Re: [PHP] Lasting syntax error when there's none
It seems the problem was caused by shared folder between host and guest systems, respectively by files’ owner and group. When I copied file to designated folder, everything started to work. However permissions and other things are the same from the point of readability and writability. It’s just that files are not shared between systems and are owned by someone else. It is strange anyway… And honestly, I see no reason why this is happening. On Apr 10, 2013, at 12:57 AM, Filip Zrůst fr...@me.com wrote: Hi Stephen, I looked there before but I’ve increased debug level after you suggestion and there’s still nothing helpful I guess. But just to be sure: Reverse proxy (“load balancer”): - error log: nothing - access log: 192.168.60.2 - - [09/Apr/2013:15:25:08 −0700] GET /offer/create HTTP/1.1 500 42008 http://localhost:8080/need/create; Mozilla/5.0 (Macintosh; Intel Mac OS X 10_8_3) AppleWebKit/536.28.10 (KHTML, like Gecko) Version/6.0.3 Safari/536.28.10 FPM pool: - error log: [09-Apr-2013 22:25:08 UTC] PHP Parse error: syntax error, unexpected $end in /mnt/hgfs/vagrant-root/temp/cache/_Nette.FileTemplate/_Offer.create.latte-76106eddfc5f39910a042247bcba6d4f.php on line 191 - access log: 127.0.0.1 - 09/Apr/2013:22:25:08 + “GET /index.php” 200 I’m not sure why FPM access log reports status code 200 but this value might mean something else. As you can see, there’s really not much in the logs. AFAIK permissions are fine, otherwise applying `touch` on those files wouldn’t resolve a thing. Timezones are also somewhat messed up, but that’s just a configuration issue I guess. I’ll try running everything on near production system instead of Vagrant which may solve the issue. But I would like know the mechanics behind this issue anyway. I’m still playing with the idea that application framework we use is behind that, but I see no reason why and why it affects different SAPIs. I also don’t get why touching resolves the problem, because it means some caching is in play. But where can it be configured? Or, is it some OS specific trickery? Don’t know yet… Best, -- frzng On Apr 9, 2013, at 5:10 PM, Stephen stephe...@rogers.com wrote: You first step is to check the log files. No matter how sure we are that there is no syntax error, always start with the logs. It could be a file permission problem. Stephen On 13-04-09 11:00 AM, fr...@me.com wrote: Hi everyone, I have some weird problem with PHP compiler or something of this sort of things. We have some PHP files which are generated during the first request to the site. These files are normally executed via PHP then. For some reason PHP thinks that they contain syntax errors (verified using HTTP request, or `php -l`). I've found out it is extremely easy to resolve this issue manually when developing - simply renaming or touching that file resolves the issue. So, apparently those generated PHP files don't contain any syntax error. However, PHP thinks they do even across different SAPIs (CLI and FPM). Since fixing the issue in this manner doesn't seam reasonable even by some script on production, I'd like to know whether do you have any suggestion what settings to tweak or what might be the problem. Here is some information about the environment (feel free to ask for more): - PHP version: 5.3.10-1ubuntu3.6 - SAPI: FPM and CLI - OS: Ubuntu 12.04 - Software: Ubuntu packages only (updated) - HTTP request handling: nginx load balancer → PHP FPM daemon - Machine: VMware Fusion (managed by Vagrant) hosted on OS X 10.8.3 Thanks, -- Stephen -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Lasting syntax error when there's none
You first step is to check the log files. No matter how sure we are that there is no syntax error, always start with the logs. It could be a file permission problem. Stephen On 13-04-09 11:00 AM, fr...@me.com wrote: Hi everyone, I have some weird problem with PHP compiler or something of this sort of things. We have some PHP files which are generated during the first request to the site. These files are normally executed via PHP then. For some reason PHP thinks that they contain syntax errors (verified using HTTP request, or `php -l`). I've found out it is extremely easy to resolve this issue manually when developing - simply renaming or touching that file resolves the issue. So, apparently those generated PHP files don't contain any syntax error. However, PHP thinks they do even across different SAPIs (CLI and FPM). Since fixing the issue in this manner doesn't seam reasonable even by some script on production, I'd like to know whether do you have any suggestion what settings to tweak or what might be the problem. Here is some information about the environment (feel free to ask for more): - PHP version: 5.3.10-1ubuntu3.6 - SAPI: FPM and CLI - OS: Ubuntu 12.04 - Software: Ubuntu packages only (updated) - HTTP request handling: nginx load balancer ? PHP FPM daemon - Machine: VMware Fusion (managed by Vagrant) hosted on OS X 10.8.3 Thanks, -- Stephen
Re: [PHP] Lasting syntax error when there's none
Am 09.04.2013 17:00, schrieb fr...@me.com: Hi everyone, I have some weird problem with PHP compiler or something of this sort of things. We have some PHP files which are generated during the first request to the site. These files are normally executed via PHP then. For some reason PHP thinks that they contain syntax errors (verified using HTTP request, or `php -l`). I've found out it is extremely easy to resolve this issue manually when developing - simply renaming or touching that file resolves the issue. So, apparently those generated PHP files don't contain any syntax error. However, PHP thinks they do even across different SAPIs (CLI and FPM). Since fixing the issue in this manner doesn't seam reasonable even by some script on production, I'd like to know whether do you have any suggestion what settings to tweak or what might be the problem. If touching resolves the error, maybe it is some kind of bytecode cache. Do you use APC or something like that? Touch the file after creating it http://www.php.net/touch Here is some information about the environment (feel free to ask for more): - PHP version: 5.3.10-1ubuntu3.6 - SAPI: FPM and CLI - OS: Ubuntu 12.04 - Software: Ubuntu packages only (updated) - HTTP request handling: nginx load balancer → PHP FPM daemon - Machine: VMware Fusion (managed by Vagrant) hosted on OS X 10.8.3 Thanks, -- Marco Behnke Dipl. Informatiker (FH), SAE Audio Engineer Zend Certified Engineer PHP 5.3 Tel.: 0174 / 9722336 e-Mail: ma...@behnke.biz Softwaretechnik Behnke Heinrich-Heine-Str. 7D 21218 Seevetal http://www.behnke.biz smime.p7s Description: S/MIME Kryptografische Unterschrift
Re: [PHP] Lasting syntax error when there's none
Hi Stephen, I looked there before but I’ve increased debug level after you suggestion and there’s still nothing helpful I guess. But just to be sure: Reverse proxy (“load balancer”): - error log: nothing - access log: 192.168.60.2 - - [09/Apr/2013:15:25:08 −0700] GET /offer/create HTTP/1.1 500 42008 http://localhost:8080/need/create; Mozilla/5.0 (Macintosh; Intel Mac OS X 10_8_3) AppleWebKit/536.28.10 (KHTML, like Gecko) Version/6.0.3 Safari/536.28.10 FPM pool: - error log: [09-Apr-2013 22:25:08 UTC] PHP Parse error: syntax error, unexpected $end in /mnt/hgfs/vagrant-root/temp/cache/_Nette.FileTemplate/_Offer.create.latte-76106eddfc5f39910a042247bcba6d4f.php on line 191 - access log: 127.0.0.1 - 09/Apr/2013:22:25:08 + “GET /index.php” 200 I’m not sure why FPM access log reports status code 200 but this value might mean something else. As you can see, there’s really not much in the logs. AFAIK permissions are fine, otherwise applying `touch` on those files wouldn’t resolve a thing. Timezones are also somewhat messed up, but that’s just a configuration issue I guess. I’ll try running everything on near production system instead of Vagrant which may solve the issue. But I would like know the mechanics behind this issue anyway. I’m still playing with the idea that application framework we use is behind that, but I see no reason why and why it affects different SAPIs. I also don’t get why touching resolves the problem, because it means some caching is in play. But where can it be configured? Or, is it some OS specific trickery? Don’t know yet… Best, -- frzng On Apr 9, 2013, at 5:10 PM, Stephen stephe...@rogers.com wrote: You first step is to check the log files. No matter how sure we are that there is no syntax error, always start with the logs. It could be a file permission problem. Stephen On 13-04-09 11:00 AM, fr...@me.com wrote: Hi everyone, I have some weird problem with PHP compiler or something of this sort of things. We have some PHP files which are generated during the first request to the site. These files are normally executed via PHP then. For some reason PHP thinks that they contain syntax errors (verified using HTTP request, or `php -l`). I've found out it is extremely easy to resolve this issue manually when developing - simply renaming or touching that file resolves the issue. So, apparently those generated PHP files don't contain any syntax error. However, PHP thinks they do even across different SAPIs (CLI and FPM). Since fixing the issue in this manner doesn't seam reasonable even by some script on production, I'd like to know whether do you have any suggestion what settings to tweak or what might be the problem. Here is some information about the environment (feel free to ask for more): - PHP version: 5.3.10-1ubuntu3.6 - SAPI: FPM and CLI - OS: Ubuntu 12.04 - Software: Ubuntu packages only (updated) - HTTP request handling: nginx load balancer → PHP FPM daemon - Machine: VMware Fusion (managed by Vagrant) hosted on OS X 10.8.3 Thanks, -- Stephen -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Preferred Syntax
On Dec 14, 2011, at 12:09 PM, Peter Ford wrote: With respect to tedd and Al, you've misread the question: the important PHP-related bit is about whether to embed variables in double-quoted strings or to concatenate them. These are only two of the options, and each has it's pros and cons. There has been (some time ago) plenty of discussion on this list about this sort of thing, including (ISTR) a timed test of the performance implications of various forms - that only really matters in big loops, of course... Horses for courses. I use whatever I feel like at the time, and mix various styles, as long as it's readable! Cheers Pete I didn't misread the OP's post. Realize that the OP provided two ways of doing the task and asked which way was best? I responded with a recommendation to remove all style elements and my recommended solution to his problem. He can either consider or not. Cheers, tedd _ t...@sperling.com http://sperling.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Preferred Syntax
On Dec 14, 2011, at 7:59 AM, Rick Dwyer wrote: Hello all. Can someone tell me which of the following is preferred and why? echo a style='text-align:left;size:14;font-weight:bold' href='/mypage.php/$page_id'$page_name/abr; echo a style='text-align:left;size:14;font-weight:bold' href='/mypage.php/.$page_id.'.$page_name./abr; When I come across the above code in line 1, I have been changing it to what you see in line 2 for no other reason than it delineates out better in BBEdit. Is this just a preference choice or is one method better than the other? --Rick Neither. My advice, take all the style elements out of the anchor tag. echo(a href='/mypage.php/$page_id'$page_name/a); Even the 'br' can be (perhaps should be) handled by css. Cheers, tedd _ t...@sperling.com http://sperling.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Preferred Syntax
BBEdit. Is this just a preference choice or is one method better than the other? As far as I know it's just preference. Your choice of editor could influence your decision; one form might be given nicer highlighting. Marc -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Preferred Syntax
On Wed, Dec 14, 2011 at 4:59 AM, Rick Dwyer rpdw...@earthlink.net wrote: Can someone tell me which of the following is preferred and why? echo a style='text-align:left;size:**14;font-weight:bold' href='/mypage.php/$page_id'$**page_name/abr; echo a style='text-align:left;size:**14;font-weight:bold' href='/mypage.php/.$page_id.**'.$page_name./abr; On Wed, Dec 14, 2011 at 9:09 AM, Peter Ford p...@justcroft.com wrote: Horses for courses. I use whatever I feel like at the time, and mix various styles, as long as it's readable! I agree with Peter here. I would bet that the string with embedded variables is parsed once when the file is loaded and turned into the same bytecode as the second form. If you are going to use the second style above, I would at least switch the quotes around so you can use the double-quotes in the HTML as that to me reads nicer and avoids the minor cost of scanning the string for embedded code. I also put spaces around the dots to make the variable concatenation easier to spot when skimming it. echo 'a style=text-align:left;size:**14;font-weight:bold href=/mypage.php/' . $page_id . '' . $page_name . '/abr'; David
Re: [PHP] Preferred Syntax
Tedd Sperling tedd.sperl...@gmail.com wrote: On Dec 14, 2011, at 7:59 AM, Rick Dwyer wrote: Hello all. Can someone tell me which of the following is preferred and why? echo a style='text-align:left;size:14;font-weight:bold' href='/mypage.php/$page_id'$page_name/abr; echo a style='text-align:left;size:14;font-weight:bold' href='/mypage.php/.$page_id.'.$page_name./abr; When I come across the above code in line 1, I have been changing it to what you see in line 2 for no other reason than it delineates out better in BBEdit. Is this just a preference choice or is one method better than the other? --Rick Neither. My advice, take all the style elements out of the anchor tag. echo(a href='/mypage.php/$page_id'$page_name/a); Even the 'br' can be (perhaps should be) handled by css. I think you may have missed the question. The OP was asking whether: text $var text or text .$var. text was preferrable. For me, I tend to use the first unless the second makes things clearer where they need to be. Syntax hilighing can easily be one of those times. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Preferred Syntax
