chronos.phenomena chronos.phenomena at gmail.com writes:
This is really annoying me... when I click R application icon it brings
already opened session in the focus and it DOESN'T open new session
any ideas?
In Leopard from a terminal, you can try
open -n /Applications/R.app
to
Hi Julia,
I would really recommend reading a book on R. A good option might by the
Introductory statistics with R by Peter Dalgaard, or the MASS (Modern
Applied Statistics with S) book. The advantage of a book is that it
presents a coherent overview, saving you time to wade through the
Manuel Jesús López Rodríguez wrote:
Dear all,
I would like to know how could I execute a sequence or orders with just a
function, i.e, that just typing the function name, R gives me all the
parameters I want (for instance, if I want to see the summary, the standard
deviation, the number of
My apologies, that must have been a copypaste error and the essential
argument got lost. I can reproduce it now under R-2.10.0 both Windows
and Linux.
Please report your findings to the package maintainer who might be able
to debug this under Linux (probably easier than under Windows).
Ok, i reported it.
thanks for trying it out again.
Am 30. November 2009 11:06 schrieb Uwe Ligges
lig...@statistik.tu-dortmund.de:
My apologies, that must have been a copypaste error and the essential
argument got lost. I can reproduce it now under R-2.10.0 both Windows and
Linux.
Please
Dear all,
I cannot find a function which would allow drawing hist and density on the
same graph.
x - seq(1,40,1)
y - 2*x+1+5*rnorm(length(x))
hist(y,freq = FALSE)
plot(density(y))
thanks a lot for the help
[[alternative HTML version deleted]]
The 'NMF' package implements a number of standard algorithms to perform
Nonnegative Matrix Factorization.
It also provides a flexible framework to easily test and develop new
methods, as well as a layer to work with Bioconductor objects.
The package is available from CRAN. Feedbacks are
The lattice function panel.identify() allows the labeling of mouse-selected
plot points.
But ... how does one save the resulting plot? E.g., to png() or pdf()
Thank you!
# example code
library(lattice)
xyplot(rnorm(10,0,1)~rnorm(10,0,1))
trellis.focus() # left click on plot panel to select
On 30-Nov-09 11:09:12, Trafim wrote:
Dear all,
I cannot find a function which would allow drawing hist and density
on the same graph.
x - seq(1,40,1)
y - 2*x+1+5*rnorm(length(x))
hist(y,freq = FALSE)
plot(density(y))
thanks a lot for the help
plot() initiates a completely new plot,
Hi,
I have an experiment with 5 treatments, of which 2 with 10
repetitions and 2 with 7 replications.
I conducted the test of Bartlett step-by-step and compared
with the value calculated directly by the R and the values
are different.
Anyone know tell me why?
#---
n =
This is a mixed question, between theory and practice.
I have a dataset with a continous variable grouped by a 33 levels
factor. After having log-tranformed my original data I can assume the
normality of my data but I have two strong departures from the basic
assumptions for anova and t tests:
I've forgot to cite the Games and Howell procedure, which some
literature (eg in Pairwise Multiple Comparison Procedures: A Review
[1]) referes as a good one for uneual samples and non homogeneus
variance. Yet I haven't found an implementation for R...
giovanni
[1]
These are some good resources for learning R:
Quick-R - http://www.statmethods.net/
From Data to Graphics - http://zoonek2.free.fr/UNIX/48_R/03.html
UCLA Resources to help you learn and use R - http://www.ats.ucla.edu/stat/r/
Good luck!
--
View this message in context:
We don't do homework.
On Sun, Nov 29, 2009 at 11:21 PM, dovii dovii...@yahoo.com wrote:
So, I need some serious help with an R project. The project essentially
consists of some problems that have to be analyzed to decide the correct
statistical test to use, and then correctly use R to answer
Julia Cains wrote:
Dear R helpers,
Almost 15 days back I have become member of this very active and wonderful
group. So far I have been only raising queries and in turn got them solved too
and I really thank for the spirit this group member show when it comes to the
guidance.
I wish to
Hello,
the only thing I found to fit a sin/cos is s.th like lm(a~cos+sin) But
this is not what I want.
