z : C
Miss! 10.1.40.1 : Z : Z
Hit! 10.9.1.1 : Z : C
Thanks!
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RE: [PHP] Array help.
From: Paul Halliday [paul.halli...@gmail.com]
Sent: 24 October 2012 18:38
To: PHP-General
Subject: [PHP] Array help.
$groupMappings = array('40' ='A','41' ='B','1' ='C');
$ocTest = explode(., $ip);
$groupKeys = array_keys($groupMappings);
$groupTest = array_search($ocTest[2], $groupKeys);
if($groupTest != FALSE) {
I think you're making a little bit of a meal of this. My initial thoughts
included pointing you at array_key_exists() (and, why on earth
have you got $ocTest[2] in quotes?), but then I realised if I were
writing this I'd probably just use isset(), thus:
$ocTest = explode(., $ip);
if (isset($groupMappings[$ocTest[2]])):
// success
else:
// fail
endif;
Hope this helps!
Cheers!
Mike
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Re: [PHP] Array help.
On Jul 30, 2010, at 2:36 PM, Paul Halliday wrote:
I have a query that may not always return a result for a value, I need
to reflect this with a 0. I am trying to overcome this by doing this
(the keys are ID's):
while ($row = mysql_fetch_row($statusQuery)) {
$cat =
array(0=0,1=0,11=0,12=0,13=0,14=0,15=0,16=0,17=0,19=0);
switch ($row[1]) {
case 0: $cat[0] = $row[0]; break;
case 1: $cat[1] = $row[0]; break;
case 11: $cat[11] = $row[0]; break;
case 12: $cat[12] = $row[0]; break;
case 13: $cat[13] = $row[0]; break;
case 14: $cat[14] = $row[0]; break;
case 15: $cat[15] = $row[0]; break;
case 16: $cat[16] = $row[0]; break;
case 17: $cat[17] = $row[0]; break;
case 19: $cat[19] = $row[0]; break;
}
print_r($cat);
}
Which gives me this:
Array ( [0] = 15547 [1] = 0 [11] = 0 [12] = 0 [13] = 0 [14] = 0
[15] = 0 [16] = 0 [17] = 0 [19] = 0 )
Array ( [0] = 0 [1] = 0 [11] = 0 [12] = 0 [13] = 0 [14] = 0 [15]s
= 30 [16] = 0 [17] = 0 [19] = 0 )
The query only return 2 rows:
15 | 30
0 | 15547
What am I doing wrong? Is there a more elegant way to achieve what I want?
Thanks.
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Paul-
Why not say:
$cat = array();
if(isset($row[1])
{
$cat[$row[1]] = $row[0];
}
print_r($cat);
Regards,
-Josh
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Re: [PHP] Array help.
On Fri, Jul 30, 2010 at 3:44 PM, Joshua Kehn josh.k...@gmail.com wrote:
On Jul 30, 2010, at 2:36 PM, Paul Halliday wrote:
I have a query that may not always return a result for a value, I need
to reflect this with a 0. I am trying to overcome this by doing this
(the keys are ID's):
while ($row = mysql_fetch_row($statusQuery)) {
$cat =
array(0=0,1=0,11=0,12=0,13=0,14=0,15=0,16=0,17=0,19=0);
switch ($row[1]) {
case 0: $cat[0] = $row[0]; break;
case 1: $cat[1] = $row[0]; break;
case 11: $cat[11] = $row[0]; break;
case 12: $cat[12] = $row[0]; break;
case 13: $cat[13] = $row[0]; break;
case 14: $cat[14] = $row[0]; break;
case 15: $cat[15] = $row[0]; break;
case 16: $cat[16] = $row[0]; break;
case 17: $cat[17] = $row[0]; break;
case 19: $cat[19] = $row[0]; break;
}
print_r($cat);
}
Which gives me this:
Array ( [0] = 15547 [1] = 0 [11] = 0 [12] = 0 [13] = 0 [14] = 0
[15] = 0 [16] = 0 [17] = 0 [19] = 0 )
Array ( [0] = 0 [1] = 0 [11] = 0 [12] = 0 [13] = 0 [14] = 0 [15]s
= 30 [16] = 0 [17] = 0 [19] = 0 )
The query only return 2 rows:
15 | 30
0 | 15547
What am I doing wrong? Is there a more elegant way to achieve what I want?
Thanks.
--
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Paul-
Why not say:
$cat = array();
if(isset($row[1])
{
$cat[$row[1]] = $row[0];
}
print_r($cat);
Regards,
-Josh
I need the results that don't have values assigned though.
ex:
c = 0
h = 9
t = 0
f = 21
Even if the query returned only:
h = 9
f = 21
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Re: [PHP] Array help.
On Jul 30, 2010, at 3:03 PM, Paul Halliday wrote: Paul- Why are those values not defaulted to 0 in the database? Regards, -Josh They are defaulted, the query is grouping: select count(status) as count, status from table group by status order by status desc; Paul- Correct, so stuff with a status of 0 will still show up unless I'm missing something. Regards, -Josh -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Array help
Ryan A wrote:
I have a login/password file with these kind of values:
user1:pass1
user2:pass2
cat:dog
love:hate
I have opened the file and put it into an array with this code:
(thanks to richard lynch from this list for idea and code snippets)
$file = file_get_contents('a.htpasswd');
preg_match_all('/(.*):(.*)$/msU', $file, $htpassd);
but how do I get it into this format :
$users['username'] = 'password'
without using a loop? I was thinking something like array_flip or
array_splice??