On 11-12-14 01:10 PM, David Harkness wrote: On Wed, Dec 14, 2011 at 4:59 AM, Rick Dwyerrpdw...@earthlink.net wrote: Can someone tell me which of the following is preferred and why? echo a style='text-align:left;size:**14;font-weight:bold' href='/mypage.php/$page_id'$**page_name/abr; echo a style='text-align:left;size:**14;font-weight:bold' href='/mypage.php/.$page_id.**'.$page_name./abr; On Wed, Dec 14, 2011 at 9:09 AM, Peter Fordp...@justcroft.com wrote: Horses for courses. I use whatever I feel like at the time, and mix various styles, as long as it's readable! I agree with Peter here. I would bet that the string with embedded variables is parsed once when the file is loaded and turned into the same bytecode as the second form. If you are going to use the second style above, I would at least switch the quotes around so you can use the double-quotes in the HTML as that to me reads nicer and avoids the minor cost of scanning the string for embedded code. I also put spaces around the dots to make the variable concatenation easier to spot when skimming it. echo 'a style=text-align:left;size:**14;font-weight:bold href=/mypage.php/' . $page_id . '' . $page_name .'/abr'; +1 on the use of single quotes instead of double quotes. With a bytecode cache it's not really going to make a lick of difference, but using double quotes for HTML seems far more palatable to me. I too like to pull the variable out into code space. I also like to format my attributes for easy reading and commenting: echo 'a' .' style=text-align:left;size:**14;font-weight:bold' .' href=/mypage.php/'.$page_id.'' .'' .$page_name .'/a' .'br /'; Although, I usually only do the above for tags that have lots of attributes. Otherwise the following is more likely: echo 'div class=some-class' .'Something something' .'/div'; As I said before though, a bytecode cache with any degree of optimization should make any particular style have zero impact on runtime (beyond original parse) by optimizing the strings into a minimal set of operations. For instance 'foo'.'fee' would be coverted to 'foofee' by the bytecode engine. Cheers, Rob. -- E-Mail Disclaimer: Information contained in this message and any attached documents is considered confidential and legally protected. This message is intended solely for the addressee(s). Disclosure, copying, and distribution are prohibited unless authorized. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] Preferred Syntax
-Original Message- From: Tamara Temple [mailto:tamouse.li...@tamaratemple.com] Sent: Wednesday, December 14, 2011 1:40 PM To: Tedd Sperling Cc: Rick Dwyer; PHP-General Subject: Re: [PHP] Preferred Syntax Tedd Sperling tedd.sperl...@gmail.com wrote: On Dec 14, 2011, at 7:59 AM, Rick Dwyer wrote: Hello all. Can someone tell me which of the following is preferred and why? echo a style='text-align:left;size:14;font-weight:bold' href='/mypage.php/$page_id'$page_name/abr; echo a style='text-align:left;size:14;font-weight:bold' href='/mypage.php/.$page_id.'.$page_name./abr; When I come across the above code in line 1, I have been changing it to what you see in line 2 for no other reason than it delineates out better in BBEdit. Is this just a preference choice or is one method better than the other? --Rick Neither. My advice, take all the style elements out of the anchor tag. echo(a href='/mypage.php/$page_id'$page_name/a); Even the 'br' can be (perhaps should be) handled by css. I think you may have missed the question. The OP was asking whether: text $var text or text .$var. text was preferrable. For me, I tend to use the first unless the second makes things clearer where they need to be. Syntax hilighing can easily be one of those times. -- The key thing to remember here is that this is a preference and not a performance thing. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Preferred Syntax
On Wed, Dec 14, 2011 at 7:59 AM, Rick Dwyer rpdw...@earthlink.net wrote: Hello all. Can someone tell me which of the following is preferred and why? echo a style='text-align:left;size:**14;font-weight:bold' href='/mypage.php/$page_id'$**page_name/abr; echo a style='text-align:left;size:**14;font-weight:bold' href='/mypage.php/.$page_id.**'.$page_name./abr; When I come across the above code in line 1, I have been changing it to what you see in line 2 for no other reason than it delineates out better in BBEdit. Is this just a preference choice or is one method better than the other? I prefer sending arguments to the echo language construct (note, if you send more than one argument, you can't use parentheses.) I perceive this usage to be a clean presentation of the code's intent, easy to use in most IDE's, and it's very fast relative to the other options: echo a style='text-align:left;size:**14;font-weight:bold' href='/mypage.php/$page_id'$**page_name/abr; echo a style='text-align:left;size:**14;font-weight:bold' href='/mypage.php/.$page_id.**'.$page_name./abr; echo a style='text-align:left;size:**14;font-weight:bold' href='/mypage.php/, $page_id, ', $**page_name, /abr; And, for longer lines, I'll often break it up into separate lines by argument like below: echo a style='text-align:left;size:**14;font-weight:bold' href='/mypage.php/, $page_id, ', $**page_name, /abr; That all said, I don't change code that uses another convention, as I think it's most beneficial to stay with the established conventions in any codebase (unless you're establishing a new convention and refactoring the entire code base.) This is just my general preference, and I don't believe there is consensus as to the most appropriate. Adam -- Nephtali: A simple, flexible, fast, and security-focused PHP framework http://nephtaliproject.com
RE: [PHP] Preferred Syntax
-Original Message- From: Adam Richardson [mailto:simples...@gmail.com] Sent: Wednesday, December 14, 2011 2:19 PM To: Rick Dwyer Cc: PHP-General Subject: Re: [PHP] Preferred Syntax On Wed, Dec 14, 2011 at 7:59 AM, Rick Dwyer rpdw...@earthlink.net wrote: Hello all. Can someone tell me which of the following is preferred and why? echo a style='text-align:left;size:**14;font-weight:bold' href='/mypage.php/$page_id'$**page_name/abr; echo a style='text-align:left;size:**14;font-weight:bold' href='/mypage.php/.$page_id.**'.$page_name./abr; When I come across the above code in line 1, I have been changing it to what you see in line 2 for no other reason than it delineates out better in BBEdit. Is this just a preference choice or is one method better than the other? I prefer sending arguments to the echo language construct (note, if you send more than one argument, you can't use parentheses.) I perceive this usage to be a clean presentation of the code's intent, easy to use in most IDE's, and it's very fast relative to the other options: echo a style='text-align:left;size:**14;font-weight:bold' href='/mypage.php/$page_id'$**page_name/abr; echo a style='text-align:left;size:**14;font-weight:bold' href='/mypage.php/.$page_id.**'.$page_name./abr; echo a style='text-align:left;size:**14;font-weight:bold' href='/mypage.php/, $page_id, ', $**page_name, /abr; And, for longer lines, I'll often break it up into separate lines by argument like below: echo a style='text-align:left;size:**14;font-weight:bold' href='/mypage.php/, $page_id, ', $**page_name, /abr; That all said, I don't change code that uses another convention, as I think it's most beneficial to stay with the established conventions in any codebase (unless you're establishing a new convention and refactoring the entire code base.) This is just my general preference, and I don't believe there is consensus as to the most appropriate. Adam -- Nephtali: A simple, flexible, fast, and security-focused PHP framework http://nephtaliproject.com Adam, You are very correct, the last discussions and testing of theories caused my head to hurt!!! Neither side gained ground in testing or discussion. Having said that to me it is a preference only and not a performance enhancing or degrading factor in syntax. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Preferred Syntax
On Dec 14, 2011, at 1:53 PM, ad...@buskirkgraphics.com ad...@buskirkgraphics.com wrote: The key thing to remember here is that this is a preference and not a performance thing. Thank you... this is basically what I wanted to know. I was concerned that not breaking the VARS out separately from the echo'ed text might cause some sort of performance problem or confusion for PHP. Therefore, whenever I came across them, I was breaking them out with the . $var . technique. Will no longer do that for existing code, as it appears not necessary, but I do prefer it for readability sake... expecially in BBEdit. So will continue to write new code breaking it out. And I too prefer a single quote for PHP and a double for HTML... even though the sample I displayed showed otherwise. Thanks to all who responded. --Rick
Re: [PHP] PHP syntax - novice question
On 30/10/2011, at 1:15 PM, Phil Dobbin wrote:
Hi, all.
I’m new to the list PHP in general have a syntax question.
I have a script that calls both DB MDB2. This is the part of the script
where the error occurs:
if($type == DB)
{
$db = DB::connect($dsn);
if (PEAR::isError($db)) { die($db-getMessage()); }
$db-setFetchMode(DB_FETCHMODE_ASSOC);
$res = $db-query( 'SELECT * FROM users');
if (PEAR::isError($res)) {
die($res-getMessage());
}
echo ‘pre’;
while( $res-fetchInto( $row ) ) {
print_R($row);
}
echo ‘/pre’;
} else if($type == MDB2) {
$mdb2 = MDB2::connect($dsn);
if (PEAR::isError($mdb2)) { die($mdb2-getMessage()); }
$res = $mdb2-query( 'SELECT * FROM users');
// Always check that result is not an error
if (PEAR::isError($res)) {
die($res-getMessage());
}
echo ‘pre’;
while ($row = $res-fetchRow(MDB2_FETCHMODE_ASSOC)) {
print_R($row);
}
echo ‘/pre’;
}
###
The syntax checker calls the first instance ofecho ‘pre’; saying
unexpected
I’m at a loss to understand why...
I’m using PHP 5.3.8 PEAR 1.9.4 with MySQL 5.1.59 on Mac OS X 10.6.8.
Any help appreciated.
Cheers,
Phil.
It seems as though your editor has changed the normal quotes around pre into
pretty quotes. Change the ‘s and ’s back to '.
---
Simon Welsh
Admin of http://simon.geek.nz/
--
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Re: [PHP] PHP syntax - novice question
On 30/10/11 at 01:18, si...@welsh.co.nz (Simon J Welsh) wrote: It seems as though your editor has changed the normal quotes around pre into pretty quotes. Change the ‘s and ’s back to '. Hi, Simon. Thanks for that. Couldn’t see for looking... Cheers, Phil. -- Please consider the environment before reading this email... -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] SQL Syntax
On Tue, Jun 15, 2010 at 8:58 PM, Jan Reiter the-fal...@gmx.net wrote: Hi folks! I'm kind of ashamed to ask a question, as I haven't followed this list very much lately. This isn't exactly a PHP question, but since mysql is the most popular database engine used with php, I figured someone here might have an idea. I have 2 tables. Table A containing 2 fields. A user ID and a picture ID = A(uid,pid) and another table B, containing 3 fields. The picture ID, an attribute ID and a value for that attribute = B(pid,aid,value). Table B contains several rows for a single PID with various AIDs and values. Each AID is unique to a PID. (e.g. AID = 1 always holding the value for the image size and AID = 3 always holding a value for the image type) This is known as an EAV (Entity-Attribute-Value) design. It is usually (some would say always) a very bad idea to implement this in a relational database. and this is no exception. The goal is now to join table A on table B using pid, and selecting the rows based on MULTIPLE attributes. So the result should only contain rows for images, that relate to an attribute ID = 1 (size) that is bigger than 100 AND!!! an attribute ID = 5 that equals 'jpg'. I know that there is an easy solution to this, doing it in one query and I have the feeling, that I can almost touch it with my fingertips in my mind, but I can't go that final step, if you know what I mean. AND THAT DRIVES ME CRAZY!! The easy solution is to redesign the tables. There are a lot of reasons why this design is usually a very bad idea. For starters, what should be a simple query is anything but simple, as you have just discovered. What's more, there is no simple way (if any way at all) for your design to prevent an image from having a mime-type of 20174 or a size of 'jpg'. Andrew -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] SQL Syntax [improved SQL]
Hi, this is the solution I came up with, that is over 10 times faster than my first attemps. Tested @31,871 entries in table 'picture' and 222,712 entries in table 'picture_attrib_rel'. Old Version: SELECT * FROM picture as p INNER JOIN picture_attrib_rel as pr1 ON (p.pid = pr1.pid) INNER JOIN picture_attrib_rel as pr2 ON (p.pid = pr2.pid and pr2.val_int 1500) WHERE pr1.aid = 2 AND pr1.val_int = 1500 AND pr2.aid = 5 AND pr2.val_int 1000 Takes about 1.9 Seconds on average to return. The version with temporary tables: DROP temporary table if exists tmp_size; DROP temporary table if exists tmp_qi; CREATE temporary table tmp_size SELECT pid FROM picture_attrib_rel WHERE aid = 2 AND val_int = 1500; CREATE temporary table tmp_qi SELECT pid FROM picture_attrib_rel WHERE aid = 5 AND val_int 1000; SELECT pid,uid FROM tmp_size JOIN tmp_qi USING(pid) JOIN pictures USING(pid); DROP temporary table if exists tmp_size; DROP temporary table if exists tmp_qi; This takes 0.12 seconds to return, which is quite bearable for now. Thanks again for all your input! Regards, Jan -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] SQL Syntax [improved SQL]
-Original Message- From: Jan Reiter [mailto:the-fal...@gmx.net] Sent: Wednesday, June 16, 2010 8:55 AM To: php-general@lists.php.net Subject: Re: [PHP] SQL Syntax [improved SQL] Hi, this is the solution I came up with, that is over 10 times faster than my first attemps. Tested @31,871 entries in table 'picture' and 222,712 entries in table 'picture_attrib_rel'. Old Version: SELECT * FROM picture as p INNER JOIN picture_attrib_rel as pr1 ON (p.pid = pr1.pid) INNER JOIN picture_attrib_rel as pr2 ON (p.pid = pr2.pid and pr2.val_int 1500) WHERE pr1.aid = 2 AND pr1.val_int = 1500 AND pr2.aid = 5 AND pr2.val_int 1000 Takes about 1.9 Seconds on average to return. The version with temporary tables: DROP temporary table if exists tmp_size; DROP temporary table if exists tmp_qi; CREATE temporary table tmp_size SELECT pid FROM picture_attrib_rel WHERE aid = 2 AND val_int = 1500; CREATE temporary table tmp_qi SELECT pid FROM picture_attrib_rel WHERE aid = 5 AND val_int 1000; SELECT pid,uid FROM tmp_size JOIN tmp_qi USING(pid) JOIN pictures USING(pid); DROP temporary table if exists tmp_size; DROP temporary table if exists tmp_qi; This takes 0.12 seconds to return, which is quite bearable for now. Thanks again for all your input! Regards, Jan Jan, What do you get from this query and how fast does it execute? SELECT * FROM picture_attrib_rel par INNER JOIN pictures p ON p.pid = par.pid WHERE (par.aid = 2 AND par.val_int = 1500) OR (par.aid = 5 AND par.val_int 1000) Regards, Tommy -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] SQL Syntax
