Hi Ron, There's a point in the solve where I can tell edge parity. So that you might picture it, generally it follows my 3x3x3 solving method.
Solve: 1 two opposing centers (for reference call them left and right centers) 2 pair up four specific edge pairs (comprising the middle level) 3 place two middle level edge pairs 4 place four FL corners (on the bottom) 5 place the other two middle level edge pairs 6 pair up two specific edge pairs (DL and DR) Although some of what remains may be solved, this usually leaves me with the following still scrambled: 1 Four centers in a line Down, Front, Up and Back 2 Six edge pairs DF UF UB DB UL and UR 3 Last Level corners At this point you can learn to see if you have and edge parity problem, and if you do turn r or l one quarter turn, then solve the rest with an even number of half turns. Have lots of fun, David J --- In [email protected], "Ron" <[EMAIL PROTECTED]> wrote: > > Hi friends, > > I had a nice talk with Frédérick Badie during WC 2005 about > improvements on 4x4x4. > > One of the subjects was avoiding the orientation parity, as already > investigated by Chris Hardwick. > I really think there must be an easier way to check this parity, > than to count the cycles. Counting cycles takes quite a lot of time, > because you have to follow all pieces around the cube. > > I am pretty convinced there must be an easier way. Something like > this: > Take the orientation of all edges according to blindfolded cubing. > For each edge pair, count whether the single cubies are oriented > according to that standard. The total number of flipped edge cubies > must have the factor 4. > > I took some randomly scrambled cubes and it was correct, but I am > sure that in fact this hypothesis is not correct. > Factor 2 does not work (1 flipped edge pair has that...) > > Anyway, please find a counter example of the factor 4. > > Or better, please find an easy way to check the 4x4x4 orientation > parity. Maybe you can do this with diagonal cubies or whatever? > > Or proof that the only way is to follow the cycles. > > Thanks and have fun, > > Ron > ------------------------ Yahoo! Groups Sponsor --------------------~--> Get fast access to your favorite Yahoo! Groups. Make Yahoo! your home page http://us.click.yahoo.com/dpRU5A/wUILAA/yQLSAA/MXMplB/TM --------------------------------------------------------------------~-> Yahoo! Groups Links <*> To visit your group on the web, go to: http://groups.yahoo.com/group/speedsolvingrubikscube/ <*> To unsubscribe from this group, send an email to: [EMAIL PROTECTED] <*> Your use of Yahoo! Groups is subject to: http://docs.yahoo.com/info/terms/