(The reason I dont want to use a loop (for,while) is there can be thousands of
user:pass combos in the files and thousands of logins and attempted logins a
day)
My advice would be to swap to using a database. With that number of
users it's going to give you a huge boost in performance. SQLite would do.
If you *need* to stick to using the file, are you looking for a
particular username or just want to load the whole list?
-Stut
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Re: [PHP] Array help
Hey Stut,
Thanks for replying.
Will be making two versions, one with a DB and one to work with the file for
the old school folks who dont want to convert their file and use new fangled
databases... some people its easier to just not argue or try to convince...
and however stupid someone's opinion is, they are still entitled to it...esp
when you are thinking of (maybe) selling a future product it does not make much
sense telling them they are stupid :-))
If you *need* to stick to using the file, are you looking for a
particular username or just want to load the whole list?
I'm looking to match a login (user:pass)... so I would need to load the whole
list right? or do you have an alternative idea? am totally open to suggestions
and alternatives at this point... just looking for the easiest way in terms of
server load and processing..which is why I am trying to avoid a for() or
while() loop.
Thanks!
Ryan
Stut [EMAIL PROTECTED] wrote: Ryan A wrote:
I have a login/password file with these kind of values:
user1:pass1
user2:pass2
cat:dog
love:hate
I have opened the file and put it into an array with this code:
(thanks to richard lynch from this list for idea and code snippets)
$file = file_get_contents('a.htpasswd');
preg_match_all('/(.*):(.*)$/msU', $file, $htpassd);
but how do I get it into this format :
$users['username'] = 'password'
without using a loop? I was thinking something like array_flip or
array_splice??
(The reason I dont want to use a loop (for,while) is there can be thousands
of user:pass combos in the files and thousands of logins and attempted logins
a day)
My advice would be to swap to using a database. With that number of
users it's going to give you a huge boost in performance. SQLite would do.
If you *need* to stick to using the file, are you looking for a
particular username or just want to load the whole list?
-Stut
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Re: [PHP] Array help
Ryan A wrote: Will be making two versions, one with a DB and one to work with the file for the old school folks who dont want to convert their file and use new fangled databases... some people its easier to just not argue or try to convince... and however stupid someone's opinion is, they are still entitled to it...esp when you are thinking of (maybe) selling a future product it does not make much sense telling them they are stupid :-)) Fair enough. If you *need* to stick to using the file, are you looking for a particular username or just want to load the whole list? I'm looking to match a login (user:pass)... so I would need to load the whole list right? or do you have an alternative idea? am totally open to suggestions and alternatives at this point... just looking for the easiest way in terms of server load and processing..which is why I am trying to avoid a for() or while() loop. Loops are not evil, but I understand what you're saying. You basically have a few options. Firstly... is the file in alphabetical order? If yes then you can use a binary chop algorithm to seek around the file to find the right line. However, I doubt the file is organised alphabetically, so... The second option would be to load the entire file into a variable and do a regex to find the password hash. I'm not great at regexes, but you want a multi-line regex looking for \n followed by the username, followed by a :. Should be pretty easy to knock that up. However, this is not great if the file is not trivial in size. The third option is to use fgets to read each line in the file, check if it starts with username:, and if it does then you've found it. This would be the slowest option, but the most economical and I think you'd be surprised at how fast PHP can do this. Another option would be to break the single file in to several files, maybe one for each first character. That way you would limit the number of entries you need to check. Hope that helps. -Stut -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Array help
Well, you are using the file_get_contents function right now, what about a
loop that reads the file line by line, checks if the user matches, and stops
when found the right user?
it's an all in one loop :)
just like this:
$found = false;
$fp = fopen($file,r);
while(!feof($fp) $found == false)
{
$line = fread($fp,256);
if($line == $user.:.$pass)
{
$found = true;
}
}
It is possible to get it even smaller, but i'm not a genius in writing fast
code :P
Tijnema
On 3/4/07, Ryan A [EMAIL PROTECTED] wrote:
Hey Stut,
Thanks for replying.
Will be making two versions, one with a DB and one to work with the file
for the old school folks who dont want to convert their file and use new
fangled databases... some people its easier to just not argue or try to
convince...
and however stupid someone's opinion is, they are still entitled to
it...esp when you are thinking of (maybe) selling a future product it does
not make much sense telling them they are stupid :-))
If you *need* to stick to using the file, are you looking for a
particular username or just want to load the whole list?
I'm looking to match a login (user:pass)... so I would need to load the
whole list right? or do you have an alternative idea? am totally open to
suggestions and alternatives at this point... just looking for the easiest
way in terms of server load and processing..which is why I am trying to
avoid a for() or while() loop.
Thanks!
Ryan
Stut [EMAIL PROTECTED] wrote: Ryan A wrote:
I have a login/password file with these kind of values:
user1:pass1
user2:pass2
cat:dog
love:hate
I have opened the file and put it into an array with this code:
(thanks to richard lynch from this list for idea and code snippets)
$file = file_get_contents('a.htpasswd');
preg_match_all('/(.*):(.*)$/msU', $file, $htpassd);
but how do I get it into this format :
$users['username'] = 'password'
without using a loop? I was thinking something like array_flip or
array_splice??