[Top-post.] You'll probably have much better luck on the MySQL General list. CC'ed on this email. On Tue, Jun 15, 2010 at 20:58, Jan Reiter the-fal...@gmx.net wrote: Hi folks! I'm kind of ashamed to ask a question, as I haven't followed this list very much lately. This isn't exactly a PHP question, but since mysql is the most popular database engine used with php, I figured someone here might have an idea. I have 2 tables. Table A containing 2 fields. A user ID and a picture ID = A(uid,pid) and another table B, containing 3 fields. The picture ID, an attribute ID and a value for that attribute = B(pid,aid,value). Table B contains several rows for a single PID with various AIDs and values. Each AID is unique to a PID. (e.g. AID = 1 always holding the value for the image size and AID = 3 always holding a value for the image type) The goal is now to join table A on table B using pid, and selecting the rows based on MULTIPLE attributes. So the result should only contain rows for images, that relate to an attribute ID = 1 (size) that is bigger than 100 AND!!! an attribute ID = 5 that equals 'jpg'. I know that there is an easy solution to this, doing it in one query and I have the feeling, that I can almost touch it with my fingertips in my mind, but I can't go that final step, if you know what I mean. AND THAT DRIVES ME CRAZY!! I appreciate your thoughts on this. Regards, Jan -- /Daniel P. Brown daniel.br...@parasane.net || danbr...@php.net http://www.parasane.net/ || http://www.pilotpig.net/ We now offer SAME-DAY SETUP on a new line of servers! -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] SQL Syntax
On Wed, 2010-06-16 at 02:58 +0200, Jan Reiter wrote: Hi folks! I'm kind of ashamed to ask a question, as I haven't followed this list very much lately. This isn't exactly a PHP question, but since mysql is the most popular database engine used with php, I figured someone here might have an idea. I have 2 tables. Table A containing 2 fields. A user ID and a picture ID = A(uid,pid) and another table B, containing 3 fields. The picture ID, an attribute ID and a value for that attribute = B(pid,aid,value). Table B contains several rows for a single PID with various AIDs and values. Each AID is unique to a PID. (e.g. AID = 1 always holding the value for the image size and AID = 3 always holding a value for the image type) The goal is now to join table A on table B using pid, and selecting the rows based on MULTIPLE attributes. So the result should only contain rows for images, that relate to an attribute ID = 1 (size) that is bigger than 100 AND!!! an attribute ID = 5 that equals 'jpg'. I know that there is an easy solution to this, doing it in one query and I have the feeling, that I can almost touch it with my fingertips in my mind, but I can't go that final step, if you know what I mean. AND THAT DRIVES ME CRAZY!! I appreciate your thoughts on this. Regards, Jan You'll be looking for something like this (untested): SELECT * FROM a LEFT JOIN b ON (a.pid = b.pid) WHERE (b.aid = 1 AND b.value 100) OR (b.aid = 3 AND b.value = 'jpg') Obviously instead of the * you may have to change to a list of field names to avoid fieldname collision on the two tables. Thanks, Ash http://www.ashleysheridan.co.uk
RE: [PHP] SQL Syntax
Thanks. That was my first attempt, too. Only this will throw out rows, that meet only one of the conditions, too. For example, I would get all pictures that are bigger than 100, regardless of type, and all pictures that are of type jpg, no matter the size. Doing it with a view would be an option, but that would immensely decrease flexibility. I guess I have to keep on cooking my brain on this ;-) I think I did it before, a few years ago when MySQL didn't support views yet, but I can't find that stuff ... @Dan: Thanks for forwarding my mail to the MySQL List! Regards, Jan From: Ashley Sheridan [mailto:a...@ashleysheridan.co.uk] Sent: Wednesday, June 16, 2010 3:09 AM To: Jan Reiter Cc: php-general@lists.php.net Subject: Re: [PHP] SQL Syntax On Wed, 2010-06-16 at 02:58 +0200, Jan Reiter wrote: Hi folks! I'm kind of ashamed to ask a question, as I haven't followed this list very much lately. This isn't exactly a PHP question, but since mysql is the most popular database engine used with php, I figured someone here might have an idea. I have 2 tables. Table A containing 2 fields. A user ID and a picture ID = A(uid,pid) and another table B, containing 3 fields. The picture ID, an attribute ID and a value for that attribute = B(pid,aid,value). Table B contains several rows for a single PID with various AIDs and values. Each AID is unique to a PID. (e.g. AID = 1 always holding the value for the image size and AID = 3 always holding a value for the image type) The goal is now to join table A on table B using pid, and selecting the rows based on MULTIPLE attributes. So the result should only contain rows for images, that relate to an attribute ID = 1 (size) that is bigger than 100 AND!!! an attribute ID = 5 that equals 'jpg'. I know that there is an easy solution to this, doing it in one query and I have the feeling, that I can almost touch it with my fingertips in my mind, but I can't go that final step, if you know what I mean. AND THAT DRIVES ME CRAZY!! I appreciate your thoughts on this. Regards, Jan You'll be looking for something like this (untested): SELECT * FROM a LEFT JOIN b ON (a.pid = b.pid) WHERE (b.aid = 1 AND b.value 100) OR (b.aid = 3 AND b.value = 'jpg') Obviously instead of the * you may have to change to a list of field names to avoid fieldname collision on the two tables. Thanks, Ash http://www.ashleysheridan.co.uk -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] SQL Syntax
On Wed, 2010-06-16 at 03:23 +0200, Jan Reiter wrote: Thanks. That was my first attempt, too. Only this will throw out rows, that meet only one of the conditions, too. For example, I would get all pictures that are bigger than 100, regardless of type, and all pictures that are of type jpg, no matter the size. Doing it with a view would be an option, but that would immensely decrease flexibility. I guess I have to keep on cooking my brain on this ;-) I think I did it before, a few years ago when MySQL didn't support views yet, but I can't find that stuff ... @Dan: Thanks for forwarding my mail to the MySQL List! Regards, Jan From: Ashley Sheridan [mailto:a...@ashleysheridan.co.uk] Sent: Wednesday, June 16, 2010 3:09 AM To: Jan Reiter Cc: php-general@lists.php.net Subject: Re: [PHP] SQL Syntax On Wed, 2010-06-16 at 02:58 +0200, Jan Reiter wrote: Hi folks! I'm kind of ashamed to ask a question, as I haven't followed this list very much lately. This isn't exactly a PHP question, but since mysql is the most popular database engine used with php, I figured someone here might have an idea. I have 2 tables. Table A containing 2 fields. A user ID and a picture ID = A(uid,pid) and another table B, containing 3 fields. The picture ID, an attribute ID and a value for that attribute = B(pid,aid,value). Table B contains several rows for a single PID with various AIDs and values. Each AID is unique to a PID. (e.g. AID = 1 always holding the value for the image size and AID = 3 always holding a value for the image type) The goal is now to join table A on table B using pid, and selecting the rows based on MULTIPLE attributes. So the result should only contain rows for images, that relate to an attribute ID = 1 (size) that is bigger than 100 AND!!! an attribute ID = 5 that equals 'jpg'. I know that there is an easy solution to this, doing it in one query and I have the feeling, that I can almost touch it with my fingertips in my mind, but I can't go that final step, if you know what I mean. AND THAT DRIVES ME CRAZY!! I appreciate your thoughts on this. Regards, Jan You'll be looking for something like this (untested): SELECT * FROM a LEFT JOIN b ON (a.pid = b.pid) WHERE (b.aid = 1 AND b.value 100) OR (b.aid = 3 AND b.value = 'jpg') Obviously instead of the * you may have to change to a list of field names to avoid fieldname collision on the two tables. Thanks, Ash http://www.ashleysheridan.co.uk I think maybe your table structure could do with a little work, as it doesn't lend itself to simple queries. It could probably be done the way you need with sub-queries, but as the tables become more populated and more people are triggering the queries, this is going to become very slow. Thanks, Ash http://www.ashleysheridan.co.uk
Re: [PHP] PHP Syntax Help - Check?
Rick Dwyer wrote:
Hello all.
I'm trying to learn PHP on the fly and I have a line of code that
contains syntax I can't find documented anywhere:
php echo check('element8');
In the above line, can someone tell me what check means?
In the above, check is a function. It is being called with parameter
'element8'.
Cheers,
Rob.
--
http://www.interjinn.com
Application and Templating Framework for PHP
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Re: [PHP] PHP Syntax Help - Check?
On Thu, Feb 25, 2010 at 12:16:08AM -0500, Robert Cummings wrote:
Rick Dwyer wrote:
Hello all.
I'm trying to learn PHP on the fly and I have a line of code that
contains syntax I can't find documented anywhere:
php echo check('element8');
In the above line, can someone tell me what check means?
In the above, check is a function. It is being called with parameter
'element8'.
This is true. But perhaps more importantly, check() is not a native PHP
function. Thus it comes from some other library or group of external
functions.
Paul
--
Paul M. Foster
--
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Re: [PHP] PHP Syntax Help - Check?
OK... external function... that would explain why I could not locate it.
Let me get right to the problem I am having with this code as someone
may be able to help directly.
I have a link on a page that opens a contact form. The link is
mypage.php?my_id=5
So on mypage.php, I capture this value with:
$my_id=$_GET['my_id'];
I understand this much. But when the end user submits this contact
form they do so to formcheck.php and if formcheck.php sees a required
field is blank, it throws it back to mypage.php with an alert. BUT, I
lose the value of the variable $my_id. SO, I created a hidden field
on mypate.php with value=?php echo $my_id; ? and on
formcheck.php, I added $my_id = $_Post['my_id'];
However, when formcheck.php returns me to mypage.php, $my_id is still
blank.
Very frustrating.
Any help determining what I am doing wrong is greatly appreciated.
Thanks.
--Rick
On Feb 25, 2010, at 12:31 AM, Paul M Foster wrote:
On Thu, Feb 25, 2010 at 12:16:08AM -0500, Robert Cummings wrote:
Rick Dwyer wrote:
Hello all.
I'm trying to learn PHP on the fly and I have a line of code that
contains syntax I can't find documented anywhere:
php echo check('element8');
In the above line, can someone tell me what check means?
In the above, check is a function. It is being called with parameter
'element8'.
This is true. But perhaps more importantly, check() is not a native
PHP
function. Thus it comes from some other library or group of external
functions.
Paul
--
Paul M. Foster
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
--
PHP General Mailing List (http://www.php.net/)
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Re: [PHP] PHP Syntax Help - Check?
if you do the redirection with header('Location: /mypage.php'),
setting a variable on formcheck.php is not enough.
if you modify the header('Location: /mypage.php') to..
header('Location: /mypage.php?my_id=5')
it will take the variable to mypage.php as $_GET['my_id]
you can not expect a variable value set in to $_POST array to reflect
on a totally different page without making it a form post (aka use of
proper headers).
i guess, it's time to you to read about session_start() method and the
array $_SESSION available in php :)
~viraj
On Thu, Feb 25, 2010 at 11:22 AM, Rick Dwyer rpdw...@earthlink.net wrote:
OK... external function... that would explain why I could not locate it.
Let me get right to the problem I am having with this code as someone may be
able to help directly.
I have a link on a page that opens a contact form. The link is
mypage.php?my_id=5
So on mypage.php, I capture this value with:
$my_id=$_GET['my_id'];
I understand this much. But when the end user submits this contact form
they do so to formcheck.php and if formcheck.php sees a required field is
blank, it throws it back to mypage.php with an alert. BUT, I lose the value
of the variable $my_id. SO, I created a hidden field on mypate.php with
value=?php echo $my_id; ? and on formcheck.php, I added $my_id =
$_Post['my_id'];
However, when formcheck.php returns me to mypage.php, $my_id is still blank.
Very frustrating.
Any help determining what I am doing wrong is greatly appreciated.
Thanks.
--Rick
On Feb 25, 2010, at 12:31 AM, Paul M Foster wrote:
On Thu, Feb 25, 2010 at 12:16:08AM -0500, Robert Cummings wrote:
Rick Dwyer wrote:
Hello all.
I'm trying to learn PHP on the fly and I have a line of code that
contains syntax I can't find documented anywhere:
php echo check('element8');
In the above line, can someone tell me what check means?
In the above, check is a function. It is being called with parameter
'element8'.
This is true. But perhaps more importantly, check() is not a native PHP
function. Thus it comes from some other library or group of external
functions.
Paul
--
Paul M. Foster
--
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To unsubscribe, visit: http://www.php.net/unsub.php
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
--
~viraj
--
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Re: [PHP] PHP Syntax Help - Check?
On Thu, Feb 25, 2010 at 4:22 PM, Rick Dwyer rpdw...@earthlink.net wrote: OK... external function... that would explain why I could not locate it. Let me get right to the problem I am having with this code as someone may be able to help directly. I have a link on a page that opens a contact form. The link is mypage.php?my_id=5 So on mypage.php, I capture this value with: $my_id=$_GET['my_id']; I understand this much. But when the end user submits this contact form they do so to formcheck.php and if formcheck.php sees a required field is blank, it throws it back to mypage.php with an alert. BUT, I lose the value of the variable $my_id. SO, I created a hidden field on mypate.php with value=?php echo $my_id; ? and on formcheck.php, I added $my_id = $_Post['my_id']; However, when formcheck.php returns me to mypage.php, $my_id is still blank. Use the right varialble for the method you're using, so if you're posting, use $_POST, if you're getting use $_GET.. Going by your example, $_GET is what you should probably be using, this is usually the default method if no method is specified on the form tag. Cheers -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] PHP Syntax Help - Check?
Hmm. OK with the help below, I am closer.
The other fields on the page are getting passed via form fields that
look like this:
input type=text value=?php echo check('element9'); ?
name=form[element9] size=40 maxlength=255
so I added:
input type=text value=?php echo check('my_id'); ?
name=form[my_id] size=40 maxlength=255
and formcheck.php has:
?php
//start the session
session_start();
//array of fields in form. (In the format field_name = field_label)
$form_fields = array(
element0 = 'Your Name:',
element1 = 'Your Email:',
element4 = 'Item Number:',
.
);
and I added:
my_id = 'My ID Is:',
And this works!
So when I am on mypage.php and I enter a value into the form field
my_id it carries over and repopulates should the form fail validation.
But upon initial load of the page from my link of mypage.php?my_id=5
(so I am not getting there via a form submit) how do I get the value
into the form field?