I have a magnitude which is sinusoidal with offset and it doesn't start
at phi=0.
The data is:
angle-c(0,10,20,30,40,50,60,70,80,90,100,110,120,130,140,150,160,170,180)
Voltage-c(-45.07,
Thanks a lot Ted!
I use R help but also cannot find how to expand the graph, i.e. sometimes
the top of it is cut for some reason. Maybe there are some limits imposed on
y axes, but cannot find it.
On Mon, Nov 30, 2009 at 12:27 PM, Ted Harding
ted.hard...@manchester.ac.ukwrote:
On 30-Nov-09
Good morning Markus,
Perhaps ?nls might be useful in this case.
HTH,
Jorge
On Mon, Nov 30, 2009 at 7:19 AM, Markus Häge wrote:
Hello,
the only thing I found to fit a sin/cos is s.th like lm(a~cos+sin) But
this is not what I want.
I have a magnitude which is sinusoidal with offset and it
Trafim,
If you are plotting more than one variables on the same plot e.g. by using
the lines() or points() function, then the limits of the X and Y axes are
set based on the first variable you plot. So, you would have to set the xlim
and ylim to the limits of the variable with the widest range,
Hello,
I am a newbie using the JRI java interface to R. Actually I have just
tried to use the examples provided in the rJava distribution.
Well, I have a problem when loading the jri native library (see
bellow), indeed I have tried both to compile the library and to use the
pre-compiled
Chek the topic Second y-axis --- alternative to par(new= which was
discussed recently - in that one, there are a few examples, how that can be
achieved.
Essentially, you have to make sure, that the xlims of the hist() and
plot(density()) are the same, and you have to use the par(new=TRUE) (or
I plot only
hist(y,freq = FALSE)
lines(density(y))
and the graph of density goes higher then hist, but i didn't find any lim
parameter for y axes for lines command.
Thanks a lot
On Mon, Nov 30, 2009 at 1:51 PM, Hrishi Mittal hrishimit...@gmail.comwrote:
Trafim,
If you are plotting more
Hi,
You probably want to use this mailing list instead :
http://mailman.rz.uni-augsburg.de/mailman/listinfo/stats-rosuda-devel
Romain
On 11/30/2009 02:04 PM, Javier Gil-Quijano wrote:
Hello,
I am a newbie using the JRI java interface to R. Actually I have just
tried to use the examples
Jorge Ivan Velez wrote:
Good morning Markus,
Perhaps ?nls might be useful in this case.
Or consult a compendium and realize that both formulas actually fit the
same class of shifted sinusoidals... It holds that
cos(v+phi) = cos phi cos v - sin phi sin v
so you can fairly easily find A and
Hi R-users,
I can not replicate the result for marginal effects from multinomial logistic
regression stata output below
(http://www.ats.ucla.edu/stat/stata/Library/longutil.htm) The dataset can be
found here http://www.ats.ucla.edu/stat/stata/webbooks/logistic/hsblog.dta
PART OF STATA OUTPUT
Silvano wrote:
Hi,
I have an experiment with 5 treatments, of which 2 with 10 repetitions
and 2 with 7 replications.
I conducted the test of Bartlett step-by-step and compared with the
value calculated directly by the R and the values are different.
Anyone know tell me why?
The first term
Hi everybody,
I am looking for the possibility in R to estimate joint density, just for
example:
x - seq(1,40,1)
y - 2*x+1+5*rnorm(length(x))
y1 - x^3+.5*rnorm(length(x))
Is there a way to approximate the density function s.t. I will later be able
to calculate f(Y=y, Y1=y1)
Thanks a lot
Dear R Help team,
I'm having some problems running a discriminant analysis (MASS:lda)
over my data, i have a grouping variable coming from a previous
cluster analysis and several discriminators (78 actually). I'm trying
to run lda using column index as independent variable in the formula
like
Seems that I found it - kde2d
On Mon, Nov 30, 2009 at 2:36 PM, Trafim rdapam...@gmail.com wrote:
Hi everybody,
I am looking for the possibility in R to estimate joint density, just for
example:
x - seq(1,40,1)
y - 2*x+1+5*rnorm(length(x))
y1 - x^3+.5*rnorm(length(x))
Is there a way to
Trafim,
If you are plotting more than one variables on the same plot
e.g. by using the lines() or points() function, then the limits
of the X and Y axes are set based on the first variable you plot.