(The reason I dont want to use a loop (for,while) is there can be
thousands of user:pass combos in the files and thousands of logins and
attempted logins a day)
My advice would be to swap to using a database. With that number of
users it's going to give you a huge boost in performance. SQLite would do.
If you *need* to stick to using the file, are you looking for a
particular username or just want to load the whole list?
-Stut
--
- The faulty interface lies between the chair and the keyboard.
- Creativity is great, but plagiarism is faster!
- Smile, everyone loves a moron. :-)
-
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Re: [PHP] Array help
Hey! Thanks Stut, Tijnema. I'll test out the ideas you guys contributed to me.. after I finish a working copy will ask you guys to give it a look over ;) @Stut: The list is not in alphabetical order.. and 2, I have no idea of the size of the file (for the regex suggestion) but I am guessing it can be quite big with just 5k members. I like the FGETs idea you and Tijnema gave me... I think I'll go with that. Am still working on a few other bits and pieces.. Cheers! R -- - The faulty interface lies between the chair and the keyboard. - Creativity is great, but plagiarism is faster! - Smile, everyone loves a moron. :-) - Food fight? Enjoy some healthy debate in the Yahoo! Answers Food Drink QA.
Re: [PHP] array help
Did you bother to initialize $table as an array() or are you another
lazy slob of a programmer that expects the engine to read your mind
(cluttered as that may be)?
Cheers,
Rob.
On Thu, 2005-07-14 at 18:33, Fletcher Mattox wrote:
How does one represent a MySQL table as a two dimensional array
using the column names as one of the indices? My naive attempt
went something like this:
while ($row = mysqli_fetch_assoc($result))
$table[] = $row;
but that generated this error;
Fatal error: [] operator not supported for strings
Ok. So then I try to explicitly assign each row, like this:
while ($row = mysqli_fetch_assoc($result))
$table[$i++] = $row;
While that generates no error, $table contains nothing useful when
I'm done. So then I try to assign each row and column, like this:
while ($row = mysqli_fetch_assoc($result)) {
foreach ( $row as $col = $val)
$table[$i][$col] = $val;
$i++;
}
And that got me this error:
Fatal error: Cannot use string offset as an array
So clearly my understanding of PHP arrays is lacking.
Please help.
Thanks
Fletcher
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Re: [PHP] array help
Hello Fletcher, Thursday, July 14, 2005, 11:33:36 PM, you wrote: FM while ($row = mysqli_fetch_assoc($result)) FM $table[] = $row; FM but that generated this error; FM Fatal error: [] operator not supported for strings The above WILL work providing that (1) $table hasn't been set elsewhere in your script as a string, or (2) $table has been set as an array ($table = array()) prior to being used. Best regards, Richard Davey -- http://www.launchcode.co.uk - PHP Development Services I do not fear computers. I fear the lack of them. - Isaac Asimov -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] array help
Rob writes: Did you bother to initialize $table as an array() or are you another lazy slob of a programmer that expects the engine to read your mind (cluttered as that may be)? Bingo. You seem to have no trouble reading my mind, why can't php? :) Years of perl programming has promoted a certain sloth in my character. It manifests in many different insidious forms. Ask my wife. Thanks! Fletcher lazy slob Mattox -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Array Help
I'm running into the problem of not having a server that gives me database access or ability to use files to store my data ... Yeah, I know, it sucks. If switching servers isn't an option, just pay for another one somewhere, and then re-direct or something. The time you save HAS to be worth more than the cost of cheap hosting with real service/support. -- Like Music? http://l-i-e.com/artists.htm -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Array Help
On Mon, 2005-03-14 at 18:07, Phil Neeb wrote:
Greets,
I'm running into the problem of not having a server that gives me database
access or ability to use files to store my data ... Yeah, I know, it sucks.
Anyway ... My page has a number of profiles about people involved with my
organization and all the profiles load into a set appearance. I have all
the information about each person stored in individual arrays (if there's an
easier way to do this w/o database or files, I'd love to hear it) ...
anyway, I pass a variable through the URL which causes the array info to
load, but I use an if statement for EVERYONE which makes my work way too
tedious ... The variable I pass is the same value as the name each person's
array (the variable is stored in the link) so, I'm curious if there's a way
I can use the variable as the array name and cut out those tons of if
statements.
if( isset( $$person ) )
{
$profile = $$person;
}
Where the value of $person is a string that corresponds to the profile
array name you wish to access.
Cheers,
Rob.
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RE: [PHP] Array help
[snip]
[2] = Array(
[0] = Array(
[0] = {textlinks 0_15}
[1] = {textlinks 16_30}
)
[1] = Array(
[0] = 0_15
[1] = 16_30
)
)
As you can see the third one (array [2] )for some reason is coming out
as a
double dimension array, is there any way to make it too into a single
dimension and have just one key/value like the first 2 arrays?
[/snip]
Yes.
Of course the question is, how are you builing this array?