--Rick
On Feb 25, 2010, at 1:02 AM, viraj wrote:
if you do the redirection with header('Location: /mypage.php'),
setting a variable on formcheck.php is not enough.
if you modify the header('Location: /mypage.php') to..
header('Location: /mypage.php?my_id=5')
it will take the variable to mypage.php as $_GET['my_id]
you can not expect a variable value set in to $_POST array to reflect
on a totally different page without making it a form post (aka use of
proper headers).
i guess, it's time to you to read about session_start() method and the
array $_SESSION available in php :)
~viraj
On Thu, Feb 25, 2010 at 11:22 AM, Rick Dwyer rpdw...@earthlink.net
wrote:
OK... external function... that would explain why I could not
locate it.
Let me get right to the problem I am having with this code as
someone may be
able to help directly.
I have a link on a page that opens a contact form. The link is
mypage.php?my_id=5
So on mypage.php, I capture this value with:
$my_id=$_GET['my_id'];
I understand this much. But when the end user submits this contact
form
they do so to formcheck.php and if formcheck.php sees a required
field is
blank, it throws it back to mypage.php with an alert. BUT, I lose
the value
of the variable $my_id. SO, I created a hidden field on mypate.php
with
value=?php echo $my_id; ? and on formcheck.php, I added $my_id =
$_Post['my_id'];
However, when formcheck.php returns me to mypage.php, $my_id is
still blank.
Very frustrating.
Any help determining what I am doing wrong is greatly appreciated.
Thanks.
--Rick
On Feb 25, 2010, at 12:31 AM, Paul M Foster wrote:
On Thu, Feb 25, 2010 at 12:16:08AM -0500, Robert Cummings wrote:
Rick Dwyer wrote:
Hello all.
I'm trying to learn PHP on the fly and I have a line of code that
contains syntax I can't find documented anywhere:
php echo check('element8');
In the above line, can someone tell me what check means?
In the above, check is a function. It is being called with
parameter
'element8'.
This is true. But perhaps more importantly, check() is not a
native PHP
function. Thus it comes from some other library or group of external
functions.
Paul
--
Paul M. Foster
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
--
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--
~viraj
--
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Re: [PHP] SQL syntax?
$sql = SELECT WorkOrderID AS Work_Order_ID, DATE_FORMAT(StartDate, '%b. %e, %Y %l:%i %p') AS Start_Date, DATE_FORMAT(EndDate, '%b. %e, %Y %l:%i %p') AS End_Date, ; $sql .= Advertiser AS Advertiser_Name,AccountNum AS Account_Number, Impressions AS Ad_Impressions, ; $sql .= AdSize AS Ad_Size, CPM AS CPM_Rate, ; $sql .= ORDER BY StartDate DESC; You forgot the tables, plus you have an extra comma after CPM_Rate. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] SQL syntax?
On Fri, Dec 5, 2008 at 3:57 PM, Allan Arguelles [EMAIL PROTECTED]wrote: $sql = SELECT WorkOrderID AS Work_Order_ID, DATE_FORMAT(StartDate, '%b. %e, %Y %l:%i %p') AS Start_Date, DATE_FORMAT(EndDate, '%b. %e, %Y %l:%i %p') AS End_Date, ; $sql .= Advertiser AS Advertiser_Name,AccountNum AS Account_Number, Impressions AS Ad_Impressions, ; $sql .= AdSize AS Ad_Size, CPM AS CPM_Rate, ; $sql .= ORDER BY StartDate DESC; You forgot the tables, plus you have an extra comma after CPM_Rate. well I changed it to: $sql = SELECT workorderform.WorkOrderID AS Work_Order_ID, DATE_FORMAT(workorderform.StartDate, '%b. %e, %Y %l:%i %p') AS Start_Date, DATE_FORMAT(workorderform.EndDate, '%b. %e, %Y %l:%i %p') AS End_Date, ; $sql .= workorderform.Advertiser AS Advertiser_Name,workorderform.AccountNum AS Account_Number, workorderform.Impressions AS Ad_Impressions, ; $sql .= workorderform.AdSize AS Ad_Size, workorderform.CPM AS CPM_Rate ; $sql .= ORDER BY StartDate DESC; and got the same error
Re: [PHP] SQL syntax?
Umm.. I meant you need to put $sql .= FROM workorderform ; between these: $sql .= AdSize AS Ad_Size, CPM AS CPM_Rate, ; $sql .= ORDER BY StartDate DESC; :) Terion Miller wrote: On Fri, Dec 5, 2008 at 3:57 PM, Allan Arguelles [EMAIL PROTECTED]wrote: $sql = SELECT WorkOrderID AS Work_Order_ID, DATE_FORMAT(StartDate, '%b. %e, %Y %l:%i %p') AS Start_Date, DATE_FORMAT(EndDate, '%b. %e, %Y %l:%i %p') AS End_Date, ; $sql .= Advertiser AS Advertiser_Name,AccountNum AS Account_Number, Impressions AS Ad_Impressions, ; $sql .= AdSize AS Ad_Size, CPM AS CPM_Rate, ; $sql .= ORDER BY StartDate DESC; You forgot the tables, plus you have an extra comma after CPM_Rate. well I changed it to: $sql = SELECT workorderform.WorkOrderID AS Work_Order_ID, DATE_FORMAT(workorderform.StartDate, '%b. %e, %Y %l:%i %p') AS Start_Date, DATE_FORMAT(workorderform.EndDate, '%b. %e, %Y %l:%i %p') AS End_Date, ; $sql .= workorderform.Advertiser AS Advertiser_Name,workorderform.AccountNum AS Account_Number, workorderform.Impressions AS Ad_Impressions, ; $sql .= workorderform.AdSize AS Ad_Size, workorderform.CPM AS CPM_Rate ; $sql .= ORDER BY StartDate DESC; and got the same error
Re: [PHP] SQL syntax?
ah...I also though it was because I didn't have a statement like where adsize = adsize or something but I tried that and got the same error I have been getting ... You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'FROM workorderform, WHERE WorkOrderID = WorkOrderID ORDER BY StartDate DESC' at line 2 and why does it keep saying line 2... here is the snippet as it is now: $sql = SELECT WorkOrderID AS Work_Order_ID, DATE_FORMAT(StartDate, '%b. %e, %Y %l:%i %p') AS Start_Date, DATE_FORMAT(EndDate, '%b. %e, %Y %l:%i %p') AS End_Date, ; $sql .= Advertiser AS Advertiser_Name,AccountNum AS Account_Number, Impressions AS Ad_Impressions, ; $sql .= AdSize AS Ad_Size, CPM AS CPM_Rate, ; $sql.= FROM workorderform, ; $sql .= WHERE WorkOrderID = WorkOrderID ORDER BY StartDate DESC; On Fri, Dec 5, 2008 at 4:14 PM, Allan Arguelles [EMAIL PROTECTED]wrote: Umm.. I meant you need to put $sql .= FROM workorderform ; between these: $sql .= AdSize AS Ad_Size, CPM AS CPM_Rate, ; $sql .= ORDER BY StartDate DESC; :) Terion Miller wrote: On Fri, Dec 5, 2008 at 3:57 PM, Allan Arguelles [EMAIL PROTECTED] [EMAIL PROTECTED]wrote: $sql = SELECT WorkOrderID AS Work_Order_ID, DATE_FORMAT(StartDate, '%b. %e, %Y %l:%i %p') AS Start_Date, DATE_FORMAT(EndDate, '%b. %e, %Y %l:%i %p') AS End_Date, ; $sql .= Advertiser AS Advertiser_Name,AccountNum AS Account_Number, Impressions AS Ad_Impressions, ; $sql .= AdSize AS Ad_Size, CPM AS CPM_Rate, ; $sql .= ORDER BY StartDate DESC; You forgot the tables, plus you have an extra comma after CPM_Rate. well I changed it to: $sql = SELECT workorderform.WorkOrderID AS Work_Order_ID, DATE_FORMAT(workorderform.StartDate, '%b. %e, %Y %l:%i %p') AS Start_Date, DATE_FORMAT(workorderform.EndDate, '%b. %e, %Y %l:%i %p') AS End_Date, ; $sql .= workorderform.Advertiser AS Advertiser_Name,workorderform.AccountNum AS Account_Number, workorderform.Impressions AS Ad_Impressions, ; $sql .= workorderform.AdSize AS Ad_Size, workorderform.CPM AS CPM_Rate ; $sql .= ORDER BY StartDate DESC; and got the same error
Re: [PHP] SQL syntax?
Try this: $sql = SELECT WorkOrderID AS Work_Order_ID, DATE_FORMAT(StartDate, '%b. %e, %Y %l:%i %p') AS Start_Date, DATE_FORMAT(EndDate, '%b. %e, %Y %l:%i %p') AS End_Date, ; $sql .= Advertiser AS Advertiser_Name,AccountNum AS Account_Number, Impressions AS Ad_Impressions, ; $sql .= AdSize AS Ad_Size, CPM AS CPM_Rate ; $sql.= FROM workorderform ; $sql .= WHERE WorkOrderID = WorkOrderID ORDER BY StartDate DESC; I just removed extra commas from CPM_Rate and workorderform Terion Miller wrote: ah...I also though it was because I didn't have a statement like where adsize = adsize or something but I tried that and got the same error I have been getting ... You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'FROM workorderform, WHERE WorkOrderID = WorkOrderID ORDER BY StartDate DESC' at line 2 and why does it keep saying line 2... here is the snippet as it is now: $sql = SELECT WorkOrderID AS Work_Order_ID, DATE_FORMAT(StartDate, '%b. %e, %Y %l:%i %p') AS Start_Date, DATE_FORMAT(EndDate, '%b. %e, %Y %l:%i %p') AS End_Date, ; $sql .= Advertiser AS Advertiser_Name,AccountNum AS Account_Number, Impressions AS Ad_Impressions, ; $sql .= AdSize AS Ad_Size, CPM AS CPM_Rate, ; $sql.= FROM workorderform, ; $sql .= WHERE WorkOrderID = WorkOrderID ORDER BY StartDate DESC; On Fri, Dec 5, 2008 at 4:14 PM, Allan Arguelles [EMAIL PROTECTED]wrote: Umm.. I meant you need to put $sql .= FROM workorderform ; between these: $sql .= AdSize AS Ad_Size, CPM AS CPM_Rate, ; $sql .= ORDER BY StartDate DESC; :) Terion Miller wrote: On Fri, Dec 5, 2008 at 3:57 PM, Allan Arguelles [EMAIL PROTECTED] [EMAIL PROTECTED]wrote: $sql = SELECT WorkOrderID AS Work_Order_ID, DATE_FORMAT(StartDate, '%b. %e, %Y %l:%i %p') AS Start_Date, DATE_FORMAT(EndDate, '%b. %e, %Y %l:%i %p') AS End_Date, ; $sql .= Advertiser AS Advertiser_Name,AccountNum AS Account_Number, Impressions AS Ad_Impressions, ; $sql .= AdSize AS Ad_Size, CPM AS CPM_Rate, ; $sql .= ORDER BY StartDate DESC; You forgot the tables, plus you have an extra comma after CPM_Rate. well I changed it to: $sql = SELECT workorderform.WorkOrderID AS Work_Order_ID, DATE_FORMAT(workorderform.StartDate, '%b. %e, %Y %l:%i %p') AS Start_Date, DATE_FORMAT(workorderform.EndDate, '%b. %e, %Y %l:%i %p') AS End_Date, ; $sql .= workorderform.Advertiser AS Advertiser_Name,workorderform.AccountNum AS Account_Number, workorderform.Impressions AS Ad_Impressions, ; $sql .= workorderform.AdSize AS Ad_Size, workorderform.CPM AS CPM_Rate ; $sql .= ORDER BY StartDate DESC; and got the same error
Re: [PHP] SQL syntax?
Excellent Allan thanks so much, sometimes I think php is causing me blindness!! Terion On Fri, Dec 5, 2008 at 4:26 PM, Allan Arguelles [EMAIL PROTECTED]wrote: Try this: $sql = SELECT WorkOrderID AS Work_Order_ID, DATE_FORMAT(StartDate, '%b. %e, %Y %l:%i %p') AS Start_Date, DATE_FORMAT(EndDate, '%b. %e, %Y %l:%i %p') AS End_Date, ; $sql .= Advertiser AS Advertiser_Name,AccountNum AS Account_Number, Impressions AS Ad_Impressions, ; $sql .= AdSize AS Ad_Size, CPM AS CPM_Rate ; $sql.= FROM workorderform ; $sql .= WHERE WorkOrderID = WorkOrderID ORDER BY StartDate DESC; I just removed extra commas from CPM_Rate and workorderform Terion Miller wrote: ah...I also though it was because I didn't have a statement like where adsize = adsize or something but I tried that and got the same error I have been getting ... You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'FROM workorderform, WHERE WorkOrderID = WorkOrderID ORDER BY StartDate DESC' at line 2 and why does it keep saying line 2... here is the snippet as it is now: $sql = SELECT WorkOrderID AS Work_Order_ID, DATE_FORMAT(StartDate, '%b. %e, %Y %l:%i %p') AS Start_Date, DATE_FORMAT(EndDate, '%b. %e, %Y %l:%i %p') AS End_Date, ; $sql .= Advertiser AS Advertiser_Name,AccountNum AS Account_Number, Impressions AS Ad_Impressions, ; $sql .= AdSize AS Ad_Size, CPM AS CPM_Rate, ; $sql.= FROM workorderform, ; $sql .= WHERE WorkOrderID = WorkOrderID ORDER BY StartDate DESC; On Fri, Dec 5, 2008 at 4:14 PM, Allan Arguelles [EMAIL PROTECTED] [EMAIL PROTECTED]wrote: Umm.. I meant you need to put $sql .= FROM workorderform ; between these: $sql .= AdSize AS Ad_Size, CPM AS CPM_Rate, ; $sql .= ORDER BY StartDate DESC; :) Terion Miller wrote: On Fri, Dec 5, 2008 at 3:57 PM, Allan Arguelles [EMAIL PROTECTED] [EMAIL PROTECTED] [EMAIL PROTECTED] [EMAIL PROTECTED]wrote: $sql = SELECT WorkOrderID AS Work_Order_ID, DATE_FORMAT(StartDate, '%b. %e, %Y %l:%i %p') AS Start_Date, DATE_FORMAT(EndDate, '%b. %e, %Y %l:%i %p') AS End_Date, ; $sql .= Advertiser AS Advertiser_Name,AccountNum AS Account_Number, Impressions AS Ad_Impressions, ; $sql .= AdSize AS Ad_Size, CPM AS CPM_Rate, ; $sql .= ORDER BY StartDate DESC; You forgot the tables, plus you have an extra comma after CPM_Rate. well I changed it to: $sql = SELECT workorderform.WorkOrderID AS Work_Order_ID, DATE_FORMAT(workorderform.StartDate, '%b. %e, %Y %l:%i %p') AS Start_Date, DATE_FORMAT(workorderform.EndDate, '%b. %e, %Y %l:%i %p') AS End_Date, ; $sql .= workorderform.Advertiser AS Advertiser_Name,workorderform.AccountNum AS Account_Number, workorderform.Impressions AS Ad_Impressions, ; $sql .= workorderform.AdSize AS Ad_Size, workorderform.CPM AS CPM_Rate ; $sql .= ORDER BY StartDate DESC; and got the same error
Re: [PHP] SQL syntax?