So, you would have to set the xlim and ylim to the limits of the
variable with the widest
Error in firstlib(which.lib.loc, package) :
Tcl/Tk support is not available on this system
Error : package 'tcltk' could not be loaded
Ubuntu 9.10
I have both the 8.5 and 8.4 tcl and tk regular and dev libraries
installed. I need both of these because some of my GIS software
requires the 8.4
I have installed
apt-get build-dep r-base - also
On Mon, Nov 30, 2009 at 7:58 AM, stephen sefick ssef...@gmail.com wrote:
Error in firstlib(which.lib.loc, package) :
Tcl/Tk support is not available on this system
Error : package 'tcltk' could not be loaded
Ubuntu 9.10
I have both the 8.5
stephen sefick wrote:
Error in firstlib(which.lib.loc, package) :
Tcl/Tk support is not available on this system
Error : package 'tcltk' could not be loaded
Ubuntu 9.10
I have both the 8.5 and 8.4 tcl and tk regular and dev libraries
installed. I need both of these because some of my
Silvano wrote:
Hi,
I have an experiment with 5 treatments, of which 2 with 10 repetitions
and 2 with 7 replications.
I conducted the test of Bartlett step-by-step and compared with the
value calculated directly by the R and the values are different.
Anyone know tell me why?
Yes. Is
Unfortunately, it doesn't work.
Can you, please, help me with it?
Thanks a lot.
On Mon, Nov 30, 2009 at 2:53 PM, Trafim rdapam...@gmail.com wrote:
Seems that I found it - kde2d
On Mon, Nov 30, 2009 at 2:36 PM, Trafim rdapam...@gmail.com wrote:
Hi everybody,
I am looking for the
Can someone please help me with this
I am trying to use this model because I have temporal replication in my data
results-read.table(file=file.choose(),header=T)
attach(results)
names(results)
results-na.omit(results)
library(nlme)
library(lattice)
Hello,
I am a newbie using the JRI java interface to R. Actually I have just
tried to use the examples provided in the rJava distribution.
Well, I have a problem when loading the jri native library (see
bellow), indeed I have tried both to compile the library and to use the
pre-compiled
Dear all,
I cannot find a function which would allow drawing hist and density on the
same graph.
x - seq(1,40,1)
y - 2*x+1+5*rnorm(length(x))
hist(y,freq = FALSE)
plot(density(y))
thanks a lot for the help
[[alternative HTML version deleted]]
Thanks Ben for your reply,
I would very much appreciate if you could share your code. That would be great!
Sebastien
PS: As suggested, I will forward this email to John Nash.
Sébastien Bihorel pomchip at free.fr writes:
*
** Dear R-users,
**
** I am trying to port to R something that I wrote
It's easy with the ggplot2 package
set.seed(1234)
dataset - data.frame(x = seq(1,40,1))
dataset$Response - with(dataset, 2*x+1+5*rnorm(length(x)))
library(ggplot2)
ggplot(dataset, aes(x = Response)) + geom_histogram(aes(y =
..density..)) + geom_density(colour = red)
HTH,
Thierry
Dear all,
I have decided after much deliberation to use backward elimination and
forward selection to produce a multivariate model. Having read about the
problems with choosing selection values I have chosen to base my decisions
of inclusion and exclusion on the AIC and am consequently using the
On Nov 30, 2009, at 9:30 AM, Trafim wrote:
Unfortunately, it doesn't work.
Can you, please, help me with it?
In order to support the notion of a 2 dimensional distribution, you
need a function that depends on ... 2 dimensions. All you have at the
moment are two different one-dimensional
jerry83 chaohan1983 at yahoo.com writes:
Jerry, see below:
Hi John,
Thanks A LOT for your reply and the code. What I want to do is to include the
ggobi display window to the widget
window setup by me. I tried add before but it said can not do it for
GGobiScatterplotDisplay. Do you have
I've just realised that this is a very silly post as I can't read!!! The
output in the anova is the excluded variables - very sorry!