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Re: [PHP] Array help
I've got a field in my database that contains a single numerical character (1 or 2 or 3, etc.). I need to load a different background image in one cell of a table depending upon what the number the field contains. What's the easy syntax for associating entries in the field (1 or 2 or 3, etc.) with image filenames (bkgrnd-default.gif or bkgrnd-positive.gif or bkgrnd-negative.gif, etc.) $images[1] = 'bkgrnd-default.gif'; $images[2] = 'bkgrnd-positive.gif'; $images[3] = 'bkgrnd-negative.gif'; do you query, get the result in a variable, I'll use $field img src=?php echo $images[$field];? / you could do some error checking to make sure the value in $field exists in the $images array -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Array help
You can either hard code the associations, with something like a swtich statement, or i suppose loop thru one array, adding a key value pair of the numbers = background images. Or, you could create a table called Backgrounds, give them an id which you store in the existing field of your db, and use a table join to query the background name out . Does this help any? Jason On Fri, 23 Jul 2004 16:02:06 -0500, Robb Kerr [EMAIL PROTECTED] wrote: I've got a field in my database that contains a single numerical character (1 or 2 or 3, etc.). I need to load a different background image in one cell of a table depending upon what the number the field contains. What's the easy syntax for associating entries in the field (1 or 2 or 3, etc.) with image filenames (bkgrnd-default.gif or bkgrnd-positive.gif or bkgrnd-negative.gif, etc.) Thanx, Robb -- Robb Kerr Digital IGUANA Helping Digital Artists Achieve their Dreams http://www.digitaliguana.com http://www.cancerreallysucks.org -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Array help
I've got a field in my database that contains a single numerical character (1 or 2 or 3, etc.). I need to load a different background image in one cell of a table depending upon what the number the field contains. What's the easy syntax for associating entries in the field (1 or 2 or 3, etc.) with image filenames (bkgrnd-default.gif or bkgrnd-positive.gif or bkgrnd-negative.gif, etc.) Thanx, Robb You mean like: imgBkgrnd = array(1= bkgrnd-default.gif, 2 = bkgrnd-positive.gif, 3 = bkgrnd-negative.gif); http://us2.php.net/manual/en/function.array.php -- --Matthew Sims --http://killermookie.org -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Array help
On Fri, 23 Jul 2004 14:21:42 -0700 (PDT), Matthew Sims wrote: imgBkgrnd = array(1= bkgrnd-default.gif, 2 = bkgrnd-positive.gif, 3 = bkgrnd-negative.gif); You got it... imgBkgrnd = array(1= bkgrnd-default.gif, 2 = bkgrnd-positive.gif, 3 = bkgrnd-negative.gif); imgNeeded = table['field']; imgName = ??? Now, how do I get the image name associated with the key number obtained from my table out of the array and into the variable so that I can use it later in the HTML? Thanx, Robb -- Robb Kerr Digital IGUANA -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] Array help
Robb Kerr wrote: On Fri, 23 Jul 2004 14:21:42 -0700 (PDT), Matthew Sims wrote: imgBkgrnd = array(1= bkgrnd-default.gif, 2 = bkgrnd-positive.gif, 3 = bkgrnd-negative.gif); You got it... imgBkgrnd = array(1= bkgrnd-default.gif, 2 = bkgrnd-positive.gif, 3 = bkgrnd-negative.gif); imgNeeded = table['field']; imgName = ??? Now, how do I get the image name associated with the key number obtained from my table out of the array and into the variable so that I can use it later in the HTML? Thanx, Robb -- Robb Kerr Digital IGUANA $imgBkgrnd[i] where 'i' is the number returned from your DB. HTH. Pablo -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Array help
imgBkgrnd = array(1= bkgrnd-default.gif, 2 = bkgrnd-positive.gif, 3 = bkgrnd-negative.gif); You got it... imgBkgrnd = array(1= bkgrnd-default.gif, 2 = bkgrnd-positive.gif, 3 = bkgrnd-negative.gif); imgNeeded = table['field']; imgName = ??? http://us3.php.net/array $imgBkgrnd = array(1= bkgrnd-default.gif, 2 = bkgrnd-positive.gif, 3 = bkgrnd-negative.gif); $imgNeeded = table['field']; $imgName = $imgBkgrnd[$imgNeeded]; -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Array help
imgBkgrnd = array(1= bkgrnd-default.gif, 2 = bkgrnd-positive.gif, 3 = bkgrnd-negative.gif); You got it... imgBkgrnd = array(1= bkgrnd-default.gif, 2 = bkgrnd-positive.gif, 3 = bkgrnd-negative.gif); imgNeeded = table['field']; imgName = ??? http://us3.php.net/array $imgBkgrnd = array(1= bkgrnd-default.gif, 2 = bkgrnd-positive.gif, 3 = bkgrnd-negative.gif); $imgNeeded = table['field']; $imgName = $imgBkgrnd[$imgNeeded]; Yup, just like that. You can even get away with just: $imgBkgrnd = array(1= bkgrnd-default.gif,bkgrnd-positive.gif,bkgrnd-negative.gif); as PHP will automatically assign bkgrnd-positive.gif with 2 and bkgrnd-negative.gif with 3. And can even do this: $imgName = $imgBkgrnd[$table['field']]; Though I admit it looks clunky. -- --Matthew Sims --http://killermookie.org -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Array help
because in reality I don't have just these 4 fields but 43 fields in one table that have to be taken. Select *... seems a much easier way to get it you have 43 fields in 1 table? if you are seriously considering offering hosting packages, then i'm guessing your wanting to be half professional about it. you should look into restructuring you table. do you really NEED to have all 43 fields in 1 table? i've made the same mistake myself, and believe me, it's a lot easier if you simplify your tables. you might get a little more complicated code, but it'll help you tremendously in the future. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Array help
On Monday 28 July 2003 10:19, Ryan A wrote:
After asking for help on the list Skate gave me the following code as an
example:
**
$n = 0;
$result = mysql_query( SELECT id, title, text, date FROM news ORDER BY
date DESC );
while ($rows = mysql_fetch_array($result)) {
if( $rows == ){ continue; }
extract( $rows ); ///extract our result into variables named after our
fields
$content[id][$n] = $id;
$content[title][$n] = $title;
$content[text][$n] = $text;
$content[date][$n] = $date;
$n++; //increment our number for next time...