On Fri, 2008-12-05 at 16:51 -0600, Terion Miller wrote: Excellent Allan thanks so much, sometimes I think php is causing me blindness!! Terion On Fri, Dec 5, 2008 at 4:26 PM, Allan Arguelles [EMAIL PROTECTED]wrote: Try this: $sql = SELECT WorkOrderID AS Work_Order_ID, DATE_FORMAT(StartDate, '%b. %e, %Y %l:%i %p') AS Start_Date, DATE_FORMAT(EndDate, '%b. %e, %Y %l:%i %p') AS End_Date, ; $sql .= Advertiser AS Advertiser_Name,AccountNum AS Account_Number, Impressions AS Ad_Impressions, ; $sql .= AdSize AS Ad_Size, CPM AS CPM_Rate ; $sql.= FROM workorderform ; $sql .= WHERE WorkOrderID = WorkOrderID ORDER BY StartDate DESC; I just removed extra commas from CPM_Rate and workorderform Terion Miller wrote: ah...I also though it was because I didn't have a statement like where adsize = adsize or something but I tried that and got the same error I have been getting ... You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'FROM workorderform, WHERE WorkOrderID = WorkOrderID ORDER BY StartDate DESC' at line 2 and why does it keep saying line 2... here is the snippet as it is now: $sql = SELECT WorkOrderID AS Work_Order_ID, DATE_FORMAT(StartDate, '%b. %e, %Y %l:%i %p') AS Start_Date, DATE_FORMAT(EndDate, '%b. %e, %Y %l:%i %p') AS End_Date, ; $sql .= Advertiser AS Advertiser_Name,AccountNum AS Account_Number, Impressions AS Ad_Impressions, ; $sql .= AdSize AS Ad_Size, CPM AS CPM_Rate, ; $sql.= FROM workorderform, ; $sql .= WHERE WorkOrderID = WorkOrderID ORDER BY StartDate DESC; On Fri, Dec 5, 2008 at 4:14 PM, Allan Arguelles [EMAIL PROTECTED] [EMAIL PROTECTED]wrote: Umm.. I meant you need to put $sql .= FROM workorderform ; between these: $sql .= AdSize AS Ad_Size, CPM AS CPM_Rate, ; $sql .= ORDER BY StartDate DESC; :) Terion Miller wrote: On Fri, Dec 5, 2008 at 3:57 PM, Allan Arguelles [EMAIL PROTECTED] [EMAIL PROTECTED] [EMAIL PROTECTED] [EMAIL PROTECTED]wrote: $sql = SELECT WorkOrderID AS Work_Order_ID, DATE_FORMAT(StartDate, '%b. %e, %Y %l:%i %p') AS Start_Date, DATE_FORMAT(EndDate, '%b. %e, %Y %l:%i %p') AS End_Date, ; $sql .= Advertiser AS Advertiser_Name,AccountNum AS Account_Number, Impressions AS Ad_Impressions, ; $sql .= AdSize AS Ad_Size, CPM AS CPM_Rate, ; $sql .= ORDER BY StartDate DESC; You forgot the tables, plus you have an extra comma after CPM_Rate. well I changed it to: $sql = SELECT workorderform.WorkOrderID AS Work_Order_ID, DATE_FORMAT(workorderform.StartDate, '%b. %e, %Y %l:%i %p') AS Start_Date, DATE_FORMAT(workorderform.EndDate, '%b. %e, %Y %l:%i %p') AS End_Date, ; $sql .= workorderform.Advertiser AS Advertiser_Name,workorderform.AccountNum AS Account_Number, workorderform.Impressions AS Ad_Impressions, ; $sql .= workorderform.AdSize AS Ad_Size, workorderform.CPM AS CPM_Rate ; $sql .= ORDER BY StartDate DESC; and got the same error If I run into troubles with SQL (specifically MySQL) I run the query in phpMyAdmin, which is so helpful. If you're using another SQL variant like that god-forsaken M$ SQL, then you have to use the appropriate tool to interface with the database there. It sure helps remove the SQL problems from PHP, which was your problem in this case. Ash www.ashleysheridan.co.uk -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Weird Syntax Error
-Original Message-
From: Edgar da Silva (Fly2k) [mailto:[EMAIL PROTECTED]
Sent: Thursday, November 13, 2008 9:39 AM
To: Kyle Terry
Cc: PHP General Mailing List
Subject: Re: [PHP] Weird Syntax Error
Try:
$insert = INSERT INTO release_file_upload (upl_file_name,
upl_file_type,
upl_file_size, upl_date, upl_by, upl_path, release_id) VALUES
('$filename',
'{$_SESSION['upload']['type']}', '{$_SESSION['upload']['size']}',
now(),
'$username', '$path', '$release_id');
2008/11/13 Kyle Terry [EMAIL PROTECTED]:
I keep getting this syntax error on the following string...
syntax error unexpected T_ENCAPSED_AND_WHITESPACE expecting T_STRING
or
T_VARIABLE or T_NUM_STRING
$insert = INSERT INTO release_file_upload (upl_file_name,
upl_file_type,
upl_file_size, upl_date, upl_by, upl_path, release_id) VALUES
('$filename',
'$_SESSION['upload']['type']', '$_SESSION['upload']['size']', now(),
'$username', '$path', '$release_id');
Yup... I was just about to say--you need to wrap your array references with curly braces {}.
Otherwise, I believe PHP will look for a primitive variable named $_SESSION, not an array whose
indices are upload and size.
HTH,
Todd Boyd
Web Programmer
You could also use the . operator instead and quote using the quote
method if you are using PDO.
But this is a personal style I guess.
--
Thodoris
Re: [PHP] Weird Syntax Error
On 13 Nov 2008, at 15:28, Kyle Terry wrote:
I keep getting this syntax error on the following string...
syntax error unexpected T_ENCAPSED_AND_WHITESPACE expecting T_STRING
or
T_VARIABLE or T_NUM_STRING
$insert = INSERT INTO release_file_upload (upl_file_name,
upl_file_type,
upl_file_size, upl_date, upl_by, upl_path, release_id) VALUES
('$filename',
'$_SESSION['upload']['type']', '$_SESSION['upload']['size']', now(),
'$username', '$path', '$release_id');
I can't see anything wrong with that line (except that I don't think
those variables will interpolate correctly, and you don't seem to be
escaping stuff going into your SQL which is, ya know, bad!!). Your
problem is probably on the line before, possible several lines before.
Post a bit of the surrounding code.
-Stut
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Re: [PHP] Weird Syntax Error
Hi Kyle,
The line looks fine in my text editor (SciTE).
Have you checked the line above it is properly enclosed and ended?
Michael Kubler
*G*rey *P*hoenix *P*roductions http://www.greyphoenix.biz
Kyle Terry wrote:
I keep getting this syntax error on the following string...
syntax error unexpected T_ENCAPSED_AND_WHITESPACE expecting T_STRING or
T_VARIABLE or T_NUM_STRING
$insert = INSERT INTO release_file_upload (upl_file_name, upl_file_type,
upl_file_size, upl_date, upl_by, upl_path, release_id) VALUES ('$filename',
'$_SESSION['upload']['type']', '$_SESSION['upload']['size']', now(),
'$username', '$path', '$release_id');
Re: [PHP] Weird Syntax Error
Try:
$insert = INSERT INTO release_file_upload (upl_file_name, upl_file_type,
upl_file_size, upl_date, upl_by, upl_path, release_id) VALUES ('$filename',
'{$_SESSION['upload']['type']}', '{$_SESSION['upload']['size']}', now(),
'$username', '$path', '$release_id');
2008/11/13 Kyle Terry [EMAIL PROTECTED]:
I keep getting this syntax error on the following string...
syntax error unexpected T_ENCAPSED_AND_WHITESPACE expecting T_STRING or
T_VARIABLE or T_NUM_STRING
$insert = INSERT INTO release_file_upload (upl_file_name, upl_file_type,
upl_file_size, upl_date, upl_by, upl_path, release_id) VALUES ('$filename',
'$_SESSION['upload']['type']', '$_SESSION['upload']['size']', now(),
'$username', '$path', '$release_id');
--
Kyle Terry | www.kyleterry.com
--
Abraços
Edgar Ferreira da Silva
Engenheiro de Software
Campinas - SP
(19) 8110-0733
-
Aprenda PHP, cole códigos, saiba das vagas de empregos:
http://www.manjaphp.com.br
RE: [PHP] Weird Syntax Error
-Original Message-
From: Edgar da Silva (Fly2k) [mailto:[EMAIL PROTECTED]
Sent: Thursday, November 13, 2008 9:39 AM
To: Kyle Terry
Cc: PHP General Mailing List
Subject: Re: [PHP] Weird Syntax Error
Try:
$insert = INSERT INTO release_file_upload (upl_file_name,
upl_file_type,
upl_file_size, upl_date, upl_by, upl_path, release_id) VALUES
('$filename',
'{$_SESSION['upload']['type']}', '{$_SESSION['upload']['size']}',
now(),
'$username', '$path', '$release_id');
2008/11/13 Kyle Terry [EMAIL PROTECTED]:
I keep getting this syntax error on the following string...
syntax error unexpected T_ENCAPSED_AND_WHITESPACE expecting T_STRING
or
T_VARIABLE or T_NUM_STRING
$insert = INSERT INTO release_file_upload (upl_file_name,
upl_file_type,
upl_file_size, upl_date, upl_by, upl_path, release_id) VALUES
('$filename',
'$_SESSION['upload']['type']', '$_SESSION['upload']['size']', now(),
'$username', '$path', '$release_id');
Yup... I was just about to say--you need to wrap your array references with
curly braces {}. Otherwise, I believe PHP will look for a primitive variable
named $_SESSION, not an array whose indices are upload and size.
HTH,
Todd Boyd
Web Programmer
Re: [PHP] Re: syntax question
None of the previous posts added any security...
They all ONLY provided different syntax to leave your database wide
open for abuse.
This is much safer:
$cat_name_sql = myqsl_real_escape_string($_POST['cat_name']);
$query = insert into categories (category_name) values
('$cat_name_sql');
You could/should also check for what you consider valid characters in
a 'cat_name'
if (!preg_match(|^[a-z0-9_ -]+$|i', $_POST['cat_name'])){
//tell the user their cat_name is invalid, and don't do the INSERT
}
On Mon, March 26, 2007 10:14 am, Ross wrote:
thanks.
Ross [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
Can I put post values directly into insert statements?