Laura
2009/11/30 Laura Bonnett l.j.bonn...@googlemail.com
Dear all,
I have decided after much deliberation to use backward elimination and
forward selection
Hi,
I am building a regression tree (method=anova) by using rpart package
and as a final result I get the final leaves characterized by
different means and standard deviations for the dependent variable.
However, differently from the classification tree for categorical
variables I cannot find a
You are right.
I brought this example just to see how to use its with two time series. In
reality I have price process and returns, and I need conditional density.
Will highly appreciate your help.
I found function kde2d but cannot understand how to call for the values of
the matrix.
On Mon,
Hi,
I am building a regression tree (method=anova) by using rpart package
and as a final result I get the final leaves characterized by
different means and standard deviations for the dependent variable.
However, differently from the classification tree for categorical
variables I cannot find a
Dear Julia,
Welcome. It is good that you wish to learn more about R.
R has certainly become very vast in the last few years. Do you wish to
learn R for a particular reason (financial analyses, multivariate,
prediction/classification, genetics)? You might get more targeted
reading materials,
Also what if the grid matrix is not squared? How can I then find this kernel
density matrix/
Thanks a lot.
On Mon, Nov 30, 2009 at 4:56 PM, Trafim rdapam...@gmail.com wrote:
You are right.
I brought this example just to see how to use its with two time series. In
reality I have price process
On 30 November 2009 at 15:12, Peter Dalgaard wrote:
| stephen sefick wrote:
| Error in firstlib(which.lib.loc, package) :
|Tcl/Tk support is not available on this system
| Error : package 'tcltk' could not be loaded
|
| Ubuntu 9.10
| I have both the 8.5 and 8.4 tcl and tk regular and
Working with an NxMxO sized matrix, currently I can do this in my code:
if (max(colSums(array)) = number)
But to get an equivalent result using rowSums, I have to do:
for (i in 1:10)
{
if (max(rowSums(array[,,i])) = number)
}
I'm running both in a much larger loop that loops millions of
Hi,
I am building a regression tree (method=anova) by using rpart package
and as a final result I get the final leaves characterized by
different means and standard deviations for the dependent variable.
However, differently from the classification tree for categorical
variables I cannot find a
I used the archives, but I didn't use the FAQs. I removed the
compiled version- and all other R versions. I reinstalled through the
repository, and everything works fine. Sorry for the inconvenience.
regards,
Stephen
On Mon, Nov 30, 2009 at 10:14 AM, Dirk Eddelbuettel e...@debian.org wrote:
Hi Robert and Wai-Kuan,
I'd be interested as well. I see in the JMP Scripting Book that there appear
to be 3 possibilities (all in Chapter 11-at least for version 8):
1. using a JMP DataFeed object
2. using sockets
3. OLE automation
Sockets with something like RServe may be the way to go. I have
On Nov 30, 2009, at 11:02 AM, Henry Thorogood wrote:
Hi,
I'm doing some work with linear models, and I've scaled my data
using the
scale(dataset) function. This was great at removing the skew, but I
now
can't perform the Box Cox transformation on the data set (using the
boxcox(dataset)
Hello,
I am trying to import data from an SQLite database to R.
Unfortunately, I seem to get wrong data when I try to import very large
numbers.
For example:
I look at the database via SQLiteStudio(v.1.1.3) and I see the following
values:
OrderID Day TimeToclose
1
The scale function seems to have tackled the skew, just looking at the
boxplots for the data.
The boxcox function I'm using is boxcox(), from MASS. I've looked through
the help page, but I don't think (from what I can see) there's a way to make
the boxcox function handle the negative values,
Hi Julia,
I'm also a newcomer to R and to this listserv (in the past two weeks). One
book that was recommended to me, and has been extraordinarily helpful in
learning how to really make use of R, is A Beginner's Guide to R, which
focuses on data entry/import, data manipulation, functions, and
It appears that you were reading the number in as an integer and not
numeric. The value that you are seeing (-596864072) is the numeric
value trucated to 32 bit. The number would have been in hex
(6DC6C93B8) but dropping the leading '6' you will get the result as a
32 bit integer. Check your
Julia,
I can vouch for the 'Statistical Analysis in R'. Very good book, I learnt R
from it. The other one to look at is Spoetry. It solves a lot of problem for me.