}
**
My question is: is there anyway I can use a select * from to do the
same thing and then dump as usual to
$content[id][$n] = $id; $content[title][$n] = $title; instead of a select
id, title, text, date because in reality I don't have just these 4 fields
but 43 fields in one table that have to be taken. Select *... seems a
much easier way to get it
*** Untried and untested ***
$query = SELECT * FROM table;
$result = mysql_query($query) or die(Query failed);
$n = 0;
while ($line = mysql_fetch_assoc($result)) {
foreach ($line as $field = $value) {
$data[$field][$n] = $value;
}
$n++;
}
print_r($data);
Season to taste.
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Open Source Software Systems Integrators
* Web Design Hosting * Internet Intranet Applications Development *
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Re: [PHP] array help please
John, et al -- ...and then John Fishworld said... % % can someone give me a bit of help / walthrough the following for me ! Let's see if I can help. % this first bits is okay % $mysql query1 % result % array[cityid][cityname] % % mysql query2 % result % array[cityid][cityname] Are CityIDs unique, like US-GA-ATL and CN-QC-MON or 214365 and 214387, or is duplication possible? If the IDs are unique then adding duplicates won't cause duplicate entries. % % now what i want to do is kick out any doubles in my array and resort them % alphebetically by cityname ?! Check out array_merge and array_multisort to put the two together and sort on the second key, respectively. % % % help ! HTH HAND :-D -- David T-G * There is too much animal courage in (play) [EMAIL PROTECTED] * society and not sufficient moral courage. (work) [EMAIL PROTECTED] -- Mary Baker Eddy, Science and Health http://justpickone.org/davidtg/ Shpx gur Pbzzhavpngvbaf Qrprapl Npg! msg91646/pgp0.pgp Description: PGP signature
RE: [PHP] array help please
$mysql query1 result array[cityid][cityname] mysql query2 result array[cityid][cityname] now what i want to do is kick out any doubles in my array and resort them alphebetically by cityname ?! It's difficult to answer this question without knowing more about the context and the way you have your database laid out. In any event, sorting stuff and getting removing duplicates is probably better achieved in your mysql query than in php. Something like this would get you close (you'll have to figure it out for your database as you didn't give much to go on)... SELECT cityid, DISTINCE(cityname) FROM my_table WHERE some = 'condition' ORDER BY cityname Basically, use DISTINCT() to remove duplicates and use ORDER BY to set the display order. CYA, Dave -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] Array Help
you can just kept adding []'s $var[category][subcategory][Item] = url; -Original Message- From: Brian V Bonini [mailto:[EMAIL PROTECTED]] Sent: Tuesday, November 27, 2001 4:56 PM To: PHP Lists Subject: [PHP] Array Help How can I access the inner most info in this array? Ie, Item and url $var = array( category = array( subcategory = array( Item = url ), ) ); -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
RE: [PHP] Array HELP PLEASE
Oops, guess I posted too soon. Just figured out the problem myself (use a
do/while...). Thanks anyways.
-Original Message-
From: René Fournier [mailto:[EMAIL PROTECTED]]
Sent: Thursday, November 08, 2001 3:25 PM
To: Php-General
Subject: [PHP] Array HELP PLEASE
(Before you write RTFM, please know that I have checked www.php.net,
zend.com, phpbuilder.com, et all, and--in the eternal words of
Bono--I still
haven't found what I'm looking.)
The situation: I extract an array from a MySQL table. Code:
$models = mysql_fetch_array(mysql_query(SELECT * FROM models WHERE
lang='$lang' AND key1='data' AND key2='$series',$db));
Based on the above criteria, there should be two rows in $modelsrow, with
each row containing about twenty elements. (A two-dimensional array,
right?) All I want to do is display the contents of $models. With the
following...
for ($i = 1; $i = 20; $i++) {
echo $models[$i].p;
}
...I get just one row. How can I also display the other row? I've tried
variations of $models[1][2], but I just can't get right syntax. (Help is
much appreciated. Thanks.)
If you know of a good tutorial on multidimension arrays + mySQL,
that would
be nice too.
...Rene
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Re: [PHP] Array HELP PLEASE
read this page a little closer!
http://www.php.net/manual/en/function.mysql-fetch-array.php
the mysql_fetch_array(); does not pull all the results in one big array.
it IS only a single row of data.
try this out, it should do what you are looking to do.