$query = INSERT INTO categories (category_name) VALUES
('$_POST['cat_name']);
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Re: [PHP] heredoc syntax vs Double-Quotes
Chris Kennon wrote: Hi, Not looking to start some pugilistic fray, but when is using heredoc advisable over Double-Quotes? Probably with really long strings or pages of data so you don't have to worry about quotes etc. Pretty much comes down to personal preference I think. -- Postgresql php tutorials http://www.designmagick.com/ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] heredoc syntax vs Double-Quotes
At 07:06 PM 3/15/2006, Chris Kennon wrote: when is using heredoc advisable over Double-Quotes? I love using heredoc primarily because it helps me separate logic from markup when generating HTML. The text in a heredoc expression is vanilla, no escape sequences needed, so there's less worry about typos. I find it one of the strongest features of PHP as compared to other scripting languages. Paul -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP]PHP Syntax Notation
I'm trying to expand my understanding of PHP by looking at some pre- built code modules. I don't fully understand the syntax $site-Run (); in the following code. Can someone offer a helpful explanation? ?php //define(PB_CRYPT_LINKS , 1); define(_LIBPATH,./lib/); require_once _LIBPATH . site.php; $site = new CSite(./site.xml,true); $site-Run(); ? The $site variable is an object, specifically an instance of the CSite class. Run() is a method (i.e., a function) defined within this class, so the statement $site-Run() executes that function. This is basic object oriented stuff which you may not have run across before. Hope that helps, larry -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP]PHP Syntax Notation
Lowell Herbert wrote: I'm trying to expand my understanding of PHP by looking at some pre- built code modules. I don't fully understand the syntax $site-Run (); in the following code. Can someone offer a helpful explanation? ?php //define(PB_CRYPT_LINKS , 1); define(_LIBPATH,./lib/); require_once _LIBPATH . site.php; $site = new CSite(./site.xml,true); $site-Run(); ? Run() is a method of the CSite class - you will need to look in the defination of that class to find out what it does, Mikey -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP]PHP Syntax Notation
On Sep 27, 2005, at 2:16 PM, Mikey wrote: Lowell Herbert wrote: I'm trying to expand my understanding of PHP by looking at some pre- built code modules. I don't fully understand the syntax $site-Run (); in the following code. Can someone offer a helpful explanation? ?php //define(PB_CRYPT_LINKS , 1); define(_LIBPATH,./lib/); require_once _LIBPATH . site.php; $site = new CSite(./site.xml,true); $site-Run(); ? Run() is a method of the CSite class - you will need to look in the defination of that class to find out what it does, Mikey Thanks for all the responses. I understand that $site is an instance of the class CSite, and that Run() is a function in that class. I do not understand what the operater - means, and what meaning the result of the function Run() has to $site. Clarification anyone? Thanks in advance, Lowell -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP]PHP Syntax Notation
Lowell Herbert wrote: Thanks for all the responses. I understand that $site is an instance of the class CSite, and that Run() is a function in that class. I do not understand what the operater - means, and what meaning the result of the function Run() has to $site. Clarification anyone? The operator - in this context ( $site-Run() ) sort of means the function Run() inside the object $site. The result of the function (if there is one) is thrown away, because you don't assign it to anything. If you did this then it would be assigned to something: $result = $site-Run(); -- Jasper Bryant-Greene Freelance web developer http://jasper.bryant-greene.name/ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP]PHP Syntax Notation
Lowell, The - operator was taken from the pointer operator in C. It's used to access a method or variable within an INSTANCE of an object, as opposed to the :: operator, which is used to access a static method of a class. Note the difference between a class and an object -- an object is an instance of a class. if Run() is a static method (I.E. it has no references to $this) and $site is an instance of SiteClass, the following are equivalent: $site-Run(); SiteClass::Run(); If you're still confused, I can go further into the difference between an Object and a Class. -- Sincerely, A.J. Brown BitNotion Technologies Lowell Herbert [EMAIL PROTECTED] wrote in message news:[EMAIL PROTECTED] On Sep 27, 2005, at 2:16 PM, Mikey wrote: Lowell Herbert wrote: I'm trying to expand my understanding of PHP by looking at some pre- built code modules. I don't fully understand the syntax $site-Run (); in the following code. Can someone offer a helpful explanation? ?php //define(PB_CRYPT_LINKS , 1); define(_LIBPATH,./lib/); require_once _LIBPATH . site.php; $site = new CSite(./site.xml,true); $site-Run(); ? Run() is a method of the CSite class - you will need to look in the defination of that class to find out what it does, Mikey Thanks for all the responses. I understand that $site is an instance of the class CSite, and that Run() is a function in that class. I do not understand what the operater - means, and what meaning the result of the function Run() has to $site. Clarification anyone? Thanks in advance, Lowell -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP]PHP Syntax Notation
On Sep 27, 2005, at 4:19 PM, Jasper Bryant-Greene wrote: Lowell Herbert wrote: Thanks for all the responses. I understand that $site is an instance of the class CSite, and that Run() is a function in that class. I do not understand what the operater - means, and what meaning the result of the function Run() has to $site. Clarification anyone? The operator - in this context ( $site-Run() ) sort of means the function Run() inside the object $site. The result of the function (if there is one) is thrown away, because you don't assign it to anything. If you did this then it would be assigned to something: $result = $site-Run(); Thank you for your clear explanation!!! Lowell -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP]PHP Syntax Notation
Hi As a complement to the answers you have had here I wish to ammend the following. The Run in the example is a function, and because this function is inside a Class object, it is called a method. A class is a set of variables (properties) and functions (methods) that you can create instances of. I suggest you consult the complete php documentation with user comments and examples at php.net. Available in many languages. This manual is used by many -including me- on a daily basis. Hope this helps With kind regards Andy On Tuesday 27 September 2005 22:29, Lowell Herbert wrote: On Sep 27, 2005, at 4:19 PM, Jasper Bryant-Greene wrote: Lowell Herbert wrote: Thanks for all the responses. I understand that $site is an instance of the class CSite, and that Run() is a function in that class. I do not understand what the operater - means, and what meaning the result of the function Run() has to $site. Clarification anyone? The operator - in this context ( $site-Run() ) sort of means the function Run() inside the object $site. The result of the function (if there is one) is thrown away, because you don't assign it to anything. If you did this then it would be assigned to something: $result = $site-Run(); Thank you for your clear explanation!!! Lowell -- Registered Linux User Number 379093 Now listening to [silence] amaroK::the Coolest Media Player in the known Universe! Cockroaches and socialites are the only things that can stay up all night and eat anything. Herb Caen -- -- --BEGIN GEEK CODE BLOCK- Version: 3.1 GAT/O/E$ d-(---)+ s:(+): a--(-)? C$(+++) UL$ P-(+)++ L+++$ E---(-)@ W++$ !N@ o? !K? W--(---) !O !M- V-- PS++(+++) PE--(-) Y+ PGP++(+++) t+(++) 5-- X++ R*(+)@ !tv b-() DI(+) D+(+++) G(+) e$@ h++(*) r--++ y--() -- ---END GEEK CODE BLOCK-- -- Check out these few php utilities that I released under the GPL2 and that are meant for use with a php cli binary: http://www.vlaamse-kern.com/sas/ -- pgpfMLvuAfYVj.pgp Description: PGP signature
Re: [PHP] Re: syntax error, unexpected T_STRING
George B wrote:
George B wrote:
I am trying to connect to a datbase:
mysql_select_db ('database')
or die (couldnt connect to databse)
What is wrong here?
This is the error:
Parse error: syntax error, unexpected T_STRING in file name on line 12
this code works though
the semicolon delimits a single statement (however complex).
tabs and spaces have no 'token' meaning. as in the parser doesn't give a
hoot if you write the whole scripton a single line. (I use the word statement
but I'm not sure that's the correct name for it - anyone care to add?)
if/else/else if/while/for(/etc?) have the quality that you can leave
out the braces if you are only wish to conditionally execute 1 statement
... e.g:
// run this on the cmdline or change the '\n's to 'br /'
$a = $b = $c = A; $d = array(A); $e = B;
echo \nplainfoos and foofoos:\n;
// this one you dont see (the silentfoo)
if (!in_array(str_replace($a,$b,$c),$d))
echo silentfoo\n;
// this is like the next one
if (in_array(str_replace($a,$b,$c),$d))
echo foo\n;
// this is like the previous one
if (in_array(str_replace($a,$b,$c),$d)) {
echo foo\n;
}
///
// this is not like the next one
if (in_array(str_replace($a,$b,$c),array($e)))
echo foo;
echo foo\n;
// this is not like the previous one
if (in_array(str_replace($a,$b,$c),$d)) {
echo foo;
echo foo\n;
}
and now a word from our sponsor for this evening about die()ing ...
$db = mysql_connect(localhost, myaccount, mypass) or die(Could
not connect.);
?
function yourmoney($kids = 1) { return 80 - (90 * $kids); }
function yourlife($lastWords = errr) { die(strval($s)); }
yourmoney() or yourlife(is no choice at all.);
?
(it has to be added that we are talking about those special kind of
children that are capable of 'breaking' your friends Hummer ;-))
[not a true story - just popped into my head.]
if(!$db)
die(no db);
if(!mysql_select_db(database,$db))
die(No database selected.);
die(); die(); die() ... see it doesn't even sound very nice ;-)
have fun!
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RE: [PHP] Right syntax for max value??
[snip] $getnewstitle = SELECT newstitle FROM `news` WHERE news_id = ( SELECT max( news_id ) FROM news ) ; Does anybody know the right syntax? [/snip] Yes, people on the MySQL list. Actually you do not need the sub-select here (your remote host may not have a MySQL version that supports sub-queries) $getnewstitle = SELECT MAX(news_id), newstitle FROM `news` ; -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Right syntax for max value??
twistednetadmin wrote: I am making a table at my homepage that automatically collects the latest news from mysql db. I have got it to work at my own server at home, but not at www.torewestre.com (my remote site) Local settings:(WinXP Pro) Apache 2.0.54, PHP 5.0.4 and MySQL 4.1.11 Remote settings:(Unix) Apache 1.3.27, PHP 4.3.4 and MySQL 3.23.54 This is the query that works on localhost: $getnewstitle = SELECT newstitle FROM `news` WHERE news_id = ( SELECT max( news_id ) FROM news ) ; What it does: collects the newstitle from the field where PRIMARY key(news_id) is the highest auto_increment number. This works just as excpected on localhost but not on remote. Does anybody know the right syntax? Not a php question, and you can't do this in MySQL 3.x -- John C. Nichel ÜberGeek KegWorks.com 716.856.9675 [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Right syntax for max value??
I would do $getnewstitle = SELECT newstitle FROM `news` ORDER BY news_id DESC LIMIT 1; This sorts the records by news_id and the limit 1 only returns the first record. On 6/14/05, twistednetadmin [EMAIL PROTECTED] wrote: I am making a table at my homepage that automatically collects the latest news from mysql db. I have got it to work at my own server at home, but not at www.torewestre.com http://www.torewestre.com (my remote site) Local settings:(WinXP Pro) Apache 2.0.54, PHP 5.0.4 and MySQL 4.1.11 Remote settings:(Unix) Apache 1.3.27, PHP 4.3.4 and MySQL 3.23.54 This is the query that works on localhost: $getnewstitle = SELECT newstitle FROM `news` WHERE news_id = ( SELECT max( news_id ) FROM news ) ; What it does: collects the newstitle from the field where PRIMARY key(news_id) is the highest auto_increment number. This works just as excpected on localhost but not on remote. Does anybody know the right syntax? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] Right syntax for max value??
Mysql 3.23 does not support the subquery you are using in your sql statement. Check http://dev.mysql.com/doc/mysql/en/subqueries.html for more information. Neal -Original Message- From: twistednetadmin [mailto:[EMAIL PROTECTED] Sent: Tuesday, June 14, 2005 9:44 AM To: php-general@lists.php.net Subject: [PHP] Right syntax for max value?? I am making a table at my homepage that automatically collects the latest news from mysql db. I have got it to work at my own server at home, but not at www.torewestre.com (my remote site) Local settings:(WinXP Pro) Apache 2.0.54, PHP 5.0.4 and MySQL 4.1.11 Remote settings:(Unix) Apache 1.3.27, PHP 4.3.4 and MySQL 3.23.54 This is the query that works on localhost: $getnewstitle = SELECT newstitle FROM `news` WHERE news_id = ( SELECT max( news_id ) FROM news ) ; What it does: collects the newstitle from the field where PRIMARY key(news_id) is the highest auto_increment number. This works just as excpected on localhost but not on remote. Does anybody know the right syntax? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] sql syntax problem
Merlin wrote:
SELECT c.name AS city
FROM geo_de.geodb_locations AS c, fix.user AS u
WHERE u.user_id =4 AND c.plz
LIKE %u.plz%;
I believe you want something not unlike this:
WHERE u.user_id = 4
AND c.plz LIKE concat('%', u.plz, '%')
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Re: [PHP] sql syntax problem
This is the PHP mailing list, not the SQL mailing list ;) but here is the syntax ( not tested ): SELECT c.name AS city FROM geodb_locations AS c, user AS u WHERE u.user_id = 4 AND c.plz LIKE u.plz; Hello everybody, I am trying to create a sql query with php and I do have a syntax problem with the mysql query. One row is called plz and I would like to search for a value inside that with a like statement. Problem is, the system takes the u.plz as a character not as a table element: LIKE %u.plz% Has anybody an idea how the correct sytnax is? I am lost here. Thank you in advance, Merlin PS: This is the complete statement: SELECT c.name AS city FROM geo_de.geodb_locations AS c, fix.user AS u WHERE u.user_id =4 AND c.plz LIKE %u.plz%; -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Re: Syntax problem - dynamic static member access
Jason Barnett wrote:
Jake, as you probably already know you usually have to give the class
name when attempting to get a static variable, i.e.
YourClassName::$bob;
You *can* dynamically refer to a static class variable from within an
object without knowing the name of the class; this is what self is
for. i.e.
class YourClassName {
function getStatic($var) {
return self::$var;
}
}
Hi Jason,
Thanks for your response. :)
That doesnt seem to be an answer at all applicable to my question tho...
Ofcourse i realise you need to give the class name when attempting to
get a static variable...
heh... im sure it would be interesting referencing a class without its
name :)
Yours Sincerely
Jake Press
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Re: [PHP] Re: Syntax problem - dynamic static member access
Thanks Tul, Okay, so its a limitation :( I cant find the line of posts, any idea on it - or possible keywords i can google with ? I'd like to find out the reasons behind why this a fixed limitation Best Regards Jake Press M. Sokolewicz wrote: hi, it's a limitation, and not allowed in PHP. There was a whole line of posts about it in internals. - Tul -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] PHP5 syntax question
Gerard Samuel wrote: I dont see it in the documentation, but I've seen samples of code using something to the effect of - $foo-method1()-method2() It's called object dereferencing and its not implemented in PHP4. It is avalaible in PHP5. If method1() returns an instance of some object then the returned object method2() will be called. I think PHP5 docs are not full yet. Wasnt there supposed to be namespaces in PHP5? PHP documentation doesnt even mentions them... -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] PHP5 syntax question
On Fri, 05 Nov 2004 09:19:58 +0200, Simas Toleikis [EMAIL PROTECTED] wrote: I think PHP5 docs are not full yet. Wasnt there supposed to be namespaces in PHP5? PHP documentation doesnt even mentions them... No, they were cut, and it is highly doubtful they will show up any time before php6. -- Using M2, Opera's revolutionary e-mail client: http://www.opera.com/m2/ http://www.smempire.org -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] heredoc syntax
Adil wrote: anyone know why heredoc syntax might not work with php5/apache installed. I can't get even the simplest strings in heredoc syntax to work and I've tried just cutting and pasting other peoples stuff in that syntax as well, and still no luck thx. Adil. Heredoc syntax is pretty rigid and it's easy to have it wrong invisibly. $varname = END Text of string END; The first END must be at the end of the line, nothing after it, not even a blank space. The last END must be at the beginning of the line, not before it, not even a blank space. Janet -- Janet Valade -- janet.valade.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] heredoc syntax
* Janet Valade [EMAIL PROTECTED]: Adil wrote: anyone know why heredoc syntax might not work with php5/apache installed. I can't get even the simplest strings in heredoc syntax to work and I've tried just cutting and pasting other peoples stuff in that syntax as well, and still no luck Heredoc syntax is pretty rigid and it's easy to have it wrong invisibly. ^ That's the key -- whitespace is invisible to the naked eye typically. $varname = END Text of string END; The first END must be at the end of the line, nothing after it, not even a blank space. The last END must be at the beginning of the line, not before it, not even a blank space. And don't forget that the last END must be followed by a semi-colon ONLY, no other characters on that line... ;-) -- Matthew Weier O'Phinney | mailto:[EMAIL PROTECTED] Webmaster and IT Specialist | http://www.garden.org National Gardening Association| http://www.kidsgardening.com 802-863-5251 x156 | http://nationalgardenmonth.org -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] what syntax error are they talking about?