Paul
http://www.burns-stat.com/pages/spoetry.html
On 30 Nov 2009, at 17:17, Ben Seligman wrote:
Hi Julia,
I'm also a
Does this
max(apply(yourArray, 3, rowSums))
give you what you want?
-Peter Ehlers
Will Carr wrote:
Working with an NxMxO sized matrix, currently I can do this in my code:
if (max(colSums(array)) = number)
But to get an equivalent result using rowSums, I have to do:
for (i in 1:10)
{
if
On Nov 30, 2009, at 11:47 AM, Henry Thorogood wrote:
The scale function seems to have tackled the skew, just looking at the
boxplots for the data.
The boxcox function I'm using is boxcox(), from MASS.
I'm puzzled. When I look at the boxcox function in MASS it says:
Arguments
object a
Great! Have managed to shift my dataset to positive. Thanks for all your
help. Henry.
2009/11/30 David Winsemius dwinsem...@comcast.net
On Nov 30, 2009, at 11:47 AM, Henry Thorogood wrote:
The scale function seems to have tackled the skew, just looking at the
boxplots for the data.
The
On Nov 30, 2009, at 11:20 AM, Trafim wrote:
Sorry, maybe I confused everybody with what I want.
I have time process X_k, and corresponding returns process R_k
I am interesting in f(r|x), which I can find knowing f(r,x) and
f(x). I know
the latter I need the first.
How can I apploximate
Or maybe aperm() is faster:
max(colSums(aperm(yourArray, c(2,1,3
-Peter Ehlers
Peter Ehlers wrote:
Does this
max(apply(yourArray, 3, rowSums))
give you what you want?
-Peter Ehlers
Will Carr wrote:
Working with an NxMxO sized matrix, currently I can do this in my code:
if
On Nov 30, 2009, at 11:10 AM, Will Carr wrote:
Working with an NxMxO sized matrix, currently I can do this in my
code:
What are M, N, and O? All the same magnitude?
if (max(colSums(array)) = number)
But to get an equivalent result using rowSums, I have to do:
for (i in 1:10)
{
if
One of the reasons we ask for a *reproducible* example, is that
it allows us to test our ideas and make sure that all the details
are taken care of. Here's a reproducible example that may help
solve your problem:
lx100=c(1,1,1,.8,.5,.4,.2,0)
day100=c(0,1,2,3,4,5,6,7)
Let me begin stating that I read all help files and faq's on the subject
matter (there aren't more than about a dozen) but either did not find
solutions or found them not to work.
Here is the issue. I am trying to run a spatial regression on a
medium-sized dataset. Part of the functions in the
David Winsemius wrote:
What are M, N, and O? All the same magnitude?
In this case, 4,13,10.
What are you doing based on that if( ) determination?
Increasing a counter.
Are you sure you are interpreting your profile results correctly?
No, but I think I am. I'm using proc.time()
This gives the correct result but appears to be slower than the for loop I
was using, I do appreciate the suggestion though.
Peter Ehlers wrote:
Does this
max(apply(yourArray, 3, rowSums))
give you what you want?
-Peter Ehlers
Will Carr wrote:
Working with an NxMxO sized
This seems to work quite well and gives an ~85% speed increase compared to
the for loop. Thanks a bunch!
Peter Ehlers wrote:
Or maybe aperm() is faster:
max(colSums(aperm(yourArray, c(2,1,3
-Peter Ehlers
Peter Ehlers wrote:
Does this
max(apply(yourArray, 3, rowSums))
Hello,
I'm running into a very strange problem:
xrange - c(-2.5,2.5)
xdim - 100
mobility - 0.1
slope - 1.16
urange - slope*xrange
udim - max(slope*xdim,5)
du - (urange[2]-urange[1])/udim
uvec - urange[1]+(1:udim-0.5)*du
# type dependent weight function
Dear R-guru's,
I have some data that I'm writing to a mysql database. I need the database to
generate the primary key and it's not being generated as a unique ID. My
understanding was that primary keys should be unique. I submit a data.frame
with named columns. The only name that it's missing
Proably ole Faq 7.21 again. You are using floating point numbers and
expecting coercion to result in upward rounding.