$results = mysql_query(SELECT * FROM models WHERE lang='$lang' AND
key1='data' AND key2='$series',$db);
while ($models = mysql_fetch_array($results))
{
echo $models .p;
}
Jim
- Original Message -
From: René Fournier [EMAIL PROTECTED]
To: Php-General [EMAIL PROTECTED]
Sent: Thursday, November 08, 2001 2:25 PM
Subject: [PHP] Array HELP PLEASE
(Before you write RTFM, please know that I have checked www.php.net,
zend.com, phpbuilder.com, et all, and--in the eternal words of Bono--I
still
haven't found what I'm looking.)
The situation: I extract an array from a MySQL table. Code:
$models = mysql_fetch_array(mysql_query(SELECT * FROM models WHERE
lang='$lang' AND key1='data' AND key2='$series',$db));
Based on the above criteria, there should be two rows in $modelsrow, with
each row containing about twenty elements. (A two-dimensional array,
right?) All I want to do is display the contents of $models. With the
following...
for ($i = 1; $i = 20; $i++) {
echo $models[$i].p;
}
...I get just one row. How can I also display the other row? I've tried
variations of $models[1][2], but I just can't get right syntax. (Help is
much appreciated. Thanks.)
If you know of a good tutorial on multidimension arrays + mySQL, that
would
be nice too.
...Rene
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RE: [PHP] Array HELP PLEASE
Or maybe not. :-) Although I got both rows displaying, they're actually two
long to fit comfortably (w/o horizontally scrolling). So... I'd like to
flip the axis of the table, so my header row runs vertically. But with the
vagaries of html tables, I'm kinda stumped as to how to run the do/while+for
loop. This is what I've got now (more or less):
fld1fld2fld3
big red house
little bluedog
longyellow string
With this code:
===
// MODELS A
echo table border=1 cellpadding=2 cellspacing=0;
echo tr;
for ($i = 6; $i = 25; $i++) {
echo td valign=top align=left
class=deemph.stripslashes($modelsheader[$i])./td;
}
echo /tr;
do {
echo tr;
for ($i = 6; $i = 25; $i++) {
echo td valign=top align=left
class=normal.stripslashes($models[$i])./td;
}
echo /tr;
} while ($models = mysql_fetch_array($result));
echo /table;
=
This is what I WOULD LIKE to have:
fld1big little long
fld2red blueyellow
fld3house dog string
==
I can't figure how I would display element 1 of $modelsheader and every
first element of $models, then increment and loop... That is, I would like
to be able to refer to $models such that $models[0][0] referred to the first
element of the first row and, say, $models[1][0] referred to the first
element of the second row, and so on.
-Original Message-
From: René Fournier [mailto:[EMAIL PROTECTED]]
Sent: Thursday, November 08, 2001 3:39 PM
To: Php-General
Subject: RE: [PHP] Array HELP PLEASE
Oops, guess I posted too soon. Just figured out the problem myself (use a
do/while...). Thanks anyways.
-Original Message-
From: René Fournier [mailto:[EMAIL PROTECTED]]
Sent: Thursday, November 08, 2001 3:25 PM
To: Php-General
Subject: [PHP] Array HELP PLEASE
(Before you write RTFM, please know that I have checked www.php.net,
zend.com, phpbuilder.com, et all, and--in the eternal words of
Bono--I still
haven't found what I'm looking.)
The situation: I extract an array from a MySQL table. Code:
$models = mysql_fetch_array(mysql_query(SELECT * FROM models WHERE
lang='$lang' AND key1='data' AND key2='$series',$db));
Based on the above criteria, there should be two rows in
$modelsrow, with
each row containing about twenty elements. (A two-dimensional array,
right?) All I want to do is display the contents of $models. With the
following...
for ($i = 1; $i = 20; $i++) {
echo $models[$i].p;
}
...I get just one row. How can I also display the other row?
I've tried
variations of $models[1][2], but I just can't get right syntax.
(Help is
much appreciated. Thanks.)
If you know of a good tutorial on multidimension arrays + mySQL,
that would
be nice too.
...Rene
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RE: [PHP] Array HELP PLEASE
try changing these lines:
echo tr;
for ($i = 6; $i = 25; $i++) {
echo td valign=top align=left
class=normal.stripslashes($models[$i])./td;
}
echo /tr;
to:
echo trtd valign=top align=left class=normal;
for ($i = 6; $i = 25; $i++) {
echo
stripslashes($models[$i]).br;
}
echo /td/tr;
Martin T
-Original Message-
From: René Fournier [mailto:[EMAIL PROTECTED]]
Sent: Friday, November 09, 2001 10:06 AM
To: Php-General
Subject: RE: [PHP] Array HELP PLEASE
Or maybe not. :-) Although I got both rows displaying, they're actually two
long to fit comfortably (w/o horizontally scrolling). So... I'd like to
flip the axis of the table, so my header row runs vertically. But with the
vagaries of html tables, I'm kinda stumped as to how to run the do/while+for
loop. This is what I've got now (more or less):
fld1fld2fld3
big red house
little bluedog
longyellow string
With this code:
===
// MODELS A
echo table border=1 cellpadding=2 cellspacing=0;
echo tr;
for ($i = 6; $i = 25; $i++) {
echo td valign=top align=left
class=deemph.stripslashes($modelsheader[$i])./td;
}
echo /tr;
do {
echo tr;
for ($i = 6; $i = 25; $i++) {
echo td valign=top align=left
class=normal.stripslashes($models[$i])./td;
}
echo /tr;
} while ($models = mysql_fetch_array($result));
echo /table;
=
This is what I WOULD LIKE to have:
fld1big little long
fld2red blueyellow
fld3house dog string
==
I can't figure how I would display element 1 of $modelsheader and every
first element of $models, then increment and loop... That is, I would like
to be able to refer to $models such that $models[0][0] referred to the first
element of the first row and, say, $models[1][0] referred to the first
element of the second row, and so on.