[snip] Error message: You have an error in your SQL syntax. Check the manual that corresponds to your MySQL server version for the right syntax to use near '(20),username text (10),password varchar (10))' at line 1 [/snip] We'd have to see the whole query. Can you echo $sql and give us the whole thing? [snip] A separate question: What is the meaning of the . on each end of the .$_POST[field_length][$i]. ? [/snip] Those are concatenation operators. If I say foo . bar it becomes foobar -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] if syntax using multiple conditions
Thanks! And, *wow* yes I just did try php2asp. Pretty good translation, although a few things need adjusting, it seems to do a remarkable job. I'll definitely have to play with it some more. :) -Brian -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] if syntax using multiple conditions
Brian Anderson wrote:
What is the proper syndax in an if statement for containing multiple conditions?
both examples you have given are valid but their logic is slightly
different.
example:
if ( condition1 condition2 ) {
dothis;
}
if ( condition1 (condition2 || condition3) ) {
dothis;
}
I am trying to translate this from asp to php:
how about using the asp2php program?
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Re: [PHP] if syntax using multiple conditions
On Mon, 13 Sep 2004 11:32:00 -0500, Brian Anderson
[EMAIL PROTECTED] wrote:
What is the proper syndax in an if statement for containing multiple conditions?
example:
if ( condition1 condition2 ) {
dothis;
}
if ( condition1 (condition2 || condition3) ) {
dothis;
}
Looks good to me.
I am trying to translate this from asp to php:
If WhichAction = 7 And (InStr(filename, \) Or InStr(filename, /) Or
(Left(filename, 1) = chr(32)) Or InStr(filename, *) Or InStr(filename, ?) Or
InStr(filename, |) Or InStr(filename, ) Or InStr(filename, ) Or
InStr(filename, :) Or InStr(filename, ) Or InStr(filename, ')) Then
messages = Bad filename
filename =
WhichAction = 0
End If
I'd use a regular expression so as to match all those symbols with one
command. Check out eregi() or maybe strstr().
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Re: [PHP] if syntax using multiple conditions
Brian Anderson wrote:
What is the proper syndax in an if statement for containing multiple conditions?
example:
if ( condition1 condition2 ) {
dothis;
}
if ( condition1 (condition2 || condition3) ) {
dothis;
}
Both are valid. First example will validate if both condition1 and
condition2 evaluate to true (they're set, and not null or false, etc.).
Second example will validate if condition1 evaluates to true AND EITHER
condition2 OR condition3 evaluate to true
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Re: [PHP] TAB Syntax
I know I'm probably going to get flamed for this but it is only a development site but I am having some trouble getting the syntax right for using the tab when echoing information. My current command is: print_r(Host: $hostbrUser: $userbrPassword: $password); I've tried: print_r(Host: \t$hostbrUser: $userbrPassword: $password); and god knows what else with the brackets etc. Any ideas...? I think your understanding of print_r is a little fuzzy. Try just using print. --Matthew Sims --http://killermookie.org -- - Michael Mason Arras People www.arraspeople.co.uk - -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Class Syntax Help or Globals issue
Thanks very much!
Marek Kilimajer wrote:
bob pilly wrote:
Hi All
I am new to classes and are trying to work out whether
they will make my coding experience easier. I have
written the following test class which is trying to
take three variables from a mssql query and add them
as variables in a new class. This isnt working as i
keep getting an error that says ;
Warning: Missing argument 1 for app() in
/var/www/htdocs/temp3.php on line 13
Warning: Missing argument 2 for app() in
/var/www/htdocs/temp3.php on line 13
Warning: Missing argument 3 for app() in
/var/www/htdocs/temp3.php on line 13
the code .
//a basic class to store basic appointment details in
class App {
var $name;
var $the_date;
var $result;
//add values to the variables
This is the function's constructor, it's called when you create a
class instance using new operator:
function App($app1name,$appdate,$appresult){
$this-name=$app1name;
$this-the_date=$appdate;
$this-result=$appresult;
}
}
$query=select app1name,appdate,appresult from
appresult where appdate 'jun 01 2004';
$qresult=mssql_query($query,$numero);//get the number
of rows returned
$numrow=mssql_num_rows($qresult);
if($row=mssql_fetch_array($qresult)){
$i=0;
do{
$j=$i;
So instead of:
$j= new App;
$j-App($row[app1name],$row['appdate'],$row['appresult']);
you have to suply the arguments to the contructor this way:
$j= new App($row[app1name],$row['appdate'],$row['appresult']);
}
while($row=mssql_fetch_array($qresult));
}
?
Is there a syntax problem with the way im trying to
pass the value of the $row array cells into the class
function?
I have looked at the online manual for classes but
find it a bit confusing on how to input and extract
variables data in classes. Any help or pointing in the
direction of some good docs would be greatly
appreciated!
thanks for any help in advance.
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Re: [PHP] Class Syntax Help or Globals issue
bob pilly wrote:
Hi All
I am new to classes and are trying to work out whether
they will make my coding experience easier. I have
written the following test class which is trying to
take three variables from a mssql query and add them
as variables in a new class. This isnt working as i
keep getting an error that says ;
Warning: Missing argument 1 for app() in
/var/www/htdocs/temp3.php on line 13
Warning: Missing argument 2 for app() in
/var/www/htdocs/temp3.php on line 13
Warning: Missing argument 3 for app() in
/var/www/htdocs/temp3.php on line 13
the code .
//a basic class to store basic appointment details in
class App {
var $name;
var $the_date;
var $result;
//add values to the variables
This is the function's constructor, it's called when you create a class
instance using new operator:
function App($app1name,$appdate,$appresult){
$this-name=$app1name;
$this-the_date=$appdate;
$this-result=$appresult;
}
}
$query=select app1name,appdate,appresult from
appresult where appdate 'jun 01 2004';
$qresult=mssql_query($query,$numero);//get the number
of rows returned
$numrow=mssql_num_rows($qresult);
if($row=mssql_fetch_array($qresult)){
$i=0;
do{
$j=$i;
So instead of:
$j= new App;
$j-App($row[app1name],$row['appdate'],$row['appresult']);
you have to suply the arguments to the contructor this way:
$j= new App($row[app1name],$row['appdate'],$row['appresult']);
}
while($row=mssql_fetch_array($qresult));
}
?
Is there a syntax problem with the way im trying to
pass the value of the $row array cells into the class
function?
I have looked at the online manual for classes but
find it a bit confusing on how to input and extract
variables data in classes. Any help or pointing in the
direction of some good docs would be greatly
appreciated!
thanks for any help in advance.
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Re: [PHP] PHP syntax error or javascript mistake?
Kenn Murrah wrote: I'm trying to open a new window on top of the current window, and it does that, but the original (bottom) window changes to read Object Window ... I can get back to the original with the Back button but of course don't want to ask that of the user ... I simply want a new window to appear on top of the original, after which the user can close the top window and be back where he started Oh, here's the code: echo a href='javascript:window.open(\$fg_id\,\\,\height=400,width=300,left=80,top=80,scrollbars=1\)'; Browser follows the link, you need to return false after opening the window: a href='javascript:window.open(\$fg_id\,\\,\height=400,width=300,left=80,top=80,scrollbars=1\); return false;' -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] hard(?) syntax problem
On Tuesday, November 04, 2003 8:12 AM Adam wrote:
I want to access a value of an array by key, but the array is not a
variable - it is a constant.
How do I do it?
I tried
$value = PL_ORT[$key];
, but this doesn't work (parse error)...
I even tried
$value = {PL_ORT[$key]};
Hi Adam.
As per the manual, constants may only evaluate to scalar values. Are
you sure what you're trying to do is even possible here?
If you try to define a constant as an array, as follows:
?php
define('something',array('foo','bar'));
?
the following error results:
Warning: Constants may only evaluate to scalar values in
c:\phpdev\www\constant.php on line 2.
The valid types for use within constants are:
- boolean
- integer
- floating-point number (float)
- string
Cheers,
Pablo
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Re: [PHP] custom syntax highlighting in html-kit
This is not possible... yet. I would like this feature too, but it has been
addressed a few times on the newsgroups at chami.com.
You can check the newsgroups out at
http://www.chami.com/html-kit/newsgroups/.
As far as I know, this feature is on Chami's long-term to-do list.
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Web Developer
Parts Canada
- Original Message -
From: Chris W. Parker [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Wednesday, August 20, 2003 2:55 PM
Subject: [PHP] custom syntax highlighting in html-kit
Hello,
I'd REALLY REALLY like to be able to modify the syntax highlighting in
html-kit. Is this possible?
Right now in PHP if you have a line like:
echo this is the text i want to echo.;
Everything between the two 's will be gray. I don't necessarily want to
change that color (that parts easy) want I do want to do is highlight {
} within . For example a line like:
echo this is the text and this is the value: {$arra[0]}.;
I want everything starting at { and ending with } to be a different
color, maybe yellow, or orange.
Anyone have any clues? I've been googling and searching chami's site but
can't find a definitive yes or no.
Thanks!
Chris.
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Re: [PHP] Unknown Syntax
Hello, This is a reply to an e-mail that you wrote on Fri, 11 Jul 2003 at 13:55, lines prefixed by '' were originally written by you. Does anybody recognize this: !== with 2 '=' Ive known != to mean not equal to but i'm just looking at someone elses script and they use this instead. Does anyone know if this works or any problems with it? Cheers This compares type as well as content, for example: 2 !== 2 evaluates to true but 2 != 2 evaluates to false David. -- phpmachine :: The quick and easy to use service providing you with professionally developed PHP scripts :: http://www.phpmachine.com/ Professional Web Development by David Nicholson http://www.djnicholson.com/ QuizSender.com - How well do your friends actually know you? http://www.quizsender.com/ (developed entirely in PHP) -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Unknown Syntax
On Fri, Jul 11, 2003 at 01:56:46PM +0100, Chris Morrow wrote: Does anybody recognize this: !== with 2 '=' Ive known != to mean not equal to but i'm just looking at someone elses script and they use this instead. Does anyone know if this works or any problems with it? Cheers The syntax means 'not true' You can use it after a strpos operation to distinguish 'string was not found' from 'string was found at position 0'. -- Jim Kaufman mailto:[EMAIL PROTECTED] Linux Evangelistcell: 612-481-9778 public key 0x6D802619 fax: 952-937-9832 http://www.linuxforbusiness.net -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Unknown Syntax
Chris Morrow wrote: Does anybody recognize this: !== with 2 '=' Ive known != to mean not equal to but i'm just looking at someone elses script and they use this instead. Does anyone know if this works or any problems with it? Not identical. Negative ===. http://us2.php.net/manual/en/language.operators.comparison.php -- The above message is encrypted with double rot13 encoding. Any unauthorized attempt to decrypt it will be prosecuted to the full extent of the law. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] correct syntax
-Original Message- From: Harry Wiens [mailto:[EMAIL PROTECTED] Sent: 25 June 2003 09:04 What would be the correct syntax? 1. $_SESSION[test] 2. $_SESSION['test'] 3. $_SESSION[test] All of these are correct depending on the context. What's your context? Cheers! Mike - Mike Ford, Electronic Information Services Adviser, Learning Support Services, Learning Information Services, JG125, James Graham Building, Leeds Metropolitan University, Beckett Park, LEEDS, LS6 3QS, United Kingdom Email: [EMAIL PROTECTED] Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] PHP syntax colouring on documentation
check phpinfo()... it lists the colors that highlight_file()/show_source() uses. Better yet, here's the values: highlight.bg#FF #FF highlight.comment #FF9900 #FF9900 highlight.default #CC #CC highlight.html #00 #00 highlight.keyword #006600 #006600 highlight.string#CC #CC HTH. Pete Randum Ian wrote: Hi there, I am currently writing a number of guides on PHP, SMARTY and Syntax and I was wondering if there is a set schema for the colouring of code within these guides. Is there a website that can give me an idea? Regards, Ian. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] PHP syntax colouring on documentation
Good stuff thanks Pete. check phpinfo()... it lists the colors that highlight_file()/show_source() uses. Better yet, here's the values: highlight.bg #FF #FF highlight.comment #FF9900 #FF9900 highlight.default #CC #CC highlight.html#00 #00 highlight.keyword #006600 #006600 highlight.string #CC #CC HTH. Pete Randum Ian wrote: Hi there, I am currently writing a number of guides on PHP, SMARTY and Syntax and I was wondering if there is a set schema for the colouring of code within these guides. Is there a website that can give me an idea? Regards, Ian. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] PHP syntax colouring on documentation
Randum Ian wrote: Hi there, I am currently writing a number of guides on PHP, SMARTY and Syntax and I was wondering if there is a set schema for the colouring of code within these guides. Is there a website that can give me an idea? Regards, Ian. RTFM http://www.php.net/manual/en/function.highlight-string.php http://www.php.net/manual/en/function.highlight-file.php -- Burhan Khalid phplist[at]meidomus[dot]com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] PHP syntax colouring on documentation
Randum Ian wrote: [ snip ] RTFM http://www.php.net/manual/en/function.highlight-string.php http://www.php.net/manual/en/function.highlight-file.php Hi Burhan, I wasn't wanting to highlight anything like that, I am writing a guide which will be printed out in colour and wanted to highlight the code appropriately. Thanks for replying. Regards, Ian. Apologies Ian -- I am still on first cup of coffee. I don't suppose there is a standard scheme for highlighting such matters, but I think that since its dealing with PHP, you would be better off sticking with the default color highlighting that comes with PHP. To find out what colors are used for what, check your friendly php.ini :) Again, I apologize for my rash post earlier. -- Burhan Khalid phplist[at]meidomus[dot]com Don't worry about it mate, I understand how p* off experienced coders can get with the young ones! I have had a look at the phpinfo() file and it has come up with what it uses to highlight code so I might as well just use that! Regards, Ian. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Array syntax not covered in documentation
I want to do the following: $u=preg_replace(/[^$chars]/e,'%.unpack(H2, $0)', $u); However, as you know, unpack returns an array. I tried this instead: $u=preg_replace(/[^$chars]/e,'%.(unpack(H2, $0)[])', $u); but that isn't syntactically correct. I know that this is possible to remedy using a user function but I do this kind of thing very often (grab the contents of an array value in one line of code) and want to be able to do it without splitting it into multiple lines. Is that possible? What exactly are you trying to do? Can you explain it and give some same strings and output you're looking to achieve? ---John Holmes... -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Array syntax not covered in documentation
maybe implode?