My guess is that if you use trunc(udim) you will get a different number.
Yep:
trunc(udim)
[1] 115
On Nov 30, 2009, at 2:15 PM, Rupert Mazzucco wrote:
Hello,
I'm running
Simply a manifestation of FAQ 7.31, i.e., a floating-point arithmetic issue.
On my machine,
1.16 * 100 == 116
[1] FALSE
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
On Behalf Of Rupert Mazzucco
Sent: Monday, November 30, 2009 1:15
Dim argument must be a integer, see the return of:
as.integer(slope*xdim)
Try this:
udim - ceiling(max(slope*xdim,5))
On Mon, Nov 30, 2009 at 5:15 PM, Rupert Mazzucco r...@gmx.net wrote:
Hello,
I'm running into a very strange problem:
xrange - c(-2.5,2.5)
xdim - 100
mobility - 0.1
Hi all, I'm trying to convert a series of rgb codes into a color name.
What is my easiest option? So far I'm stuck with just converting to
hex using rgb() and I know R knows a number of colours() but a mapping
of the two has failed me.
Any help in this regard will be highly appreciated.
Regards,
In answer to your 4th question: you are trying to allocate an object
whose size is 1/4 of the addressable memory on your machine. You might
be lucky and have that much available in one piece, but I'm guessing you
don't, which is why the allocation fails. So don't worry about
questions 1,2,
On 30/11/2009 2:25 PM, Jorgy Porgee wrote:
Hi all, I'm trying to convert a series of rgb codes into a color name.
What is my easiest option? So far I'm stuck with just converting to
hex using rgb() and I know R knows a number of colours() but a mapping
of the two has failed me.
Any help in this
Try this:
mycolor - col2rgb(red); mycolor
[,1]
red255
green0
blue 0
colors()[sapply(lapply(colors(), col2rgb), identical, mycolor)]
[1] red red1
On Mon, Nov 30, 2009 at 2:25 PM, Jorgy Porgee jorgy.por...@gmail.comwrote:
Hi all, I'm trying to convert a series of rgb codes
Fantastic. Thanks Duncan. Clearly my google key words were the wrong
ones, nothing of this sort came up. Hope my title is easier to find
somehow..
Regards,
George
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE
You can try something about like this:
yourColor - c(250,235,215)
colors()[which.min(colSums(col2rgb(colors()) - yourColor
)[colSums(col2rgb(colors()) - yourColor) = 0])]
On Mon, Nov 30, 2009 at 5:25 PM, Jorgy Porgee jorgy.por...@gmail.com wrote:
Hi all, I'm trying to convert a series of rgb
On Nov 30, 2009, at 2:24 PM, Henrique Dallazuanna wrote:
Dim argument must be a integer, see the return of:
Less true than you might expect:
x - 3.5
y - 5.2
z - array(0, dim=c(x,y))
z
[,1] [,2] [,3] [,4] [,5]
[1,]00000
[2,]00000
[3,]0
Hi
I have a ts from 1980:1 trough 2009:9 with a frequency of 12. I want to make
25 6 month forecast where the first 6 month forecast is between 2007:4 -
2007:9 and the last 2009:4 - 2009:9.
My script:
Forecast - list()
for (i in 1:25){
j - i + 326
Data - window(omxr, end = time(omxr)[j])
Hello again,
i got this message from the maintainer:
Am Montag, den 30.11.2009, 11:22 +0100 schrieb Heiko Strathmann:
Ok, i reported it.
thanks for trying it out again.