-Original Message-
From: René Fournier [mailto:[EMAIL PROTECTED]]
Sent: Thursday, November 08, 2001 3:39 PM
To: Php-General
Subject: RE: [PHP] Array HELP PLEASE
Oops, guess I posted too soon. Just figured out the problem myself (use a
do/while...). Thanks anyways.
-Original Message-
From: René Fournier [mailto:[EMAIL PROTECTED]]
Sent: Thursday, November 08, 2001 3:25 PM
To: Php-General
Subject: [PHP] Array HELP PLEASE
(Before you write RTFM, please know that I have checked www.php.net,
zend.com, phpbuilder.com, et all, and--in the eternal words of
Bono--I still
haven't found what I'm looking.)
The situation: I extract an array from a MySQL table. Code:
$models = mysql_fetch_array(mysql_query(SELECT * FROM models WHERE
lang='$lang' AND key1='data' AND key2='$series',$db));
Based on the above criteria, there should be two rows in
$modelsrow, with
each row containing about twenty elements. (A two-dimensional array,
right?) All I want to do is display the contents of $models. With the
following...
for ($i = 1; $i = 20; $i++) {
echo $models[$i].p;
}
...I get just one row. How can I also display the other row?
I've tried
variations of $models[1][2], but I just can't get right syntax.
(Help is
much appreciated. Thanks.)
If you know of a good tutorial on multidimension arrays + mySQL,
that would
be nice too.
...Rene
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Re: [PHP] Array help please
On Fri, May 04, 2001 at 01:19:57PM +0100, peter.beal wrote: I'm trying to debug some software that I downloaded from the web. It seems to work fine most of the time however it occasionally crashed with database errors. When I look at the code it has a lot of array references that i don't understand e.g. $Session[clientID] most references at are of the form $arrayname[item] or $arrayname[$item] as I would expect. is the example correct code? if so what does it mean? It either does the same thing as $Sessin[clientID] The quotes are optional but recommended, because clientID could be defined as a constant and that could give unexpected results. -- Jason Stechschulte [EMAIL PROTECTED] -- : How would you disambiguate these situations? By shooting the person who did the latter. -- Larry Wall in [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
Re: [PHP] Array help please
Thanks Peter Jason Stechschulte [EMAIL PROTECTED] wrote in message [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... On Fri, May 04, 2001 at 01:19:57PM +0100, peter.beal wrote: I'm trying to debug some software that I downloaded from the web. It seems to work fine most of the time however it occasionally crashed with database errors. When I look at the code it has a lot of array references that i don't understand e.g. $Session[clientID] most references at are of the form $arrayname[item] or $arrayname[$item] as I would expect. is the example correct code? if so what does it mean? It either does the same thing as $Sessin[clientID] The quotes are optional but recommended, because clientID could be defined as a constant and that could give unexpected results. -- Jason Stechschulte [EMAIL PROTECTED] -- : How would you disambiguate these situations? By shooting the person who did the latter. -- Larry Wall in [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
Re: [PHP] Array help
On Thu, 15 Mar 2001 10:56, Chris wrote: Hi, Is there a way to do an array_pop with php3? Off the top of my head: use count to get the number of elements in the array grab element(count - 1) as the popped value Then (maybe) unset(element[count-1]) may work; if not you might have to play around with assigning all the elements bar the last of your original array to a new array. -- Please don't hit Reply to respond - use this address instead: [EMAIL PROTECTED] Local SMTP server is creatively munging domains!!! David Robley| WEBMASTER Mail List Admin RESEARCH CENTRE FOR INJURY STUDIES | http://www.nisu.flinders.edu.au/ AusEinet| http://auseinet.flinders.edu.au/ Flinders University, ADELAIDE, SOUTH AUSTRALIA -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
RE: [PHP] Array help
Hi,
Is there a way to do an array_pop with php3?