$u=preg_replace(/[^$chars]/e,%.implode('',unpack(H2, $0)), $u);
adrian porter wrote:
I want to do the following:
$u=preg_replace(/[^$chars]/e,'%.unpack(H2, $0)', $u);
However, as you know, unpack returns an array. I tried this instead:
$u=preg_replace(/[^$chars]/e,'%.(unpack(H2, $0)[])', $u);
but that isn't syntactically correct. I know that this is possible to
remedy using a user function but I do this kind of thing very often
(grab the contents of an array value in one line of code) and want to
be able to do it without splitting it into multiple lines. Is that
possible?
thanks.
adrian
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Re: [PHP] PHP_SELF syntax
What you might try is removing the single-quotes from around PHP_SELF.
Before: $_SERVER['PHP_SELF']
After: $_SERVER[PHP_SELF]
Another note: as far as I can tell you do not need the braces ({}) to
enclose a variable within a double-quoted string. I may be wrong, but
nothing I've read advocates doing this, and I've never had a problem
with my code when I've written it this way.
Jason
Ernest E Vogelsinger wrote:
At 00:55 24.02.2003, Peter Gumbrell said:
[snip]
Could someone tell me why this code prompts a parse error. I have tried it
several different way. The statement is called from within a function:
print form method=\POST\ name=\update_workshop\
action=\$_SERVER['PHP_SELF']\\n;
[snip]
When using array elements within a string you must enclose it in curly
brackets, like this:
print form method=\POST\ name=\update_workshop\
action=\{$_SERVER['PHP_SELF']}\\n;
HTH,
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Re: [PHP] PHP_SELF syntax
What you might try is removing the single-quotes from around PHP_SELF.
Before: $_SERVER['PHP_SELF']
After: $_SERVER[PHP_SELF]
Another note: as far as I can tell you do not need the braces ({}) to
enclose a variable within a double-quoted string. I may be wrong, but
nothing I've read advocates doing this, and I've never had a problem
with my code when I've written it this way.
Just so there's no confusion, with double quoted strings, you can do it one
of two ways.
echo The value is {$_SERVER['PHP_SELF']};
or
echo The value is $_SERVER[PHP_SELF];
Neither is any more right than the other. You can always end the string and
concatinate the variable, too...
echo The value is . $_SERVER['PHP_SELF'];
In that case, you should always use quotes around the key, single or double,
doesn't matter much.
---John Holmes...
[snip]
Could someone tell me why this code prompts a parse error. I have tried
it
several different way. The statement is called from within a function:
print form method=\POST\ name=\update_workshop\
action=\$_SERVER['PHP_SELF']\\n;
[snip]
When using array elements within a string you must enclose it in curly
brackets, like this:
print form method=\POST\ name=\update_workshop\
action=\{$_SERVER['PHP_SELF']}\\n;
HTH,
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Re: [PHP] PHP_SELF syntax
At 01:42 24.02.2003, Jason Lange spoke out and said:
[snip]
What you might try is removing the single-quotes from around PHP_SELF.
Before: $_SERVER['PHP_SELF']
After: $_SERVER[PHP_SELF]
This is only valid if the array is contained within a double quoted string
- it will generate a parser warning outside a string (undefind constant
PHP_SELF).
Another note: as far as I can tell you do not need the braces ({}) to
enclose a variable within a double-quoted string. I may be wrong, but
nothing I've read advocates doing this, and I've never had a problem
with my code when I've written it this way.
The docs on strings
(http://www.php.net/manual/en/language.types.string.php) clearly states this:
If a dollar sign ($) is encountered, the parser will greedily take as much
tokens as possible to form a valid variable name. Enclose the variable name
in curly braces if you want to explicitly specify the end of the name.
$fruits = array('strawberry' = 'red', 'banana' = 'yellow');
// Works but note that this works differently outside string-quotes
echo A banana is $fruits[banana].;
// Works
echo A banana is {$fruits['banana']}.;
// Works but PHP looks for a constant named banana first
// as described below.
echo A banana is {$fruits[banana]}.;
// Won't work, use braces. This results in a parse error.
echo A banana is $fruits['banana'].;
// Works
echo A banana is . $fruits['banana'] . .;
--
O Ernest E. Vogelsinger
(\) ICQ #13394035
^ http://www.vogelsinger.at/
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Re: [PHP] PHP_SELF syntax
on 24/02/03 11:42 AM, Jason Lange ([EMAIL PROTECTED]) wrote:
What you might try is removing the single-quotes from around PHP_SELF.
Before: $_SERVER['PHP_SELF']
After: $_SERVER[PHP_SELF]
Another note: as far as I can tell you do not need the braces ({}) to
enclose a variable within a double-quoted string. I may be wrong, but
nothing I've read advocates doing this, and I've never had a problem
with my code when I've written it this way.
Wrapping vars in braces helps clarify the code, and can avoid problems like:
?
$price = '44.99';
echo Price: US$$priceeach;// probably won't work
echo Price: US${$price}each; // will work for sure
echo Price: US$ . $price . each;// will work, but not my pref
?
I've also found it helps with things like:
?
echo a href='{$_SERVER['PHP_SELF']}'click/a;
?
... where normally the single quotes would cause confusion, or require the
href to be wrapped in escaped double quotes.
In otherwords, wrapping $vars in {braces} provides clarity to both the PHP
parser, and to the writer, IMHO.
Justin
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Re: [PHP] PHP_SELF syntax
At 00:55 24.02.2003, Peter Gumbrell said:
[snip]
Could someone tell me why this code prompts a parse error. I have tried it
several different way. The statement is called from within a function:
print form method=\POST\ name=\update_workshop\
action=\$_SERVER['PHP_SELF']\\n;
[snip]
When using array elements within a string you must enclose it in curly
brackets, like this:
print form method=\POST\ name=\update_workshop\
action=\{$_SERVER['PHP_SELF']}\\n;
HTH,
--
O Ernest E. Vogelsinger
(\)ICQ #13394035
^ http://www.vogelsinger.at/
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Re: [PHP] PHP_SELF syntax
On Sun, 23 Feb 2003 18:55:06 -0500, you wrote:
Could someone tell me why this code prompts a parse error. I have tried it
several different way. The statement is called from within a function:
print form method=\POST\ name=\update_workshop\
action=\$_SERVER['PHP_SELF']\\n;
echo ('form method=POST name=update_workshop action=' .
$_SERVER['PHP_SELF'] . '' . \n);
works for me (moved the variable outside the string). I first thought it
might be a scope problem, but $_SERVER is apparently a superglobal so
that's not it.
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Re: [PHP] POP3 ... syntax error
I'm aware it's not a PHP problem, I was trying to be nice by helping figure out what the problem was in his raw communication. On Wed, 2003-02-05 at 15:24, Jason Wong wrote: On Wednesday 05 February 2003 23:32, Adam Voigt wrote: How about some code? On Wed, 2003-02-05 at 10:21, Christian Ista wrote: Hello, I'm trying to access pop3 server via PHP code. I can establish the connection, send the USER command (I receive the +OK answer). After that I sent the PASS command but I receive the answer -ERR syntax error. I don't understand why syntax error. Do you have an idea ? No need for code, it's not a php problem. Google for pop3 commands to find out how to talk to pop3 servers. -- Jason Wong - Gremlins Associates - www.gremlins.biz Open Source Software Systems Integrators * Web Design Hosting * Internet Intranet Applications Development * -- Search the list archives before you post http://marc.theaimsgroup.com/?l=php-general -- /* The Beatles: Paul McCartney's old back-up band. */ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- Adam Voigt ([EMAIL PROTECTED]) The Cryptocomm Group My GPG Key: http://64.238.252.49:8080/adam_at_cryptocomm.asc signature.asc Description: This is a digitally signed message part
Re: [PHP] POP3 ... syntax error
How about some code? On Wed, 2003-02-05 at 10:21, Christian Ista wrote: Hello, I'm trying to access pop3 server via PHP code. I can establish the connection, send the USER command (I receive the +OK answer). After that I sent the PASS command but I receive the answer -ERR syntax error. I don't understand why syntax error. Do you have an idea ? Christian, --- Christian Ista (AFAS member) Hosting - Dedicated server http://www.bee-hosting.com http://www.your-softwares.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- Adam Voigt ([EMAIL PROTECTED]) The Cryptocomm Group My GPG Key: http://64.238.252.49:8080/adam_at_cryptocomm.asc signature.asc Description: This is a digitally signed message part
Re: [PHP] POP3 ... syntax error
On Wednesday 05 February 2003 23:32, Adam Voigt wrote: How about some code? On Wed, 2003-02-05 at 10:21, Christian Ista wrote: Hello, I'm trying to access pop3 server via PHP code. I can establish the connection, send the USER command (I receive the +OK answer). After that I sent the PASS command but I receive the answer -ERR syntax error. I don't understand why syntax error. Do you have an idea ? No need for code, it's not a php problem. Google for pop3 commands to find out how to talk to pop3 servers. -- Jason Wong - Gremlins Associates - www.gremlins.biz Open Source Software Systems Integrators * Web Design Hosting * Internet Intranet Applications Development * -- Search the list archives before you post http://marc.theaimsgroup.com/?l=php-general -- /* The Beatles: Paul McCartney's old back-up band. */ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] PHP Syntax - mail statement
Probably just a problem with register_globals
Try:
$contents = {$_REQUEST['firstname']}, {$_REQUEST['lastname']}, {$_REQUEST['email']};
Marco
php|architect - The magazine for PHP Professionals
The monthly worldwide magazine dedicated to PHP programmers
Check us out on the web at http://www.phparch.com
On Sat, 2002-11-23 at 18:13, Michael Sharp wrote:
I have a html form that has just 3 fields and each are defined as
name=firstname, name=lastname, and name=email . The action is
calling a sendmail.php file and the method is POST. Here is the contents
of sendmail.php:
?php
$to = [EMAIL PROTECTED];
$subject = Form Submission;
$contents = $firstname, $lastname, $email;
mail ($to, $subject, $contents);
header (Location: http://probsd.org/rlewis/thankyou.txt;);
?
When submitting the form, mail gets sent to [EMAIL PROTECTED] with the
subject defined in sendmail.php, but the contents simply displayes both of
the commas from $contents = and not $firstname, $lastname, and $email.
Syntax error or what?
Michael
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Re: [PHP] if syntax
This will only work if you have a single line of code after the else and
if. At least that is my understanding of all languages :)
J
Alexander Ross [EMAIL PROTECTED]
07/10/2002 08:25 AM
To: [EMAIL PROTECTED]
cc:
Subject:[PHP] if syntax
I know this is correct:
if ($something)
{
...
}
else
{
...
}
But I recently saw someone use this instead:
if($something):
...
else:
...
Is that also correct?? No brackets needed?
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Re: [PHP] if syntax
There are no brackets necessary if you only have one line of code to be executed in
the case. For example:
if($var == 1)
echo Var equals 1;
} else {
echo Var does not equal 1;
}
But this is not valid:
if($var == 1)
echo Var equals ;
echo 1;
} else {
}
HTH
Martin
Alexander Ross [EMAIL PROTECTED] 07/10/02 10:25AM
I know this is correct:
if ($something)
{
...
}
else
{
...
}
But I recently saw someone use this instead:
if($something):
...
else:
...
Is that also correct?? No brackets needed?
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Re: [PHP] if syntax
read here for the alternative control structures in php
http://www.php.net/manual/en/control-structures.alternative-syntax.php
- Original Message -
From: [EMAIL PROTECTED]
To: Alexander Ross [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Sent: Wednesday, July 10, 2002 7:28 AM
Subject: Re: [PHP] if syntax
This will only work if you have a single line of code after the else and
if. At least that is my understanding of all languages :)
J
Alexander Ross [EMAIL PROTECTED]
07/10/2002 08:25 AM
To: [EMAIL PROTECTED]
cc:
Subject:[PHP] if syntax
I know this is correct:
if ($something)
{
...
}
else
{
...
}
But I recently saw someone use this instead:
if($something):
...
else:
...
Is that also correct?? No brackets needed?
--
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Re: [PHP] if syntax
OK...
This is another easy question that everyone has an answer for.
Here's mine
:D
the if statement has many ways of being formed.
1 line code: (Echo or exit command)
if(empty($Variable))
exit;
else
echo Variable exists
Multiple line code:
if(empty($Variable))
{
header(Location: Here.com);
exit;
}
else
{
echo Valid variable;
eixt;
}
Combined:
if(empty($Variable))
echo Variable empty;
else
{
Header(Location: Here.com);
exit;
}
or the other alternative
(empty($Variable)) ? echo Empty : echo Contains Something;
[EMAIL PROTECTED] wrote in message
news:OFF48BDDD0.BCC82414-ON87256BF2.004F65C2-87256BF2.004F6811@blackhillscor
p.com...
This will only work if you have a single line of code after the else and
if. At least that is my understanding of all languages :)
J
Alexander Ross [EMAIL PROTECTED]
07/10/2002 08:25 AM
To: [EMAIL PROTECTED]
cc:
Subject:[PHP] if syntax
I know this is correct:
if ($something)
{
...
}
else
{
...
}
But I recently saw someone use this instead:
if($something):
...
else:
...
Is that also correct?? No brackets needed?
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Re: [PHP] if syntax
Alexander, The thing to do is to try it yourself. Yes its OK for single statements (I assume the colon after the $condition): is a typo. The first two examples in the manual (Chapter 11, if) show this syntax though not with else. HTH Chris Alexander Ross wrote: if($something): ... else: ... Is that also correct?? No brackets needed? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