Am 30. November 2009 11:06 schrieb Uwe Ligges
lig...@statistik.tu-dortmund.de:
My apologies, that must have
Esmail esmail...@gmail.com [Mon, Nov 30, 2009 at 01:07:15PM CET]:
ps: Just checked, 'R in a Nutshell':
http://oreilly.com/catalog/9780596801717
release date dec 2009/jan 2010
You can't really judge a book by its cover, and in this case not even
the cover is presented to us. But
Dear List,
I am trying to plot a color.legend() in the right outer margin of my device
region. I have read multiple threads on the subject and still can't get it
right. I have stolen an example from one of the threads to demonstrate my
problem. I have extended the outer margin using
Hello,
I have installed R on my Apple Laptop. Next I wanted to install the
package Rcmdr which requires the package tcltk. But then I get errors
like:
The downloaded packages are in
/var/folders/0p/0pD8fDrwHouNDsQ+k8dGmU+++TI/-Tmp-//RtmpSp4q7p/
downloaded_packages
Loading required
On Mon, 30 Nov 2009, Karin Groothuis wrote:
Hello,
I have installed R on my Apple Laptop. Next I wanted to install the package
Rcmdr which requires the package tcltk. But then I get errors like:
The downloaded packages are in
Data Analysis and Graphics Using R - An Example-Based Approach
John Maindonald and John Braun
2nd edn, Cambridge University Press, January 2007
susan jacobs wrote:
Hi,
im working in R but honestly i don t know how to apply the formulas in my
problem, can someone give some help?
Hi there,
I am trying to use funcion metaMDS (vegan pakage) for Community Ecology
data, but I find no way to calculate the expressed variance of the first 2
axis? is there a way to do that?
Thanks a lot in advance,
Gian
--
View this message in context:
Hi,
im working in R but honestly i don t know how to apply the formulas in my
problem, can someone give some help?
I already learn how we use the formulas but im not understanding the main
issue in my problem.
Johannes Huesing wrote:
Esmail esmail...@gmail.com [Mon, Nov 30, 2009 at
Census from 1990 california in USA. It’s a data frame with data from 20640
zones from Califórnia. Zones are chosen as being geograficly near, wich one
with 1500 persons (mean).
For each zone are provided several informations in the colums from data
frame:
- longitude e latitude from the
Sorry, heres the message:
Hi
yes the freeze is rather a result of the kernelMatrix being non-positive
definite, have a look at the eigenvalues of kernelMatrix
with eigs and you will see even small negative values. This is usualy
the result of small numerical inacuracies in the computation of the
As Ben Bolker has indicated, I am working on various improvements to the
functionality of optim() along with others, esp. Ravi Varadhan and Kate
Mullen.
With relevance to the posts by Sebastien Bihorel and Ben Bolker about
output of point/function value information on each evaluation, I am
Tim Clark wrote:
Dear List,
I am trying to plot a color.legend() in the right outer margin of my device region. I have read multiple threads on the subject and still can't get it right. I have stolen an example from one of the threads to demonstrate my problem. I have extended the outer
You should do your own homework.
cheers,
Rolf Turner
On 1/12/2009, at 10:37 AM, susan jacobs wrote:
Census from 1990 california in USA. It’s a data frame with data
from 20640
zones from Califórnia. Zones are chosen as being geograficly near,
wich one
with 1500
Hey!
Can anyone help me coding in R a normalized kernel matrix.
Basically, I want
K(x,y)/sqrt(*K*(*x, x*)*K*(*y, y*))
Anyone has a piece of code that you could share?
Many thanks,
Parmee
[[alternative HTML version deleted]]
__
Is this book worth its dollar? If so, why?, if not, why not?
Cheers.
--
View this message in context:
http://n4.nabble.com/Ggplot2-Elegant-Graphics-for-Data-Analysis-Use-R-2009-Paperback-tp931702p931702.html
Sent from the R help mailing list archive at Nabble.com.
Hello everyone:
I tried to fit a Beta distribution on a right-skewed dataset using:
fitdistr(temp,densfun=beta,start=list(shape1=3,shape2=2))
To assess the fit, I proceeded as follows:
Using distribution parameters from the sample resulting from fitdistr()
function, I generated 1000 samples
1 - 100 of 138 matches
Mail list logo