Here's some PHP 3 compatable code that works the same as array_pop:
function _array_pop($stack) {
$arrSize = count($stack);
$x = 1;
while(list($key, $val) = each($stack)) {
if($x count($stack)) {
$tmpArr[] = $val;
}
else {
$return_val = $val;
}
$x++;
}
$stack = $tmpArr;
return($return_val);
}
Enjoy :)
- James
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RE: [PHP] Array help
On 15-Mar-01 Chris wrote: Hi, Is there a way to do an array_pop with php3? unset($dirs[sizeof($dirs)-1]); // php4 array_pop(); Regards, -- Don Read [EMAIL PROTECTED] -- If you are going to sin, sin against God, not the bureaucracy. God will forgive you but the bureaucrats won't. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
Re: [PHP] Array Help
Addressed to: [EMAIL PROTECTED]
[EMAIL PROTECTED]
** Reply to note from [EMAIL PROTECTED] Fri, 23 Feb 2001 12:20:12 -0500
I've tried and tried and tried ;-)
I have this array;
$bikes = array(
"Road" = array(
"Trek" = array(
"Trek 5200" = "road.php?brand=t5200"
),
"Schwinn" = array(
"Schwinn Fastback Pro" = "road.php?brand=schfp"
),
"Moots" = array(
"VaMoots" = "road.php?brand=vamoots"
),
"Lemond" = array(
"Zurich" = "road.php?brand=zurich",
"Chambery" = "road.php?brand=chambery",
"BuenosAries" = "road.php?brand=bueno",
"Tourmalet" = "road.php?brand=tourmalet"
)
),
"Dirt" = array(
)
);
I would probably do something like:
# reset( $Bikes )
while( list( $BikeType, $Manufacturers ) = each( $bikes )) {
echo "$BikeTypeBR\n";
# reset( $Manufacturers );
while( list( $Mfr, $Models ) = each( $Manufacturers )) {
echo "nbsp;nbsp;$MfrBR\n";
# reset( $Models );
while( list( $Model, $URL ) = each( $Models )) {
echo "nbsp;nbsp;nbsp;nbsp;" .
"A href=\"$URL\"$Model/ABR\n"; }
}
}
This would give
Road
Trek
Trek -- is a link
Schwinn
Schwinn Fastback Pro -- is a link
Moots
VaMoots -- is a link
Lemond
Zurich -- is a link
Chambery -- is a link
BuenosAries -- is a link
Tourmalet -- is a link
Dirt
If you realy want
Trek
Schwinn
Moots
Lemond
Trek -- is a link
Schwinn Fastback Pro -- is a link
VaMoots -- is a link
Zurich -- is a link
Chambery -- is a link
BuenosAries -- is a link
Tourmalet -- is a link
You need to do the outer look twice, doing a reset() in it between them,
and doing the reset()s I have commented out in the example. Be aware if
you go thru the array more than once in the program it will be needed.
Rick Widmer
Internet Marketing Specialists
http://www.developersdesk.com
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Re: [PHP] Array help needed
Addressed to: CDitty [EMAIL PROTECTED]
[EMAIL PROTECTED]
** Reply to note from CDitty [EMAIL PROTECTED] Thu, 18 Jan 2001 06:58:22 -0600
I see someone else has another suggestion that might be better, using
array_count(). You learn something new every day, which is why I watch
this list...
anyway, the thing I see in your code:
while(list($index, $value) = each($dice)){ // Changed from $Input to
^
$Output[$Value]++; }
^
$Value != $value
I know my use of caps or not in this example sucks. I usually always
use Caps On Each Word for my var names, but I am trying to switch to
what appears to be the php standard, lower case everywhere. Sorry
about that...
Rick Widmer
Internet Marketing Specialists
http://www.developersdesk.com
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Re: [PHP] Array help needed
As a generalness, from what I've seen, people who just switched from ASP use somethingUppercase at first. Then forget to capitalize it a few times, and switch to completely lowercase in disgust (case-sensitivity can be quite a shock when you're not used to it). And the people who've done PHP since they started out use whatever they damn well feel like using. I use Something_Something if left ot my own devices, I have no idea why, it just happens. - Original Message - From: "Kristi Russell" [EMAIL PROTECTED] To: [EMAIL PROTECTED] Cc: [EMAIL PROTECTED] Sent: Thursday, January 18, 2001 10:40 AM Subject: Re: [PHP] Array help needed I wouldn't call it a php standard. I personally feel that readability is far more important than following anything that 'appears' to be standard. I use a format such as this for everything I name: If one word, lowercase, if more than one word: $userSelectedDate or displayCalendar(). So basically everything starts with a lowercase word and all words after that are capitalized at the beginning. Just my two cents. Kristi - Original Message - I know my use of caps or not in this example sucks. I usually always use Caps On Each Word for my var names, but I am trying to switch to what appears to be the php standard, lower case everywhere. Sorry about that... Rick Widmer Internet Marketing Specialists http://www.developersdesk.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
Re: [PHP] Array help needed
Thanks. Didn't see that myself.
Thanks for the help
Chris
At 10:28 AM 1/18/01, [EMAIL PROTECTED] wrote:
Addressed to: CDitty [EMAIL PROTECTED]
[EMAIL PROTECTED]
** Reply to note from CDitty [EMAIL PROTECTED] Thu, 18 Jan 2001
06:58:22 -0600
I see someone else has another suggestion that might be better, using
array_count(). You learn something new every day, which is why I watch
this list...
anyway, the thing I see in your code:
while(list($index, $value) = each($dice)){ // Changed from $Input to
^
$Output[$Value]++; }
^
$Value != $value
I know my use of caps or not in this example sucks. I usually always
use Caps On Each Word for my var names, but I am trying to switch to
what appears to be the php standard, lower case everywhere. Sorry
about that...
Rick Widmer
Internet Marketing Specialists
http://www.developersdesk.com
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
To contact the list administrators, e-mail: [EMAIL PROTECTED]
